Explain how the three germ layers participate in the formation of ext.pdf

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Explain how the three germ layers participate in the formation of extraembryonic membranes, and discuss the importance of the placenta as an endocrine organ. Solution The three germ layers are not only responsible for the differentiation of specialized tissue rather are also responsible for the formation of the extraembryonic membrane, that protects and nourishes the embryo. The three extraembryonic membranes are formed from the primitive germ layers: The yolk sac is the membrane that forms from the endoderm and splanchnic mesoderm that grows from the area opaca to form the sac. the yolk sac surrounds the yolk and draws the. the endodermal gets more specialized and digest the yolk and pass its nutrients to the vitelline circulation and thus to the membrane. The amnion is formed from the ectoderm and somatic mesoderm that surrounds the embryo, forming a protective cover for the embryo. the inner layer of the main secretes amniotic fluid in which the embryo floats and prevents it from drying. The chorion-allantoic membrane in which the chorion is made from the ectoderm and somatic mesoderm while the allantoic membrane is formed from the endoderm and splanchnic mesoderm. the allantoic membrane works with the chorion to exchange gasses between the embryo and the outside environment. The allantois also stores the wastes of the embryo. The placenta is considered as an endocrine gland present temporarily during pregnancy. the placenta is responsible for the production of hormones that are responsible for the healthy pregnancy. It secretes placental lactogen, placental growth relaxin as these hormones are important for the healthy propagation of the pregnancy..

Question Completion Status: QUESTION In the absence of oxygen, animal cells, through a series of reactions, convert pyruvate to O lactic O CO2 and ethyl alcohol O carbon dioxide O citric acid QUESTION 2 The prepatory reaction converts the pyruvate into for use in the citric acid cycle) and (which leaves the cell O NADH: NAD O ATP: ADP O glucose; CO2 O acetyl- CoA, carbon dioxide QUESTION 3 Energy released as electrons are transported down the electron transport chain in cellular respiration is directly used to O oxygen O produce co2 O produce NADH and FADH2 O establish a proton (H gradient OS Solution 1.pyruvate is converted to CO2 and ethyl alcohol. 2.preparatory reaction convertpyruvate to acetyl coA and CO2 3.to produce oxygen. 4.glucose is ultimately converted to CO2. 5.cellular respiration requires glucose and CO2. 6.TCA, ETS take place in mitochondria. 7.purpose of dellular respiration to produce ATP. 8.ATP SYNTHASE PHOSPHORYLATES ADP TP ATP. 9.all organisms respire. 10.oxygen is not a product of respiration. 11.oxygen is the final electron acceptor. 12.glycolysis break glucose in 2 molecule pyruvate. 13.CO2 is produced in the preparatory reaction of citric acid cycle. 14.FADH2 and NADH carry electron . 15.in CYTRIC ACID CYCLE 34 molecule ATP produced from one glucose..

Short Answer 1. What are the 5 mechanisms of evolutionary ch.pdf

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Short Answer: 1. What are the 5 mechanisms of evolutionary change that make up Modern synthesis? Solution Answer = 1] Five mechanisms of evolutionary change that make up modern synthesis are 1] Natural selection = is the process by which traits that enhance survival & reproduction becomes more common in succesive generations of population 2] Biased mutation =When there are different probabilities occure at molecular level for different mutations to occur known as biased mutation 3] Genetic drift = is the change in allele frequency from one generation to next that occure because alleles are subjected to sampling error drift acts faster & has more drastic effects in smaller populations genetic drift contribute to speciation 4] Genetic hitchhiking =When one allele in particular haplotype is strongly beneficial natural selection can drive a selective sweep that will also cause the other allales in haplotype to become more common in population is called as genetic hitchhiking 5] Gene flow = Involves the exchange of genes between populations & species gene flow between population can introduce traits & alleles.

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Question Completion Status QUESTION In the absence of oxygen, animal.pdf

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Review Preparation for Statistics A statistics instructor wanted to s.pdf

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Review Preparation for Statistics A statistics instructor wanted to see if student participation in review preparation methods led to higher examination scores. Five students were randomly selected and placed in each test group for a three-week unit on statistical inference. Everyone took the same examination at the end of the unit, and the resulting scores are shown below Is there sufficient evidence at 0.05 to conclude an interaction between the two factors? Is there sufficient evidence to conclude a difference in mean scores based on formula delivery system? Is there sufficient evidence to conclude a difference in mean scores based on the review organization technique? (12-3) Solution.

Problem 3-8BRIDGEPORT ADVERTISING TRIAL BALANCE DECEMBER 31, 2.pdf

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Problem 3-8 BRIDGEPORT ADVERTISING TRIAL BALANCE DECEMBER 31, 2017 Unadjusted Adjusted Dr. Cr. Dr. Cr. $148,820 $148,820 $158,950 $158,950 No. Date Account Titles and Explanation Debit Credit (To record accrued service revenue) (To record supplies used) (To expired insurance) (To record depreciation on equiment) (To record interest accrued on the note) (To record service revenue earned) (To record accrued wages) Assets Liabilities and Stockholders’ Equity % Open Show Work SAVE FOR LATER SUBMIT ANSWER Problem 3-8 Bridgeport Advertising was founded by Murali Vedula in January 2015. Presented below are both the adjusted and unadjusted trial balances as of December 31, 2017. BRIDGEPORT ADVERTISING TRIAL BALANCE DECEMBER 31, 2017 Unadjusted Adjusted Dr. Cr. Dr. Cr.Cash$16,740$16,740Accounts Receivable19,17023,012Supplies9,7606,845Prepaid Insurance4,2202,625Equipment64,70064,700Accumulated Depreciation- Equipment$24,120$29,050Notes Payable8,6008,600Accounts Payable1,8901,890Interest Payable0602Unearned Service Revenue5,3503,405Salaries and Wages Payable0756Common Stock19,22019,220Retained Earnings27,24727,247Dividends19,30019,300Service Revenue62,39368,180Salaries and Wages Expense9,40010,156Insurance Expense1,595Interest Expense602Depreciation Expense4,930Supplies Expense2,915Rent Expense5,5305,530 $148,820 $148,820 $158,950 $158,950Journalize the annual adjusting entries that were made. (Credit account titles are automatically indented when amount is entered. Do not indent manually. If no entry is required, select \"No entry\" for the account titles and enter 0 for the amounts.) No. Date Account Titles and Explanation Debit Credit1.Dec. 31 (To record accrued service revenue)2.Dec. 31 (To record supplies used)3.Dec. 31 (To expired insurance)4.Dec. 31 (To record depreciation on equiment)5.Dec. 31 (To record interest accrued on the note)6.Dec. 31 (To record service revenue earned)7.Dec. 31 (To record accrued wages)Prepare an income statement for the year ended December 31. (Enter loss using either a negative sign preceding the number e.g. -45 or parentheses e.g. (45).) BRIDGEPORTADVERTISING Income Statement December 31, 2017For the Year Ended December 31, 2017For the Quarter Ended December 31, 2017 DividendsExpensesNet Income / (Loss)Retained Earnings, Janaury 1Retained Earnings, December 31RevenuesTotal ExpensesTotal Revenues $ DividendsExpensesNet Income / (Loss)Retained Earnings, Janaury 1Retained Earnings, December 31RevenuesTotal ExpensesTotal Revenues $ Dividends Expenses Net Income / (Loss) Retained Earnings, Janaury 1 Retained Earnings, December 31 Revenues Total Expenses Total Revenues DividendsExpensesNet Income / (Loss)Retained Earnings, Janaury 1Retained Earnings, December 31RevenuesTotal ExpensesTotal Revenues$ Prepare a retained earnings statement for the year ended December 31. (List items that increase retained earnings first.) BRIDGEPORTADVERTISING Retained Earnings Statement December 31, 2017For the Year Ended December 31, 2017For .

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Q1: Define the three types of data flow. Q2: What are the two principles of Protocol Layering? Q3: A sine wave is offset 1/4 cycle with respect to time 0. What is its phase in degrees and radians? Q4: List three properties for Infrared waves. Solution : 4) Infrared (IR) waves are : - electromagnetic in nature with longer wavelengths than visible light - wavelength is from 0.74 micrometres (µm) to 300 µm. - frequency range is from 1 to 400 THz IR is thermal radiation emitted by objects near room temperature. 3) phase in degree : 1 complete cycle = 360 ° Then 1/4th cycle =1/4*360= 90° Phase in radians : 1° =2/360 radians Then 90° = 90*2/360 = /2 rad = 1.57 rad 1) Simplex:All the data flow is unidirectional from transmitter to receiver. Duplex communication is two way in that we have two types: Half-duplex: communication may be likened to two way Either can may be used to transmit or receive, but not at the same time Fullduplex:Full-duplex communication is more like a true telephone, where two people can talk at the same time and hear one another simultaneously. 1) When communication is simple we may need only one protocol. When the communication is Complex we need a protocol at each layer which is called protocol layering We need to understand two simple principles for that a) The first principle dictates that if we want bidirectional communication, we need to make each layer so that it is able to perform two opposite tasks, one in each direction. b) The second principle that we need to follow in protocol layering is that the two objects under each layer at both sides should be identical..

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mitosis is a special set of events that occur in what region of the cell? mitosis is a special set of events that occur in what region of the cell? mitosis is a special set of events that occur in what region of the cell? Solution Mitosis is found to occur in the cell nuclei of eukaryotic cells. In the process of mitosis, one cell divides into two cells and these two cells will be genetically identical to the original cell. Our body will grow and repair itself due to the process of mitosis. Mitosis includes five phases: prophase, prometaphase, metaphase, anaphase and telophase..

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Identify nursing diagnoses goal and outcome criteria and interventions for the postoperative patient Identify nursing diagnoses goal and outcome criteria and interventions for the postoperative patient Solution ASSESSMENT: - After the surgery, when the operation procedure is completed, the patient is usually shifted to intensive care unit. When patient is admitted to PACU determine the medical diagnosis, the surgery procedure, pain, consciousness, vital signs, medical history, how patient tolerated the procedure? what was the medication given, and other assessment data listed earlier. Check and set up equipment like oxygen, suction devices, urinary drainage etc. A more detailed assessment should be performed when a patient returns to the nursing unit. It is actually collecting, organizing, validating, and documenting patient data and its purpose is to establish a database about the patient’s response to health concerns or illness and the ability to manage health care needs. DIAGNOSIS: - Medical diagnoses are important factors influencing patient outcomes during hospitalization. For example, ICU patients with infectious diseases at admission had higher mortality than the patients with gastrointestinal diseases. After surgery patients are at an increased risk of severe complication. Nursing diagnosis is the nurse’s clinical judgment about the patient’s response to potential health conditions and comorbid medical conditions. Several studies show that these diagnosis influence 31 different types of patient outcomes (e.g. hospital mortality, the length of stay, and ICU readmission) and interventions. A standard nursing diagnosis includes three structural components: the problem, the etiology and supporting data. Its purpose is to identify patient’s strengths and health problems that can be prevented or resolved by collaborative and independent nursing interventions. and to develop a list of nursing diagnoses and collaborative problems. GOAL AND OUTCOME: - The goal is aimed at the medical diagnosis. The outcomes are aimed at meeting the goals. A patient goal represents a predicted resolution of a diagnosis, evidence of progress toward resolution, progress toward improved health, or continued maintenance of good health. Each goal is limited to a time so the health care team has a common time limit for solving the problem. For example, the goal of “patient will achieve pain relief. A short-term goal is an objective behavior or response that you expect a patient to achieve in a short time, usually in a week. A long-term goal is an objective behavior or response that you expect a patient to achieve over a longer period, usually over several weeks, or even several months (for example “Patient will leave nicotine products within two months”). Determine how to prevent, reduce, or resolve the identified patient problems; how to support patient strengths; and how to implement nursing interventions in a well organized, individualized, and goal-directed way, .

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How would you arrange these concepts in terms of concreteness (from most to least concrete)? Justify your arrangement. Asset Common stock Equity Investment Security Stock Solution Below is the arrangement of concepts in terms of concreteness (most to least): 1. Stock 2. Common Stock 3. Security 4. Investment 5. Asset 6. Equity Justification : As per my understanding, I have arranged all concepts based on how easily can we do the valuation and the scope of a particular concept. Stock is a current asset i.e. the valuation of stock can be done on an yearly basis. Since, it is short term in nature and can be valued at cost using methods like FIFO, LIFO, etc. Cost is easily available by looking at the invoices, purchase orders, etc. Common Stock is a long term liability also called as equity shares. They can be valued using different techniques like Dividend Discount model. Stock prices are easily available in the exchange markets. Securities comes next as they are wider than Common stock. They are the tradeable financial instruments. They are divided into three parts - equity securities, debt securities and derivatives. We can value securities from the market which is determined by the demand and supply forces. Investments includes short term and long term investments. They are valued at the lesser of cost or fair market value. The market value of investemnts can not be seen on stock exchanges and hence lesser concrete than securities. Assets includes both short term and long term assets. Fixed assets like Long term investments, building, factory, machinery and current assets like Stock, short term investments, account receivables, cash are included in the broad defination of assets. Hence, investments are a subset of assets and hence more concrete than assets. Again, there is no trade market for assets to do the asset valuation. Equity is difference between assets and liabilities. Equity is a wider term which includes common stock, preffered stock, retained earnings (calculated from Income statement), security premium, revaluation reserves (calculated as the difference between the fair market value and book value of assets). Hence, they can be regarded as least concrete of the given list..

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Compare and contrast the structure of a nephron with that of an alveolus in the lung. Identify TWO (2) similarities and TWO (2) differences. (2 marks) Solution DIFFERENCES:1=Each alveolas is a very small bag_like structure bearing a component known as Surfactant while as each nephron is a curled tube_like arrangement with a cup_shaped structure called Bowman\'s capsule.2=Alveoli are present inside the lungs while as nephrons are lying in kidneys. SIMILARITIES:1=Both Alveoli and nephrons are present in larger quantity in their respective organs.2=Both the structures act as functional units..

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Classless addressing was introduced to extend the life of the IPv address scheme: a. True b. False Solution True. Explanation: IP addresses are described as consisting of two groups of bits in the address: the most significant bits are the network address (or network prefix or network block), which identifies a whole network or subnet, and the least significant set forms the host identifier, which specifies a particular interface of a host on that network. This division is used as the basis of traffic routing between IP networks and for address allocation policies. Classful network design for IPv4 sized the network address as one or more 8-bit groups, resulting in the blocks of Class A, B, or C addresses. Classless Inter-Domain Routing allocates address space to Internet service providers and end users on any address bit boundary, instead of on 8-bit segments. In IPv6, however, the interface identifier has a fixed size of 64 bits by convention, and smaller subnets are never allocated to end users..

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Before first law of thermodynamics, there is zeroth law of thermodynamics. The thermometer works on the principle of zeroth law of thermodynamics. Can you explain what is a zeroth law of thermodynamics? Solution Zeroth law states that Objects into contact will reach a thermal equilibrium (and heat transfers from hotter to colder), this means one can use a device that can measure this difference of this quantity as follows: We have a device (called a thermometer) which has an indication. When the \"thermometer device\" comes into contact with another object, 0th law states that they wil reach thermal equilibrium . Then the indication of the device will change to reflect the difference of this quantity that changed or transfered and refered to as temperature . One such device is the thermometer based on mercury (which is used as the indicator due to its special heat expansion factor)..

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An enzyme that has lost its shape a. is denatured and no longer functional. b. is denatured but still functional. c. is not different from a regular enzyme as shape is not important. d. can be restored by extreme temperatures or pH swings. Predict whether each of the following has ionic, polar covalent, or not O_2 Solution 7) Each enzyme has specific active sites. When an enzyme loses its shape then its active sites are no longer functional. As a result, the properties of the enzyme are destroyed. This process is called denaturation. Therefore, an enzyme that has lost its shape is denatured and no longer functional. (Answer) (a) 8) In oxygen molecule (O2), two oxygen atoms are joined by double covalent bond. The bonds are formed by sharing of electron pairs. The electron pairs are equally shared between two oxygen atoms. For this reason, oxygen molecule has non-polar covalent bonds..

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