1) The document discusses horizontal forces on pile foundations, including temporary forces from wind, earthquakes, and boat impacts, as well as permanent forces from active soil pressure and groundwater pressure. 2) It explains passive soil pressure diagrams and calculations for determining the passive soil force and its point of application on a pile. 3) Formulas are provided for calculating the allowed temporary horizontal force on a pile based on the passive soil resistance, and checking if it is less than the pile's allowed design capacity.

1. GAYA HORIZONTAL TERHADAP TIANG PANCANG
BebanHorizontal Sementara(Temporary)
BebanHorizontal Tetap(Permanent)
Misal: BebanAngin, BebanGempa, BenturanKapalpadaDermaga, dll
Misal: TekananTanah Aktif, TekananAir Tanah, dll
Gaya Horizontal yang mungkinditerimaTiangPancang

2. TekananTanah Pasif
H
Ld
Lp
Ld = DalamTitikJepit
dariMukaTanah
Lp= PanjangTiangyang
masukkedalamTanah
Ld = 1/4 s/d 1/3 Lp

3. A
O
K
C
G
D
H
E
I
J
F
L
M
N
Diagram TekananTanah Pasif
La
Ld
Lp
Lh= La + Ld
OK = Kpx gx Lhx B
Kp: Koef. Tekanan
Tanah Pasif
= tg2(45 + f/2)
g: BeratIsiTanah
B :LebarPoeryang menerimagayahorizontal

4. A
O
K
C
G
D
H
E
I
J
F
L
M
N
Diagram TekananTanah Pasif
Ld = 1/4 1/3 Lp
La
Ld dibagi4 bagianyang sama
CD = DE = EF = FO
CG= CG
DL= ¾ x DH
EM= ½ x EI
FN= ¼ x FJ
O= 0
CG = Kpx gx AC x B
Perhit. TekananTanah Pasif
B :LebarPoeryang menerimagayahorizontal
DH = Kpx gx AD x B
E I = Kpx gx AE x B
FJ = Kpx gx AF x B
TekananTanah PasifYang Bekerja

5. A
O
K
C
G
D
H
E
I
J
F
L
M
N
Diagram TekananTanah Pasif
P1
P2
P3
P4
P5
P1= LuasDiagram ACG= ½ x CG x AC
P2= LuasDiagram CGLD= ½ x (CG+DL) x CD
P3= LuasDiagram DLME= ½ x (DL+EM) x DE
P4= LuasDiagram EMNF= ½ x (EM+FN) x EF
P5= LuasDiagram FNO= ½ x FN x FO
+
SP

6. A
O
C
G
D
E
F
L
M
N
P1
P2
P3
P4
P5
a
b
c
d
e

7. LETAK TITIK TANGKAP GAYA (Lz)
SP x Lz= (P1 X a) + (P2 x b) + (P3 x c) + (P4 x d) + (P5 x e)
Lz=
(P1 X a) + (P2 x b) + (P3 x c) + (P4 x d) + (P5 x e)
SP
GAYA HORIZONTAL SEMENTARA YANG DIIJINKAN
S M = 0
H =
H x (La + Ld + Lz) = SP x 2 x Lz
SP x 2 x Lz
(La + Ld + Lz)

8. PERHITUNGAN BIDANG MOMEN
M1= H (La + Ld –a)
M2= H (La + Ld –b) –P1 (a –b)
M3= H (La + Ld –c) –P1 (a –c) –P2 (b –c)
M4= H (La + Ld –d) –P1 (a –d) –P2 (b –d) –P3 (c –d)
M5 = H (La + Ld –e) –P1 (a –e) –P2 (b –e) –P3 (c –e) –P4 (d –e)
M6 = H (La + Ld) –P1 x a –P2 x b –P3 x c –P4 x d –P5 x e
M1
M2
M3
M4
M5
M6
P1
P2
P3
P4
P5
a
b
c
d
e
H

9. H
S = 3m
Ph =
M max
s
Ph yang terjadipadatiaptiang(Ph tiang) =
Ph
n
n : Jumlahtiangyang menerimagayahorizontal
(contohpadagambarn = 2 tiang)
Gaya yang diperbolehkanpadatiang
P tiang= sbtiangx A tiang
sbtiang: TeganganIjinTiang
A tiang: LuasPenampangTiang
SyaratAman
Ph tiang< P tiang
B

10. KapasitasIjinTiangmenurutENR (Engineering News Record) denganeffesiensi(eh) = 1
Qu=KapasitasIjinTiang
Wh=BeratHammer
h=Tinggijatuh
F=AngkaKeamanan; F = 6
s=Penetrasiper pukulan
Qu=
Whx h
F (s + 0,25)
Qu=
Whx h
F (s + 2,5)
Drop Hammer
Single Acting Hammer