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Standard Deviation
Dr.A.Antonyraj
Assistant Professor
Department of Management studies,
Bon Secours College for women, Thanjavur.
Variance: a measure of how data
points differ from the mean
• Data Set 1: 3, 5, 7, 10, 10
Data Set 2: 7, 7, 7, 7, 7
What is the mean and median of the above data set?
Data Set 1: mean = 7, median = 7
Data Set 2: mean = 7, median = 7
But we know that the two data sets are not identical! The
variance shows how they are different.
We want to find a way to represent these two data set
numerically.
How to Calculate?
• If we conceptualize the spread of a distribution
as the extent to which the values in the
distribution differ from the mean and from each
other, then a reasonable measure of spread
might be the average deviation, or difference, of
the values from the mean.
( )x X
N
 
• Although this might seem reasonable, this expression
always equals 0, because the negative deviations about the
mean always cancel out the positive deviations about the
mean.
• We could just drop the negative signs, which is the same
mathematically as taking the absolute value, which is known
as the mean deviations.
• The concept of absolute value does not lend itself to the kind
of advanced mathematical manipulation necessary for the
development of inferential statistical formulas.
• The average of the squared deviations about the mean is
called the variance.
 
2
2
x X
N

 

 
2
2
1
x X
s
n
 


For population variance
For sample variance
X XX XScore
X
( )2
1
3
2
5
3
7
4
10
5
10
Totals
35
The mean is 35/5=7.
X XX XScore
X
( )2
1
3 3-7=-4
2
5 5-7=-2
3
7 7-7=0
4
10 10-7=3
5
10 10-7=3
Totals
35
X XX XScore
X
( )2
1
3 3-7=-4 16
2
5 5-7=-2 4
3
7 7-7=0 0
4
10 10-7=3 9
5
10 10-7=3 9
Totals
35 38
X XX XScore
X
( )2
1
3 3-7=-4 16
2
5 5-7=-2 4
3
7 7-7=0 0
4
10 10-7=3 9
5
10 10-7=3 9
Totals
35 38
 
2
2 38
7.6
5
x X
s
n
 
  
Example 2
Dive Mark Myrna
1 28 27
2 22 27
3 21 28
4 26 6
5 18 27
Find the mean, median, mode, range?
mean 23 23
median 22 27
range 10 22
What can be said about this data?
Due to the outlier, the median is more typical of overall performance.
Which diver was more consistent?
X X X XDive Mark's Score
X
( )2
1 28 5 25
2 22 -1 1
3 21 -2 4
4 26 3 9
5 18 -5 25
Totals 115 0 64
Mark’s Variance = 64 / 5 = 12.8
Myrna’s Variance = 362 / 5 = 72.4
Conclusion: Mark has a lower variance therefore he is more consistent.
standard deviation - a measure of
variation of scores about the mean
• Can think of standard deviation as the average
distance to the mean, although that's not
numerically accurate, it's conceptually helpful.
All ways of saying the same thing: higher
standard deviation indicates higher spread, less
consistency, and less clustering.
• sample standard deviation:
• population standard deviation:
 
2
1
x X
s
n
 


 
2
x
N


 

Another formula
• Definitional formula for variance for data in a
frequency distribution
• Definitional formula for standard deviation for
data in a frequency distribution
2
2
( )X X f
S
f




2
( )X X f
S
f




X X X X X XMyrna’s Score X f ( )2 ( )2 x f
28 1
27 3
6 1
115 5
The mean is 23
X X X X X XMyrna’s Score X f ( )2 ( )2 x f
28 1 5
27 3 4
6 1 -17
115 5
X X X X X XMyrna’s Score X f ( )2 ( )2 x f
28 1 5 25
27 3 4 16
6 1 -17 289
115 5
X X X X X XMyrna’s Score X f ( )2 ( )2 x f
28 1 5 25 25
27 3 4 16 48
6 1 -17 289 289
115 5 362
Variance = S2 = 362 / 5 = 72.4
Standard Deviation = 72.4 = 8.5
round-off rule – carry
one more decimal
place than was
present in the
original data
Bell shaped curve
• empirical rule for data (68-95-99) - only applies
to a set of data having a distribution that is
approximately bell-shaped: (figure pg 220)
•  68% of all scores fall with 1 standard deviation
of the mean
•  95% of all scores fall with 2 standard deviation
of the mean
•  99.7% of all scores fall with 3 standard
deviation of the mean

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  • 1. Standard Deviation Dr.A.Antonyraj Assistant Professor Department of Management studies, Bon Secours College for women, Thanjavur.
  • 2. Variance: a measure of how data points differ from the mean • Data Set 1: 3, 5, 7, 10, 10 Data Set 2: 7, 7, 7, 7, 7 What is the mean and median of the above data set? Data Set 1: mean = 7, median = 7 Data Set 2: mean = 7, median = 7 But we know that the two data sets are not identical! The variance shows how they are different. We want to find a way to represent these two data set numerically.
  • 3. How to Calculate? • If we conceptualize the spread of a distribution as the extent to which the values in the distribution differ from the mean and from each other, then a reasonable measure of spread might be the average deviation, or difference, of the values from the mean. ( )x X N  
  • 4. • Although this might seem reasonable, this expression always equals 0, because the negative deviations about the mean always cancel out the positive deviations about the mean. • We could just drop the negative signs, which is the same mathematically as taking the absolute value, which is known as the mean deviations. • The concept of absolute value does not lend itself to the kind of advanced mathematical manipulation necessary for the development of inferential statistical formulas. • The average of the squared deviations about the mean is called the variance.   2 2 x X N       2 2 1 x X s n     For population variance For sample variance
  • 5. X XX XScore X ( )2 1 3 2 5 3 7 4 10 5 10 Totals 35 The mean is 35/5=7.
  • 6. X XX XScore X ( )2 1 3 3-7=-4 2 5 5-7=-2 3 7 7-7=0 4 10 10-7=3 5 10 10-7=3 Totals 35
  • 7. X XX XScore X ( )2 1 3 3-7=-4 16 2 5 5-7=-2 4 3 7 7-7=0 0 4 10 10-7=3 9 5 10 10-7=3 9 Totals 35 38
  • 8. X XX XScore X ( )2 1 3 3-7=-4 16 2 5 5-7=-2 4 3 7 7-7=0 0 4 10 10-7=3 9 5 10 10-7=3 9 Totals 35 38   2 2 38 7.6 5 x X s n     
  • 9. Example 2 Dive Mark Myrna 1 28 27 2 22 27 3 21 28 4 26 6 5 18 27 Find the mean, median, mode, range? mean 23 23 median 22 27 range 10 22 What can be said about this data? Due to the outlier, the median is more typical of overall performance. Which diver was more consistent?
  • 10. X X X XDive Mark's Score X ( )2 1 28 5 25 2 22 -1 1 3 21 -2 4 4 26 3 9 5 18 -5 25 Totals 115 0 64 Mark’s Variance = 64 / 5 = 12.8 Myrna’s Variance = 362 / 5 = 72.4 Conclusion: Mark has a lower variance therefore he is more consistent.
  • 11. standard deviation - a measure of variation of scores about the mean • Can think of standard deviation as the average distance to the mean, although that's not numerically accurate, it's conceptually helpful. All ways of saying the same thing: higher standard deviation indicates higher spread, less consistency, and less clustering. • sample standard deviation: • population standard deviation:   2 1 x X s n       2 x N     
  • 12. Another formula • Definitional formula for variance for data in a frequency distribution • Definitional formula for standard deviation for data in a frequency distribution 2 2 ( )X X f S f     2 ( )X X f S f    
  • 13. X X X X X XMyrna’s Score X f ( )2 ( )2 x f 28 1 27 3 6 1 115 5 The mean is 23
  • 14. X X X X X XMyrna’s Score X f ( )2 ( )2 x f 28 1 5 27 3 4 6 1 -17 115 5
  • 15. X X X X X XMyrna’s Score X f ( )2 ( )2 x f 28 1 5 25 27 3 4 16 6 1 -17 289 115 5
  • 16. X X X X X XMyrna’s Score X f ( )2 ( )2 x f 28 1 5 25 25 27 3 4 16 48 6 1 -17 289 289 115 5 362 Variance = S2 = 362 / 5 = 72.4 Standard Deviation = 72.4 = 8.5 round-off rule – carry one more decimal place than was present in the original data
  • 17. Bell shaped curve • empirical rule for data (68-95-99) - only applies to a set of data having a distribution that is approximately bell-shaped: (figure pg 220) •  68% of all scores fall with 1 standard deviation of the mean •  95% of all scores fall with 2 standard deviation of the mean •  99.7% of all scores fall with 3 standard deviation of the mean