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PULSE MODULATION
EKT343 –Principle of Communication
Engineering
Chapter Outline
PART 1:
• Basic sampling technique
• Generation and recovery
– Pulse Amplitude Modulation (PAM)
– Pulse Duration Modulation (PDM)
– Pulse Position Modulation (PPM)
• Advantages & Disadvantages
EKT343 –Principle of Communication
Engineering
2
Sampling
To convert a signal from continuous time to
discrete time, a process called sampling is
used. The value of the signal is measured at
certain intervals in time. Each measurement is
referred to as a sample.
 When the continuous analog signal is sampled
at a frequency F, the resulting discrete signal has
more frequency components than did the analog
signal. To be precise, the frequency components
of the analog signal are repeated at the sample
rate.
EKT343 –Principle of Communication
Engineering
3
Sampling
• Sampling a signal: Analog → Digital conversion by
reading the value at discrete points
• A process of taking samples of information signal at a rate of
Nyquist’s sampling frequency.
EKT343 –Principle of Communication
Engineering
4
• Nyquist’s Sampling Theorem :
EKT343 –Principle of Communication
Engineering
5
The original information signal can be reconstructed at the receiver
with minimal distortion if the sampling rate in the pulse modulation
system equal to or greater than twice the maximum information
signal frequency.
fs >= 2fm (max)
EKT343 –Principle of Communication
Engineering
4
 infinite bandwidth cannot be sampled.
 the sampling rate must be at least 2 times the highest
frequency, not the bandwidth.
EKT343 –Principle of Communication
Engineering
7
A complex low-pass signal has a bandwidth of
200 kHz. What is the minimum sampling rate for
this signal?
Solution:
The bandwidth of a low-pass signal is between 0 and f,
where f is the maximum frequency in the signal.
Therefore, we can sample this signal at 2 times the
highest frequency (200 kHz). The sampling rate is
therefore 400,000 samples per second.
Example 1
EKT343 –Principle of Communication
Engineering
8
A complex bandpass signal has a bandwidth of
200 kHz. What is the minimum sampling rate for
this signal?
Solution :
We cannot find the minimum sampling rate in this case
because we do not know where the bandwidth starts or
ends. We do not know the maximum frequency in the
signal.
Example 2
Undersampling & Oversampling
Undersampling is essentially sampling too
slowly, or sampling at a rate below the
Nyquist frequency for a particular signal of
interest. Undersampling leads to aliasing and
the original signal cannot be properly
reconstructed
Oversampling is sampling at a rate beyond
twice the highest frequency component of
interest in the signal and is usually desired.
EKT343 –Principle of Communication
Engineering
9
• If the required condition of the sampling theorem that fs
>= 2fmmax is not met, then errors will occur in the
reconstruction.
• When such errors arise due to undersampling, aliasing is
said to occur
• Undersampling: Sampling rate is too low to capture high-
frequency variation
EKT343 –Principle of Communication
Engineering
10
Aliasing effect
Aliasing effect
EKT343 –Principle of Communication
Engineering
11
12
For an intuitive example of the Nyquist theorem, let us
sample a simple sine wave at three sampling rates:
a) fs = 2f (Nyquist rate)
b) fs = 4f (2 times the Nyquist rate),
c) fs = f (one-half the Nyquist rate).
Figure shows the sampling and the subsequent recovery of
the signal.
SOLUTION:
It can be seen that sampling at the Nyquist rate can create
a good approximation of the original sine wave (part a).
Oversampling in part b can also create the same
approximation, but it is redundant and unnecessary.
Sampling below the Nyquist rate (part c) does not produce
a signal that looks like the original sine wave.
Example 3
EKT343 –Principle of Communication
Engineering
13
Recovery of a sampled sine wave for different sampling rates
Natural Sampling
• Tops of the sample pulses retain their natural
shape during the sample interval.
• Frequency spectrum of the sampled output is
different from an ideal sample.
• Amplitude of frequency components
produced from narrow, finite-width sample
pulses decreases for the higher harmonics
– Requiring the use of frequency equalizers
EKT343 –Principle of Communication
Engineering
14
Natural Sampling
EKT343 –Principle of Communication
Engineering
15
Flat-top Sampling
• Common used in PCM systems.
• Accomplish in a sample-and-hold circuit
– To periodically sample the continually changing analog
input voltage & convert to a series of constant-amplitude
PAM voltage levels.
• The input voltage is sampled with a narrow pulse
and then held relatively constant until the next
sample is taken.
EKT343 –Principle of Communication
Engineering
16
Cont’d…
• Sampling process alters the frequency
spectrum & introduces aperture error.
• The amplitude of the sampled signal changes
during the sample pulse time.
• Advantages:
– Introduces less aperture distortion
– Can operate with a slower ADC
EKT343 –Principle of Communication
Engineering
17
Flat-top Sampling
EKT343 –Principle of Communication
Engineering
18
• Sampling analog information signal
• Converting samples into discrete pulses
• used to represent an analog signal with digital data
• among the first of the pulse techniques to be utilized
 Carrier signal is pulse waveform and the modulated signal
is where one of the carrier signal’s characteristic (either
amplitude, width or position) is changed according to
information signal.
EKT343 –Principle of Communication
Engineering
19
 The amplitude of
pulses is varied in
accordance with the
information signal.
 Width & position
constant.
 2 types –
double polarity
single polarity
Pulse Amplitude Modulation (PAM)
EKT343 –Principle of Communication
Engineering
20
Natural Sampling (PAM)
• A PAM signal is generated by using a pulse train, called the
sampling signal (or clock signal) to operate an electronic
switch or "chopper". This produces samples of the analog
message signal, as shown in Figure
EKT343 –Principle of Communication
Engineering
21
Flat Top Sampling (PAM)
• a sample-and-hold circuit is used in conjunction with the
chopper to hold the amplitude of each pulse at a constant
level during the sampling time
EKT343 –Principle of Communication
Engineering
22
Flat-top sampling – generation of PAM signals.
Cont’d
• Pulse duration (τ) supposed to be very small
compare to the period, Ts between 2 samples
• Lets max frequency of the signal, W
• If ON/OFF time of the pulse is same,
frequency of the PAM pulse is
EKT343 –Principle of Communication
Engineering
23
Fs >= 2 W
Ts =< 1/2W
T « Ts =< 1/2W
2
1
max f
Transmission BW of PAM Signal
• Bandwidth required for transmitter of PAM
signal will be equal to maximum frequency
EKT343 –Principle of Communication
Engineering
24
2
1
max

 fBT
Advantages & Disadvantages PAM
• Advantage:
– it allows multiplexing, i.e., the sharing of the same
transmission media by different sources (or users). This
is because a PAM signal only occurs in slots of time,
leaving the idle time for the transmission of other PAM
signals.
• Disadvantage:
– require a larger transmission bandwidth (very large
compare to its maximum frequency)
– Interference of noise is maximum
– Needed for varies transmission power
EKT343 –Principle of Communication
Engineering
25
Pulse Density Modulation (PDM)
• Sometimes called Pulse Duration Modulation/ Pulse Width
Duration (PWM).
• The width of pulses is varied in accordance to information
signal
• Amplitude & position constant.
• PDM is used in a great number of applications
Communications
• The width of the transmitted pulse corresponds to the
encoded data value
EKT343 –Principle of Communication
Engineering
26
PDM
• Immune to noise
• Power Delivery
– Reduce the total amount of power delivered to a load
• Applications: DC Motors, Light Dimmers, Anti-Lock Breaking System
EKT343 –Principle of Communication
Engineering
27
• PWM signal output is generated by comparing summation
result with reference level
EKT343 –Principle of Communication
Engineering
28
Cont’d...
EKT343 –Principle of Communication
Engineering
29
Advantages & Disadvantages PDM
• Advantage:
– Noise performance is better compare to PAM.
• Disadvantages:
– require a larger power transmission compare to
PPM
– Require very large bandwidth compare to PAM
EKT343 –Principle of Communication
Engineering
30
Pulse Position Modulation (PPM)
• Modulation in which the temporal positions of the pulses are
varied in accordance with some characteristic of the
information signal.
• Amplitude & width constant.
• The higher the amplitude of the sample, the farther to the
right the pulse is position within the prescribed time slot.
EKT343 –Principle of Communication
Engineering 31
Advantages & Disadvantages PPM
• Advantage:
– The amplitude is held constant thus less noise
interference.
– Signal and noise separation is very easy
– Due to constant pulse widths and amplitudes,
transmission power for each pulse is same.
– Require less power compare to PAM and PDM because
of short duration pulses.
• Disadvantages:
– Require very large bandwidth compare to PAM.
EKT343 –Principle of Communication
Engineering
32
Transmission BW of PDM/PPM Signal
• PPM and PDM need a sharp rise time and fall
time for pulses in order to preserve the message
information.
• Lets rise time, tr
• From formula above, we know that transmission
BW of PPM and PDM is higher than PAM
EKT343 –Principle of Communication
Engineering
33
tr« Ts
r
T
t
B
2
1

Transmission BW of PAM Signal
• Pulse duration (τ) supposed to be very small
compare to the period, Ts between 2 samples
• Lets max frequency of the signal, W
• If ON/OFF time of the pulse is same,
frequency of the PAM pulse is
EKT343 –Principle of Communication
Engineering
34
Fs >= 2 W
Ts =< 1/2W
T « Ts =< 1/2W
2
1
max f
Example 4
• For PAM transmission of voice signal with W =
3kHz. Calculate BT if fs = 8 kHz and τ = 0.1 Ts
• SOLUTION
EKT343 –Principle of Communication
Engineering
35
sxT
sx
kHzf
T
s
s
s
5
4
1025.11.0
1025.1
8
11





kHzB
WB
W
T
T
40
2
1
2
1
2
1






Example 5
For the same information as in example 1, find
minimum transmission BW needed for PPM
and PDM. Given tr= 1% of the width of the
pulse.
SOLUTION
EKT343 –Principle of Communication
Engineering
36
MHzB
t
B
sxt
T
r
T
r
4
2
1
1025.1
100
1 7


 

Pulse Modulation
EKT343 –Principle of Communication
Engineering
37
PAM PDM PPM
Relation with
modulating signal
Amplitude of the
pulse is
proportional to
amplitude of
modulating signal
Width of the pulse
is proportional to
amplitude of
modulating signal
Relative position of
the pulse is
proportional to
amplitude of
modulating signal
BW of the
transmission
channel
depends on width
of the pulse
Depends of rise
time of the pulse
Depends on rising
time of the pulse
Instantaneous
power
varies varies Remains constant
Noise interference High Minimum Minimum
Complexity of the
system
Complex Simple simple
EKT343 –Principle of Communication
Engineering
38
• PAM, PWM, PPM
EKT343 –Principle of Communication
Engineering
39
Advantages & Drawbacks of Pulse Modulation
• Noise immunity.
• Relatively low cost digital
circuitry.
• Able to be time division
multiplexed with other pulse
modulated signal.
• Storage of digital streams.
• Error detection & correction
• Requires greater BW to transmit
& receive as compared to its
analog counterpart.
• Special encoding & decoding
methods must be used to
increased transmission rates &
more difficult to be recovered.
• Requires precise
synchronization of clocks
between Tx & Rx.
EKT343 –Principle of Communication
Engineering
40

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Part 1

  • 1. PULSE MODULATION EKT343 –Principle of Communication Engineering
  • 2. Chapter Outline PART 1: • Basic sampling technique • Generation and recovery – Pulse Amplitude Modulation (PAM) – Pulse Duration Modulation (PDM) – Pulse Position Modulation (PPM) • Advantages & Disadvantages EKT343 –Principle of Communication Engineering 2
  • 3. Sampling To convert a signal from continuous time to discrete time, a process called sampling is used. The value of the signal is measured at certain intervals in time. Each measurement is referred to as a sample.  When the continuous analog signal is sampled at a frequency F, the resulting discrete signal has more frequency components than did the analog signal. To be precise, the frequency components of the analog signal are repeated at the sample rate. EKT343 –Principle of Communication Engineering 3
  • 4. Sampling • Sampling a signal: Analog → Digital conversion by reading the value at discrete points • A process of taking samples of information signal at a rate of Nyquist’s sampling frequency. EKT343 –Principle of Communication Engineering 4
  • 5. • Nyquist’s Sampling Theorem : EKT343 –Principle of Communication Engineering 5 The original information signal can be reconstructed at the receiver with minimal distortion if the sampling rate in the pulse modulation system equal to or greater than twice the maximum information signal frequency. fs >= 2fm (max)
  • 6. EKT343 –Principle of Communication Engineering 4  infinite bandwidth cannot be sampled.  the sampling rate must be at least 2 times the highest frequency, not the bandwidth.
  • 7. EKT343 –Principle of Communication Engineering 7 A complex low-pass signal has a bandwidth of 200 kHz. What is the minimum sampling rate for this signal? Solution: The bandwidth of a low-pass signal is between 0 and f, where f is the maximum frequency in the signal. Therefore, we can sample this signal at 2 times the highest frequency (200 kHz). The sampling rate is therefore 400,000 samples per second. Example 1
  • 8. EKT343 –Principle of Communication Engineering 8 A complex bandpass signal has a bandwidth of 200 kHz. What is the minimum sampling rate for this signal? Solution : We cannot find the minimum sampling rate in this case because we do not know where the bandwidth starts or ends. We do not know the maximum frequency in the signal. Example 2
  • 9. Undersampling & Oversampling Undersampling is essentially sampling too slowly, or sampling at a rate below the Nyquist frequency for a particular signal of interest. Undersampling leads to aliasing and the original signal cannot be properly reconstructed Oversampling is sampling at a rate beyond twice the highest frequency component of interest in the signal and is usually desired. EKT343 –Principle of Communication Engineering 9
  • 10. • If the required condition of the sampling theorem that fs >= 2fmmax is not met, then errors will occur in the reconstruction. • When such errors arise due to undersampling, aliasing is said to occur • Undersampling: Sampling rate is too low to capture high- frequency variation EKT343 –Principle of Communication Engineering 10 Aliasing effect
  • 11. Aliasing effect EKT343 –Principle of Communication Engineering 11
  • 12. 12 For an intuitive example of the Nyquist theorem, let us sample a simple sine wave at three sampling rates: a) fs = 2f (Nyquist rate) b) fs = 4f (2 times the Nyquist rate), c) fs = f (one-half the Nyquist rate). Figure shows the sampling and the subsequent recovery of the signal. SOLUTION: It can be seen that sampling at the Nyquist rate can create a good approximation of the original sine wave (part a). Oversampling in part b can also create the same approximation, but it is redundant and unnecessary. Sampling below the Nyquist rate (part c) does not produce a signal that looks like the original sine wave. Example 3
  • 13. EKT343 –Principle of Communication Engineering 13 Recovery of a sampled sine wave for different sampling rates
  • 14. Natural Sampling • Tops of the sample pulses retain their natural shape during the sample interval. • Frequency spectrum of the sampled output is different from an ideal sample. • Amplitude of frequency components produced from narrow, finite-width sample pulses decreases for the higher harmonics – Requiring the use of frequency equalizers EKT343 –Principle of Communication Engineering 14
  • 15. Natural Sampling EKT343 –Principle of Communication Engineering 15
  • 16. Flat-top Sampling • Common used in PCM systems. • Accomplish in a sample-and-hold circuit – To periodically sample the continually changing analog input voltage & convert to a series of constant-amplitude PAM voltage levels. • The input voltage is sampled with a narrow pulse and then held relatively constant until the next sample is taken. EKT343 –Principle of Communication Engineering 16
  • 17. Cont’d… • Sampling process alters the frequency spectrum & introduces aperture error. • The amplitude of the sampled signal changes during the sample pulse time. • Advantages: – Introduces less aperture distortion – Can operate with a slower ADC EKT343 –Principle of Communication Engineering 17
  • 18. Flat-top Sampling EKT343 –Principle of Communication Engineering 18
  • 19. • Sampling analog information signal • Converting samples into discrete pulses • used to represent an analog signal with digital data • among the first of the pulse techniques to be utilized  Carrier signal is pulse waveform and the modulated signal is where one of the carrier signal’s characteristic (either amplitude, width or position) is changed according to information signal. EKT343 –Principle of Communication Engineering 19
  • 20.  The amplitude of pulses is varied in accordance with the information signal.  Width & position constant.  2 types – double polarity single polarity Pulse Amplitude Modulation (PAM) EKT343 –Principle of Communication Engineering 20
  • 21. Natural Sampling (PAM) • A PAM signal is generated by using a pulse train, called the sampling signal (or clock signal) to operate an electronic switch or "chopper". This produces samples of the analog message signal, as shown in Figure EKT343 –Principle of Communication Engineering 21
  • 22. Flat Top Sampling (PAM) • a sample-and-hold circuit is used in conjunction with the chopper to hold the amplitude of each pulse at a constant level during the sampling time EKT343 –Principle of Communication Engineering 22 Flat-top sampling – generation of PAM signals.
  • 23. Cont’d • Pulse duration (τ) supposed to be very small compare to the period, Ts between 2 samples • Lets max frequency of the signal, W • If ON/OFF time of the pulse is same, frequency of the PAM pulse is EKT343 –Principle of Communication Engineering 23 Fs >= 2 W Ts =< 1/2W T « Ts =< 1/2W 2 1 max f
  • 24. Transmission BW of PAM Signal • Bandwidth required for transmitter of PAM signal will be equal to maximum frequency EKT343 –Principle of Communication Engineering 24 2 1 max   fBT
  • 25. Advantages & Disadvantages PAM • Advantage: – it allows multiplexing, i.e., the sharing of the same transmission media by different sources (or users). This is because a PAM signal only occurs in slots of time, leaving the idle time for the transmission of other PAM signals. • Disadvantage: – require a larger transmission bandwidth (very large compare to its maximum frequency) – Interference of noise is maximum – Needed for varies transmission power EKT343 –Principle of Communication Engineering 25
  • 26. Pulse Density Modulation (PDM) • Sometimes called Pulse Duration Modulation/ Pulse Width Duration (PWM). • The width of pulses is varied in accordance to information signal • Amplitude & position constant. • PDM is used in a great number of applications Communications • The width of the transmitted pulse corresponds to the encoded data value EKT343 –Principle of Communication Engineering 26
  • 27. PDM • Immune to noise • Power Delivery – Reduce the total amount of power delivered to a load • Applications: DC Motors, Light Dimmers, Anti-Lock Breaking System EKT343 –Principle of Communication Engineering 27
  • 28. • PWM signal output is generated by comparing summation result with reference level EKT343 –Principle of Communication Engineering 28
  • 29. Cont’d... EKT343 –Principle of Communication Engineering 29
  • 30. Advantages & Disadvantages PDM • Advantage: – Noise performance is better compare to PAM. • Disadvantages: – require a larger power transmission compare to PPM – Require very large bandwidth compare to PAM EKT343 –Principle of Communication Engineering 30
  • 31. Pulse Position Modulation (PPM) • Modulation in which the temporal positions of the pulses are varied in accordance with some characteristic of the information signal. • Amplitude & width constant. • The higher the amplitude of the sample, the farther to the right the pulse is position within the prescribed time slot. EKT343 –Principle of Communication Engineering 31
  • 32. Advantages & Disadvantages PPM • Advantage: – The amplitude is held constant thus less noise interference. – Signal and noise separation is very easy – Due to constant pulse widths and amplitudes, transmission power for each pulse is same. – Require less power compare to PAM and PDM because of short duration pulses. • Disadvantages: – Require very large bandwidth compare to PAM. EKT343 –Principle of Communication Engineering 32
  • 33. Transmission BW of PDM/PPM Signal • PPM and PDM need a sharp rise time and fall time for pulses in order to preserve the message information. • Lets rise time, tr • From formula above, we know that transmission BW of PPM and PDM is higher than PAM EKT343 –Principle of Communication Engineering 33 tr« Ts r T t B 2 1 
  • 34. Transmission BW of PAM Signal • Pulse duration (τ) supposed to be very small compare to the period, Ts between 2 samples • Lets max frequency of the signal, W • If ON/OFF time of the pulse is same, frequency of the PAM pulse is EKT343 –Principle of Communication Engineering 34 Fs >= 2 W Ts =< 1/2W T « Ts =< 1/2W 2 1 max f
  • 35. Example 4 • For PAM transmission of voice signal with W = 3kHz. Calculate BT if fs = 8 kHz and τ = 0.1 Ts • SOLUTION EKT343 –Principle of Communication Engineering 35 sxT sx kHzf T s s s 5 4 1025.11.0 1025.1 8 11      kHzB WB W T T 40 2 1 2 1 2 1      
  • 36. Example 5 For the same information as in example 1, find minimum transmission BW needed for PPM and PDM. Given tr= 1% of the width of the pulse. SOLUTION EKT343 –Principle of Communication Engineering 36 MHzB t B sxt T r T r 4 2 1 1025.1 100 1 7     
  • 37. Pulse Modulation EKT343 –Principle of Communication Engineering 37
  • 38. PAM PDM PPM Relation with modulating signal Amplitude of the pulse is proportional to amplitude of modulating signal Width of the pulse is proportional to amplitude of modulating signal Relative position of the pulse is proportional to amplitude of modulating signal BW of the transmission channel depends on width of the pulse Depends of rise time of the pulse Depends on rising time of the pulse Instantaneous power varies varies Remains constant Noise interference High Minimum Minimum Complexity of the system Complex Simple simple EKT343 –Principle of Communication Engineering 38
  • 39. • PAM, PWM, PPM EKT343 –Principle of Communication Engineering 39
  • 40. Advantages & Drawbacks of Pulse Modulation • Noise immunity. • Relatively low cost digital circuitry. • Able to be time division multiplexed with other pulse modulated signal. • Storage of digital streams. • Error detection & correction • Requires greater BW to transmit & receive as compared to its analog counterpart. • Special encoding & decoding methods must be used to increased transmission rates & more difficult to be recovered. • Requires precise synchronization of clocks between Tx & Rx. EKT343 –Principle of Communication Engineering 40