OPERATION AMPLIFIER
DONE BY:DOMINIC HENDRY
GOKUL
DINESH KUMAR
DANIEL JESTUS
OPERATION AMPLIFIER
inverting
non-inverting
output
Op-amp circuit symbol
Open loop mode
Vo = Aod ( v2 – v1)
Aod is referred to as the
open loop gain.
Notice that is v2 = v1, the
open loop gain equals to 
• Op amp can be configured to be used for
different type of circuit applications:
– Inverting Amplifier
– Non – inverting Amplifier
– Summing Amplifier
– Integrator
– Differentiator
Op-amp as an inverting amplifier
Inverting Amplifier
Voltage at node 1 (inverting) = voltage at node 2 (non-inverting )
KCL at node 1:
I1 – I2 – Iin = 0
(Vi – 0) / R1 = (0 – Vo) / R2
Vi / R1 = - Vo / R2
Vo = - R2
Vi R1
Noninverting amplifier
Non - Inverting Amplifier
Voltage at node 1 (inverting) = voltage at node 2 (non-inverting )
KCL at node 1:
i1 – i2 = 0
(0– Vi) / R1 = (Vi – Vo) / R2
-(Vi / R1) = (Vi / R2) – (Vo / R2)
Vo / R2 = (Vi / R2) + (Vi / R1) = Vi 1 + 1
Vo / Vi = R2 1 + 1
R2 R1
R2 R1
Voltage Follower / Buffer Amplifier
vo = vI
Hence, gain = 1
Summing Amplifier
Summing Amplifier
Output voltage
i1 + i2 + i3 – i4 – 0 = 0
Similarly,
Solution: output voltage
When the feedback resistor of an inverter circuit is replaced by a capacitor the circuit is
worked as an integrator circuit -cause the output to respond to changes in the input voltage
over time
Integrator
Integrator circuit
Differentiator
When the inverting input terminal resistor of an op-amp inverter circuit is replaced by a
capacitor the circuit is worked as a differentiator circuit.
Differentiator circuit
Because Q = CVS

op amp

  • 1.
    OPERATION AMPLIFIER DONE BY:DOMINICHENDRY GOKUL DINESH KUMAR DANIEL JESTUS
  • 2.
    OPERATION AMPLIFIER inverting non-inverting output Op-amp circuitsymbol Open loop mode Vo = Aod ( v2 – v1) Aod is referred to as the open loop gain. Notice that is v2 = v1, the open loop gain equals to 
  • 3.
    • Op ampcan be configured to be used for different type of circuit applications: – Inverting Amplifier – Non – inverting Amplifier – Summing Amplifier – Integrator – Differentiator
  • 4.
    Op-amp as aninverting amplifier Inverting Amplifier Voltage at node 1 (inverting) = voltage at node 2 (non-inverting ) KCL at node 1: I1 – I2 – Iin = 0 (Vi – 0) / R1 = (0 – Vo) / R2 Vi / R1 = - Vo / R2 Vo = - R2 Vi R1
  • 5.
    Noninverting amplifier Non -Inverting Amplifier Voltage at node 1 (inverting) = voltage at node 2 (non-inverting ) KCL at node 1: i1 – i2 = 0 (0– Vi) / R1 = (Vi – Vo) / R2 -(Vi / R1) = (Vi / R2) – (Vo / R2) Vo / R2 = (Vi / R2) + (Vi / R1) = Vi 1 + 1 Vo / Vi = R2 1 + 1 R2 R1 R2 R1
  • 6.
    Voltage Follower /Buffer Amplifier vo = vI Hence, gain = 1
  • 7.
    Summing Amplifier Summing Amplifier Outputvoltage i1 + i2 + i3 – i4 – 0 = 0 Similarly,
  • 8.
  • 9.
    When the feedbackresistor of an inverter circuit is replaced by a capacitor the circuit is worked as an integrator circuit -cause the output to respond to changes in the input voltage over time Integrator Integrator circuit
  • 10.
    Differentiator When the invertinginput terminal resistor of an op-amp inverter circuit is replaced by a capacitor the circuit is worked as a differentiator circuit. Differentiator circuit Because Q = CVS