Introduction to CMOS VLSI Design.
This presentation covers lecture 4 (DC & Transient Response). It is adapted from Harri's lecture notes and made available by UFPE
This presentation discusses the basics of Pass Transistor Logic, its advantages, limitation and finally implementation of Boolean functions/Combinational Logic circuits using Pass Transistor Logic.
As we push through lower technology nodes in the IC and chip design, the wire width goes thinner along with transistor size. This makes the wire resistance more dominant on 16nm and below technology nodes. This increasing resistance and the decreasing width of metal wires introduce many Electromigration and IR drop issues. These two issues play major roles in reducing the lifespan of an electronic device and are the causes of functionality failure in any electronic devices with lower technology nodes.
In this article, we will discuss the problems of electromigration and IR drop, and techniques to prevent the occurrence of these issues in electronic devices.
Electromigration is the gradual displacement of metal atoms in a semiconductor. It occurs when the current density is high enough to cause the drift of metal ions in the direction of the electron flow, and is characterized by the ion flux density. This density depends on the magnitude of forces that tend to hold the ions in place, i.e., the nature of the conductor, crystal size, interface and grain-boundary chemistry, and the magnitude of forces that tend to dislodge them, including the current density, temperature and mechanical stresses.
The Power supply in the chip is distributed uniformly through metal layers (Vdd & Vss) across the design. These metal layers have finite amount of resistance. When voltage is applied to this metal wires current starts flowing through the metal layers and some voltage is dropped due to that resistance of metal wires and current. this drop is called as IR drop.
Reduced channel length cause departures from long channel behaviour as two-dimensional potential distribution and high electric fields give birth to Short channel effects.
This presentation discusses the basics of Pass Transistor Logic, its advantages, limitation and finally implementation of Boolean functions/Combinational Logic circuits using Pass Transistor Logic.
As we push through lower technology nodes in the IC and chip design, the wire width goes thinner along with transistor size. This makes the wire resistance more dominant on 16nm and below technology nodes. This increasing resistance and the decreasing width of metal wires introduce many Electromigration and IR drop issues. These two issues play major roles in reducing the lifespan of an electronic device and are the causes of functionality failure in any electronic devices with lower technology nodes.
In this article, we will discuss the problems of electromigration and IR drop, and techniques to prevent the occurrence of these issues in electronic devices.
Electromigration is the gradual displacement of metal atoms in a semiconductor. It occurs when the current density is high enough to cause the drift of metal ions in the direction of the electron flow, and is characterized by the ion flux density. This density depends on the magnitude of forces that tend to hold the ions in place, i.e., the nature of the conductor, crystal size, interface and grain-boundary chemistry, and the magnitude of forces that tend to dislodge them, including the current density, temperature and mechanical stresses.
The Power supply in the chip is distributed uniformly through metal layers (Vdd & Vss) across the design. These metal layers have finite amount of resistance. When voltage is applied to this metal wires current starts flowing through the metal layers and some voltage is dropped due to that resistance of metal wires and current. this drop is called as IR drop.
Reduced channel length cause departures from long channel behaviour as two-dimensional potential distribution and high electric fields give birth to Short channel effects.
Introduction to CMOS VLSI Design:
This Presentations is design in way to provide basic summary of CMOS Vlsi design
This Presentation is Made at Eutectics.blogspot.in
the following is the structure of presentation :
2: Outline
3: Introduction
4: MOS capacitor
5: Terminal Voltage
6: nMOS Cutoff
7: nMOS Linear
8: nMOS Saturation
9: I-V Characteristics
10 : Channel Charge
11: Carrier velocity
12: nMOS Linear I-V
13: nMOS Saturation
14: nMOS I-V Summary
15: Example
16: pMOS I-V
17: Capacitance
18: Gate Capacitance
19: Diffusion Capacitane
20: Pass Transistor
21: Pass transistor ckts
22: Effective Resistance
23: RC Delay Model
24: RC values
25: Inverter Delay Estimate
VLSI affords IC designers the ability to design utilizing less space. Typically, electronic circuits incorporate a CPU, RAM, ROM, and other peripherals on a single PCBA. However, very large-scale integration (VLSI) technology affords an IC designer the ability to add all of these into one chip.
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...Levi Shapiro
Letter from the Congress of the United States regarding Anti-Semitism sent June 3rd to MIT President Sally Kornbluth, MIT Corp Chair, Mark Gorenberg
Dear Dr. Kornbluth and Mr. Gorenberg,
The US House of Representatives is deeply concerned by ongoing and pervasive acts of antisemitic
harassment and intimidation at the Massachusetts Institute of Technology (MIT). Failing to act decisively to ensure a safe learning environment for all students would be a grave dereliction of your responsibilities as President of MIT and Chair of the MIT Corporation.
This Congress will not stand idly by and allow an environment hostile to Jewish students to persist. The House believes that your institution is in violation of Title VI of the Civil Rights Act, and the inability or
unwillingness to rectify this violation through action requires accountability.
Postsecondary education is a unique opportunity for students to learn and have their ideas and beliefs challenged. However, universities receiving hundreds of millions of federal funds annually have denied
students that opportunity and have been hijacked to become venues for the promotion of terrorism, antisemitic harassment and intimidation, unlawful encampments, and in some cases, assaults and riots.
The House of Representatives will not countenance the use of federal funds to indoctrinate students into hateful, antisemitic, anti-American supporters of terrorism. Investigations into campus antisemitism by the Committee on Education and the Workforce and the Committee on Ways and Means have been expanded into a Congress-wide probe across all relevant jurisdictions to address this national crisis. The undersigned Committees will conduct oversight into the use of federal funds at MIT and its learning environment under authorities granted to each Committee.
• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
Introduction to AI for Nonprofits with Tapp NetworkTechSoup
Dive into the world of AI! Experts Jon Hill and Tareq Monaur will guide you through AI's role in enhancing nonprofit websites and basic marketing strategies, making it easy to understand and apply.
Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
Model Attribute Check Company Auto PropertyCeline George
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
Safalta Digital marketing institute in Noida, provide complete applications that encompass a huge range of virtual advertising and marketing additives, which includes search engine optimization, virtual communication advertising, pay-per-click on marketing, content material advertising, internet analytics, and greater. These university courses are designed for students who possess a comprehensive understanding of virtual marketing strategies and attributes.Safalta Digital Marketing Institute in Noida is a first choice for young individuals or students who are looking to start their careers in the field of digital advertising. The institute gives specialized courses designed and certification.
for beginners, providing thorough training in areas such as SEO, digital communication marketing, and PPC training in Noida. After finishing the program, students receive the certifications recognised by top different universitie, setting a strong foundation for a successful career in digital marketing.
A workshop hosted by the South African Journal of Science aimed at postgraduate students and early career researchers with little or no experience in writing and publishing journal articles.
How to Make a Field invisible in Odoo 17Celine George
It is possible to hide or invisible some fields in odoo. Commonly using “invisible” attribute in the field definition to invisible the fields. This slide will show how to make a field invisible in odoo 17.
Biological screening of herbal drugs: Introduction and Need for
Phyto-Pharmacological Screening, New Strategies for evaluating
Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
for Anti-inflammatory, Antiulcer, Anticancer, Wound healing, Antidiabetic, Hepatoprotective, Cardio protective, Diuretics and
Antifertility, Toxicity studies as per OECD guidelines
Unit 8 - Information and Communication Technology (Paper I).pdfThiyagu K
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
This slide is special for master students (MIBS & MIFB) in UUM. Also useful for readers who are interested in the topic of contemporary Islamic banking.
2. CMOS VLSI Design
4: DC and Transient Response Slide 2
Outline
DC Response
Logic Levels and Noise Margins
Transient Response
Delay Estimation
3. CMOS VLSI Design
4: DC and Transient Response Slide 3
Activity
1) If the width of a transistor increases, the current will
increase decrease not change
2) If the length of a transistor increases, the current will
increase decrease not change
3) If the supply voltage of a chip increases, the maximum
transistor current will
increase decrease not change
4) If the width of a transistor increases, its gate capacitance will
increase decrease not change
5) If the length of a transistor increases, its gate capacitance will
increase decrease not change
6) If the supply voltage of a chip increases, the gate capacitance
of each transistor will
increase decrease not change
4. CMOS VLSI Design
4: DC and Transient Response Slide 4
Activity
1) If the width of a transistor increases, the current will
increase decrease not change
2) If the length of a transistor increases, the current will
increase decrease not change
3) If the supply voltage of a chip increases, the maximum
transistor current will
increase decrease not change
4) If the width of a transistor increases, its gate capacitance will
increase decrease not change
5) If the length of a transistor increases, its gate capacitance will
increase decrease not change
6) If the supply voltage of a chip increases, the gate capacitance
of each transistor will
increase decrease not change
5. CMOS VLSI Design
4: DC and Transient Response Slide 5
DC Response
DC Response: Vout vs. Vin for a gate
Ex: Inverter
– When Vin = 0 -> Vout = VDD
– When Vin = VDD -> Vout = 0
– In between, Vout depends on
transistor size and current
– By KCL, must settle such that
Idsn = |Idsp|
– We could solve equations
– But graphical solution gives more insight
Idsn
Idsp
Vout
VDD
Vin
6. CMOS VLSI Design
4: DC and Transient Response Slide 6
Transistor Operation
Current depends on region of transistor behavior
For what Vin and Vout are nMOS and pMOS in
– Cutoff?
– Linear?
– Saturation?
15. CMOS VLSI Design
4: DC and Transient Response Slide 15
I-V Characteristics
Make pMOS is wider than nMOS such that bn = bp
Vgsn5
Vgsn4
Vgsn3
Vgsn2
Vgsn1
Vgsp5
Vgsp4
Vgsp3
Vgsp2
Vgsp1
VDD
-VDD
Vdsn
-Vdsp
-Idsp
Idsn
0
16. CMOS VLSI Design
4: DC and Transient Response Slide 16
Current vs. Vout, Vin
Vin5
Vin4
Vin3
Vin2
Vin1
Vin0
Vin1
Vin2
Vin3
Vin4
Idsn
, |Idsp
|
Vout
VDD
17. CMOS VLSI Design
4: DC and Transient Response Slide 17
Load Line Analysis
Vin5
Vin4
Vin3
Vin2
Vin1
Vin0
Vin1
Vin2
Vin3
Vin4
Idsn
, |Idsp
|
Vout
VDD
For a given Vin:
– Plot Idsn, Idsp vs. Vout
– Vout must be where |currents| are equal in
Idsn
Idsp
Vout
VDD
Vin
18. CMOS VLSI Design
4: DC and Transient Response Slide 18
Load Line Analysis
Vin0
Vin0
Idsn
, |Idsp
|
Vout
VDD
Vin = 0
19. CMOS VLSI Design
4: DC and Transient Response Slide 19
Load Line Analysis
Vin1
Vin1
Idsn
, |Idsp
|
Vout
VDD
Vin = 0.2VDD
20. CMOS VLSI Design
4: DC and Transient Response Slide 20
Load Line Analysis
Vin2
Vin2
Idsn
, |Idsp
|
Vout
VDD
Vin = 0.4VDD
21. CMOS VLSI Design
4: DC and Transient Response Slide 21
Load Line Analysis
Vin3
Vin3
Idsn
, |Idsp
|
Vout
VDD
Vin = 0.6VDD
22. CMOS VLSI Design
4: DC and Transient Response Slide 22
Load Line Analysis
Vin4
Vin4
Idsn
, |Idsp
|
Vout
VDD
Vin = 0.8VDD
23. CMOS VLSI Design
4: DC and Transient Response Slide 23
Load Line Analysis
Vin5
Vin0
Vin1
Vin2
Vin3
Vin4
Idsn
, |Idsp
|
Vout
VDD
Vin = VDD
24. CMOS VLSI Design
4: DC and Transient Response Slide 24
Load Line Summary
Vin5
Vin4
Vin3
Vin2
Vin1
Vin0
Vin1
Vin2
Vin3
Vin4
Idsn
, |Idsp
|
Vout
VDD
25. CMOS VLSI Design
4: DC and Transient Response Slide 25
DC Transfer Curve
Transcribe points onto Vin vs. Vout plot
Vin5
Vin4
Vin3
Vin2
Vin1
Vin0
Vin1
Vin2
Vin3
Vin4
Vout
VDD
C
Vout
0
Vin
VDD
VDD
A B
D
E
Vtn
VDD
/2 VDD
+Vtp
26. CMOS VLSI Design
4: DC and Transient Response Slide 26
Operating Regions
Revisit transistor operating regions
C
Vout
0
Vin
VDD
VDD
A B
D
E
Vtn
VDD
/2 VDD
+Vtp
Region nMOS pMOS
A
B
C
D
E
27. CMOS VLSI Design
4: DC and Transient Response Slide 27
Operating Regions
Revisit transistor operating regions
C
Vout
0
Vin
VDD
VDD
A B
D
E
Vtn
VDD
/2 VDD
+Vtp
Region nMOS pMOS
A Cutoff Linear
B Saturation Linear
C Saturation Saturation
D Linear Saturation
E Linear Cutoff
28. CMOS VLSI Design
4: DC and Transient Response Slide 28
Beta Ratio
If bp / bn 1, switching point will move from VDD/2
Called skewed gate
Other gates: collapse into equivalent inverter
Vout
0
Vin
VDD
VDD
0.5
1
2
10
p
n
b
b
0.1
p
n
b
b
29. CMOS VLSI Design
4: DC and Transient Response Slide 29
Noise Margins
How much noise can a gate input see before it does
not recognize the input?
Indeterminate
Region
NML
NMH
Input Characteristics
Output Characteristics
VOH
VDD
VOL
GND
VIH
VIL
Logical High
Input Range
Logical Low
Input Range
Logical High
Output Range
Logical Low
Output Range
30. CMOS VLSI Design
By definition, VIH and VIL are the operational points of
the inverter where
4: DC and Transient Response Slide 30
VDD
Vin
Vout
VOH
VDD
VOL
VIL
VIH
Vtn
Unity Gain Points
Slope = -1
VDD
-
|Vtp
|
bp
/bn
> 1
Vin
Vout
0
A high gain (g) is
desirable
31. CMOS VLSI Design
4: DC and Transient Response Slide 31
Logic Levels
To maximize noise margins, select logic levels at
VDD
Vin
Vout
VDD
bp
/bn
> 1
Vin
Vout
0
32. CMOS VLSI Design
4: DC and Transient Response Slide 32
Logic Levels
To maximize noise margins, select logic levels at
– unity gain point of DC transfer characteristic
VDD
Vin
Vout
VOH
VDD
VOL
VIL
VIH
Vtn
Unity Gain Points
Slope = -1
VDD
-
|Vtp
|
bp
/bn
> 1
Vin
Vout
0
33. CMOS VLSI Design
4: DC and Transient Response Slide 33
Transient Response
DC analysis tells us Vout if Vin is constant
Transient analysis tells us Vout(t) if Vin(t) changes
– Requires solving differential equations
Input is usually considered to be a step or ramp
– From 0 to VDD or vice versa
34. CMOS VLSI Design
4: DC and Transient Response Slide 34
Inverter Step Response
Ex: find step response of inverter driving load cap
0
( )
(
)
)
(
o
i
ut
n
out
V t t
t
V
t
V
d
d
t
Vin(t)
Vout
(t)
Cload
Idsn(t)
35. CMOS VLSI Design
4: DC and Transient Response Slide 35
Inverter Step Response
Ex: find step response of inverter driving load cap
0
0
( )
( )
( )
( )
ou
DD
in
t
out
u t t V
d
d
t
t t
V t
V
V
t
Vin(t)
Vout
(t)
Cload
Idsn(t)
36. CMOS VLSI Design
4: DC and Transient Response Slide 36
Inverter Step Response
Ex: find step response of inverter driving load cap
0
0
(
( )
)
(
(
)
)
DD
D
o
i
D
o t
n
ut
u
V t
u t t V
V
d
d
t
t
V
V
t
t
Vin(t)
Vout
(t)
Cload
Idsn(t)
37. CMOS VLSI Design
4: DC and Transient Response Slide 37
Inverter Step Response
Ex: find step response of inverter driving load cap
0
0
( )
( )
( )
(
(
)
)
DD
DD
loa
d
ou
i
d
t
o
n
ut sn
V
V
u t t V
t t
V t
V
d
dt C
t
I t
0
( ) DD t
out
ou
ds
t DD t
n
I t V V
V
V V
V
t t
Vin(t)
Vout
(t)
Cload
Idsn(t)
38. CMOS VLSI Design
4: DC and Transient Response Slide 38
Inverter Step Response
Ex: find step response of inverter driving load cap
0
0
( )
( )
( )
(
(
)
)
DD
DD
loa
d
ou
i
d
t
o
n
ut sn
V
V
u t t V
t t
V t
V
d
dt C
t
I t
0
2
2
0
2
)
)
(
( )
( DD DD t
DD
out
out
out out D t
n
t
ds
D
I V
t t
V V V V
V V V V
V
t
V t
V t
b
b
Vin(t)
Vout
(t)
Cload
Idsn(t)
39. CMOS VLSI Design
4: DC and Transient Response Slide 39
Inverter Step Response
Ex: find step response of inverter driving load cap
0
0
( )
( )
( )
(
(
)
)
DD
DD
loa
d
ou
i
d
t
o
n
ut sn
V
V
u t t V
t t
V t
V
d
dt C
t
I t
0
2
2
0
2
)
)
(
( )
( DD DD t
DD
out
out
out out D t
n
t
ds
D
I V
t t
V V V V
V V V V
V
t
V t
V t
b
b
Vout(t)
Vin(t)
t0
t
Vin(t)
Vout
(t)
Cload
Idsn(t)
nMOS – “1” transfer is bad
40. CMOS VLSI Design
4: DC and Transient Response Slide 40
Delay Definitions
tpdr: rising propagation delay
– From input to rising output crossing VDD/2 (upper bound)
tpdf: falling propagation delay
– From input to falling output crossing VDD/2 (upper bound)
tpd: average propagation delay
– tpd = (tpdr + tpdf)/2
tr: rise time
– time required for a node to charge from the 10% point to
90% ( 0.1 VDD to 0.9 VDD )
tf: fall time
– time required for a node to discharge from 90% to 10%
point (0.9 VDD to 0.1 VDD )
43. 43
Trajectory of a n-transistor
operating point
a. Transistor is Cut off
b. Capacitance CL is loaded with VDD
a. Applying a Vgs=VDD
b. Vout -> 0,9 to (VDD-Tth)
a. VDD-Tth -> to 0.1V
44. Slide 44
Fall-time equivalent circuit
Rise-time equivalent circuit
The fall-time is faster than the rise
time,
tf=tr/2
primarily due to different carrier
mobilities associated with the p and
n- devices:
µn = 2 µp
It is true considering equally
sized n and p transistors
βn = 2 βp
45. CMOS VLSI Design
If the designer wants to have both n an p transistor
with the same rise and fall time:
βn / βp = 1
This implies that channel width for the p-device must
be increased to approximately two to three times of
the n-device:
wp = 2 – 3 wn
4: DC and Transient Response Slide 45
n+ n+
p-type body
W
L
tox
SiO2
gate oxide
(good insulator, ox
= 3.90
)
polysilicon
gate
Trajectory of a n-transistor
operating point
46. CMOS VLSI Design
4: DC and Transient Response Slide 46
Delay Estimation
We would like to be able to easily estimate delay
– Not as accurate as simulation
– But easier to ask “What if?”
The step response usually looks like a 1st order RC
response with a decaying exponential.
Use RC delay models to estimate delay
– C = total capacitance on output node
– Use effective resistance R
– So that tpd = RC
Characterize transistors by finding their effective R
– Depends on average current as gate switches
47. CMOS VLSI Design
4: DC and Transient Response Slide 47
RC Delay Models
Use equivalent circuits for MOS transistors
– Ideal switch + capacitance and ON resistance
– Unit nMOS has resistance R, capacitance C
– Unit pMOS has resistance 2R, capacitance C
Capacitance proportional to width
Resistance inversely proportional to width
k
g
s
d
g
s
d
kC
kC
kC
R/k
k
g
s
d
g
s
d
kC
kC
kC
2R/k
Capacitance
proportional to width
Resistance
inversely
proportional to
width
nMOS pMOS
48. CMOS VLSI Design
4: DC and Transient Response Slide 48
Resistance of a uniform slab:
– R = (l/A) = (/t) (L/W) where is the
resistivity in ohm-cm, t is the
thickness in cm, L is the length, W is
the width, and A is the cross-sectional
area
– Using the concept of sheet resistance,
R = Rs (L/W) where Rs is called the
sheet resistance and given in ohms
per square
• Rs = / t
Gate Capacitance
- Cg = oxWL/tox = oxA/tox
n+ n+
p-type body
W
L
tox
SiO2
gate oxide
(good insulator, ox
= 3.90
)
polysilicon
gate
RC Delay Models
49. CMOS VLSI Design
MOS device capacitances
MOS Device capacitances
– Cgs, Cgd = gate-to-channel capacitances, which are lumped at the
source and the drain regions.
– Csb, Cdb = source and drain-duiffusion capacitances to bulk (or
substrate)
– Cgb = gate –to-bulk capacitance
4: DC and Transient Response Slide 49
50. CMOS VLSI Design
4: DC and Transient Response Slide 50
1. Off region, where Vgs < Vt. There is no channel Cgs, Cgd = 0.
2. Non-saturated region, where Vgs - Vt. > Vds. Cgb = 0
3. Saturated region, where Vgs <-Vt. < Vds. Channel is heavely inverted.
The drain is pinched off causing Cgd = 0.
MOS device capacitances
51. CMOS VLSI Design
RC Delay Models
4: DC and Transient Response Slide 51
pMOS capacitance
= 2x nMOS
capacitance
52. CMOS VLSI Design
4: DC and Transient Response Slide 52
Example: 3-input NAND
Sketch a 3-input NAND with transistor widths
chosen to achieve effective rise and fall resistances
equal to a unit inverter (R).
53. CMOS VLSI Design
4: DC and Transient Response Slide 53
Example: 3-input NAND
Sketch a 3-input NAND with transistor widths
chosen to achieve effective rise and fall resistances
equal to a unit inverter (R).
54. CMOS VLSI Design
4: DC and Transient Response Slide 54
Example: 3-input NAND
Sketch a 3-input NAND with transistor widths
chosen to achieve effective rise and fall resistances
equal to a unit inverter (R).
3
3
2
2
2
3
55. CMOS VLSI Design
4: DC and Transient Response Slide 55
3-input NAND Caps
Annotate the 3-input NAND gate with gate and
diffusion capacitance.
2 2 2
3
3
3
56. CMOS VLSI Design
4: DC and Transient Response Slide 56
3-input NAND Caps
Annotate the 3-input NAND gate with gate and
diffusion capacitance.
2 2 2
3
3
3
3C
3C
3C
3C
2C
2C
2C
2C
2C
2C
3C
3C
3C
2C 2C 2C
Resultant capacitance
per gate = 2C+3C = 5C
Parallel capacitances
3x2C+3C = 9C
57. CMOS VLSI Design
4: DC and Transient Response Slide 57
3-input NAND Caps
Annotate the 3-input NAND gate with gate and
diffusion capacitance.
9C
3C
3C
3
3
3
2
2
2
5C
5C
5C
58. CMOS VLSI Design
4: DC and Transient Response Slide 58
Elmore Delay
ON transistors look like resistors
Pullup or pulldown network modeled as RC ladder
Elmore delay of RC ladder
R1
R2
R3
RN
C1
C2
C3
CN
nodes
1 1 1 2 2 1 2
... ...
pd i to source i
i
N N
t R C
R C R R C R R R C
59. CMOS VLSI Design
4: DC and Transient Response Slide 59
Example: 2-input NAND
Estimate worst-case rising and falling delay of 2-
input NAND driving h identical gates.
h copies
2
2
2
2
B
A
x
Y
60. CMOS VLSI Design
4: DC and Transient Response Slide 60
Example: 2-input NAND
Estimate worst-case rising and falling delay of 2-
input NAND driving h identical gates.
h copies
61. CMOS VLSI Design
4: DC and Transient Response Slide 61
Example: 2-input NAND
Estimate worst-case rising and falling delay of 2-
input NAND driving h identical gates.
h copies
Parallel capacitances
2C+2C+2C= 6C
62. CMOS VLSI Design
4: DC and Transient Response
Example: 2-input NAND
Estimate rising and falling propagation delays of a 2-
input NAND driving h identical gates.
h copies
6C
2C
2
2
2
2
4hC
B
A
x
Y
63. CMOS VLSI Design
4: DC and Transient Response Slide 63
Example: 2-input NAND
Estimate rising and falling propagation delays of a 2-
input NAND driving h identical gates.
h copies
6C
2C
2
2
2
2
4hC
B
A
x
Y
R
(6+4h)C
Y
pdr
t
64. CMOS VLSI Design
4: DC and Transient Response Slide 64
Example: 2-input NAND
Estimate rising and falling propagation delays of a 2-
input NAND driving h identical gates.
h copies
6C
2C
2
2
2
2
4hC
B
A
x
Y
R
(6+4h)C
Y
6 4
pdr
t h RC
Rising time: nMOS - “off”
pMOS - “on”
65. CMOS VLSI Design
4: DC and Transient Response Slide 65
Example: 2-input NAND
Estimate rising and falling propagation delays of a 2-
input NAND driving h identical gates.
h copies
6C
2C
2
2
2
2
4hC
B
A
x
Y
66. CMOS VLSI Design
4: DC and Transient Response Slide 66
Example: 2-input NAND
Estimate rising and falling propagation delays of a 2-
input NAND driving h identical gates.
h copies
6C
2C
2
2
2
2
4hC
B
A
x
Y
pdf
t
(6+4h)C
2C
R/2
R/2
x Y
Consider that the nMOS resistance = (pMOS resistance)/2 = R/2
67. CMOS VLSI Design
4: DC and Transient Response Slide 67
Example: 2-input NAND
Estimate rising and falling propagation delays of a 2-
input NAND driving h identical gates.
h copies
6C
2C
2
2
2
2
4hC
B
A
x
Y
2 2 2
2 6 4
7 4
R R R
pdf
t C h C
h RC
(6+4h)C
2C
R/2
R/2
x Y
68. CMOS VLSI Design
4: DC and Transient Response Slide 68
Delay Components
Delay has two parts
– Parasitic delay
• 6 or 7 RC
• Independent of load
– Effort delay
• 4h RC
• Proportional to load capacitance
69. CMOS VLSI Design
4: DC and Transient Response Slide 69
Contamination Delay
Best-case (contamination) delay can be substantially
less than propagation delay.
Ex: If both inputs fall simultaneously
6C
2C
2
2
2
2
4hC
B
A
x
Y
R
(6+4h)C
Y
R
3 2
cdr
t h RC
70. CMOS VLSI Design
4: DC and Transient Response Slide 70
7C
3C
3C
3
3
3
2
2
2
3C
2C
2C
3C
3C
Isolated
Contacted
Diffusion
Merged
Uncontacted
Diffusion
Shared
Contacted
Diffusion
Diffusion Capacitance
we assumed contacted diffusion on every source/drain
Good layout minimizes diffusion area
Ex: NAND3 layout shares one diffusion contact
– Reduces output capacitance by 2C
– Merged uncontacted diffusion might help too
Capacitance = 2C+2C+3C = 7C
71. CMOS VLSI Design
4: DC and Transient Response Slide 71
Layout Comparison
Which layout is better?
A
VDD
GND
B
Y
A
VDD
GND
B
Y