Using the method of
squares
The parabola we are
to graph are having origin as
our
vertex
Compare the equation
to x2=4py
for a parabola with y-axis as its
axis of symmetry
Compare the equation
to y2=4px
for a parabola with x-axis as its
axis of symmetry
In graphing parabola
we use squares to asses
our graphing
Parts of a parabola
Focus: F(0,p)
for a parabola of the form
x2=4py
Use the six squares
whose sides equal to
2p
Sample: x2=6y
Solution: compare the problem , x2 =6y
to x2 = 4py
4py=6y by transitive property, and
p=1.5 by dividing
4y to both sides
From the results
Focus (0, 1.5) or (0,p)
Length of latus rectum 4p or 6 units
Vertex (0,0)
Directrix: y= -1.5 or y= -p
We draw the graph
using six squares
with sides equal to 2p or 3 units
x2 =6y length of latus rectum
6
1
2 5
4
3 Vertex (0,0)
Directrix: y= -1.5
The ordered pairs
 The red colors on previous slide are the points on the
parabola.
 The ordered pairs are found on the vertex of the
squares, upper vertex of squares 1,3,4 and 6.
 The lower portion which is the origin is found on the
sides of squares 3 and 4.

Sample 2: y2 =8x
In this case the graph has an
axis of symmetry which is the
x- axis , and the directrix is at
the left side of the origin
Solution
y2= 8x will be compared to
 y2=4px, which yields p=2
The squares
Length of latus rectum
directrix
Vertex (0,0)
The red colored are the points
on the parabola that passes the
edges of the squares
All the
squares have
the sides of 4
units
Thank you for viewing
Virgilio Rollon Paragele
Tomas Cabili National High
School

Graphing parabola presentation

  • 1.
    Using the methodof squares
  • 2.
    The parabola weare to graph are having origin as our vertex
  • 3.
    Compare the equation tox2=4py for a parabola with y-axis as its axis of symmetry
  • 4.
    Compare the equation toy2=4px for a parabola with x-axis as its axis of symmetry
  • 5.
    In graphing parabola weuse squares to asses our graphing
  • 6.
    Parts of aparabola Focus: F(0,p) for a parabola of the form x2=4py
  • 7.
    Use the sixsquares whose sides equal to 2p
  • 8.
    Sample: x2=6y Solution: comparethe problem , x2 =6y to x2 = 4py 4py=6y by transitive property, and p=1.5 by dividing 4y to both sides
  • 9.
    From the results Focus(0, 1.5) or (0,p) Length of latus rectum 4p or 6 units Vertex (0,0) Directrix: y= -1.5 or y= -p
  • 10.
    We draw thegraph using six squares with sides equal to 2p or 3 units
  • 11.
    x2 =6y lengthof latus rectum 6 1 2 5 4 3 Vertex (0,0) Directrix: y= -1.5
  • 12.
    The ordered pairs The red colors on previous slide are the points on the parabola.  The ordered pairs are found on the vertex of the squares, upper vertex of squares 1,3,4 and 6.  The lower portion which is the origin is found on the sides of squares 3 and 4. 
  • 13.
    Sample 2: y2=8x In this case the graph has an axis of symmetry which is the x- axis , and the directrix is at the left side of the origin
  • 14.
    Solution y2= 8x willbe compared to  y2=4px, which yields p=2
  • 15.
    The squares Length oflatus rectum directrix Vertex (0,0) The red colored are the points on the parabola that passes the edges of the squares All the squares have the sides of 4 units
  • 16.
  • 17.
    Virgilio Rollon Paragele TomasCabili National High School