This document discusses the concepts of centroid, center of gravity, momentum, and impulse. It begins by defining the centroid as the geometrical center of an area, while the center of gravity is the point where all the mass of a body can be assumed to be concentrated. It then explains how momentum is calculated as mass times velocity, and how impulse is equal to the change in momentum caused by an applied force over time. Several examples are provided to illustrate these concepts, such as how changing the time over which a force is applied affects the force magnitude. The document aims to build an understanding of these foundational physics concepts.
this is about center of mass, center of mass for complicated shapes, center of mass of hemisphere, center of mass of many particles, center of mass of solids, center of mass of uniform cylinder, center of mass of uniform rod
this is about center of mass, center of mass for complicated shapes, center of mass of hemisphere, center of mass of many particles, center of mass of solids, center of mass of uniform cylinder, center of mass of uniform rod
This power point presentation includes concept of beam, moment of inertia, radius of gyration, perpendicular axis and parallel axis theorem, theory of simple bending or pure bending and assumptions of it, derivation of bending stress formula or flexural formula, moment of resistance, section modulus and numerical based on above said topic. It also includes concept of shear stress and its derivation for circular, rectangular cross section, concepts of complementary shear stress and numerical based on shear stress concept.
Friction. Do you know what is friction and how it plays different roles in our general life. There are many section in our life where friction is necessary like - in playing sitar and guitar, walking on the road and to hold something in our hand or in any mechanical devices. But there are many field where friction is not required like - in machines where two surfaces meet at a point. Due to this the life of the machine parts get decreased and failure may be occur there. Know more about different laws of friction, types of friction, elimination of the friction.
This power point presentation includes concept of beam, moment of inertia, radius of gyration, perpendicular axis and parallel axis theorem, theory of simple bending or pure bending and assumptions of it, derivation of bending stress formula or flexural formula, moment of resistance, section modulus and numerical based on above said topic. It also includes concept of shear stress and its derivation for circular, rectangular cross section, concepts of complementary shear stress and numerical based on shear stress concept.
Friction. Do you know what is friction and how it plays different roles in our general life. There are many section in our life where friction is necessary like - in playing sitar and guitar, walking on the road and to hold something in our hand or in any mechanical devices. But there are many field where friction is not required like - in machines where two surfaces meet at a point. Due to this the life of the machine parts get decreased and failure may be occur there. Know more about different laws of friction, types of friction, elimination of the friction.
Lab 05 – Gravitation and Keplers Laws Name __________________.docxDIPESH30
Lab 05 – Gravitation and Keplers Laws Name: _____________________
Why everyone in this class is attracted to everyone else.
https://phet.colorado.edu/en/simulation/gravity-force-lab
Adapted from Chris Bier’s Collisions PhET Lab OPTION A: CREATIVE COMMONS - ATTRIBUTION
Introduction:
Every object around you is attracted to you. In fact, every object in the galaxy is attracted to every other object in the galaxy. Newton postulated and Cavendish confirmed that all objects with mass are attracted to all other objects with mass by a force that is proportional to their masses and inversely proportional to the square of the distance between the objects' centers. This relationship became Newton's Law of Universal Gravitation. In this simulation, you will look at two massive objects and their gravitational force between them to observe G, the constant of universal gravity that Cavendish investigated.
Important Formulas:
Procedure: https://phet.colorado.edu/en/simulation/gravity-force-lab
1. Take some time and familiarize yourself with the simulation. Notice how forces change as mass changes and as distance changes.
2. Fill out the chart below for the two objects at various distances.
3. Rearranging the equation for Force, you can CALCULATE the value of G using the values given below for m1, m2, and d, and the value for the Force that you obtain in the simulation. Record the force between the two object and then solve (calculate G) for the universal gravitation constant, G and compare it to values published in books, online, or your text book. The numbers you calculate for G will vary slightly from row to row. Remember significant digits!15 pts
Mass Object 1 Mass Object 2 Distance Force Gravitation Constant,G
50.00 kg
25.00 kg
3.0m
50.00 kg
25.00 kg
4.0m
50.00 kg
25.00 kg
5.0m
50.00 kg
25.00 kg
6.0m
50.00 kg
25.00 kg
9.0m
What do you notice about the force that acts on each object? 3 pts
[Answer Here]
Average value of G: _________________2 ptsUnits of G: _______________2 pts
Published value of G: ________________2 pts Source: _______________2 pts
How did your average value of G compare to the published value for G that you found? 3 pts
[Answer Here]
Conclusion Questions and Calculations:Bold and Underlinethe correct answer to each question.
1. Gravitational force is always attractive / repulsive. (circle) 2 pts
2. Newton’s 3rd Law tells us that if a gravitational force exists between two objects, one very massive and one less massive, then the force on the less massive object will be greater than / equal to / less than the force on the more massive object. 2 pts
3. The distance between masses is measured from their edges between them / from their centers / from the edge of one to the center of the other. 2 pts
4. As the distance between masses decreases, force increases / decreases. 2 pts
5. Doubling the mass of both masses would result in a change of force between the mas ...
Ph2A Win 2020 Numerical Analysis Lab
Max Yuen
Mar 2020
(use g = 9.8m/s2 for all problems.)
Background
Many physics problems cannot be solved directly by hand or analytically. We resort to numerical
methods to give us approximations to the problem. In this lab you will learn the Euler method,
which allows you to solve Newton’s laws of motion. This is done by treating the velocity as a
piecewise linear function with many time intervals and during interval the acceleration is assumed
to be uniform. This allows us to use the kinematic equations we learned about in the first half
of the class to approximate the motion. If we choose to partition the motion into smaller time
intervals, the approximation becomes much better since the differences between adjacent intervals
become smaller. In this lab, this numerical analysis method will be applied to the motion of a
falling object under the influence of gravity and drag force. If you are adventurous, you can even
try to extend this to 2D and compute the realistic trajectory of a baseball. You might even try
some other problems, such as a mass attached to a spring.
Euler’s Method Foundations
This method is well suited for problems where the acceleration is a function of the velocity, as in
the case of a falling object under the influence of gravity and drag:
a = f(v) (1)
Falling object with drag force
The model for drag fits the prescription for using Euler’s method since the net force on a falling
object with drag is given by:
ma = −mg −FD (2)
ma = −mg −
1
2
ρairACDv
2 · sgn(v) (3)
a = −g
(
1 +
ρairACDv
2 · sgn(v)
2mg
)
(4)
a = f(v) ← Equation of Motion (5)
where m is the mass of the falling object, a is the acceleration of the object (which is positive when
pointed up), ρair is the density of air (about 1.29 ·10−3kg/m3), A is the cross-sectional area, CD is
the drag coefficient, v is the object’s velocity, and sgn(v) is the signum function which returns the
sign of the argument. The second signum function is there to guarantee that the direction of the
drag force is always in the opposite direction of the velocity function. Note that we see that the
acceleration is an explicit function of v, which sort of makes this a chicken or egg problem. This is
because we need a to get v, but to get a we need v, so which one do we compute first? Hold that
thought. We’ll talk more on how to program this in EXCEL or Google Sheets later.
1
Figure 1: FBD for an object falling under the pull of gravity and resistance by drag force
Terminal Velocity
In lecture, we talked about how after waiting for some time, if the object started at rest the
speed will increase and the drag force will also become larger and eventually balance out with the
gravitational force. When this happens, we have reached terminal velocity vterm = −v. This can
be solved by setting a = 0:
0 = −mg −
1
2
ρairACDv
2 · sgn(v) (6)
2mg = ρairACDv
2
term (7)
→ vterm =
√
2mg
ρairACD
(8)
Using this definition for the terminal ...
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June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...Levi Shapiro
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4. Centroids
The centroid of an area is situated at its geometrical
centre. In each of the following figures ‘G’ represents the
centroid, and if each area was suspended from this point it
would balance.
5. Center of gravity or mass
The centre of gravity of a body is:
•The point at which all the mass of the body may be
assumed to be concentrated.
•The point through which the force of gravity is
considered to act vertically downwards, with a force
equal to the weight of the body.
•The point about which the body would balance.
The centre of gravity of a homogeneous body is at its
geometrical centre.
7. Difference Between Centre of Gravity and Centroid
Centre of Gravity Centroid
The point where the total
weight of the body focuses
upon
It is referred to as the
geometrical centre of a body
It is the point where the
gravitational force (weight)
acts on the body
It is referred to the centre of
gravity of uniform density
objects
It is denoted by g It is denoted by c
Centre of Gravity in a uniform
gravitational field is the
average of all points, weighted
by local density or specific
weight
The centroid is a point in a
plane area in such a way that
the moment of area about any
axis throughout that point is 0
It is a physical behaviour of
the object, a point where all
the weight of an object is
acting
It is a geometrical behaviour.
It is the centre of measure of
the amount of geometry.
10. Changing our Point of
View
The great Greek mathematician
Archimedes said, “give me a
place to stand and I will move
the Earth,” meaning that if he
had a lever long enough he
could lift the Earth by his own
effort.
11. In other words. . .
We can think of leaving the masses in place and moving the
fulcrum.
It would have to be a pretty
long see-saw in order to
balance the school bus and
the race car, though!
12. In other words. . .
(We still) need:
M1 d1 = M2 d2
M2
d1 d2
M1
13. What happens if there are many
things trying to balance on the
see-saw?
Where do we place the fulcrum?
Mathematical Setting
First we fix an origin and a coordinate system. .
.
0 1
-1
-2 2
14. Mathematical Setting
And place the objects in the coordinate system.
. .
0
M2
M1
M3
M4
d2
d1
d3 d4
Except that now d1, d2, d3, d4, . . . denote the placement of the
objects in the coordinate system, rather than relative to the
fulcrum.
(Because we don’t, as yet, know where the fulcrum will be!)
15. Mathematical Setting
And place the objects in the coordinate system.
. .
0
M2
M1
M3
M4
d2
d1
d3 d4
Place the fulcrum at some coordinate .
is called the center of mass of the system.
x
x
x
16. Mathematical Setting
And place the objects in the coordinate system.
. .
0
M2
M1
M3
M4
d2
d1
d3 d4
In order to balance 2 objects, we needed:
M1 d1 = M2 d2 OR M1 d1 - M2 d2 =0
For a system with n objects we need:
x
1 1 2 2 3 3
( ) ( ) ( ) ( ) 0
n n
M d x M d x M d x M d x
17. Finding the Center of Mass of the System
1 1 2 2 3 3
( ) ( ) ( ) ( ) 0
leads to the following set of calculations
n n
M d x M d x M d x M d x
x
1 1 1 2 2 2 3 3 3 0
n n n
M d M x M d M x M d M x M d M x
Now we solve for .
1 1 2 2 3 3 1 2 3
n n n
M d M d M d M d M x M x M x M x
1 1 2 2 3 3 1 2 3
n n n
M d M d M d M d M M M M x
1 1 2 2 3 3
1 2 3
And finally . . .
n n
n
M d M d M d M d
x
M M M M
18. The Center of Mass of the System
1 1 2 2 3 3
1 2 3
n n
n
M d M d M d M d
x
M M M M
In the expression
The numerator is called the
first moment of the system
The denominator is the
total mass of the
system
19. Let’s start with everyday
language
What do you say when a sports
team is on a roll?
They may not have the lead but
they may have ___________
MOMENTUM
A team that has momentum is hard
to stop.
21. What is Momentum?
An object with a lot of
momentum is also hard to
stop
Momentum = p = mv
Units: kg∙m/s^2
m=mass
v=velocity
Momentum is also a vector (it
has direction)
22. Let’s practice
•
A 1200 kg car drives west at 25 m/s
for 3 hours. What is the car’s
momentum?
•
Identify the variables:
–
1200 kg = mass
–
25m/s, west = velocity
–
3 hours = time
P = mv = 1200 x 25 = 30000 kg m/s^2,
west
23. How hard is it to stop a
moving object?
To stop an object, we have to apply a
force over a period of time.
This is called Impulse
Impulse = FΔt Units: N∙s
F = force (N)
Δt = time elapsed (s)
24. How hard is it to stop a
moving object?
•
Using Newton’s 2nd Law we get
FΔt= mΔv
Which means
Impulse = change in momentum
25. Why does an egg break or
not break?
•
An egg dropped on a tile floor breaks, but
an egg dropped on a pillow does not. Why?
FΔt= mΔv
In both cases, m and Δv are the same.
If Δt goes up, what happens to F, the force?
Right! Force goes down. When dropped on a
pillow, the egg starts to slow down as soon
as it touches it. A pillow increases the
time the egg takes to stops.
26. Practice Problem
A 57 gram tennis ball falls on a tile floor.
The ball changes velocity from -1.2 m/s to
+1.2 m/s in 0.02 s. What is the average
force on the ball?
Identify the variables:
Mass = 57 g = 0.057 kg
Δvelocity = +1.2 – (-1.2) = 2.4 m/s
Time = 0.02 s
using FΔt= mΔv
F x (0.02 s) = (0.057 kg)(2.4 m/s)
F= 6.8 N
27. Car Crash
Would you rather be in a
head on collision with an
identical car, traveling at
the same speed as you,
or a brick wall?
Assume in both situations you
come to a complete stop.
Take a guess
http://techdigestuk.typepad.com/photos/uncategorized/car_crash.J
PG
28. Car Crash (cont.)
Everyone should vote now
Raise one finger if you
think it is better to hit
another car, two if it’s
better to hit a wall and
three if it doesn’t
matter.
And the answer is…..
29. Car Crash (cont.)
The answer is…
It Does Not Matter!
Look at FΔt= mΔv
In both situations, Δt, m, and Δv
are the same! The time it
takes you to stop depends on
your car, m is the mass of
your car, and Δv depends on
how fast you were initially
traveling.
30. Egg Drop connection
•
How are you going to use this in your egg
drop?
Which of these variables can you control?
FΔt= mΔv
Which of them do you want to maximize,
which do you want to minimize
(note: we are looking at the force on the egg.
Therefore, m represents the egg mass, not
the entire mass of the project)