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A –Level Physics:
Kinematics- SUVAT equations
Additionalskillsgained:
• Advancedcalculation
• ComponentIsolation
Objectives:
• Spec point 9: be able to use the equations for uniformly
accelerated motion in one dimension using SUVAT equations
• Spec point 15: understand how to make use of the
independence of vertical and horizontal motion of a projectile
moving freely under gravity
Lesson-Link: The string of beads…
https://www.youtube.com/watc
h?v=nDKGHGdXLEg
You have 10mins to
figure it out….
What is
Kinematics?
KINEMATICS
Motion Scientific
Study
What you’ll be
able to calculate
From simple…
What is the simplest equation you can
think of that relates distance, speed
and time?
Convert this into a vector form
You use this equation when there is
NO ACCELERATION
OCCURRING!
s =
𝒅
𝒕
v =
𝒔
𝒕
Careful! Displacement
is shown by an ‘s’ but
it’s not representing
speed!
To complex…
So far, we have covered equations for constant motion but
without acceleration. So how do we deal with motion with
constant acceleration?....
SUVAT
It’s an acronym! Write the word nice and big and using colours!
For each one, annotate what it represents and the unit it is
measured in!
Unravelling the maths…
Don’t forget as we’re going through this that these equations
only work with constant acceleration and that often the value
for acceleration can be substituted for ‘g’ as gravitational force
is commonly used in questions!
SUVAT
Task: We are soon going to start a flow chart of the equations!
Start these on a new page with clear highlighting of the
equations.
Step 1, equation 1 SUVAT
Rearrange the equation for acceleration to have v as the
subject
𝒂 =
𝒗 − 𝒖
𝒕
𝒗 = 𝒖 + 𝒂𝒕
Step 2, equation 2 SUVAT
If acceleration is constant then what is the average velocity of a
journey between two points?
𝒖 𝒗
𝒖 + 𝒗
𝟐
a.k.a
Average ‘v’
Try combining this with the equation
for non-acceleration displacement
(s= v x t)
s = (
𝒖+𝒗
𝟐
) × 𝒕
1 + 2 makes equation 3!
SUVAT
We need to combine the first and second equations. Let’s try
first to do it by putting the first into the second…
Work out the simplest form…
s = (
𝒖+𝒗
𝟐
) × 𝒕
𝒗 = 𝒖 + 𝒂𝒕
1 + 2 makes equation 3!
SUVAT
Work out the
simplest form…
𝐬 = 𝐮𝐭 +
𝟏
𝟐
𝐚𝐭𝟐
𝐬 =
(𝐮+ 𝐮+𝐚𝐭 )
𝟐
× 𝐭
𝐬 =
𝟐𝐮+𝐚𝐭
𝟐
× 𝐭
𝐬 =
𝟐𝐮𝐭 + 𝐚𝐭𝟐
𝟐
𝐬 = 𝐮𝐭 +
𝟏
𝟐
𝐚𝐭𝟐
1 + 2 makes equation
4…as well…
SUVAT
If we combine the equations again but this time changing
equation 1 to be in the form of t….
s = (
𝒖+𝒗
𝟐
) × 𝒕
𝒗 = 𝒖 + 𝒂𝒕
𝒕 =
𝒗 − 𝒖
𝒂
s = (
𝒖+𝒗
𝟐
) ×
(𝒗−𝒖)
𝒂
2as = 𝒖 + 𝒗 × (𝒗 − 𝒖)
2as = 𝒖𝒗 + 𝒗𝟐 − 𝒖𝟐 − 𝒗𝒖
v2 = 𝒖𝟐 + 𝟐𝒂𝒔
What we haven’t got… SUVAT
Make a table whereby you have all of the equations on the left
hand side, and the quantity that is missing each time. If the
SUVAT doesn’t contain the needed variable then don’t use it!
𝒗 = 𝒖 + 𝒂𝒕
s = (
𝒖+𝒗
𝟐
) × 𝒕
𝐬 = 𝐮𝐭 +
𝟏
𝟐
𝐚𝐭𝟐
v2 = 𝒖𝟐 + 𝟐𝒂𝒔
Worked
Example
A man drops a rock from the top of a cliff and the rock
takes 3 second to reach the bottom. Calculate both the
velocity it reaches before hitting the ground and the
distance it fell
1. Pick the Equation:
• Which equation contains the quantity we want and a quantity we know?
• Only two equations have both, and
• We can’t use the first one as it contains ‘s’ which we do not know yet! So we
use the second!
We want: v
We have: t
𝐬 = 𝐮𝐭 +
𝟏
𝟐
𝐚𝐭𝟐 𝒗 = 𝒖 + 𝒂𝒕
2. Rearrange:
• Rearrange the equation to make the needed quantity the subject. Luckily in
this case we don’t need to!
3. Plug the values in:
• We know that time here is 3s, we know that the initial velocity was 0m/s and
acceleration must be 9.81 m/s2.
𝒗 = 𝒖 + 𝒂𝒕 𝒗 = 𝟎 + (𝟗. 𝟖𝟏 × 𝟑) 𝒗 = 𝟐𝟗. 𝟒 m/s1
Worked
Example
A man drops a rock from the top of a cliff and the rock
takes 3 second to reach the bottom. Calculate both the
velocity it reaches before hitting the ground and the
distance it fell
4. Repeat for the other quantity:
• Which equation contains the quantity we want and a quantity we know?
• Two equations can be used here: and
• So s = 0 m/s*3s + ½ *9,81 m/s2 * (3 s)2 s = 44.1 m
• Solving for ‘s’ gives us 44.1 m!
We want: s
We have: t (3 s) and v (29.4 m/s)
𝐬 = 𝐮𝐭 +
𝟏
𝟐
𝐚𝐭𝟐 v2 = 𝒖𝟐 + 𝟐𝒂𝒔
The key to SUVAT calculations is just to spend a little
time working out the correct equation to use!
Practice Questions
A bird drops a stone
from 88m above a
pond, how long will it
take the stone to hit
the surface and what
speed will it be
travelling at just before
it hits the water?
An alien is holidaying
on Pluto and throws a
tennis ball vertically
upward at a speed of
20ms-1 causing it to
reach the peak of its
journey a whopping
303m above the point
of release. Calculate the
acceleration due to
gravity on Pluto
Extension/IS
Write
Additionalskillsgained:
• Advancedcalculation
• ComponentIsolation
Objectives:
• Spec point 9: be able to use the equations for uniformly
accelerated motion in one dimension using SUVAT equations
• Spec point 15: understand how to make use of the
independence of vertical and horizontal motion of a projectile
moving freely under gravity

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Motion_Equations.ppt

  • 2. Additionalskillsgained: • Advancedcalculation • ComponentIsolation Objectives: • Spec point 9: be able to use the equations for uniformly accelerated motion in one dimension using SUVAT equations • Spec point 15: understand how to make use of the independence of vertical and horizontal motion of a projectile moving freely under gravity
  • 3. Lesson-Link: The string of beads… https://www.youtube.com/watc h?v=nDKGHGdXLEg You have 10mins to figure it out….
  • 5. What you’ll be able to calculate
  • 6. From simple… What is the simplest equation you can think of that relates distance, speed and time? Convert this into a vector form You use this equation when there is NO ACCELERATION OCCURRING! s = 𝒅 𝒕 v = 𝒔 𝒕 Careful! Displacement is shown by an ‘s’ but it’s not representing speed!
  • 7. To complex… So far, we have covered equations for constant motion but without acceleration. So how do we deal with motion with constant acceleration?.... SUVAT It’s an acronym! Write the word nice and big and using colours! For each one, annotate what it represents and the unit it is measured in!
  • 8. Unravelling the maths… Don’t forget as we’re going through this that these equations only work with constant acceleration and that often the value for acceleration can be substituted for ‘g’ as gravitational force is commonly used in questions! SUVAT Task: We are soon going to start a flow chart of the equations! Start these on a new page with clear highlighting of the equations.
  • 9. Step 1, equation 1 SUVAT Rearrange the equation for acceleration to have v as the subject 𝒂 = 𝒗 − 𝒖 𝒕 𝒗 = 𝒖 + 𝒂𝒕
  • 10. Step 2, equation 2 SUVAT If acceleration is constant then what is the average velocity of a journey between two points? 𝒖 𝒗 𝒖 + 𝒗 𝟐 a.k.a Average ‘v’ Try combining this with the equation for non-acceleration displacement (s= v x t) s = ( 𝒖+𝒗 𝟐 ) × 𝒕
  • 11. 1 + 2 makes equation 3! SUVAT We need to combine the first and second equations. Let’s try first to do it by putting the first into the second… Work out the simplest form… s = ( 𝒖+𝒗 𝟐 ) × 𝒕 𝒗 = 𝒖 + 𝒂𝒕
  • 12. 1 + 2 makes equation 3! SUVAT Work out the simplest form… 𝐬 = 𝐮𝐭 + 𝟏 𝟐 𝐚𝐭𝟐 𝐬 = (𝐮+ 𝐮+𝐚𝐭 ) 𝟐 × 𝐭 𝐬 = 𝟐𝐮+𝐚𝐭 𝟐 × 𝐭 𝐬 = 𝟐𝐮𝐭 + 𝐚𝐭𝟐 𝟐 𝐬 = 𝐮𝐭 + 𝟏 𝟐 𝐚𝐭𝟐
  • 13. 1 + 2 makes equation 4…as well… SUVAT If we combine the equations again but this time changing equation 1 to be in the form of t…. s = ( 𝒖+𝒗 𝟐 ) × 𝒕 𝒗 = 𝒖 + 𝒂𝒕 𝒕 = 𝒗 − 𝒖 𝒂 s = ( 𝒖+𝒗 𝟐 ) × (𝒗−𝒖) 𝒂 2as = 𝒖 + 𝒗 × (𝒗 − 𝒖) 2as = 𝒖𝒗 + 𝒗𝟐 − 𝒖𝟐 − 𝒗𝒖 v2 = 𝒖𝟐 + 𝟐𝒂𝒔
  • 14. What we haven’t got… SUVAT Make a table whereby you have all of the equations on the left hand side, and the quantity that is missing each time. If the SUVAT doesn’t contain the needed variable then don’t use it! 𝒗 = 𝒖 + 𝒂𝒕 s = ( 𝒖+𝒗 𝟐 ) × 𝒕 𝐬 = 𝐮𝐭 + 𝟏 𝟐 𝐚𝐭𝟐 v2 = 𝒖𝟐 + 𝟐𝒂𝒔
  • 15. Worked Example A man drops a rock from the top of a cliff and the rock takes 3 second to reach the bottom. Calculate both the velocity it reaches before hitting the ground and the distance it fell 1. Pick the Equation: • Which equation contains the quantity we want and a quantity we know? • Only two equations have both, and • We can’t use the first one as it contains ‘s’ which we do not know yet! So we use the second! We want: v We have: t 𝐬 = 𝐮𝐭 + 𝟏 𝟐 𝐚𝐭𝟐 𝒗 = 𝒖 + 𝒂𝒕 2. Rearrange: • Rearrange the equation to make the needed quantity the subject. Luckily in this case we don’t need to! 3. Plug the values in: • We know that time here is 3s, we know that the initial velocity was 0m/s and acceleration must be 9.81 m/s2. 𝒗 = 𝒖 + 𝒂𝒕 𝒗 = 𝟎 + (𝟗. 𝟖𝟏 × 𝟑) 𝒗 = 𝟐𝟗. 𝟒 m/s1
  • 16. Worked Example A man drops a rock from the top of a cliff and the rock takes 3 second to reach the bottom. Calculate both the velocity it reaches before hitting the ground and the distance it fell 4. Repeat for the other quantity: • Which equation contains the quantity we want and a quantity we know? • Two equations can be used here: and • So s = 0 m/s*3s + ½ *9,81 m/s2 * (3 s)2 s = 44.1 m • Solving for ‘s’ gives us 44.1 m! We want: s We have: t (3 s) and v (29.4 m/s) 𝐬 = 𝐮𝐭 + 𝟏 𝟐 𝐚𝐭𝟐 v2 = 𝒖𝟐 + 𝟐𝒂𝒔 The key to SUVAT calculations is just to spend a little time working out the correct equation to use!
  • 17. Practice Questions A bird drops a stone from 88m above a pond, how long will it take the stone to hit the surface and what speed will it be travelling at just before it hits the water? An alien is holidaying on Pluto and throws a tennis ball vertically upward at a speed of 20ms-1 causing it to reach the peak of its journey a whopping 303m above the point of release. Calculate the acceleration due to gravity on Pluto
  • 19. Additionalskillsgained: • Advancedcalculation • ComponentIsolation Objectives: • Spec point 9: be able to use the equations for uniformly accelerated motion in one dimension using SUVAT equations • Spec point 15: understand how to make use of the independence of vertical and horizontal motion of a projectile moving freely under gravity

Editor's Notes

  1. Force for one = cos 35 x 6500 = 5324. Both = 10648N. A= F/m = 10.6ms-2