Chapter 6
BJT Amplifiers
Objectives
 Understand the concept of amplifiers
 Identify and apply internal transistor parameters
 Understand and analyze common-emitter
Introduction
One of the primary uses of a transistor is to
amplify ac signals. This could be an audio
signal or perhaps some high frequency radio
signal. It has to be able to do this without
distorting the original input.
Amplifier Operation
Recall from the previous chapter that the purpose of
dc biasing was to establish the Q-point for operation.
The collector curves and load lines help us to relate
the Q-point and its proximity to cutoff and saturation.
The Q-point is best established where the signal
variations do not cause the transistor to go into
saturation or cutoff.
What we are most interested in is the ac signal itself.
Since the dc part of the overall signal is filtered out in
most cases, we can view a transistor circuit in terms
of just its ac component.
Amplifier Operation
For the analysis of transistor circuits from both dc and ac
perspectives, the ac subscripts are lower case and italicized.
Instantaneous values use both italicized lower case letters
and subscripts.
Amplifier Operation
The boundary between cutoff and saturation is called the
linear region. A transistor which operates in the linear
region is called a linear amplifier. Note that only the ac
component reaches the load because of the capacitive
coupling and that the output is 180º out of phase with
input.
Transistor Equivalent Circuits
We can view transistor circuits by use of resistance
or r parameters for better understanding. Since
the base resistance, rb is small it normally is not
considered and since the collector resistance, rc is
fairly high we consider it as an open. The emitter
resistance, rc is the main parameter that is viewed.
You can determine rc
from this simplified
equation. (Appendix
B)
re = 25 mV/IE
Transistor Equivalent Circuits
The two graphs best illustrate the difference
between DC and ac. The two only differ slightly.
Transistor Equivalent Circuits
Since r parameters are used throughout the rest of the
textbook we will not go into deep discussion about h
parameters. However, since some data sheets include or
exclusively provide h parameters these formulas can be
used to convert them to r parameters.
r’e = hre/hoe
r’c = hre + 1/hoe
r’b = hie – hre/hoe(1+ hfe)
The Common-Emitter Amplifier
The common-emitter amplifier exhibits high voltage and
current gain. The output signal is 180º out of phase with the
input.
Now let’s use our dc and ac analysis methods to view this type
of transistor circuit.
The Common Emitter Amplifier
DC Analysis
The dc component of the
circuit “sees” only the part
of the circuit that is within
the boundaries of C1, C2,
and C3 as the dc will not
pass through these
components. The equivalent
circuit for dc analysis is
shown.
The methods for dc analysis
are just are the same as
dealing with a voltage-
divider circuit.
Common Emitter Amplifier
AC Equivalent Circuit
The ac equivalent
circuit basically
replaces the
capacitors with
shorts, being that ac
passes through
easily through them.
The power supplies
are also effectively
shorts to ground for
ac analysis.
Common Emitter Amplifier
AC Equivalent Circuit
We can look at the input voltage in terms of the equivalent
base circuit (ignore the other components from the previous
diagram). Note the use of simple series-parallel analysis skills
for determining Vin.
S
inS
in
in V
RR
R

V
Common Emitter Amplifier
AC Equivalent Circuit
The input resistance as seen by the input voltage
can be illustrated by the r parameter equivalent circuit.
The simplified formula below is used.
Rin(base) = acr’e
Example 6-3
The output
resistance is
for all practical
purposes the
value of
Rc=RC||RL.
Common Emitter Amplifier
AC Equivalent Circuit
Voltage gain can be
easily determined by
dividing the ac output
voltage by the ac input
voltage.
Av = Vout/Vin = Vc/Vb
Voltage gain can also be
determined by the
simplified formula below.
Av = RC/r’e
Common Emitter Amplifier
AC Equivalent Circuit
v
totalins
totalin
v A
RR
R
)(
)('
A


Taking the attenuation
from the ac supply internal
resistance and input
resistance into consideration
is included in the overall
gain.
A’v = (Vb/Vs)Av
or
inS
S
S
S
C
i
RR
V
I
I
I

 ,A ivp AAA
Summary
 Transistor circuits can be view in terms of its ac equivalent
for better understanding.
 The common-emitter amplifier has high voltage and
current gain.
 The common-collector has a high current gain and
voltage gain of 1. It has a high input impedance and low
output impedance.
 Most transistors amplifiers are designed to operate
in the linear region.
Summary
 The common-base has a high voltage gain and a
current gain of 1. It has a low input impedance and
high output impedance

Elec ch06bjt amplifiers

  • 1.
  • 2.
    Objectives  Understand theconcept of amplifiers  Identify and apply internal transistor parameters  Understand and analyze common-emitter
  • 3.
    Introduction One of theprimary uses of a transistor is to amplify ac signals. This could be an audio signal or perhaps some high frequency radio signal. It has to be able to do this without distorting the original input.
  • 4.
    Amplifier Operation Recall fromthe previous chapter that the purpose of dc biasing was to establish the Q-point for operation. The collector curves and load lines help us to relate the Q-point and its proximity to cutoff and saturation. The Q-point is best established where the signal variations do not cause the transistor to go into saturation or cutoff. What we are most interested in is the ac signal itself. Since the dc part of the overall signal is filtered out in most cases, we can view a transistor circuit in terms of just its ac component.
  • 5.
    Amplifier Operation For theanalysis of transistor circuits from both dc and ac perspectives, the ac subscripts are lower case and italicized. Instantaneous values use both italicized lower case letters and subscripts.
  • 6.
    Amplifier Operation The boundarybetween cutoff and saturation is called the linear region. A transistor which operates in the linear region is called a linear amplifier. Note that only the ac component reaches the load because of the capacitive coupling and that the output is 180º out of phase with input.
  • 7.
    Transistor Equivalent Circuits Wecan view transistor circuits by use of resistance or r parameters for better understanding. Since the base resistance, rb is small it normally is not considered and since the collector resistance, rc is fairly high we consider it as an open. The emitter resistance, rc is the main parameter that is viewed. You can determine rc from this simplified equation. (Appendix B) re = 25 mV/IE
  • 8.
    Transistor Equivalent Circuits Thetwo graphs best illustrate the difference between DC and ac. The two only differ slightly.
  • 9.
    Transistor Equivalent Circuits Sincer parameters are used throughout the rest of the textbook we will not go into deep discussion about h parameters. However, since some data sheets include or exclusively provide h parameters these formulas can be used to convert them to r parameters. r’e = hre/hoe r’c = hre + 1/hoe r’b = hie – hre/hoe(1+ hfe)
  • 10.
    The Common-Emitter Amplifier Thecommon-emitter amplifier exhibits high voltage and current gain. The output signal is 180º out of phase with the input. Now let’s use our dc and ac analysis methods to view this type of transistor circuit.
  • 11.
    The Common EmitterAmplifier DC Analysis The dc component of the circuit “sees” only the part of the circuit that is within the boundaries of C1, C2, and C3 as the dc will not pass through these components. The equivalent circuit for dc analysis is shown. The methods for dc analysis are just are the same as dealing with a voltage- divider circuit.
  • 12.
    Common Emitter Amplifier ACEquivalent Circuit The ac equivalent circuit basically replaces the capacitors with shorts, being that ac passes through easily through them. The power supplies are also effectively shorts to ground for ac analysis.
  • 13.
    Common Emitter Amplifier ACEquivalent Circuit We can look at the input voltage in terms of the equivalent base circuit (ignore the other components from the previous diagram). Note the use of simple series-parallel analysis skills for determining Vin. S inS in in V RR R  V
  • 14.
    Common Emitter Amplifier ACEquivalent Circuit The input resistance as seen by the input voltage can be illustrated by the r parameter equivalent circuit. The simplified formula below is used. Rin(base) = acr’e Example 6-3 The output resistance is for all practical purposes the value of Rc=RC||RL.
  • 15.
    Common Emitter Amplifier ACEquivalent Circuit Voltage gain can be easily determined by dividing the ac output voltage by the ac input voltage. Av = Vout/Vin = Vc/Vb Voltage gain can also be determined by the simplified formula below. Av = RC/r’e
  • 16.
    Common Emitter Amplifier ACEquivalent Circuit v totalins totalin v A RR R )( )(' A   Taking the attenuation from the ac supply internal resistance and input resistance into consideration is included in the overall gain. A’v = (Vb/Vs)Av or inS S S S C i RR V I I I   ,A ivp AAA
  • 17.
    Summary  Transistor circuitscan be view in terms of its ac equivalent for better understanding.  The common-emitter amplifier has high voltage and current gain.  The common-collector has a high current gain and voltage gain of 1. It has a high input impedance and low output impedance.  Most transistors amplifiers are designed to operate in the linear region.
  • 18.
    Summary  The common-basehas a high voltage gain and a current gain of 1. It has a low input impedance and high output impedance