BASIC DIAMOND LATTICE
formed by the carbon atoms in a diamond crysta)
DEFINITION
 The diamond lattice can be considered to be formed by
interpenetrating two fcc lattices along the body diagonal by ¼ cube
edge.
 One sublattice has its orgin at the point (0,0,0 )and the order at the
point quarter of the way along the body daigonal (at the point
a/4,a/4,a/4).
 The diamond cubic structure is loosely packed ,since each atom has
four nearest neighbour
NUMBER OF ATOMS PER UNIT CELL
 In the eight corner each atom is shared by eight unit cells
1/8 *8=1
 The each 6 faces ever single atom which is shared by 2 unit cells
½*6=3
 And in every unit cell it has 4 atoms inside 4
 1+3+4=8
THE FIGURES OF BOTH POSITION AND BASIC
DAIMOND LATTICE
ATOMIC RADIUS
 (𝑥𝑧)2
=𝑎2
/8
 (𝑥𝑦)2
= (𝑥𝑧)2
+(𝑦𝑧)2
=𝑎2
/8+𝑎2
/16=3𝑎2
/16
 XY=2r
 (2𝑟)2
= 3𝑎2
/16
 r=√3/8*a
 Or a=
COORDINATION NUMBER
 In a diamond crystal, the carbon atom are
linked by the directional covalent bond
 Carbon atoms from covalent bonds with four
other carbon atoms that occupy four corners
of the cube in a tetrehedral structure.
 In the diamond lattice each atom has four
nearest neighbour with which it forms covalent
bonds ,thus the coordination number of
diamond crystal is 4
PACKING FACTOR
 Packing factor =volume of all atoms in the unit cell /volume of the unit cell
 = number of the atoms in the unit cell*volume of one
atom
 /volume of the unit cell
 =8*(4/3*π𝒓 𝟑
)/𝒂 𝟑
 =(π√3)/16
 =0.34
 Packing factor =34%
 Thus it islossely packed structure
 Carbon ,silicon ,germanium ,and grey tin crystallize in the diamond stucture
Thanking you

Diamond cubic structure

  • 2.
    BASIC DIAMOND LATTICE formedby the carbon atoms in a diamond crysta)
  • 3.
    DEFINITION  The diamondlattice can be considered to be formed by interpenetrating two fcc lattices along the body diagonal by ¼ cube edge.  One sublattice has its orgin at the point (0,0,0 )and the order at the point quarter of the way along the body daigonal (at the point a/4,a/4,a/4).  The diamond cubic structure is loosely packed ,since each atom has four nearest neighbour
  • 4.
    NUMBER OF ATOMSPER UNIT CELL  In the eight corner each atom is shared by eight unit cells 1/8 *8=1  The each 6 faces ever single atom which is shared by 2 unit cells ½*6=3  And in every unit cell it has 4 atoms inside 4  1+3+4=8
  • 5.
    THE FIGURES OFBOTH POSITION AND BASIC DAIMOND LATTICE
  • 6.
    ATOMIC RADIUS  (𝑥𝑧)2 =𝑎2 /8 (𝑥𝑦)2 = (𝑥𝑧)2 +(𝑦𝑧)2 =𝑎2 /8+𝑎2 /16=3𝑎2 /16  XY=2r  (2𝑟)2 = 3𝑎2 /16  r=√3/8*a  Or a=
  • 7.
    COORDINATION NUMBER  Ina diamond crystal, the carbon atom are linked by the directional covalent bond  Carbon atoms from covalent bonds with four other carbon atoms that occupy four corners of the cube in a tetrehedral structure.  In the diamond lattice each atom has four nearest neighbour with which it forms covalent bonds ,thus the coordination number of diamond crystal is 4
  • 8.
    PACKING FACTOR  Packingfactor =volume of all atoms in the unit cell /volume of the unit cell  = number of the atoms in the unit cell*volume of one atom  /volume of the unit cell  =8*(4/3*π𝒓 𝟑 )/𝒂 𝟑  =(π√3)/16  =0.34  Packing factor =34%  Thus it islossely packed structure  Carbon ,silicon ,germanium ,and grey tin crystallize in the diamond stucture
  • 10.