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Design Procedure for an Integrator
The document describes the design procedure for an integrator circuit. The procedure involves: 1) Assuming a gain value if not given and calculating resistor values accordingly 2) Calculating the feedback and capacitor frequencies based on the input and gain values 3) Sizing the feedback resistor and capacitor to achieve the desired frequencies 4) Calculating the equivalent input resistor value. The document then applies this procedure to design an integrator circuit to process 1 kHz sinusoidal signals with 10 mV amplitude. It selects component values of R1=10kΩ, Rf=100kΩ, Cf=15.91nF to achieve the design requirements.
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Design Procedure for an Integrator
- 1. DESIGN PROCEDURE FOR ANINTEGRATOR By Bhagyashri Tanaji Thorat Assistant Professor Department of Electronics & Telecommunication Hope Foundation’s International Institute of Information Technology Hope Foundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in
- 2. DESIGN PROCEDURE FORAN INTEGRATOR • If gain is not given in problem statement assume gain =10 • From the value of gain. Assume R1& calculate RF. • Calculate fa from fb • 𝑓𝑎 = 𝑓𝑏/10 • Calculate 𝐶 𝐹 from the value of 𝑓𝑎 • Calculate 𝑅 𝐶𝑜𝑚𝑝 = 𝑅1 ∥ 𝑅 𝐹 Hope Foundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in
- 3. PROBLEM STATEMENT TODESIGN INTEGRATOR Design a practical Integrator circuit to properly process input sinusodial waveform upto 1kHz . The input amplitude is 10 mV. Hope Foundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in
- 4. CIRCUIT DIAGRAM INTEGRATOR HopeFoundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in
- 5. SOLUTION • Given 𝑓= 1 𝑘𝐻𝑧 ; 𝑉𝑖 = 10 𝑚𝑉 • ∴ 𝑓𝑏 = 1 𝑘𝐻𝑧 • Assume dc gain 10 • 𝑓𝑏 ≥ 10 𝑓𝑎 & 𝑓𝑎 ≤ 100 𝐻𝑧 • 𝑓𝑎 = 1 2𝜋 𝑅 𝐹 𝐶 𝐹 𝑅 𝐹 𝐶 𝐹 = 1 2×3.14×100 𝐻𝑧 = 1.59 × 10−3 Hope Foundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in
- 6. SOLUTION • 𝑅 𝐹 𝑅1 = 10∴ 𝑅1 = 10 𝑘𝛺 & 𝑅 𝐹 = 100 𝑘𝛺 • Substituting value of 𝑅 𝐹 • 𝐶 𝐹 = 1.59 ×10−3 100 × 103 = 15.91 𝑛𝐹 Hope Foundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in
- 7. SOLUTION Calculate 𝑅 𝐶𝑜𝑚𝑝= 𝑅1 ∥ 𝑅 𝐹 = 10 𝑘𝛺 100 𝑘𝛺 ≈ 10 𝑘𝛺 Hope Foundation’s International Institute of Information Technology, I²IT, P-14 Rajiv Gandhi Infotech Park, Hinjawadi, Pune - 411 057 Tel - +91 20 22933441 / 2 / 3 | Website - www.isquareit.edu.in ; Email - info@isquareit.edu.in
- 8. Thank You For furtherdetails please feel free to contact Bhagyashri Thorat Department of Electronics & Telecommunication Hope Foundation’s International Institute of Information Technology, I²IT P-14, Rajiv Gandhi Infotech Park, MIDC Phase 1, Hinjawadi, Pune – 411 057 Tel +91 20 22933441 / 2 /3 www.isquareit.edu.in bhagyashrit@isquareit.edu.in | info@isquareit.edu.in