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[object Object],[object Object],[object Object],[object Object],Chapter 16:  Current Electricity Part I
[object Object],[object Object],[object Object],Chapter 14 At the end of the chapter, you should be able to: 1. Electric Current
Electric Current ,[object Object],[object Object],[object Object],[object Object],Chapter 14 Pg 241 Definition:  Current is a rate of flow of charge.  ,[object Object],[object Object],[object Object],Actual Conventional
Ampere (A) Coulomb (C) second (s) Measurement of Current Definition: Current is a rate of flow of charge.   The amount of charge passing thru a given pt in 1 sec. Chapter 14 Pg 241 Time (t) Charge (Q) Current (I) SI Unit Quantity Q _______ I t Formula: I =  or Q = I t Q t
Example 1:  A current of 10 A flows through an electric heater for 10 minutes. What is the total charge circulated through the heater? [Solution] t = 10 min x 60 = 600 s I = 10 A Q  = I t    = 10 A x 600 s =  6000 C The total charge is 6000 C Measurement of Current Chapter 14 Q _______ I t
Example 2:  In an electrical circuit, a charge of 60C flows past a point in 10s. What is the current in the circuit? Measurement of Current Chapter 14 [Solution] t  = 10 s ; Q = 60 C Q  = I t    I  =   = 60 / 10   =  6 A The current is 6 A Q _______ I t Q t
Example 3:  A lightning flash carries 25 C of charge and lasts for 0.01 s.  What is the current? [Solution] Q = 25 C ; t = 0.01 s   Q  = I t   25 C  = I x 0.01s   25 / 0.01  = I   I  =  2500A Current is 2500A Measurement of Current Chapter 14
Example 4:  A current of 2 A is flowing through a conductor. How long  does it take for 10 C of charge to pass any point? [Solution] I = 2 A ; Q = 10 C   Q =  I t 10C  =  2A x t 10 / 2 =  t   t  =  5 s Time taken is 5 s Measurement of Current Chapter 14
[object Object],[object Object],[object Object],[object Object],[object Object],There must be a  closed path  in order for current to flow. Ammeter Chapter 14 Pg 241 A A A +  + 
More common symbols can be found on pg 243 Chapter 14 Pg 243 Electric Symbols
Circuit Diagram Variable resistor Bulb Ammeter Voltmeter Battery Fixed resistor Switch Chapter 14 Pg 243
[object Object],[object Object],[object Object],Chapter 14:  Current Electricity Chapter 14 Pg 245 Part II
[object Object],[object Object],At the end of the chapter, you should be able to: 2. Electromotive Force & Potential Difference Chapter 14 Pg 245
Electromotive Force (e.m.f) Chapter 14 Pg 245 Definition:  Electromotive force is defined as the total work done by a source in driving a  unit charge  around a complete circuit 1 Unit charge = 1 coulomb of charge
Electromotive Force (e.m.f) Chapter 14 Pg 245 ,[object Object],[object Object],[object Object],[object Object],[object Object]
2V Electromotive Force (e.m.f) Hi I’m Mr Coulomb (1 C) 2J of  energy 2J of  energy 2 J of work is done when 1 C of charge moves round the circuit Mr Coulomb goes back to  the source for energy Note: 2J of electrical energy 2J of light and heat energy 2 J of energy is  supplied by the  cell in moving 1 C of charge round
Electromotive Force (e.m.f) Chapter 14 Pg 245 ,[object Object],[object Object],[object Object],Work done/energy  is used to light up the bulb. Direction of current travel
Analogy The pump pushes the  water to flow flow of water Work done/ energy is used to move the mill
Potential Difference (p.d.) Chapter 14 Pg 246 Definition:  The p.d. between two points is the energy required to move 1 C of charge between them.  Potential Difference (p.d.)  OR   Voltage (V) SI Unit :  V (volts)
The p.d. between 2 points is the energy required to move 1 C of charge between the two points. energy  E  p.d. = --------------- ,  V  =  ------  or  E = VQ  charge  Q e.g.  2V = 2 J/C Potential Difference (p.d.) Formula: E _______ V Q
V ,[object Object],[object Object],[object Object],[object Object],[object Object],+  +  Voltmeter Chapter 14 Pg 247 2J of  energy 2J of  energy
The diagram shows a battery with an electromotive force of  6 V in a circuit. How much energy is needed to drive 30C of  charge round the circuit? E = VQ = 6V x 30C =  180 J or [Solution] Example 1 6 V
[object Object],[object Object],[object Object],Example 2 B
[object Object],[object Object],[object Object],Q = I t = 0.5A x (10 x 60)s =  300 C   Total charge is  300 C   E  =  V Q 2400J  =  V x 300C V = 2400 / 300  =  8 V     The p.d. is  8 V Example 3
[object Object],[object Object],[object Object],Chapter 14:  Current Electricity Chapter 14 Pg 247 Part III
Chapter 14 Pg 247 The resistance is a measure of how difficult it is for an electric current to pass through a substance. Resistance
Chapter 14 Pg 247 Definition:  The resistance of a conductor is defined as the ratio of the potential difference across the conductor to the current flowing in it. Resistance Formula: R = SI Unit :   Ohms (  ) V I where R = resistance V = p.d / voltage I = current or   V = IR
The size of the current depends on the resistance in the circuit. A A 2  5  10  With the same cell used  (i.e. voltage is the same),  as resistance, R increases,  current, I ____________  Resistance 20 V 20 V 20 V decreases I = 10 A I = 4 A I = 2 A A
[object Object],[object Object],Flow of current Resistance Resistance Chapter 14 Pg 248
V = I R  6 = I x 4 6 / 4 = I I =  1.5 A Reading on the ammeter is  1.5 A A 4    resistor is connected in series with an ammeter and a 6 V battery, as shown. What is the reading shown on the ammeter.  Example 1 R I _______ V
Chapter 14 Pg 249 The resistance R (= V / I) of a metallic conductor is  CONSTANT  under steady physical conditions Ohm's Law
For Ohmic conductors  (Conductors that obeys Ohm’s law) e.g. pure metal Chapter 14 Pg 248 For non-Ohmic conductor e.g. filament lamp bulb I /A V/V I /A V/V Metal A Metal B I /A V/V
[object Object],[object Object],[object Object],[object Object],[object Object],Resistor
[object Object],[object Object],Resistor
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],To determine the unknown resistance, R of a fixed resistor Pg 253   Fixed resistor A V Variable  Resistor/ Rheostat
The unknown resistance of the resistor is found by obtaining the gradient of the straight line graph. ,[object Object],[object Object],[object Object],[object Object],Experiment to find Resistance Chapter 14 Pg 253 I /A V/V
Example 2 C
Example 3 C
Example 4 B
Example 5 B
Resistivity ,[object Object],[object Object],[object Object],[object Object]
Resistivity Formula: where    R = resistance   ρ = resistivity   l = length   A = cross-sectional area
Example 6
Example 7
Resistors in Series Resistors in Parallel Simulation from Crocodile Physics
Example 8
Example 9

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Current Electricity (NA)

  • 1.
  • 2.
  • 3.
  • 4. Ampere (A) Coulomb (C) second (s) Measurement of Current Definition: Current is a rate of flow of charge. The amount of charge passing thru a given pt in 1 sec. Chapter 14 Pg 241 Time (t) Charge (Q) Current (I) SI Unit Quantity Q _______ I t Formula: I = or Q = I t Q t
  • 5. Example 1: A current of 10 A flows through an electric heater for 10 minutes. What is the total charge circulated through the heater? [Solution] t = 10 min x 60 = 600 s I = 10 A Q = I t = 10 A x 600 s = 6000 C The total charge is 6000 C Measurement of Current Chapter 14 Q _______ I t
  • 6. Example 2: In an electrical circuit, a charge of 60C flows past a point in 10s. What is the current in the circuit? Measurement of Current Chapter 14 [Solution] t = 10 s ; Q = 60 C Q = I t I = = 60 / 10 = 6 A The current is 6 A Q _______ I t Q t
  • 7. Example 3: A lightning flash carries 25 C of charge and lasts for 0.01 s. What is the current? [Solution] Q = 25 C ; t = 0.01 s Q = I t 25 C = I x 0.01s 25 / 0.01 = I I = 2500A Current is 2500A Measurement of Current Chapter 14
  • 8. Example 4: A current of 2 A is flowing through a conductor. How long does it take for 10 C of charge to pass any point? [Solution] I = 2 A ; Q = 10 C Q = I t 10C = 2A x t 10 / 2 = t t = 5 s Time taken is 5 s Measurement of Current Chapter 14
  • 9.
  • 10. More common symbols can be found on pg 243 Chapter 14 Pg 243 Electric Symbols
  • 11. Circuit Diagram Variable resistor Bulb Ammeter Voltmeter Battery Fixed resistor Switch Chapter 14 Pg 243
  • 12.
  • 13.
  • 14. Electromotive Force (e.m.f) Chapter 14 Pg 245 Definition: Electromotive force is defined as the total work done by a source in driving a unit charge around a complete circuit 1 Unit charge = 1 coulomb of charge
  • 15.
  • 16. 2V Electromotive Force (e.m.f) Hi I’m Mr Coulomb (1 C) 2J of energy 2J of energy 2 J of work is done when 1 C of charge moves round the circuit Mr Coulomb goes back to the source for energy Note: 2J of electrical energy 2J of light and heat energy 2 J of energy is supplied by the cell in moving 1 C of charge round
  • 17.
  • 18. Analogy The pump pushes the water to flow flow of water Work done/ energy is used to move the mill
  • 19. Potential Difference (p.d.) Chapter 14 Pg 246 Definition: The p.d. between two points is the energy required to move 1 C of charge between them. Potential Difference (p.d.) OR Voltage (V) SI Unit : V (volts)
  • 20. The p.d. between 2 points is the energy required to move 1 C of charge between the two points. energy E p.d. = --------------- , V = ------ or E = VQ charge Q e.g. 2V = 2 J/C Potential Difference (p.d.) Formula: E _______ V Q
  • 21.
  • 22. The diagram shows a battery with an electromotive force of 6 V in a circuit. How much energy is needed to drive 30C of charge round the circuit? E = VQ = 6V x 30C = 180 J or [Solution] Example 1 6 V
  • 23.
  • 24.
  • 25.
  • 26. Chapter 14 Pg 247 The resistance is a measure of how difficult it is for an electric current to pass through a substance. Resistance
  • 27. Chapter 14 Pg 247 Definition: The resistance of a conductor is defined as the ratio of the potential difference across the conductor to the current flowing in it. Resistance Formula: R = SI Unit : Ohms (  ) V I where R = resistance V = p.d / voltage I = current or V = IR
  • 28. The size of the current depends on the resistance in the circuit. A A 2  5  10  With the same cell used (i.e. voltage is the same), as resistance, R increases, current, I ____________ Resistance 20 V 20 V 20 V decreases I = 10 A I = 4 A I = 2 A A
  • 29.
  • 30. V = I R 6 = I x 4 6 / 4 = I I = 1.5 A Reading on the ammeter is 1.5 A A 4  resistor is connected in series with an ammeter and a 6 V battery, as shown. What is the reading shown on the ammeter. Example 1 R I _______ V
  • 31. Chapter 14 Pg 249 The resistance R (= V / I) of a metallic conductor is CONSTANT under steady physical conditions Ohm's Law
  • 32. For Ohmic conductors (Conductors that obeys Ohm’s law) e.g. pure metal Chapter 14 Pg 248 For non-Ohmic conductor e.g. filament lamp bulb I /A V/V I /A V/V Metal A Metal B I /A V/V
  • 33.
  • 34.
  • 35.
  • 36.
  • 41.
  • 42. Resistivity Formula: where R = resistance ρ = resistivity l = length A = cross-sectional area
  • 45. Resistors in Series Resistors in Parallel Simulation from Crocodile Physics