cost chapter missing value question with complete solution step by step. for more economics and business studies topics login to www.eakanchha.com

1. OUTPUT AFC AC AVC MC
1 140 50
2 45
3 45
4 22.5 48
5 18 52
•The value given in question are written in red colour. Solution I will write in black colour.
Q.2

2. OUTPUT AFC AC AVC MC TFC TC
1 140 50
2 45
3 45
4 22.5 48
5 18 52
•The value given in question are written in red colour. Solution I will write in black colour.
• Two more columns are required for calculation i.e. TFC and TC.

3. OUTPUT AFC AC AVC MC TFC TC
1 140 50 90
2 45 90
3 45 90
4 22.5 48 90
5 18 52 90
• TFC = AFC × OUTPUT.
= 22.5 × 4
= 90
And TFC remains same at all the level of output.

4. OUTPUT AFC AC AVC MC TFC TC
1 90 ÷ 1
= 90
140 50 90
2 90 ÷ 2
= 45
45 90
3 90 ÷ 3
= 30
45 90
4 22.5 48 90
5 18 52 90
• AFC = TFC ÷ OUTPUT.
•THE VALUES I HAVE USED HERE IN CALCULATION ARE IN GREEN COLOUR.

5. OUTPUT AFC AC AVC MC TFC TC
1 90 ÷ 1
= 90
140 50 90
2 90 ÷ 2
= 45
45+45
=90
45 90
3 90 ÷ 3
= 30
45 90
4 22.5 22.5+48
=70.5
48 90
5 18 18+52
=70
52 90
• AC=AFC+AVC.

6. OUTPUT AFC AC AVC MC TFC TC
1 90 ÷ 1
= 90
140 140 – 90
= 50
50 90
2 90 ÷ 2
= 45
45+45
=90
45 90
3 90 ÷ 3
= 30
45 90
4 22.5 22.5+48
=70.5
48 90
5 18 18+52
=70
52 90
• AVC=AC – AFC .

7. OUTPUT AFC AC AVC MC TFC TC
1 90 ÷ 1
= 90
140 140 – 90
= 50
50 90 140 × 1
= 140
2 90 ÷ 2
= 45
45+45
=90
45 90 90 × 2
= 180
3 90 ÷ 3
= 30
45 90
4 22.5 22.5+48
=70.5
48 90 70.5 × 4
= 282
5 18 18+52
=70
52 90 70 × 5
= 350
• TC= AC × OUTPUT .
• Now using TC we will find MC in the next slide.

8. OUTPUT AFC AC AVC MC TFC TC
1 90 ÷ 1
= 90
140 140 – 90
= 50
50 90 140 × 1
= 140
2 90 ÷ 2
= 45
45+45
=90
45 180 – 140
= 40
90 90 × 2
= 180
3 90 ÷ 3
= 30
45 90
4 22.5 22.5+48
=70.5
48 90 70.5 × 4
= 282
5 18 18+52
=70
52 90 70 × 5
= 350
• MC n = TC n – TC n-1.

9. OUTPUT AFC AC AVC MC TFC TC
1 90 ÷ 1
= 90
140 140 – 90
= 50
50 90 140 × 1
= 140
2 90 ÷ 2
= 45
45+45
=90
45 180 – 140
= 40
90 90 × 2
= 180
3 90 ÷ 3
= 30
45 90
4 22.5 22.5+48
=70.5
48 90 70.5 × 4
= 282
5 18 18+52
=70
52 90 70 × 5
= 350
• Now find TC value at output = 3. So that we can find corresponding value of AC and AVC.
• ∑MC= TVC.
50+40+45=TVC.
Therefore; TVC= 135.
AND TC= TVC + TFC.
TC= 135 + 90 = 225. (at output = 3)
225

10. OUTPUT AFC AC AVC MC TFC TC
1 90 ÷ 1
= 90
140 140 – 90
= 50
50 90 140 × 1
= 140
2 90 ÷ 2
= 45
45+45
=90
45 180 – 140
= 40
90 90 × 2
= 180
3 90 ÷ 3
= 30
225 ÷ 3
=75
45 90 225
4 22.5 22.5+48
=70.5
48 90 70.5 × 4
= 282
5 18 18+52
=70
52 90 70 × 5
= 350
• AC = TC ÷ OUTPUT.

11. OUTPUT AFC AC AVC MC TFC TC
1 90 ÷ 1
= 90
140 140 – 90
= 50
50 90 140 × 1
= 140
2 90 ÷ 2
= 45
45+45
=90
45 180 – 140
= 40
90 90 × 2
= 180
3 90 ÷ 3
= 30
225 ÷ 3
=75
75 – 30
= 45
45 90 225
4 22.5 22.5+48
=70.5
48 90 70.5 × 4
= 282
5 18 18+52
=70
52 90 70 × 5
= 350
• AVC = AC – AFC.

12. OUTPUT AFC AC AVC MC TFC TC
1 90 ÷ 1
= 90
140 140 – 90
= 50
50 90 140 × 1
= 140
2 90 ÷ 2
= 45
45+45
=90
45 180 – 140
= 40
90 90 × 2
= 180
3 90 ÷ 3
= 30
225 ÷ 3
=75
75 – 30
= 45
45 90 225
4 22.5 22.5+48
=70.5
48 282 – 225
= 57
90 70.5 × 4
= 282
5 18 18+52
=70
52
350 – 282
= 68
90 70 × 5
= 350
• MC n = TC n – TC n-1.