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OUTPUT AC MC
0
1 12
2 10
3 10
4 10.5
5 11
6 17
•The value given in question are written in red colour. Solution I will write in black colour.
Q3.
OUTPUT AC MC TC
0
1 12
2 10
3 10
4 10.5
5 11
6 17
•The value given in question are written in red colour. Solution I will write in black colour.
• One more column is required for calculation i.e. TC.
OUTPUT AC MC TC
0
1 12 12 × 1 = 12
2 10 10 × 2 = 20
3 10
4 10.5 10.5 × 4 = 42
5 11 11 × 5 = 55
6 17
 AC × OUTPUT = TC.
OUTPUT AC MC TC
0 -- 0
1 12 12 – 0 = 12 12 × 1 = 12
2 10 20 – 12 = 8 10 × 2 = 20
3 10
4 10.5 10.5 × 4 = 42
5 11 11 × 5 = 55
6 17
 As, no option is there to find TFC that’s why we are assuming TFC = 0.
i.e. TC = 0 (when output = 0)
 MC n = TC n – TC n-1.
OUTPUT AC MC TC
0 -- 0
1 12 12 – 0 = 12 12 × 1 = 12
2 10 20 – 12 = 8 10 × 2 = 20
3 10
30
4 10.5 10.5 × 4 = 42
5 11 11 × 5 = 55
6 17
 ∑ MC = TVC.
Therefore; TVC = 12 + 8 + 10 = 30
And; TC =TFC+ TVC
TC= 0 + 30 = 30
OUTPUT AC MC TC
0 -- 0
1 12 12 – 0 = 12 12 × 1 = 12
2 10 20 – 12 = 8 10 × 2 = 20
3 10 30
4 10.5 42 – 30 = 12 10.5 × 4 = 42
5 11 55 – 42 = 13 11 × 5 = 55
6 17
 MC n = TC n – TC n-1.
OUTPUT AC MC TC
0 -- 0
1 12 12 – 0 = 12 12 × 1 = 12
2 10 20 – 12 = 8 10 × 2 = 20
3 30 ÷ 3 = 10 10 30
4 10.5 42 – 30 = 12 10.5 × 4 = 42
5 11 55 – 42 = 13 11 × 5 = 55
6 17
 AC = TC ÷ OUTPUT.
OUTPUT AC MC TC
0 -- 0
1 12 12 – 0 = 12 12 × 1 = 12
2 10 20 – 12 = 8 10 × 2 = 20
3 30 ÷ 3 = 10 10 30
4 10.5 42 – 30 = 12 10.5 × 4 = 42
5 11 55 – 42 = 13 11 × 5 = 55
6 17
72
 ∑ MC = TVC.
Therefore; TVC = 12 + 8 + 10 + 12 + 13 + 17 = 72.
And; TC =TFC+ TVC
TC= 0 + 72 = 72.
OUTPUT AC MC TC
0 -- 0
1 12 12 – 0 = 12 12 × 1 = 12
2 10 20 – 12 = 8 10 × 2 = 20
3 30 ÷ 3 = 10 10 30
4 10.5 42 – 30 = 12 10.5 × 4 = 42
5 11 55 – 42 = 13 11 × 5 = 55
6 72 ÷ 6 = 12 17 72
 AC = TC ÷ OUTPUT.

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cost missing value question www.eakanchha.com

  • 1. OUTPUT AC MC 0 1 12 2 10 3 10 4 10.5 5 11 6 17 •The value given in question are written in red colour. Solution I will write in black colour. Q3.
  • 2. OUTPUT AC MC TC 0 1 12 2 10 3 10 4 10.5 5 11 6 17 •The value given in question are written in red colour. Solution I will write in black colour. • One more column is required for calculation i.e. TC.
  • 3. OUTPUT AC MC TC 0 1 12 12 × 1 = 12 2 10 10 × 2 = 20 3 10 4 10.5 10.5 × 4 = 42 5 11 11 × 5 = 55 6 17  AC × OUTPUT = TC.
  • 4. OUTPUT AC MC TC 0 -- 0 1 12 12 – 0 = 12 12 × 1 = 12 2 10 20 – 12 = 8 10 × 2 = 20 3 10 4 10.5 10.5 × 4 = 42 5 11 11 × 5 = 55 6 17  As, no option is there to find TFC that’s why we are assuming TFC = 0. i.e. TC = 0 (when output = 0)  MC n = TC n – TC n-1.
  • 5. OUTPUT AC MC TC 0 -- 0 1 12 12 – 0 = 12 12 × 1 = 12 2 10 20 – 12 = 8 10 × 2 = 20 3 10 30 4 10.5 10.5 × 4 = 42 5 11 11 × 5 = 55 6 17  ∑ MC = TVC. Therefore; TVC = 12 + 8 + 10 = 30 And; TC =TFC+ TVC TC= 0 + 30 = 30
  • 6. OUTPUT AC MC TC 0 -- 0 1 12 12 – 0 = 12 12 × 1 = 12 2 10 20 – 12 = 8 10 × 2 = 20 3 10 30 4 10.5 42 – 30 = 12 10.5 × 4 = 42 5 11 55 – 42 = 13 11 × 5 = 55 6 17  MC n = TC n – TC n-1.
  • 7. OUTPUT AC MC TC 0 -- 0 1 12 12 – 0 = 12 12 × 1 = 12 2 10 20 – 12 = 8 10 × 2 = 20 3 30 ÷ 3 = 10 10 30 4 10.5 42 – 30 = 12 10.5 × 4 = 42 5 11 55 – 42 = 13 11 × 5 = 55 6 17  AC = TC ÷ OUTPUT.
  • 8. OUTPUT AC MC TC 0 -- 0 1 12 12 – 0 = 12 12 × 1 = 12 2 10 20 – 12 = 8 10 × 2 = 20 3 30 ÷ 3 = 10 10 30 4 10.5 42 – 30 = 12 10.5 × 4 = 42 5 11 55 – 42 = 13 11 × 5 = 55 6 17 72  ∑ MC = TVC. Therefore; TVC = 12 + 8 + 10 + 12 + 13 + 17 = 72. And; TC =TFC+ TVC TC= 0 + 72 = 72.
  • 9. OUTPUT AC MC TC 0 -- 0 1 12 12 – 0 = 12 12 × 1 = 12 2 10 20 – 12 = 8 10 × 2 = 20 3 30 ÷ 3 = 10 10 30 4 10.5 42 – 30 = 12 10.5 × 4 = 42 5 11 55 – 42 = 13 11 × 5 = 55 6 72 ÷ 6 = 12 17 72  AC = TC ÷ OUTPUT.