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COLLIGATIVE PROPERTIES OF 
SOLUTION 
MOLALITY AND MOLE FRACTION
Why??? 
Although involving colligative 
properties of the solution, colligative 
properties do not depend on the 
interaction between solvent and 
solute molecules, but in 
dependence on the amount of 
solute dissolved in a solution.
MOLALITY 
Molality is the number of moles of 
solute in 1 kg (1000 grams) of solvent .
Example 
Determine the molarity of solution that 
produce 3 grams urea in 200 grams 
water???? 
Answer : 
Mole of urea= 3 g/60 g mole -1 
Mass of solvent= 200 g =0.2 kg 
m= n/p 
=0.05/0.2 
=o.25 mol kg-1
example 
A total of 1.8 g of glucose, C6H12O6 
dissolved in 100 grams of water (Ar C = 12, H 
= 1, O = 16). Determine the molality of the 
glucose solution!
Mole fraction 
Mole fraction (X) is ratio of the number of moles 
of solute or solvent to the number of moles of 
solution.
example 
In 100 grams of 20% urea solution 
contained 20 grams of urea and 80 
grams of water. Determine the moles of 
urea fraction 
Answer: 
Mole of water= 80 g/18 g mole-1 
= 4.44 mole 
Mole of urea = 20 g/60 g mole-1 
= 0.33 
Xurea = XB= 0.33/4.44+0.33= 0.069
example 
A total of 27.6 grams of ethanol 
C2H5OH dissolved in 54 grams of 
water (Ar C = 12, H = 1, O = 16). 
Calculate the mole fraction mole 
fraction of ethanol and water!
answer 
Mr.C2H5OH = 46 gr/mol 
Mr.H2O = 18 gr/mol 
n.C2H5OH = 27,6 gr/(46 gr/mol) 
n.H2O = 54 gr/(18 gr/mol) 
χ etanol = 0,6 mol/(0,6 mol + 3 mol)=0,167 
χ Air = 3 mol/(0,6 mol + 3 mol) = 0,833
exercise 
1. Determine the amount (grams) of 
NaOH must be dissolved in 1 liter of 
water (water = 1.00 g / mL) to obtain 
0.25 m NaOH. 
2. In 100 grams of 20% urea solution 
contained 20 grams of urea and 80 
grams of water. Determine the moles of 
urea fraction.
Cont. 
3. Determine the mole fraction of 
solute (Mr=60) in urea solution 10 
% 
4. Determine the percentage of urea 
in urea solution 1 m 
5.Determine the mole fraction of 2 
molal of urea solution
Remember !!!!!!!!!!!! 
Collect your assignment next week 
:D

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Colligative properties, sifat koligatif

  • 1. COLLIGATIVE PROPERTIES OF SOLUTION MOLALITY AND MOLE FRACTION
  • 2. Why??? Although involving colligative properties of the solution, colligative properties do not depend on the interaction between solvent and solute molecules, but in dependence on the amount of solute dissolved in a solution.
  • 3. MOLALITY Molality is the number of moles of solute in 1 kg (1000 grams) of solvent .
  • 4. Example Determine the molarity of solution that produce 3 grams urea in 200 grams water???? Answer : Mole of urea= 3 g/60 g mole -1 Mass of solvent= 200 g =0.2 kg m= n/p =0.05/0.2 =o.25 mol kg-1
  • 5. example A total of 1.8 g of glucose, C6H12O6 dissolved in 100 grams of water (Ar C = 12, H = 1, O = 16). Determine the molality of the glucose solution!
  • 6. Mole fraction Mole fraction (X) is ratio of the number of moles of solute or solvent to the number of moles of solution.
  • 7. example In 100 grams of 20% urea solution contained 20 grams of urea and 80 grams of water. Determine the moles of urea fraction Answer: Mole of water= 80 g/18 g mole-1 = 4.44 mole Mole of urea = 20 g/60 g mole-1 = 0.33 Xurea = XB= 0.33/4.44+0.33= 0.069
  • 8. example A total of 27.6 grams of ethanol C2H5OH dissolved in 54 grams of water (Ar C = 12, H = 1, O = 16). Calculate the mole fraction mole fraction of ethanol and water!
  • 9. answer Mr.C2H5OH = 46 gr/mol Mr.H2O = 18 gr/mol n.C2H5OH = 27,6 gr/(46 gr/mol) n.H2O = 54 gr/(18 gr/mol) χ etanol = 0,6 mol/(0,6 mol + 3 mol)=0,167 χ Air = 3 mol/(0,6 mol + 3 mol) = 0,833
  • 10. exercise 1. Determine the amount (grams) of NaOH must be dissolved in 1 liter of water (water = 1.00 g / mL) to obtain 0.25 m NaOH. 2. In 100 grams of 20% urea solution contained 20 grams of urea and 80 grams of water. Determine the moles of urea fraction.
  • 11. Cont. 3. Determine the mole fraction of solute (Mr=60) in urea solution 10 % 4. Determine the percentage of urea in urea solution 1 m 5.Determine the mole fraction of 2 molal of urea solution
  • 12. Remember !!!!!!!!!!!! Collect your assignment next week :D