A 0.12 M solution of CuCl can be prepared by diluting a 0.29 M CuCl solution. The key steps are: 1) The original solution is 10 mL of 0.29 M CuCl. This contains 0.29 moles/L x 0.01 L = 0.0029 moles of CuCl. 2) The final solution volume is not specified, but the moles of CuCl must remain 0.0029 moles. 3) Using the dilution equation, the final volume can be calculated as 0.0029 moles / 0.12 M = 0.024 L or 24 mL. 4) Add water to the original 10 mL solution to

34. But how much water do we add?