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CHAPTER 5

THE RESPONSE TIME
     ANALYSIS
5.1 FIRST AND SECOND ORDER
              SYSTEM
INTRODUCTION
• The concept of poles and zeros, fundamental to the
  analysis of and design of control system, simplifies the
  evaluation of system response.
• The poles of a transfer function are:
  i.    Values of the Laplace Transform variables s, that cause
        the transfer function to become infinite.
  ii.   Any roots of the denominator of the transfer function
        that are common to roots of the numerator.
• The zeros of a transfer function are:
  i.    The values of the Laplace Transform variable s, that
        cause the transfer function to become zero.
  ii.   Any roots of the numerator of the transfer function that
        are common to roots of the denominator.
• The concept of poles and zeros, fundamental to the analysis
  of and design of control system, simplifies the evaluation of
  system response.
• The poles of a transfer function are:
   i.    Values of the Laplace Transform variables s, that cause the
         transfer function to become infinite.
   ii.   Any roots of the denominator of the transfer function that are
         common to roots of the numerator.
• The zeros of a transfer function are:
   i.    The values of the Laplace Transform variable s, that cause
         the transfer function to become zero.
   ii.   Any roots of the numerator of the transfer function that are
         common to roots of the denominator.
• The output response of a system is a sum of
  i.    Forced response
  ii.   Natural response




            a) System showing an input and an output
            b) Pole-zero plot of the system
c) Evolution of a system response. Follow the blue
   arrows to see the evolution of system
   component generated by the pole or zero
Effect of a real-axis pole upon transient response




           a) First-order system
           b) Pole plot of the system
• General form:
                                 C (s)    K
                       G (s) =         =
                                 R( s ) τs + 1

• Problem: Derive the transfer function for the following circuit


                                                   1
                                       G (s) =
                                                 RCs + 1
• Transient Response: Gradual change of output from initial to
  the desired condition.
• Block diagram representation:

                       K                   Where,
            R(s)                    C(s)      K : Gain
                     τs + 1                   τ : Time constant

• By definition itself, the input to the system should be a step
  function which is given by the following:

                                      1
                              R( s) =
                                      s
• General form:
                 C (s)    K
         G (s) =       =                      C ( s) = G ( s) R( s)
                 R( s ) τs + 1

• Output response:
                                   1  K 
                        C ( s ) =            
                                   s  τs + 1 
                                  A       B
                                = +
                                  s τs + 1
                                     B −t τ
                          c(t ) = A + e
                                     τ
• Problem: Find the forced and natural responses for the
  following systems
First-order system response to a unit step
• Time constant, τ
   – The time for e-at to decay 37% of its       1
                                              τ=
     initial value.                              a

• Rise time, tr
   – The time for the waveform to go               2. 2
                                              tr =
     from 0.1 to 0.9 of its final value.            a

• Settling time, ts
   – The time for the response to reach,           4
                                              ts =
     and stay within 2% of its final value.        a
• Problem: For a system with the transfer function shown
  below, find the relevant response specifications

                                     50
                            G(s) =
                                   s + 50

  i.    Time constant, τ
  ii.   Settling time, ts
  iii. Rise time, tr
• General form:
                                Kω n
                                   2
                   G( s ) = 2
                           s + 2ςωn s + ωn
                                         2



             Where,
                K : Gain
                ς : Damping ratio
                ωn : Undamped natural frequency
• Roots of denominator:

                     s 2 + 2ςωn s + ωn = 0
                                     2



                   s1, 2 = −ςωn ± ωn ς 2 − 1
• Natural frequency, ωn
   – Frequency of oscillation of the system without damping.

• Damping ratio, ς
   – Quantity that compares the exponential decay frequency of
     the envelope to the natural frequency.

                  Exponential decay frequency
               ς=
                   Natural frequency (rad/s)
• Problem: Find the step response for the following transfer
  function
                                  225
                     G( s ) = 2
                             s + 30 s + 225
• Answer:

                     c( t ) = 1 − e −15t − 15te −15t
• Problem: For each of the transfer function, find the values of
  ς and ωn, as well as characterize the nature of the response.

                       400
   a) G ( s ) =
                s 2 + 12s + 400

   b) G ( s ) = 2 900
               s + 90 s + 900
   c) G ( s ) =          225
                  s 2 + 30 s + 225
   d)              625
        G( s ) = 2
                s + 625
• Step responses for second-order system damping cases
• Pole plot for the underdamped second-order system
• Second-order response as a function of damping ratio
• Second-order response as a function of damping ratio
• When 0 < ς < 1, the transfer function is given by the
  following.
                           Kω n  2              Where,
    G( s ) =                                       ωd = ωn 1 − ς 2
             ( s + ςωn + jωd )( s + ςωn − jωd )

• Pole position:
• Second-order response components generated by complex
  poles
• Second-order underdamped responses for damping ratio
  value
• Second-order underdamped response specifications
• Rise time, Tr
   – The time for the waveform to go         from 0.1 to 0.9 of its
     final value.


• Peak time, Tp                                             π
                                              Tp =              2
   – The time required to reach the first            ωn 1 − ζ
     or maximum peak.


• Settling time, Ts
                                                      4
   – The time required for the transient’s    Ts =
                                                     ζω n
     damped oscillation to reach and stay
     within ±2% of the steady-state value.
• Percent overshoot, %OS
  – The amount that the waveform overshoots the steady-state, or
    final value at peak time, expressed as a percentage of the
    steady-state value.

                             − (ζπ / 1−ζ 2 )
                   %OS = e                     × 100%

                          − ln(%OS / 100)
                   ζ =
                         π 2 + ln 2 (%OS / 100)
• Percent overshoot versus damping ratio
• Lines of constant peak time Tp, settling time Ts and percent
  overshoot %OS



                                                Ts2 < Ts1
                                                Tp2 < Tp1
                                              %OS1 < %OS2
• Step responses of second-order underdamped systems as
  poles move




                                       a) With constant
                                          real part
                                       b) With constant
                                          imaginary part
• Step responses of second-order underdamped systems as
  poles move




               c) With constant damping ratio

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Chapter 5

  • 1. CHAPTER 5 THE RESPONSE TIME ANALYSIS
  • 2. 5.1 FIRST AND SECOND ORDER SYSTEM INTRODUCTION
  • 3. • The concept of poles and zeros, fundamental to the analysis of and design of control system, simplifies the evaluation of system response. • The poles of a transfer function are: i. Values of the Laplace Transform variables s, that cause the transfer function to become infinite. ii. Any roots of the denominator of the transfer function that are common to roots of the numerator. • The zeros of a transfer function are: i. The values of the Laplace Transform variable s, that cause the transfer function to become zero. ii. Any roots of the numerator of the transfer function that are common to roots of the denominator.
  • 4. • The concept of poles and zeros, fundamental to the analysis of and design of control system, simplifies the evaluation of system response. • The poles of a transfer function are: i. Values of the Laplace Transform variables s, that cause the transfer function to become infinite. ii. Any roots of the denominator of the transfer function that are common to roots of the numerator. • The zeros of a transfer function are: i. The values of the Laplace Transform variable s, that cause the transfer function to become zero. ii. Any roots of the numerator of the transfer function that are common to roots of the denominator.
  • 5. • The output response of a system is a sum of i. Forced response ii. Natural response a) System showing an input and an output b) Pole-zero plot of the system
  • 6. c) Evolution of a system response. Follow the blue arrows to see the evolution of system component generated by the pole or zero
  • 7. Effect of a real-axis pole upon transient response a) First-order system b) Pole plot of the system
  • 8. • General form: C (s) K G (s) = = R( s ) τs + 1 • Problem: Derive the transfer function for the following circuit 1 G (s) = RCs + 1
  • 9. • Transient Response: Gradual change of output from initial to the desired condition. • Block diagram representation: K Where, R(s) C(s) K : Gain τs + 1 τ : Time constant • By definition itself, the input to the system should be a step function which is given by the following: 1 R( s) = s
  • 10. • General form: C (s) K G (s) = = C ( s) = G ( s) R( s) R( s ) τs + 1 • Output response:  1  K  C ( s ) =     s  τs + 1  A B = + s τs + 1 B −t τ c(t ) = A + e τ
  • 11. • Problem: Find the forced and natural responses for the following systems
  • 12. First-order system response to a unit step
  • 13. • Time constant, τ – The time for e-at to decay 37% of its 1 τ= initial value. a • Rise time, tr – The time for the waveform to go 2. 2 tr = from 0.1 to 0.9 of its final value. a • Settling time, ts – The time for the response to reach, 4 ts = and stay within 2% of its final value. a
  • 14. • Problem: For a system with the transfer function shown below, find the relevant response specifications 50 G(s) = s + 50 i. Time constant, τ ii. Settling time, ts iii. Rise time, tr
  • 15. • General form: Kω n 2 G( s ) = 2 s + 2ςωn s + ωn 2 Where, K : Gain ς : Damping ratio ωn : Undamped natural frequency • Roots of denominator: s 2 + 2ςωn s + ωn = 0 2 s1, 2 = −ςωn ± ωn ς 2 − 1
  • 16. • Natural frequency, ωn – Frequency of oscillation of the system without damping. • Damping ratio, ς – Quantity that compares the exponential decay frequency of the envelope to the natural frequency. Exponential decay frequency ς= Natural frequency (rad/s)
  • 17. • Problem: Find the step response for the following transfer function 225 G( s ) = 2 s + 30 s + 225 • Answer: c( t ) = 1 − e −15t − 15te −15t
  • 18. • Problem: For each of the transfer function, find the values of ς and ωn, as well as characterize the nature of the response. 400 a) G ( s ) = s 2 + 12s + 400 b) G ( s ) = 2 900 s + 90 s + 900 c) G ( s ) = 225 s 2 + 30 s + 225 d) 625 G( s ) = 2 s + 625
  • 19.
  • 20.
  • 21. • Step responses for second-order system damping cases
  • 22. • Pole plot for the underdamped second-order system
  • 23. • Second-order response as a function of damping ratio
  • 24. • Second-order response as a function of damping ratio
  • 25. • When 0 < ς < 1, the transfer function is given by the following. Kω n 2 Where, G( s ) = ωd = ωn 1 − ς 2 ( s + ςωn + jωd )( s + ςωn − jωd ) • Pole position:
  • 26. • Second-order response components generated by complex poles
  • 27. • Second-order underdamped responses for damping ratio value
  • 28. • Second-order underdamped response specifications
  • 29. • Rise time, Tr – The time for the waveform to go from 0.1 to 0.9 of its final value. • Peak time, Tp π Tp = 2 – The time required to reach the first ωn 1 − ζ or maximum peak. • Settling time, Ts 4 – The time required for the transient’s Ts = ζω n damped oscillation to reach and stay within ±2% of the steady-state value.
  • 30. • Percent overshoot, %OS – The amount that the waveform overshoots the steady-state, or final value at peak time, expressed as a percentage of the steady-state value. − (ζπ / 1−ζ 2 ) %OS = e × 100% − ln(%OS / 100) ζ = π 2 + ln 2 (%OS / 100)
  • 31. • Percent overshoot versus damping ratio
  • 32. • Lines of constant peak time Tp, settling time Ts and percent overshoot %OS Ts2 < Ts1 Tp2 < Tp1 %OS1 < %OS2
  • 33. • Step responses of second-order underdamped systems as poles move a) With constant real part b) With constant imaginary part
  • 34. • Step responses of second-order underdamped systems as poles move c) With constant damping ratio