Standard Form and Point Slope Form
Standard Form This linear equation is in standard form. 2x – 3y = 7 This linear equation is in y-intercept form. y= 3 / 2 x + 8
Write in Standard Form Start with your equation. Move the x value to the same side as the y value by adding or subtracting the same x values from both sides. +3x +3x
Try One Start with your equation. Move the x value to the same side as the y value by adding or subtracting the same x values from both sides. -2x -2x
Point Slope Form Find an equation with one set of coordinates and the slope.
What’s the Deal? We will now find the y-intercept using  Point-Slope  form. When complete, our equation will be in  y = mx + b  form.
If y = mx + b,  and  then y – y 1 =m(x-x 1 ) this is done algebraically by multiplying both sides by (x 2 -x 1 )
Related formula
y -y 1   =  m(x -x 1 )
y -y 1   =  m(x -x 1 ) We use point slope form (above) when we are given the  slope  and one  point . Such as (-7, 2) with a slope of 3.
(-7, 2) with a slope of 3 Start with  y -y 1   =  m(x -x 1 ) Fill in the slope  y -y 1   =  3(x -x 1 ) Fill in the y value  y - 2  =  3(x -x 1 ) Fill in the x value  y - 2  =  3(x - - 7)
Now use what you know about order of operations and balancing like terms. y - 2  =  3(x - - 7) Change the signs (if needed) . y - 2  =  3(x + + 7) Use the distributive property. y - 2  = 3x + 21
Add two to both sides. Then solve for y. y – 2  +2   = 3x + 21 +2 y  + 0   = 3x  + 23 y  = 3x  + 23
(4, 1) with a slope of ½  Start with  y -y 1   =  m(x -x 1 ) Fill in the slope  y -y 1   =  ½ (x -x 1 ) Fill in the y value  y - 1  = ½ (x -x 1 ) Fill in the x value  y - 1  = ½ (x - 4)
Distributive Property Then add one to both sides to balance the sides. y - 1  = ½ (x - 4) y - 1  = ½ x – 2 +1   +1 y  = ½ x – 1 The slope is ½ and the y-intercept is -1. The equation is ready to graph.
y  = ½ x – 1
Assign: 256 : 29-31 Assign 257: 39 and 40 For numbers 39 and 40 you use yesterday’s information to 1) find the slope, then use the  point-slope  form ( today’s work ) to find the equation.
Copyright D Dahlberg

5 5pt Slope

  • 1.
    Standard Form andPoint Slope Form
  • 2.
    Standard Form Thislinear equation is in standard form. 2x – 3y = 7 This linear equation is in y-intercept form. y= 3 / 2 x + 8
  • 3.
    Write in StandardForm Start with your equation. Move the x value to the same side as the y value by adding or subtracting the same x values from both sides. +3x +3x
  • 4.
    Try One Startwith your equation. Move the x value to the same side as the y value by adding or subtracting the same x values from both sides. -2x -2x
  • 5.
    Point Slope FormFind an equation with one set of coordinates and the slope.
  • 6.
    What’s the Deal?We will now find the y-intercept using Point-Slope form. When complete, our equation will be in y = mx + b form.
  • 7.
    If y =mx + b, and then y – y 1 =m(x-x 1 ) this is done algebraically by multiplying both sides by (x 2 -x 1 )
  • 8.
  • 9.
    y -y 1 = m(x -x 1 )
  • 10.
    y -y 1 = m(x -x 1 ) We use point slope form (above) when we are given the slope and one point . Such as (-7, 2) with a slope of 3.
  • 11.
    (-7, 2) witha slope of 3 Start with y -y 1 = m(x -x 1 ) Fill in the slope y -y 1 = 3(x -x 1 ) Fill in the y value y - 2 = 3(x -x 1 ) Fill in the x value y - 2 = 3(x - - 7)
  • 12.
    Now use whatyou know about order of operations and balancing like terms. y - 2 = 3(x - - 7) Change the signs (if needed) . y - 2 = 3(x + + 7) Use the distributive property. y - 2 = 3x + 21
  • 13.
    Add two toboth sides. Then solve for y. y – 2 +2 = 3x + 21 +2 y + 0 = 3x + 23 y = 3x + 23
  • 14.
    (4, 1) witha slope of ½ Start with y -y 1 = m(x -x 1 ) Fill in the slope y -y 1 = ½ (x -x 1 ) Fill in the y value y - 1 = ½ (x -x 1 ) Fill in the x value y - 1 = ½ (x - 4)
  • 15.
    Distributive Property Thenadd one to both sides to balance the sides. y - 1 = ½ (x - 4) y - 1 = ½ x – 2 +1 +1 y = ½ x – 1 The slope is ½ and the y-intercept is -1. The equation is ready to graph.
  • 16.
    y =½ x – 1
  • 17.
    Assign: 256 :29-31 Assign 257: 39 and 40 For numbers 39 and 40 you use yesterday’s information to 1) find the slope, then use the point-slope form ( today’s work ) to find the equation.
  • 18.