3.8.2 Ratio & Proportion
The student is able to (I can):
• Write and simplify ratios
• Use proportions to solve problems• Use proportions to solve problems
• Identify similar polygons
ratio A comparison of two numbers by division.
The ratioratioratioratio of two numbers a and b, where b
does not equal 0 (b ≠ 0) can be written as
a to b
a : b
a
b
Example: The ratio comparing 1 and 2 can
be written 1 to 2, 1 : 2, or .
Note: To compare more than two numbers,
use “dot” notation. Ex. 3 : 7 : 9
b
1
2
proportion An equation stating that two ratios are
equal. Two sets of numbers are
proportionalproportionalproportionalproportional if they use the same ratio.
Example: or a : b = c : d
Cross Products Property
a c
b d
=
Cross Products Property
In a proportion, if , and b and d ≠ 0,
then
ad = bc
a c
b d
=
Solving Problems with Ratios
If a problem contains a ratio of numbers,
set up a proportion and cross-multiply.
Example: The student-faculty ratio at a
college is 15: 1. If there are 500 faculty,
how many students are there?
=:
student 15s x
x = (15)(500)
= 7500 students
=
facul
:
student
ty
15
1
s x
500
If a problem contains a ratio comparing
more than two numbers, let x be the
common factor and set up an equation to
solve for x. Once we know x, we can find the
original quantities.
Example The ratio of the side lengths of a triangle is
2 : 3 : 5, and its perimeter is 80 ft. What
are the lengths of each side?
Let the side lengths be 2x, 3x, and 5x.
2x + 3x + 5x = 80
10x = 80
x = 8x = 8
This means that the sides measure
2(8) = 16 ft.
3(8) = 24 ft.
5(8) = 40 ft.
Examples Solve each proportion:
1.
8x = 96 x = 12
2.
2x = 20 x = 10
3 x
8 32
=
4 2
x 5
=
2x = 20 x = 10
3.
3x = 6(x — 2)
3x = 6x — 12
—3x = —12 x = 4
x x 2
6 3
−
=
Examples 4. The ratio of the angles of a triangle is
2: 2: 5. What is the measure of each
angle?
2x + 2x + 5x = 180˚
9x = 180˚
x = 20
2(20) = 40˚
2(20) = 40˚
5(20) = 100˚
Examples 5. A 60 meter steel pole is cut into two
parts in the ratio of 11 to 4. How much
longer is the longer part than the
shorter?
11x + 4x = 60
15x = 60
x = 4x = 4
11(4) = 44 m
4(4) = 16 m
The longer part is 28 m longer than
the shorter part. (44 — 16)
similar
polygons
Two polygons are similar if and only if their
corresponding angles are congruent and
their corresponding side lengths are
proportional.
Example:
N O
X M
6
54
12
8
∠N ≅ ∠X
∠L ≅ ∠S
∠E ≅ ∠A
∠O ≅ ∠M
EL
AS
5
3
4
10
6
8
3 4 5 6
6 8 10 12
= = =
NOEL ~ XMAS
Note: A similarity statementsimilarity statementsimilarity statementsimilarity statement describes
two similar polygons by listing their
corresponding vertices.
Example: NOEL ~ XMAS
Note: To check whether two ratios are
equal, cross-multiply them–theequal, cross-multiply them–the
products should be equal.
Example: Is ?=
3 4
6 8
=24 24
Example Determine whether the rectangles are
similar. If so, write the similarity ratio and
a similarity statement.
Q U
AD
R E
15
6
25
10
All of the angles are right angles, so all the
angles are congruent.
QUAD ~ RECT
sim. ratio:
150 = 150
CT
10
6 15
?
10 25
= 3
5

3.8.2 Ratio and Proportion

  • 1.
    3.8.2 Ratio &Proportion The student is able to (I can): • Write and simplify ratios • Use proportions to solve problems• Use proportions to solve problems • Identify similar polygons
  • 2.
    ratio A comparisonof two numbers by division. The ratioratioratioratio of two numbers a and b, where b does not equal 0 (b ≠ 0) can be written as a to b a : b a b Example: The ratio comparing 1 and 2 can be written 1 to 2, 1 : 2, or . Note: To compare more than two numbers, use “dot” notation. Ex. 3 : 7 : 9 b 1 2
  • 3.
    proportion An equationstating that two ratios are equal. Two sets of numbers are proportionalproportionalproportionalproportional if they use the same ratio. Example: or a : b = c : d Cross Products Property a c b d = Cross Products Property In a proportion, if , and b and d ≠ 0, then ad = bc a c b d =
  • 4.
    Solving Problems withRatios If a problem contains a ratio of numbers, set up a proportion and cross-multiply. Example: The student-faculty ratio at a college is 15: 1. If there are 500 faculty, how many students are there? =: student 15s x x = (15)(500) = 7500 students = facul : student ty 15 1 s x 500
  • 5.
    If a problemcontains a ratio comparing more than two numbers, let x be the common factor and set up an equation to solve for x. Once we know x, we can find the original quantities.
  • 6.
    Example The ratioof the side lengths of a triangle is 2 : 3 : 5, and its perimeter is 80 ft. What are the lengths of each side? Let the side lengths be 2x, 3x, and 5x. 2x + 3x + 5x = 80 10x = 80 x = 8x = 8 This means that the sides measure 2(8) = 16 ft. 3(8) = 24 ft. 5(8) = 40 ft.
  • 7.
    Examples Solve eachproportion: 1. 8x = 96 x = 12 2. 2x = 20 x = 10 3 x 8 32 = 4 2 x 5 = 2x = 20 x = 10 3. 3x = 6(x — 2) 3x = 6x — 12 —3x = —12 x = 4 x x 2 6 3 − =
  • 8.
    Examples 4. Theratio of the angles of a triangle is 2: 2: 5. What is the measure of each angle? 2x + 2x + 5x = 180˚ 9x = 180˚ x = 20 2(20) = 40˚ 2(20) = 40˚ 5(20) = 100˚
  • 9.
    Examples 5. A60 meter steel pole is cut into two parts in the ratio of 11 to 4. How much longer is the longer part than the shorter? 11x + 4x = 60 15x = 60 x = 4x = 4 11(4) = 44 m 4(4) = 16 m The longer part is 28 m longer than the shorter part. (44 — 16)
  • 10.
    similar polygons Two polygons aresimilar if and only if their corresponding angles are congruent and their corresponding side lengths are proportional. Example: N O X M 6 54 12 8 ∠N ≅ ∠X ∠L ≅ ∠S ∠E ≅ ∠A ∠O ≅ ∠M EL AS 5 3 4 10 6 8 3 4 5 6 6 8 10 12 = = = NOEL ~ XMAS
  • 11.
    Note: A similaritystatementsimilarity statementsimilarity statementsimilarity statement describes two similar polygons by listing their corresponding vertices. Example: NOEL ~ XMAS Note: To check whether two ratios are equal, cross-multiply them–theequal, cross-multiply them–the products should be equal. Example: Is ?= 3 4 6 8 =24 24
  • 12.
    Example Determine whetherthe rectangles are similar. If so, write the similarity ratio and a similarity statement. Q U AD R E 15 6 25 10 All of the angles are right angles, so all the angles are congruent. QUAD ~ RECT sim. ratio: 150 = 150 CT 10 6 15 ? 10 25 = 3 5