T7.2 Right Triangle Trigonometry
Chapter 7 The Unit Circle: Sine and Cosine
Functions
Concepts and Objectives
⚫ The objectives for this section are
⚫ Use right triangles to evaluate trigonometric
functions
⚫ Use equal cofunctions of complementary angles
⚫ Use the definitions of trigonometric functions for any
angle
⚫ Use right-triangle trigonometry to solve applied
problems
Trigonometric Ratio Review
⚫ In Geometry, we learned that for any given right triangle,
there are special ratios between the sides.
A
opposite
adjacent
=
opposite
sin
hypotenuse
A
=
adjacent
cos
hypotenuse
A
=
opposite
tan
adjacent
A
Trigonometric Functions
⚫ Consider a circle centered at the origin with radius r:
⚫ The equation for this circle is x2 + y2 = r2
⚫ A point (x, y) on the circle creates a right triangle whose
sides are x, y, and r.
⚫ The trig ratios are now (x, y)
r
x
y

=
sin
y
r

=
cos
x
r

=
tan
y
x

Trigonometric Functions
⚫ There are three other ratios in addition to the three we
already know : cosecant, secant, and cotangent.
⚫ These ratios are the inverses of the original three:
(x, y)
r
x
y

= =
1
csc
sin
r
y


= =
1
sec
cos
r
x


= =
1
cot
tan
x
y


Finding Function Values
⚫ Example: The terminal side of an angle  in standard
position passes through the point (15, 8). Find the
values of the six trigonometric functions of angle .
(15, 8)

Finding Function Values
⚫ Example: The terminal side of an angle  in standard
position passes through the point (15, 8). Find the
values of the six trigonometric functions of angle .
8
15
(15, 8)

We know that x = 15 and y = 8, but
we still have to calculate r:
Now, we can calculate the values.
= +
2 2
r x y
= + =
2 2
15 8 17 17
Finding Function Values
⚫ Example: The terminal side of an angle  in standard
position passes through the point (15, 8). Find the
values of the six trigonometric functions of angle .
8
15
(15, 8)

17
= =
8
sin
17
y
r

= =
15
cos
17
x
r

= =
8
tan
15
y
x

= =
17
csc
8
r
y

= =
17
sec
15
r
x

= =
15
cot
8
x
y

The Unit Circle
⚫ Angles in standard position whose terminal sides lie on
the x-axis or y-axis (90°, 180°, 270°, etc.) are called
quadrantal angles.
⚫ To find function values of quandrantal angles easily, we
⚫ Notice that at the quadrantal
angle points x and y are either
0, 1, or –1 (r is always 1).
use a circle with a radius of 1, which
is called a unit circle.
90
(0, 1)
(0, –1)
270
180
(–1, 0)
0/360
(1, 0)
Values of Quadrantal Angles
⚫ Example: Find the values of the six trigonometric
functions for an angle of 270°.
Values of Quadrantal Angles
⚫ Example: Find the values of the six trigonometric
functions for an angle of 270°.
At 270°, x = 0, y = –1, r = 1.
−
 = = −
1
sin270 1
1
 = =
0
cos270 0
1
−
 = =
1
tan270 undefined
0
(0, –1)
Values of Quadrantal Angles
⚫ Example: Find the values of the six trigonometric
functions for an angle of 270°.
At 270°, x = 0, y = –1, r = 1.
 = = −
−
1
csc270 1
1
 = =
1
sec270 undefined
0
 = =
−
0
cot270 0
1
(0, –1)
Identifying an Angle’s Quadrant
⚫ To identify the quadrant of an angle given certain
conditions, note the following:
⚫ In the first quadrant, x and y are both positive.
⚫ In QII, x is negative and y is positive.
⚫ In QIII, both are negative.
⚫ In QIV, x is positive and y is
IV
III
II I
(+,+)
(–,+)
(–,–)
negative.
(+,–)
Identifying an Angle’s Quadrant
⚫ Example: Identify the quadrant (or possible quadrants)
of an angle  that satisfies the given conditions.
a) sin  > 0, tan  < 0 b) cos  < 0, sec  < 0
Identifying an Angle’s Quadrant
⚫ Example: Identify the quadrant (or possible quadrants)
of an angle  that satisfies the given conditions.
a) sin  > 0, tan  < 0 b) cos  < 0, sec  < 0
I, II II, IV
II
II, III II, III
II, III
Classwork
⚫ Algebra & Trigonometry 2e
⚫ 7.2: 10-22 (even); 7.1: 40-48 (even)
⚫ College Algebra 2e
⚫ 9.6: 30-38 (even)
⚫ T7.2 Classwork Check
⚫ Quiz T7.1

T7.2 Right Triangle Trigonometry Presentation

  • 1.
    T7.2 Right TriangleTrigonometry Chapter 7 The Unit Circle: Sine and Cosine Functions
  • 2.
    Concepts and Objectives ⚫The objectives for this section are ⚫ Use right triangles to evaluate trigonometric functions ⚫ Use equal cofunctions of complementary angles ⚫ Use the definitions of trigonometric functions for any angle ⚫ Use right-triangle trigonometry to solve applied problems
  • 3.
    Trigonometric Ratio Review ⚫In Geometry, we learned that for any given right triangle, there are special ratios between the sides. A opposite adjacent = opposite sin hypotenuse A = adjacent cos hypotenuse A = opposite tan adjacent A
  • 4.
    Trigonometric Functions ⚫ Considera circle centered at the origin with radius r: ⚫ The equation for this circle is x2 + y2 = r2 ⚫ A point (x, y) on the circle creates a right triangle whose sides are x, y, and r. ⚫ The trig ratios are now (x, y) r x y  = sin y r  = cos x r  = tan y x 
  • 5.
    Trigonometric Functions ⚫ Thereare three other ratios in addition to the three we already know : cosecant, secant, and cotangent. ⚫ These ratios are the inverses of the original three: (x, y) r x y  = = 1 csc sin r y   = = 1 sec cos r x   = = 1 cot tan x y  
  • 6.
    Finding Function Values ⚫Example: The terminal side of an angle  in standard position passes through the point (15, 8). Find the values of the six trigonometric functions of angle . (15, 8) 
  • 7.
    Finding Function Values ⚫Example: The terminal side of an angle  in standard position passes through the point (15, 8). Find the values of the six trigonometric functions of angle . 8 15 (15, 8)  We know that x = 15 and y = 8, but we still have to calculate r: Now, we can calculate the values. = + 2 2 r x y = + = 2 2 15 8 17 17
  • 8.
    Finding Function Values ⚫Example: The terminal side of an angle  in standard position passes through the point (15, 8). Find the values of the six trigonometric functions of angle . 8 15 (15, 8)  17 = = 8 sin 17 y r  = = 15 cos 17 x r  = = 8 tan 15 y x  = = 17 csc 8 r y  = = 17 sec 15 r x  = = 15 cot 8 x y 
  • 9.
    The Unit Circle ⚫Angles in standard position whose terminal sides lie on the x-axis or y-axis (90°, 180°, 270°, etc.) are called quadrantal angles. ⚫ To find function values of quandrantal angles easily, we ⚫ Notice that at the quadrantal angle points x and y are either 0, 1, or –1 (r is always 1). use a circle with a radius of 1, which is called a unit circle. 90 (0, 1) (0, –1) 270 180 (–1, 0) 0/360 (1, 0)
  • 10.
    Values of QuadrantalAngles ⚫ Example: Find the values of the six trigonometric functions for an angle of 270°.
  • 11.
    Values of QuadrantalAngles ⚫ Example: Find the values of the six trigonometric functions for an angle of 270°. At 270°, x = 0, y = –1, r = 1. −  = = − 1 sin270 1 1  = = 0 cos270 0 1 −  = = 1 tan270 undefined 0 (0, –1)
  • 12.
    Values of QuadrantalAngles ⚫ Example: Find the values of the six trigonometric functions for an angle of 270°. At 270°, x = 0, y = –1, r = 1.  = = − − 1 csc270 1 1  = = 1 sec270 undefined 0  = = − 0 cot270 0 1 (0, –1)
  • 13.
    Identifying an Angle’sQuadrant ⚫ To identify the quadrant of an angle given certain conditions, note the following: ⚫ In the first quadrant, x and y are both positive. ⚫ In QII, x is negative and y is positive. ⚫ In QIII, both are negative. ⚫ In QIV, x is positive and y is IV III II I (+,+) (–,+) (–,–) negative. (+,–)
  • 14.
    Identifying an Angle’sQuadrant ⚫ Example: Identify the quadrant (or possible quadrants) of an angle  that satisfies the given conditions. a) sin  > 0, tan  < 0 b) cos  < 0, sec  < 0
  • 15.
    Identifying an Angle’sQuadrant ⚫ Example: Identify the quadrant (or possible quadrants) of an angle  that satisfies the given conditions. a) sin  > 0, tan  < 0 b) cos  < 0, sec  < 0 I, II II, IV II II, III II, III II, III
  • 16.
    Classwork ⚫ Algebra &Trigonometry 2e ⚫ 7.2: 10-22 (even); 7.1: 40-48 (even) ⚫ College Algebra 2e ⚫ 9.6: 30-38 (even) ⚫ T7.2 Classwork Check ⚫ Quiz T7.1