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Circle Geometry
Circle Geometry
Circle Geometry Definitions
Circle Geometry
Circle Geometry Definitions
Circle Geometry
Circle Geometry Definitions
Radius:an interval joining centre to the
circumference
radius
Circle Geometry
Circle Geometry Definitions
Radius:an interval joining centre to the
circumference
radius
Diameter:an interval passing through the
centre, joining any two points
on the circumference
diameter
Circle Geometry
Circle Geometry Definitions
Radius:an interval joining centre to the
circumference
radius
Diameter:an interval passing through the
centre, joining any two points
on the circumference
diameter Chord:an interval joining two points on
the circumference
chord
Circle Geometry
Circle Geometry Definitions
Radius:an interval joining centre to the
circumference
radius
Diameter:an interval passing through the
centre, joining any two points
on the circumference
diameter Chord:an interval joining two points on
the circumference
chord
Secant: a line that cuts the circle
secant
Circle Geometry
Circle Geometry Definitions
Radius:an interval joining centre to the
circumference
radius
Diameter:an interval passing through the
centre, joining any two points
on the circumference
diameter Chord:an interval joining two points on
the circumference
chord
Secant: a line that cuts the circle
secant
Tangent: a line that touches the circle
tangent
Circle Geometry
Circle Geometry Definitions
Radius:an interval joining centre to the
circumference
radius
Diameter:an interval passing through the
centre, joining any two points
on the circumference
diameter Chord:an interval joining two points on
the circumference
chord
Secant: a line that cuts the circle
secant
Tangent: a line that touches the circle
tangent Arc: a piece of the circumference
arc
Sector: a plane figure with two radii and an
arc as boundaries.
sector
Sector: a plane figure with two radii and an
arc as boundaries.
sector
The minor sector is the small “piece of the
pie”, the major sector is the large “piece”
Sector: a plane figure with two radii and an
arc as boundaries.
sector
The minor sector is the small “piece of the
pie”, the major sector is the large “piece”
A quadrant is a sector where the angle at
the centre is 90 degrees
Sector: a plane figure with two radii and an
arc as boundaries.
sector
The minor sector is the small “piece of the
pie”, the major sector is the large “piece”
A quadrant is a sector where the angle at
the centre is 90 degrees
Segment:a plane figure with a chord and an
arc as boundaries.
segment
Sector: a plane figure with two radii and an
arc as boundaries.
sector
The minor sector is the small “piece of the
pie”, the major sector is the large “piece”
A quadrant is a sector where the angle at
the centre is 90 degrees
Segment:a plane figure with a chord and an
arc as boundaries.
segment
A semicircle is a segment where the chord is
the diameter, it is also a sector as the diameter
is two radii.
Concyclic Points:points that lie on the same circle.
A
B
C
D
Concyclic Points:points that lie on the same circle.
concyclic points
A
B
C
D
Concyclic Points:points that lie on the same circle.
concyclic points
Cyclic Quadrilateral: a four sided shape with all vertices on the
same circle.
cyclic quadrilateral
A
B
C
D
A
B

A
B

 represents the angle
subtended at the centre by
the arc AB
A
B

 represents the angle
subtended at the centre by
the arc AB

A
B

 represents the angle
subtended at the centre by
the arc AB

 represents the angle
subtended at the
circumference by the arc AB
A
B

 represents the angle
subtended at the centre by
the arc AB

 represents the angle
subtended at the
circumference by the arc AB
A
B

 represents the angle
subtended at the centre by
the arc AB

 represents the angle
subtended at the
circumference by the arc AB
Concentric circles have the
same centre.
Circles touching internally
share a common tangent.
Circles touching internally
share a common tangent.
Circles touching externally
share a common tangent.
Circles touching internally
share a common tangent.
Circles touching externally
share a common tangent.
Circles touching internally
share a common tangent.
Circles touching externally
share a common tangent.
Chord (Arc) Theorems
Chord (Arc) Theorems
Note: = chords cut off = arcs
Chord (Arc) Theorems
Note: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects
the chord, and the perpendicular bisector of a chord passes through
the centre.
Chord (Arc) Theorems
Note: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects
the chord, and the perpendicular bisector of a chord passes through
the centre.
A
B
O
X
Chord (Arc) Theorems
Note: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects
the chord, and the perpendicular bisector of a chord passes through
the centre.
 chordbisectscentre,from BXAX
A
B
O
X
Chord (Arc) Theorems
Note: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects
the chord, and the perpendicular bisector of a chord passes through
the centre.
 chordbisectscentre,from BXAX
A
B
O
X
OXAB :Data
Chord (Arc) Theorems
Note: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects
the chord, and the perpendicular bisector of a chord passes through
the centre.
 chordbisectscentre,from BXAX
A
B
O
X
OXAB :Data
BXAX :Prove
Chord (Arc) Theorems
Note: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects
the chord, and the perpendicular bisector of a chord passes through
the centre.
 chordbisectscentre,from BXAX
A
B
O
X
OXAB :Data
BXAX :Prove
Proof: Join OA, OB
Chord (Arc) Theorems
Note: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects
the chord, and the perpendicular bisector of a chord passes through
the centre.
 chordbisectscentre,from BXAX
A
B
O
X
OXAB :Data
BXAX :Prove
Proof: Join OA, OB
  RBXOAXO given90

Chord (Arc) Theorems
Note: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects
the chord, and the perpendicular bisector of a chord passes through
the centre.
 chordbisectscentre,from BXAX
A
B
O
X
OXAB :Data
BXAX :Prove
Proof: Join OA, OB
  RBXOAXO given90

  HBOAO radii
Chord (Arc) Theorems
Note: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects
the chord, and the perpendicular bisector of a chord passes through
the centre.
 chordbisectscentre,from BXAX
A
B
O
X
OXAB :Data
BXAX :Prove
Proof: Join OA, OB
  RBXOAXO given90

  HBOAO radii
 SOX commonis
Chord (Arc) Theorems
Note: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects
the chord, and the perpendicular bisector of a chord passes through
the centre.
 chordbisectscentre,from BXAX
A
B
O
X
OXAB :Data
BXAX :Prove
Proof: Join OA, OB
  RBXOAXO given90

  HBOAO radii
 SOX commonis
 RHSBXOAXO 
Chord (Arc) Theorems
Note: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects
the chord, and the perpendicular bisector of a chord passes through
the centre.
 chordbisectscentre,from BXAX
A
B
O
X
OXAB :Data
BXAX :Prove
Proof: Join OA, OB
  RBXOAXO given90

  HBOAO radii
 SOX commonis
 RHSBXOAXO 
 matching sides in 'sAX BX   
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
A
B
O
X
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
 chordtomidpoint,tocentrejoiningline  ABOX
A
B
O
X
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
 chordtomidpoint,tocentrejoiningline  ABOX
A
B
O
X
BXAX :Data
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
 chordtomidpoint,tocentrejoiningline  ABOX
A
B
O
X
BXAX :Data
OXAB :Prove
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
 chordtomidpoint,tocentrejoiningline  ABOX
A
B
O
X
BXAX :Data
OXAB :Prove
Proof: Join OA, OB
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
 chordtomidpoint,tocentrejoiningline  ABOX
A
B
O
X
BXAX :Data
OXAB :Prove
Proof: Join OA, OB
  SBXAX given
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
 chordtomidpoint,tocentrejoiningline  ABOX
A
B
O
X
BXAX :Data
OXAB :Prove
Proof: Join OA, OB
  SBXAX given
  SBOAO radii
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
 chordtomidpoint,tocentrejoiningline  ABOX
A
B
O
X
BXAX :Data
OXAB :Prove
Proof: Join OA, OB
  SBXAX given
  SBOAO radii
 SOX commonis
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
 chordtomidpoint,tocentrejoiningline  ABOX
A
B
O
X
BXAX :Data
OXAB :Prove
Proof: Join OA, OB
  SBXAX given
  SBOAO radii
 SOX commonis
 SSSBXOAXO 
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
 chordtomidpoint,tocentrejoiningline  ABOX
A
B
O
X
BXAX :Data
OXAB :Prove
Proof: Join OA, OB
  SBXAX given
  SBOAO radii
 SOX commonis
 SSSBXOAXO 
 matching 's in 'sAXO BXO     
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
 chordtomidpoint,tocentrejoiningline  ABOX
A
B
O
X
BXAX :Data
OXAB :Prove
Proof: Join OA, OB
  SBXAX given
  SBOAO radii
 SOX commonis
 SSSBXOAXO 
 matching 's in 'sAXO BXO     
 AXBBXOAXO straight180  
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
 chordtomidpoint,tocentrejoiningline  ABOX
A
B
O
X
BXAX :Data
OXAB :Prove
Proof: Join OA, OB
  SBXAX given
  SBOAO radii
 SOX commonis
 SSSBXOAXO 
 matching 's in 'sAXO BXO     
 AXBBXOAXO straight180  
90
1802




AXO
AXO
(2) Converse of (1)
The line from the centre of a circle to the midpoint of the chord at
right angles.
 chordtomidpoint,tocentrejoiningline  ABOX
A
B
O
X
BXAX :Data
OXAB :Prove
Proof: Join OA, OB
  SBXAX given
  SBOAO radii
 SOX commonis
 SSSBXOAXO 
 matching 's in 'sAXO BXO     
 AXBBXOAXO straight180  
90
1802




AXO
AXO
OXAB 
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
A
B
O
X
C DY
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
 centrefromtequidistanchords, OYOX
A
B
O
X
C DY
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
 centrefromtequidistanchords, OYOX
 centreats'subtendchords  CODAOB
A
B
O
X
C DY
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
 centrefromtequidistanchords, OYOX
Data: , ,AB CD OX AB OY CD  
 centreats'subtendchords  CODAOB
A
B
O
X
C DY
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
 centrefromtequidistanchords, OYOX
Data: , ,AB CD OX AB OY CD  
OYOX :Prove
 centreats'subtendchords  CODAOB
A
B
O
X
C DY
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
 centrefromtequidistanchords, OYOX
Data: , ,AB CD OX AB OY CD  
OYOX :Prove
Proof: Join OA, OC
 centreats'subtendchords  CODAOB
A
B
O
X
C DY
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
 centrefromtequidistanchords, OYOX
Data: , ,AB CD OX AB OY CD  
OYOX :Prove
Proof: Join OA, OC
 givenCDAB 
 centreats'subtendchords  CODAOB
A
B
O
X
C DY
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
 centrefromtequidistanchords, OYOX
Data: , ,AB CD OX AB OY CD  
OYOX :Prove
Proof: Join OA, OC
 givenCDAB 
 chordbisects
2
1
 ABAX
 centreats'subtendchords  CODAOB
A
B
O
X
C DY
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
 centrefromtequidistanchords, OYOX
Data: , ,AB CD OX AB OY CD  
OYOX :Prove
Proof: Join OA, OC
 givenCDAB 
 chordbisects
2
1
 ABAX
 centreats'subtendchords  CODAOB
 chordbisects
2
1
 CDCY
A
B
O
X
C DY
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
 centrefromtequidistanchords, OYOX
Data: , ,AB CD OX AB OY CD  
OYOX :Prove
Proof: Join OA, OC
 givenCDAB 
 chordbisects
2
1
 ABAX
 SCYAX 
 centreats'subtendchords  CODAOB
 chordbisects
2
1
 CDCY
A
B
O
X
C DY
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
 centrefromtequidistanchords, OYOX
Data: , ,AB CD OX AB OY CD  
OYOX :Prove
Proof: Join OA, OC
 givenCDAB 
 chordbisects
2
1
 ABAX
 SCYAX 
  RCYOAXO given90

 centreats'subtendchords  CODAOB
 chordbisects
2
1
 CDCY
A
B
O
X
C DY
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
 centrefromtequidistanchords, OYOX
Data: , ,AB CD OX AB OY CD  
OYOX :Prove
Proof: Join OA, OC
 givenCDAB 
 chordbisects
2
1
 ABAX
 SCYAX 
  RCYOAXO given90

 centreats'subtendchords  CODAOB
 chordbisects
2
1
 CDCY
  HOCOA radii
A
B
O
X
C DY
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
 centrefromtequidistanchords, OYOX
Data: , ,AB CD OX AB OY CD  
OYOX :Prove
Proof: Join OA, OC
 givenCDAB 
 chordbisects
2
1
 ABAX
 SCYAX 
  RCYOAXO given90

 centreats'subtendchords  CODAOB
 chordbisects
2
1
 CDCY
  HOCOA radii
 RHSCYOAXO 
A
B
O
X
C DY
(3) Equal chords of a circle are the same distance from the centre and
subtend equal angles at the centre.
 centrefromtequidistanchords, OYOX
Data: , ,AB CD OX AB OY CD  
OYOX :Prove
Proof: Join OA, OC
 givenCDAB 
 chordbisects
2
1
 ABAX
 SCYAX 
  RCYOAXO given90

 matching sides in 'sOX OY   
 centreats'subtendchords  CODAOB
 chordbisects
2
1
 CDCY
  HOCOA radii
 RHSCYOAXO 
A
B
O
X
C DY
A
B
O
C D
A
B
O
C D
CDAB :Data
A
B
O
C D
CDAB :Data
CODAOB :Prove
A
B
O
C D
CDAB :Data
CODAOB :Prove
Proof:  givenCDAB 
A
B
O
C D
CDAB :Data
CODAOB :Prove
Proof:  givenCDAB 
 radii DOCOBOAO
A
B
O
C D
CDAB :Data
CODAOB :Prove
Proof:  givenCDAB 
 radii DOCOBOAO
 SSSCODAOB 
A
B
O
C D
CDAB :Data
CODAOB :Prove
Proof:  givenCDAB 
 radii DOCOBOAO
 matching 's in 'sAOB COD     
 SSSCODAOB 
A
B
O
C D
CDAB :Data
CODAOB :Prove
Proof:  givenCDAB 
 radii DOCOBOAO
 matching 's in 'sAOB COD     
 SSSCODAOB 
Exercise 9A; 1 ce, 2 aceg, 3, 4, 9, 10 ac, 11 ac, 13, 15, 16, 18

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Circle Geometry Definitions and Theorems

  • 4. Circle Geometry Circle Geometry Definitions Radius:an interval joining centre to the circumference radius
  • 5. Circle Geometry Circle Geometry Definitions Radius:an interval joining centre to the circumference radius Diameter:an interval passing through the centre, joining any two points on the circumference diameter
  • 6. Circle Geometry Circle Geometry Definitions Radius:an interval joining centre to the circumference radius Diameter:an interval passing through the centre, joining any two points on the circumference diameter Chord:an interval joining two points on the circumference chord
  • 7. Circle Geometry Circle Geometry Definitions Radius:an interval joining centre to the circumference radius Diameter:an interval passing through the centre, joining any two points on the circumference diameter Chord:an interval joining two points on the circumference chord Secant: a line that cuts the circle secant
  • 8. Circle Geometry Circle Geometry Definitions Radius:an interval joining centre to the circumference radius Diameter:an interval passing through the centre, joining any two points on the circumference diameter Chord:an interval joining two points on the circumference chord Secant: a line that cuts the circle secant Tangent: a line that touches the circle tangent
  • 9. Circle Geometry Circle Geometry Definitions Radius:an interval joining centre to the circumference radius Diameter:an interval passing through the centre, joining any two points on the circumference diameter Chord:an interval joining two points on the circumference chord Secant: a line that cuts the circle secant Tangent: a line that touches the circle tangent Arc: a piece of the circumference arc
  • 10.
  • 11. Sector: a plane figure with two radii and an arc as boundaries. sector
  • 12. Sector: a plane figure with two radii and an arc as boundaries. sector The minor sector is the small “piece of the pie”, the major sector is the large “piece”
  • 13. Sector: a plane figure with two radii and an arc as boundaries. sector The minor sector is the small “piece of the pie”, the major sector is the large “piece” A quadrant is a sector where the angle at the centre is 90 degrees
  • 14. Sector: a plane figure with two radii and an arc as boundaries. sector The minor sector is the small “piece of the pie”, the major sector is the large “piece” A quadrant is a sector where the angle at the centre is 90 degrees Segment:a plane figure with a chord and an arc as boundaries. segment
  • 15. Sector: a plane figure with two radii and an arc as boundaries. sector The minor sector is the small “piece of the pie”, the major sector is the large “piece” A quadrant is a sector where the angle at the centre is 90 degrees Segment:a plane figure with a chord and an arc as boundaries. segment A semicircle is a segment where the chord is the diameter, it is also a sector as the diameter is two radii.
  • 16.
  • 17. Concyclic Points:points that lie on the same circle. A B C D
  • 18. Concyclic Points:points that lie on the same circle. concyclic points A B C D
  • 19. Concyclic Points:points that lie on the same circle. concyclic points Cyclic Quadrilateral: a four sided shape with all vertices on the same circle. cyclic quadrilateral A B C D
  • 20.
  • 22. A B   represents the angle subtended at the centre by the arc AB
  • 23. A B   represents the angle subtended at the centre by the arc AB 
  • 24. A B   represents the angle subtended at the centre by the arc AB   represents the angle subtended at the circumference by the arc AB
  • 25. A B   represents the angle subtended at the centre by the arc AB   represents the angle subtended at the circumference by the arc AB
  • 26. A B   represents the angle subtended at the centre by the arc AB   represents the angle subtended at the circumference by the arc AB Concentric circles have the same centre.
  • 27.
  • 28.
  • 30. Circles touching internally share a common tangent. Circles touching externally share a common tangent.
  • 31. Circles touching internally share a common tangent. Circles touching externally share a common tangent.
  • 32. Circles touching internally share a common tangent. Circles touching externally share a common tangent.
  • 34. Chord (Arc) Theorems Note: = chords cut off = arcs
  • 35. Chord (Arc) Theorems Note: = chords cut off = arcs (1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.
  • 36. Chord (Arc) Theorems Note: = chords cut off = arcs (1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre. A B O X
  • 37. Chord (Arc) Theorems Note: = chords cut off = arcs (1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.  chordbisectscentre,from BXAX A B O X
  • 38. Chord (Arc) Theorems Note: = chords cut off = arcs (1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.  chordbisectscentre,from BXAX A B O X OXAB :Data
  • 39. Chord (Arc) Theorems Note: = chords cut off = arcs (1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.  chordbisectscentre,from BXAX A B O X OXAB :Data BXAX :Prove
  • 40. Chord (Arc) Theorems Note: = chords cut off = arcs (1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.  chordbisectscentre,from BXAX A B O X OXAB :Data BXAX :Prove Proof: Join OA, OB
  • 41. Chord (Arc) Theorems Note: = chords cut off = arcs (1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.  chordbisectscentre,from BXAX A B O X OXAB :Data BXAX :Prove Proof: Join OA, OB   RBXOAXO given90 
  • 42. Chord (Arc) Theorems Note: = chords cut off = arcs (1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.  chordbisectscentre,from BXAX A B O X OXAB :Data BXAX :Prove Proof: Join OA, OB   RBXOAXO given90    HBOAO radii
  • 43. Chord (Arc) Theorems Note: = chords cut off = arcs (1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.  chordbisectscentre,from BXAX A B O X OXAB :Data BXAX :Prove Proof: Join OA, OB   RBXOAXO given90    HBOAO radii  SOX commonis
  • 44. Chord (Arc) Theorems Note: = chords cut off = arcs (1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.  chordbisectscentre,from BXAX A B O X OXAB :Data BXAX :Prove Proof: Join OA, OB   RBXOAXO given90    HBOAO radii  SOX commonis  RHSBXOAXO 
  • 45. Chord (Arc) Theorems Note: = chords cut off = arcs (1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.  chordbisectscentre,from BXAX A B O X OXAB :Data BXAX :Prove Proof: Join OA, OB   RBXOAXO given90    HBOAO radii  SOX commonis  RHSBXOAXO   matching sides in 'sAX BX   
  • 46. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles.
  • 47. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles. A B O X
  • 48. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles.  chordtomidpoint,tocentrejoiningline  ABOX A B O X
  • 49. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles.  chordtomidpoint,tocentrejoiningline  ABOX A B O X BXAX :Data
  • 50. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles.  chordtomidpoint,tocentrejoiningline  ABOX A B O X BXAX :Data OXAB :Prove
  • 51. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles.  chordtomidpoint,tocentrejoiningline  ABOX A B O X BXAX :Data OXAB :Prove Proof: Join OA, OB
  • 52. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles.  chordtomidpoint,tocentrejoiningline  ABOX A B O X BXAX :Data OXAB :Prove Proof: Join OA, OB   SBXAX given
  • 53. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles.  chordtomidpoint,tocentrejoiningline  ABOX A B O X BXAX :Data OXAB :Prove Proof: Join OA, OB   SBXAX given   SBOAO radii
  • 54. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles.  chordtomidpoint,tocentrejoiningline  ABOX A B O X BXAX :Data OXAB :Prove Proof: Join OA, OB   SBXAX given   SBOAO radii  SOX commonis
  • 55. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles.  chordtomidpoint,tocentrejoiningline  ABOX A B O X BXAX :Data OXAB :Prove Proof: Join OA, OB   SBXAX given   SBOAO radii  SOX commonis  SSSBXOAXO 
  • 56. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles.  chordtomidpoint,tocentrejoiningline  ABOX A B O X BXAX :Data OXAB :Prove Proof: Join OA, OB   SBXAX given   SBOAO radii  SOX commonis  SSSBXOAXO   matching 's in 'sAXO BXO     
  • 57. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles.  chordtomidpoint,tocentrejoiningline  ABOX A B O X BXAX :Data OXAB :Prove Proof: Join OA, OB   SBXAX given   SBOAO radii  SOX commonis  SSSBXOAXO   matching 's in 'sAXO BXO       AXBBXOAXO straight180  
  • 58. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles.  chordtomidpoint,tocentrejoiningline  ABOX A B O X BXAX :Data OXAB :Prove Proof: Join OA, OB   SBXAX given   SBOAO radii  SOX commonis  SSSBXOAXO   matching 's in 'sAXO BXO       AXBBXOAXO straight180   90 1802     AXO AXO
  • 59. (2) Converse of (1) The line from the centre of a circle to the midpoint of the chord at right angles.  chordtomidpoint,tocentrejoiningline  ABOX A B O X BXAX :Data OXAB :Prove Proof: Join OA, OB   SBXAX given   SBOAO radii  SOX commonis  SSSBXOAXO   matching 's in 'sAXO BXO       AXBBXOAXO straight180   90 1802     AXO AXO OXAB 
  • 60. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
  • 61. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre. A B O X C DY
  • 62. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.  centrefromtequidistanchords, OYOX A B O X C DY
  • 63. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.  centrefromtequidistanchords, OYOX  centreats'subtendchords  CODAOB A B O X C DY
  • 64. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.  centrefromtequidistanchords, OYOX Data: , ,AB CD OX AB OY CD    centreats'subtendchords  CODAOB A B O X C DY
  • 65. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.  centrefromtequidistanchords, OYOX Data: , ,AB CD OX AB OY CD   OYOX :Prove  centreats'subtendchords  CODAOB A B O X C DY
  • 66. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.  centrefromtequidistanchords, OYOX Data: , ,AB CD OX AB OY CD   OYOX :Prove Proof: Join OA, OC  centreats'subtendchords  CODAOB A B O X C DY
  • 67. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.  centrefromtequidistanchords, OYOX Data: , ,AB CD OX AB OY CD   OYOX :Prove Proof: Join OA, OC  givenCDAB   centreats'subtendchords  CODAOB A B O X C DY
  • 68. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.  centrefromtequidistanchords, OYOX Data: , ,AB CD OX AB OY CD   OYOX :Prove Proof: Join OA, OC  givenCDAB   chordbisects 2 1  ABAX  centreats'subtendchords  CODAOB A B O X C DY
  • 69. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.  centrefromtequidistanchords, OYOX Data: , ,AB CD OX AB OY CD   OYOX :Prove Proof: Join OA, OC  givenCDAB   chordbisects 2 1  ABAX  centreats'subtendchords  CODAOB  chordbisects 2 1  CDCY A B O X C DY
  • 70. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.  centrefromtequidistanchords, OYOX Data: , ,AB CD OX AB OY CD   OYOX :Prove Proof: Join OA, OC  givenCDAB   chordbisects 2 1  ABAX  SCYAX   centreats'subtendchords  CODAOB  chordbisects 2 1  CDCY A B O X C DY
  • 71. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.  centrefromtequidistanchords, OYOX Data: , ,AB CD OX AB OY CD   OYOX :Prove Proof: Join OA, OC  givenCDAB   chordbisects 2 1  ABAX  SCYAX    RCYOAXO given90   centreats'subtendchords  CODAOB  chordbisects 2 1  CDCY A B O X C DY
  • 72. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.  centrefromtequidistanchords, OYOX Data: , ,AB CD OX AB OY CD   OYOX :Prove Proof: Join OA, OC  givenCDAB   chordbisects 2 1  ABAX  SCYAX    RCYOAXO given90   centreats'subtendchords  CODAOB  chordbisects 2 1  CDCY   HOCOA radii A B O X C DY
  • 73. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.  centrefromtequidistanchords, OYOX Data: , ,AB CD OX AB OY CD   OYOX :Prove Proof: Join OA, OC  givenCDAB   chordbisects 2 1  ABAX  SCYAX    RCYOAXO given90   centreats'subtendchords  CODAOB  chordbisects 2 1  CDCY   HOCOA radii  RHSCYOAXO  A B O X C DY
  • 74. (3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.  centrefromtequidistanchords, OYOX Data: , ,AB CD OX AB OY CD   OYOX :Prove Proof: Join OA, OC  givenCDAB   chordbisects 2 1  ABAX  SCYAX    RCYOAXO given90   matching sides in 'sOX OY     centreats'subtendchords  CODAOB  chordbisects 2 1  CDCY   HOCOA radii  RHSCYOAXO  A B O X C DY
  • 78. A B O C D CDAB :Data CODAOB :Prove Proof:  givenCDAB 
  • 79. A B O C D CDAB :Data CODAOB :Prove Proof:  givenCDAB   radii DOCOBOAO
  • 80. A B O C D CDAB :Data CODAOB :Prove Proof:  givenCDAB   radii DOCOBOAO  SSSCODAOB 
  • 81. A B O C D CDAB :Data CODAOB :Prove Proof:  givenCDAB   radii DOCOBOAO  matching 's in 'sAOB COD       SSSCODAOB 
  • 82. A B O C D CDAB :Data CODAOB :Prove Proof:  givenCDAB   radii DOCOBOAO  matching 's in 'sAOB COD       SSSCODAOB  Exercise 9A; 1 ce, 2 aceg, 3, 4, 9, 10 ac, 11 ac, 13, 15, 16, 18