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International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 04 Issue: 08 | Aug -2017 www.irjet.net p-ISSN: 2395-0072
© 2017, IRJET | Impact Factor value: 5.181 | ISO 9001:2008 Certified Journal | Page 72
Echo Function
Vishalkumar Sonar
Independent Researcher , Andheri-(E) , Mumbai -400069, Maharashtra , India.
---------------------------------------------------------------------***---------------------------------------------------------------------
Abstract - This Paper develop a function called Echo
Function ( Echo Function is called as Echo Function because
of its periodic nature of output ) , Which work similar to a
Mathematical function . If x is a real number and Echo
Function is applied on x than output of Echo Function will
be some real number say y , now if again Echo function is
applied on y output we get output as x and if we repeat this
process again and again we get only two value x and y from
Echo function for a real number x which is echoing
periodically .
Key Words: Hyperbolic function .
1. INTRODUCTION
In Mathematics we have many function along with its
inverse function . I have come across a mathematical
equation which is derived from a basic mathematical
equation , Which act like a function and its inverse
function too , named as Echo function. Result produced by
Echo function is periodically oscillating between two value
for a real number when applied again and again as shown
in this paper.
1.1 BASIC DEFINITION
The purpose of this section is to recall some results on
the proposed method. From basics of hyperbolic function
we know that
tanh (x) = (e2x -1)/ (e2x + 1) ____[1]
where x is a real number and Domain ( -∞,∞) ,
Range ( -1,1)
tanh-1 (z) = (1/2) ln[ (1 + z)/ (1 - z) ] ____[2]
where z is a real number , The domain is the open
interval (−1, 1).
2. ECHO FUNCTION
Let us consider a real number x such that -∞< x <∞. So
hyperbolic tangent of x will be
tanh (x) = (e2x -1)/ (e2x + 1)
As per eqn [1]. Modifying above equation we get ,
-tanh (x) = (1 -e2x )/ (1 + e2x ) _____(A)
Using eqn [2] we have ,
tanh-1 (z) = (1/2) ln [(1 + z)/ (1 - z)]
where z is a real number with domain open
interval (−1, 1). Put z = e2x in above equation , we get
tanh-1 (e2x) = (1/2) ln [(1 + e2x)/ (1 - e2x)]
Since we have replace z = e2x in above equation due to
which it working range get modified as [ x < 0 ] . Therefore
we have
tanh-1 (e2x) = (1/2) ln [(1 + e2x)/ (1 - e2x)]
__ [ for 0 > x]
Modify above equation we get ,
tanh-1 (e2x) = -(1/2) ln [(1 - e2x )/ (1 + e2x )]
____(B)
Solving eqn (A) and (B), we get
tanh-1 (e2x) = - (1/2) ln (- tanh (x) )
e2x = tanh [-(1/2) ln (-tanh (x) ) ]
x = (1/2) ln { tanh [-(1/2) ln (- tanh (x) ) ] }
We know that tanh (-x ) = - tanh (x) , modified above eqn
will be ,
x = (1/2) ln { -tanh [(1/2) ln (-tanh (x) ) ] }
_____(C)
Which is valid if x is a real number and 0 > x .
looking carefully at eqn(c) we can see that on right hand
side , x is bounded with a function { (1/2) ln (- tanh (x) ) }
which is again bounded with the same function so as to
obtain x on left hand side . It looks like value x is getting
echo backed to x through a function applied twice . To
make it understandable let us define that new function as
Echo Function ( ε ), which is defined as
ε(x) = (1/2) ln (- tanh (x) )
where x is a real number and 0 > x
So eqn (C) becomes ,
x = ε( ε(x) )
In above equation take Echo Function on both side ,we get
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 04 Issue: 08 | Aug -2017 www.irjet.net p-ISSN: 2395-0072
© 2017, IRJET | Impact Factor value: 5.181 | ISO 9001:2008 Certified Journal | Page 73
ε(x) = ε( ε( ε(x) ) )
Again take Echo Function on both side of above eqn , we
get
x = ε( ε(x) ) = ε( ε( ε( ε(x) ) ) )
So if repeat this process we get x for even repetition and
ε(x) for odd repetition . Also on odd repetition it act as a
function and on even repetition it act its own inverse.
2.1 GRAPH
Fig (2.1.1) Graph of ε(x)
Fig (2.1.2) Graph of ε( ε(x) )
Fig (2.1.3) Graph of tanh(x)
3. CONCLUSIONS
This paper shows that Echo Function produce
two different value one when applied even times on given
value and another when applied odd times on given value.
Also it act as a function and its own inverse function too.
REFERENCES
[1] G.V.kumbhojkar , Applied Mathematics -1 (F.E.
semester-1), C.jamnadas & Co.
[2] https://en.wikipedia.org/wiki/Hyperbolic_function

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Echo Function

  • 1. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 04 Issue: 08 | Aug -2017 www.irjet.net p-ISSN: 2395-0072 © 2017, IRJET | Impact Factor value: 5.181 | ISO 9001:2008 Certified Journal | Page 72 Echo Function Vishalkumar Sonar Independent Researcher , Andheri-(E) , Mumbai -400069, Maharashtra , India. ---------------------------------------------------------------------***--------------------------------------------------------------------- Abstract - This Paper develop a function called Echo Function ( Echo Function is called as Echo Function because of its periodic nature of output ) , Which work similar to a Mathematical function . If x is a real number and Echo Function is applied on x than output of Echo Function will be some real number say y , now if again Echo function is applied on y output we get output as x and if we repeat this process again and again we get only two value x and y from Echo function for a real number x which is echoing periodically . Key Words: Hyperbolic function . 1. INTRODUCTION In Mathematics we have many function along with its inverse function . I have come across a mathematical equation which is derived from a basic mathematical equation , Which act like a function and its inverse function too , named as Echo function. Result produced by Echo function is periodically oscillating between two value for a real number when applied again and again as shown in this paper. 1.1 BASIC DEFINITION The purpose of this section is to recall some results on the proposed method. From basics of hyperbolic function we know that tanh (x) = (e2x -1)/ (e2x + 1) ____[1] where x is a real number and Domain ( -∞,∞) , Range ( -1,1) tanh-1 (z) = (1/2) ln[ (1 + z)/ (1 - z) ] ____[2] where z is a real number , The domain is the open interval (−1, 1). 2. ECHO FUNCTION Let us consider a real number x such that -∞< x <∞. So hyperbolic tangent of x will be tanh (x) = (e2x -1)/ (e2x + 1) As per eqn [1]. Modifying above equation we get , -tanh (x) = (1 -e2x )/ (1 + e2x ) _____(A) Using eqn [2] we have , tanh-1 (z) = (1/2) ln [(1 + z)/ (1 - z)] where z is a real number with domain open interval (−1, 1). Put z = e2x in above equation , we get tanh-1 (e2x) = (1/2) ln [(1 + e2x)/ (1 - e2x)] Since we have replace z = e2x in above equation due to which it working range get modified as [ x < 0 ] . Therefore we have tanh-1 (e2x) = (1/2) ln [(1 + e2x)/ (1 - e2x)] __ [ for 0 > x] Modify above equation we get , tanh-1 (e2x) = -(1/2) ln [(1 - e2x )/ (1 + e2x )] ____(B) Solving eqn (A) and (B), we get tanh-1 (e2x) = - (1/2) ln (- tanh (x) ) e2x = tanh [-(1/2) ln (-tanh (x) ) ] x = (1/2) ln { tanh [-(1/2) ln (- tanh (x) ) ] } We know that tanh (-x ) = - tanh (x) , modified above eqn will be , x = (1/2) ln { -tanh [(1/2) ln (-tanh (x) ) ] } _____(C) Which is valid if x is a real number and 0 > x . looking carefully at eqn(c) we can see that on right hand side , x is bounded with a function { (1/2) ln (- tanh (x) ) } which is again bounded with the same function so as to obtain x on left hand side . It looks like value x is getting echo backed to x through a function applied twice . To make it understandable let us define that new function as Echo Function ( ε ), which is defined as ε(x) = (1/2) ln (- tanh (x) ) where x is a real number and 0 > x So eqn (C) becomes , x = ε( ε(x) ) In above equation take Echo Function on both side ,we get
  • 2. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 04 Issue: 08 | Aug -2017 www.irjet.net p-ISSN: 2395-0072 © 2017, IRJET | Impact Factor value: 5.181 | ISO 9001:2008 Certified Journal | Page 73 ε(x) = ε( ε( ε(x) ) ) Again take Echo Function on both side of above eqn , we get x = ε( ε(x) ) = ε( ε( ε( ε(x) ) ) ) So if repeat this process we get x for even repetition and ε(x) for odd repetition . Also on odd repetition it act as a function and on even repetition it act its own inverse. 2.1 GRAPH Fig (2.1.1) Graph of ε(x) Fig (2.1.2) Graph of ε( ε(x) ) Fig (2.1.3) Graph of tanh(x) 3. CONCLUSIONS This paper shows that Echo Function produce two different value one when applied even times on given value and another when applied odd times on given value. Also it act as a function and its own inverse function too. REFERENCES [1] G.V.kumbhojkar , Applied Mathematics -1 (F.E. semester-1), C.jamnadas & Co. [2] https://en.wikipedia.org/wiki/Hyperbolic_function