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Ministerul Educaţiei, Cercetării şi Inovării 
Centrul Naţional pentru Curriculum şi Evaluare în Învăţământul Preuniversitar 
Soluţie 
1. 62 = x(x − 5)⇒ x = 9 . 
2. f (−1) = −2⇒ f (2 ⋅ (−2)) =10⇒ f (2 ⋅ ( f (−1))) =10 . 
3. 2 2 , (2 1), 
x x k k x k k 
+π = −π + π ∈Z⇒ =π − ∈Z sau 
2 2 
x x k k x k 
+π = − + π + π ∈Z⇒ = π ∈Z . 
x ∈ π k − k ∈ ∪ k 
π ∈   k 
 
  Z Z . 
2 ! 
= ∈`⇒ divide (2n)!. 
2 1 2 2 2 
+ + − + ∗ 
a a a 
− < < ∈ ⇒ = 
1 0, 2 
BACALAUREAT 2009-MATEMATICĂ - Proba D, tipul subiectului MT1, programa M1 
2 
k 
2 2 , , 
2 2 3 
În final , { ( ) } 2 
2 1 
3 
4. ( ) 
( ) 
( )2 
2 2 
! 
! 
n 
n 
n 
C n 
n 
5. 2xM = xA + xN ,2xN = xB + xM ⇒ xM = 4, xN = 5; 
2yM = yA + yN ,2yN = yB + yM ⇒ yM = 3, yN = 4 , deci M (4 ; 3) , N (5 ; 4) . 
6. ( ) ( ) 
( ) 
2 1 
a a 
a a 
+ 
` . Doar pentru a = 2 se obţine triunghi .

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D mt1 i_062

  • 1. Ministerul Educaţiei, Cercetării şi Inovării Centrul Naţional pentru Curriculum şi Evaluare în Învăţământul Preuniversitar Soluţie 1. 62 = x(x − 5)⇒ x = 9 . 2. f (−1) = −2⇒ f (2 ⋅ (−2)) =10⇒ f (2 ⋅ ( f (−1))) =10 . 3. 2 2 , (2 1), x x k k x k k +π = −π + π ∈Z⇒ =π − ∈Z sau 2 2 x x k k x k +π = − + π + π ∈Z⇒ = π ∈Z . x ∈ π k − k ∈ ∪ k π ∈   k    Z Z . 2 ! = ∈`⇒ divide (2n)!. 2 1 2 2 2 + + − + ∗ a a a − < < ∈ ⇒ = 1 0, 2 BACALAUREAT 2009-MATEMATICĂ - Proba D, tipul subiectului MT1, programa M1 2 k 2 2 , , 2 2 3 În final , { ( ) } 2 2 1 3 4. ( ) ( ) ( )2 2 2 ! ! n n n C n n 5. 2xM = xA + xN ,2xN = xB + xM ⇒ xM = 4, xN = 5; 2yM = yA + yN ,2yN = yB + yM ⇒ yM = 3, yN = 4 , deci M (4 ; 3) , N (5 ; 4) . 6. ( ) ( ) ( ) 2 1 a a a a + ` . Doar pentru a = 2 se obţine triunghi .