Tourmaline Crystals – Image Source: http://www.mnh.si.edu
When objects are the exact same shape,
but they are different sizes, we say that
they are “Similar” objects or figures.
Images from Google Images
When we double the Length and
Width of our Photo we ENLARGE
it using a SCALE FACTOR of 2.
When we halve the Length and
Width of our Photo we REDUCE
it using a SCALE FACTOR of 1/2.
If the SCALE FACTOR is Greater than 1
the resulting object is an ENLARGEMENT.
If the SCALE FACTOR is Less than 1
the resulting object is a REDUCTION.
Scale Factors less than 1 are expressed
as Fractions: ¼, ½, or as decimals: 0.3 etc
3
4
6
8
We calculate the SCALE FACTOR by
comparing matching sides, using Ratios.
We always Compare the New shape, with the
Original shape (Big vs Small for these Photos).
New 6 8
Old 3 4
3
4
6
8
= 2==
For our Photo Enlargement we have:
S.F. =
When we compare the Ratios of the
matching sides, we get “2” in both cases.
We say the two photos are “Similar” :
eg. Exact same shape, but different sizes.
New 16 9
Old 4 3
4
3
8
6
NOT ==
For Photo Enlargement 2 we have:
S.F. =
4
3
16
9
When the Ratios are not all the same,
the objects are not similar to each other.
We know for certain that they are the same shape, because they contain
the same three angles. (This is the AAA rule for Similar Triangles).
E
A
Similar Triangles are the exact Same Shape,
but are Different Sizes.
ABC ~ DEF (~ means similar to)
12cm
6cm
65o
65o
40o
40o
C
B
FD
16cm 8cm10cm 5cm
75o
75o
AC 12
DF 6
The Triangles are the same
shape, because their three
Angles are identical.
(We do not have to calculate
the third angle because we
know it is 180 minus the other
two angles in both cases).
AB 10
DE 5
E
A
= 2= The Ratios of the matching sides
are all the same value. (S.F. = 2)
This proves the Triangles are Similar.
ABC ~ DEF (~ means similar to)
12cm
6cm
65o
65o
40o
40o
C
B
FD
16cm
8cm
10cm
5cm
BC 16
EF 8
= 2=
= 2=
E
A
Similar Triangles are the exact Same Shape,
but are Different Sizes.
If two different triangles contain the exact
same angles, but are different sizes, then
they are similar. We call this the AAA Rule.
ABC ~ DEF (~ means similar to)
65o
65o
40o
40o
C
B
FD
75o
75o
AC 12
DF 6
These two Triangles are
SIMILAR, because their three
Sides are all Proportional.
(Eg. When we calculate for
the matching sides, they all
give the same Scale Factor.
AB 10
DE 5
E
A
= 2= The Ratios of the matching sides
are all the same value. (S.F. = 2)
All Sides are Proportional to each other.
Triangles are Similar by PPP Rule.
ABC ~ DEF (~ means similar to)
12cm
6cm
C
B
FD
16cm
8cm
10cm
5cm
BC 16
EF 8
= 2=
= 2=
AC 12
DF 6
Two Triangles are similar if
two of their matching sides
are in Proportion, and the
included angle between
these sides is the same in
both triangles.
(This can be proven by
drawing lots of triangles and
measuring the three sides).
E
A
The Ratios of the matching sides
are all the same value. (S.F. = 2)
They have the same 40 degree angle.
Triangles are Similar by PAP or SAS.
ABC ~ DEF (~ means similar to)
12cm
6cm
40o
40o
C
B
FD
16cm
8cm
BC 16
EF 8
= 2=
= 2=
E
A
If two different sized Right Triangles contain a 90
degree angle, and one matching side, as well
as the Hypotentuse are in the same Proportion,
then they are Similar by the RHS Rule.
ABC ~ DEF (~ means similar to)
C
B
F
D
8mm
4mm
10mm 5mm
Tourmaline Crystal cross sections contain Similar Triangles
Tourmaline is found in Mozambique, and is a gem used to
make spectacular jewellery such as these colorful cufflinks.
Similar Triangles can also be used to great effect in Art and
Craft, as seen in this colourful and creative patchwork quilt.
Image Source: http://www.patchworkpatterns.co.uk
Many Similar Triangles are present in this modern art piece.
Image Source: http://www.trianglesoflight.org
Many Similar Triangles are present in the structure of the
Sydney Harbour Bridge to give it strength and stability.
Image Source: Copyright 2012 Passy’s World of Mathematics
A
B
C
All we need to do is calculate the missing third angle
C = R = 180 - (85 + 55) = 180 – 140 = 40o
ABC ~ PQR (by AAA Rule)
Use either AAA or PPP or PAP or RHS to prove these are Similar Triangles
5m 85o
P
Q
R
15m
85o
55o
55o
Now we need to check the Ratios of the matching sides
C = F = 70o
ABC ~ DEF (by PAP or SAS Rule)
Use either AAA or PPP or PAP or RHS to prove these are Similar Triangles
A
B
C
8
70o
D
E
F
12
70o
3
4.5
DF 12
AC 8
= 1.5=
EF 4.5
BC 3
= 1.5=
A
B
C
We know the third angle is 40o
so ABC ~ PQR by AAA.
Prove these are Similar Triangles and then find the value of “n”
5 85o
P
Q
R
15
85o
55o
55o
10
n = ?
PQ 15
AB 5
= 3= This Scale Factor of S.F. = 3 tells us that
PQR is three times bigger than ABC.
Using the Scale Factor of 3:
n = 3 x 10 = 30
A
B
C
We know the third angle is 40o
so ABC ~ PQR by AAA.
Prove these are Similar Triangles and then find the value of “n”
5 85o
P
Q
R
15
85o
55o
55o
10
n = ?
PQ PR
AB BC
= Substitute n 15
10 5
= Cross
Multiply
n 15
10 5
= 5n = 150 Divide by 5 n = 30
A
B
C
We know the third angle is 40o
so ABC ~ PQR by AAA.
Prove these are Similar Triangles and then find the value of “k”
30
85o
P
Q
R
15
85o
55o
55o
10k = ?
PQ PR
AB BC
= Substitute 15 30
k 10
= Cross
Multiply
15 30
k 10
= 30k = 150 Divide by 30 k = 5
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All slides are exclusive Copyright of Passy’s World of Mathematics
Visit our site for Free Mathematics PowerPoints

Similar Triangles

  • 1.
    Tourmaline Crystals –Image Source: http://www.mnh.si.edu
  • 2.
    When objects arethe exact same shape, but they are different sizes, we say that they are “Similar” objects or figures. Images from Google Images
  • 3.
    When we doublethe Length and Width of our Photo we ENLARGE it using a SCALE FACTOR of 2. When we halve the Length and Width of our Photo we REDUCE it using a SCALE FACTOR of 1/2.
  • 4.
    If the SCALEFACTOR is Greater than 1 the resulting object is an ENLARGEMENT. If the SCALE FACTOR is Less than 1 the resulting object is a REDUCTION. Scale Factors less than 1 are expressed as Fractions: ¼, ½, or as decimals: 0.3 etc 3 4 6 8
  • 5.
    We calculate theSCALE FACTOR by comparing matching sides, using Ratios. We always Compare the New shape, with the Original shape (Big vs Small for these Photos). New 6 8 Old 3 4 3 4 6 8 = 2== For our Photo Enlargement we have: S.F. =
  • 6.
    When we comparethe Ratios of the matching sides, we get “2” in both cases. We say the two photos are “Similar” : eg. Exact same shape, but different sizes. New 16 9 Old 4 3 4 3 8 6 NOT == For Photo Enlargement 2 we have: S.F. = 4 3 16 9 When the Ratios are not all the same, the objects are not similar to each other.
  • 7.
    We know forcertain that they are the same shape, because they contain the same three angles. (This is the AAA rule for Similar Triangles). E A Similar Triangles are the exact Same Shape, but are Different Sizes. ABC ~ DEF (~ means similar to) 12cm 6cm 65o 65o 40o 40o C B FD 16cm 8cm10cm 5cm 75o 75o
  • 8.
    AC 12 DF 6 TheTriangles are the same shape, because their three Angles are identical. (We do not have to calculate the third angle because we know it is 180 minus the other two angles in both cases). AB 10 DE 5 E A = 2= The Ratios of the matching sides are all the same value. (S.F. = 2) This proves the Triangles are Similar. ABC ~ DEF (~ means similar to) 12cm 6cm 65o 65o 40o 40o C B FD 16cm 8cm 10cm 5cm BC 16 EF 8 = 2= = 2=
  • 9.
    E A Similar Triangles arethe exact Same Shape, but are Different Sizes. If two different triangles contain the exact same angles, but are different sizes, then they are similar. We call this the AAA Rule. ABC ~ DEF (~ means similar to) 65o 65o 40o 40o C B FD 75o 75o
  • 10.
    AC 12 DF 6 Thesetwo Triangles are SIMILAR, because their three Sides are all Proportional. (Eg. When we calculate for the matching sides, they all give the same Scale Factor. AB 10 DE 5 E A = 2= The Ratios of the matching sides are all the same value. (S.F. = 2) All Sides are Proportional to each other. Triangles are Similar by PPP Rule. ABC ~ DEF (~ means similar to) 12cm 6cm C B FD 16cm 8cm 10cm 5cm BC 16 EF 8 = 2= = 2=
  • 11.
    AC 12 DF 6 TwoTriangles are similar if two of their matching sides are in Proportion, and the included angle between these sides is the same in both triangles. (This can be proven by drawing lots of triangles and measuring the three sides). E A The Ratios of the matching sides are all the same value. (S.F. = 2) They have the same 40 degree angle. Triangles are Similar by PAP or SAS. ABC ~ DEF (~ means similar to) 12cm 6cm 40o 40o C B FD 16cm 8cm BC 16 EF 8 = 2= = 2=
  • 12.
    E A If two differentsized Right Triangles contain a 90 degree angle, and one matching side, as well as the Hypotentuse are in the same Proportion, then they are Similar by the RHS Rule. ABC ~ DEF (~ means similar to) C B F D 8mm 4mm 10mm 5mm
  • 13.
    Tourmaline Crystal crosssections contain Similar Triangles
  • 14.
    Tourmaline is foundin Mozambique, and is a gem used to make spectacular jewellery such as these colorful cufflinks.
  • 15.
    Similar Triangles canalso be used to great effect in Art and Craft, as seen in this colourful and creative patchwork quilt. Image Source: http://www.patchworkpatterns.co.uk
  • 16.
    Many Similar Trianglesare present in this modern art piece. Image Source: http://www.trianglesoflight.org
  • 17.
    Many Similar Trianglesare present in the structure of the Sydney Harbour Bridge to give it strength and stability. Image Source: Copyright 2012 Passy’s World of Mathematics
  • 18.
    A B C All we needto do is calculate the missing third angle C = R = 180 - (85 + 55) = 180 – 140 = 40o ABC ~ PQR (by AAA Rule) Use either AAA or PPP or PAP or RHS to prove these are Similar Triangles 5m 85o P Q R 15m 85o 55o 55o
  • 19.
    Now we needto check the Ratios of the matching sides C = F = 70o ABC ~ DEF (by PAP or SAS Rule) Use either AAA or PPP or PAP or RHS to prove these are Similar Triangles A B C 8 70o D E F 12 70o 3 4.5 DF 12 AC 8 = 1.5= EF 4.5 BC 3 = 1.5=
  • 20.
    A B C We know thethird angle is 40o so ABC ~ PQR by AAA. Prove these are Similar Triangles and then find the value of “n” 5 85o P Q R 15 85o 55o 55o 10 n = ? PQ 15 AB 5 = 3= This Scale Factor of S.F. = 3 tells us that PQR is three times bigger than ABC. Using the Scale Factor of 3: n = 3 x 10 = 30
  • 21.
    A B C We know thethird angle is 40o so ABC ~ PQR by AAA. Prove these are Similar Triangles and then find the value of “n” 5 85o P Q R 15 85o 55o 55o 10 n = ? PQ PR AB BC = Substitute n 15 10 5 = Cross Multiply n 15 10 5 = 5n = 150 Divide by 5 n = 30
  • 22.
    A B C We know thethird angle is 40o so ABC ~ PQR by AAA. Prove these are Similar Triangles and then find the value of “k” 30 85o P Q R 15 85o 55o 55o 10k = ? PQ PR AB BC = Substitute 15 30 k 10 = Cross Multiply 15 30 k 10 = 30k = 150 Divide by 30 k = 5
  • 23.
    http://passyworldofmathematics.com/ All slides areexclusive Copyright of Passy’s World of Mathematics Visit our site for Free Mathematics PowerPoints