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- 1. You must have observed that in nature, many things follow a certain pattern, such as the petals of sun flower, the holes of a honeybee comb, the grains on a maize cob, the spirals on a pineapple and on a pine cone etc. We now look for some patterns which occur in our daily life. For example: Mohit applied for a job and got selected. He has been offered a job with a starting monthly salary Rs 8000, with an annual increment of Rs 500 in his salary. His salary for the 1st, 2nd,3rd,…years will be, respectively 8000, 8500, 9000,…..
- 2. In the above example, we observe a pattern. We find that the succeeding terms are obtained by adding a fixed number(500).
- 3. Consider the following lists of numbers: 1) 1,2,3,4….. 2) 100,70,40,10… 3) -3,-2,-1, 0…. 4) 3, 3, 3, 3……. 5) -1.0, -1.5, -2.0, -2.5,……. Each of the numbers in the list is called a term.
- 4. Given a term, can you write the next term in each of the lists above? If so, how will you write it? Perhaps by following a pattern or rule. Let us observe and write the rule: In(1), each term is 1 more than the term preceding it. In(2), each term is 30 less than the term preceding it. In(3), each term is obtained by adding 1 to each term preceding it. In(4), all the terms in the list are 3, ie, each term is obtained by adding 0 to the term preceding it. In(5), each term is obtained by adding - 0.5 to the term preceding it.
- 5. In all the lists above, we see that the successive terms are obtained by adding a fixed number to the preceding terms. Such lists are called ARITHMETIC PROGRESSIONS (or) AP. So, An Arithmetic Progression is a list of numbers in which each term is obtained by adding a fixed number preceding term except the first term. This fixed number is called the common difference of the AP. Remember that it can be positive(+), negative(-) or zero(0)
- 6. Let us denote the first term of an Arithmetic Progression by (a1)second term by (a2 ), nth term by (ax ) and the common difference by d . The general form of an Arithmetic Progression is : a , a +d , a + 2d , a + 3d ………………, a + (n-1)d Now, let us consider the situation again in which Mohit applied for a job and been selected. He has been offered a starting monthly salary of Rs8000, with an annual increment of Rs500. what would be his salary for the fifth year?
- 7. The nth term an of the Arithmetic Progression with first term a and common difference d is given by an=a+(n-1) d. an is also called the general term of the AP. If there are m terms in the Arithmetic Progression , then am represents the last term which is sometimes also denoted by l. The sum of the first n terms of an Arithmetic Progression is given by s=n/2[2a+(n-1) d]. We can also write it as s=n/2[a +a+(n-1) d].
- 8. •The first term = a1 =a +0 d = a + (1-1)d Let us consider an A.P. with first term ‘a’ and common difference ‘d’ ,then •The second term = a2 = a + d = a + (2-1)d •The third term = a3 = a + 2d = a + (3-1)d •The fourth term = a4 =a + 3d = a + (4-1)d The nth term = an = a + (n-1)d
- 9. To check that a given term is in A.P. or not. 2, 6, 10, 14…. (i) Here , first term a = 2, find differences in the next terms a2-a1 = 6 – 2 = 4 a3-a2 = 10 –6 = 4 a4-a3 = 14 – 10 = 4 Since the differences are common. Hence the given terms are in A.P.
- 10. Now let’s try a simple problem: Problem :Find 10th term of A.P. 12, 18, 24, 30…… Solution: Given A.P. is 12, 18, 24, 30.. First term is a = 12 Common difference is d = 18- 12 = 6 nth term is an = a + (n-1)d Put n = 10, a10 = 12 + (10-1)6 = 12 + 9 x 6 = 12 + 54 a10 = 66
- 11. Problem 2. Find the sum of 30 terms of given A.P. 12 + 20 + 28 + 36……… Solution : Given A.P. is 12 , 20, 28 , 36 Its first term is a = 12 Common difference is d = 20 – 12 = 8 The sum to n terms of an arithmetic progression Sn = ½ n [ 2a + (n - 1)d ] = ½ x 30 [ 2x 12 + (30-1)x 8] = 15 [ 24 + 29 x8] = 15[24 + 232] = 15 x 246 = 3690

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