,Does planet day period depend on its circumference,

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Does Planet Day Period Depend On Its Circumference?
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt – 13th
November 2020
Abstract
Paper Question
Can The Planet Day Period Be A Function In Its Circumference?
- This Question Is Asked Because Of Saturn
- Saturn moves during its day period 10.7 hours, by its velocity (9.7 km/sec), a
distance = Its Circumference (error only 1.3%)
- So, that pushed us to ask if any other planet behaves as such
- Jupiter moves during its day period 9.9 hours, by its velocity (13.1 km/sec), a
distance = Its Circumference (error 4%) - Although the error isn't so small but the
idea isn't disproved
- Neptune moves during its day period a distance = 2 x Neptune Circumferences
- That creates the question…
- What's the relationship between the planet motion distance during its day period
and its circumference, or in other words, if the planet day period can be defined as
a function of its circumference….
- The paper provides the data analysis and discussion concerning the question
- Noticeable to be written, the observation of Jupiter& Saturn behaviors straightness,
Where only these 2 planets follow perfectly Newton Gravitation Equation, also
their order follows the gravity concept, and their motions during their day periods
equal (almost) their circumferences – that may tell us – the deviation in the other
planets data from the gravity equation causes these planets to move distances
during their days periods different from their circumferences! We need to analyze
that as deep as possible –

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1- Can Planet Day Period Depend On Its Circumference?
1-1 Planets Days Periods Analysis
I-Data
Planet and its day
period
Its Circumference Its Motion distance
during its day period
The rate
Mercury 175.94 days 15334 km 720.7 million km 47000
Venus 116.75 days 38041 km 352.4 million km 9280
Earth moon 29.53 days 10921 km 71.16 million km 6510
The Earth 24 hours 40080 km 2.58 million km 64.3
Mars 24.7 hours 21346.6 km 2.1467 million km 100.5
Jupiter 9.9 hours 449197.5 km 466884 km 4%
Saturn 10.7 hours 378675 km 373644 km 1.3%
Uranus 17.2 160656.5 km 421056 km 2.62
Neptune 16.1 155660 km 312984 km 2
Pluto 153.3 7511.4 km 2.59 million km 345.3
The Table Data Analysis
- Saturn moves during its day period a distance = its circumference (error 1.3%) and
Jupiter does the same but with error (4%)
- Neptune moves a distance during its day period = 2 x Neptune Circumference
- Uranus moves a distance during its day period = 2.62 x Uranus Circumference and
all other planets as defined in the table…
- Let's ask …..
o Is there a relationship between the planet motion during its day period and
its circumference?
o Because
o Saturn and Jupiter give us some hope that we may discover an interesting
relationship here, but the hope is evaporated simply because no other planets
follow this rule which both planets tell us…
o From this table, we can conclude that, Pluto must be belonged once to the
inner planets, because of its data ….
o If we order the planet by their motion distances and Saturn be no. (1),
Jupiter no. (2), Neptune No. (3) Uranus no. (4) then Earth no. (5)… but how
to understand this table data? Let's discuss it in following…..

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II-Discussion
(1st
Point) The Average
- If we gather all the rates between the planets motions distances during their days
periods and their circumferences (the column no. 4), So
o The Total will be = 63290.3
o In this value I account Saturn by (1) and Jupiter by (1),
o They are 10 planets, so the average = (63920.3/10) = 6392
o The Moon Rate = 6510
o The difference between the moon rate and the average rate = 1.8%, So
we can consider that, The Moon Rate Is The Solar System Average
- It shows the Earth moon importance in the solar system and answer old questions
o Why, the moon orbital radius at apogee = all planets diameters total?
o Why, the moon orbital radius at perigee = the outer planets diameters total?
o Because
o The moon expresses the average rate of the planets motions distances during
their days periods and their circumferences
(2nd
Point) The Rates
(1)
- (Mercury Rate / Pluto Rate) = (47000/345.3) =136.1
- (Venus Rate / Pluto Rate) = (9280/345.3) =26.7 (error 0.6%)
- Equation No. A (136.1 /26.7 ) = 5.1 Where
- (moon orbital inclination =5.1 degrees) AND 26.7 degrees = Saturn Axial Tilt
- BUT 26.7 deg +90 deg = 116.7 degrees (Venus day period=116.7 days)
- Equation No. (A) tells that, the interaction in motions between Mercury and Pluto
on one side and Venus and Pluto on the other side creates the moon orbital
inclination
- The moon orbital inclination is created by these interactions processes because, the
moon rate is the average in the solar system, means, the moon motion shows
collective motions in the solar system, and because of that many planets motions
effect on the moon data – simply The Earth Moon Is A Central Planet In The
Solar System

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- Equation No. (B) 5127.4 mkm (Jupiter Pluto Distance) = 940 mkm x 5.37
(Error 1.6%)
o 940 mkm = The Earth Orbital Circumference,
o 5.37 = (Pluto Rate / The Earth Rate)
o Please Remember, Earth Orbital Circumference = Earth Jupiter distance
when both planets be at 2 different sides from the sun (error 1.2%)
o (Equation Total Error 2.8%)
- Equation No. (B) tells that, Pluto is a connection point between 2 planets, Earth
and Jupiter, and this connection is done based on the rate between Earth and Pluto,
please note the great significance of this connection between Earth and Jupiter
which are the 2 Planets their forces effect on The Earth Moon Motion, and this
connection point through Pluto is related to the moon motion definition and
because of that Pluto Rate = 345.3 (which is very near to 346.6 days the nodal
year)
Equation No. (C) 6510 (The Moon Rate)/ 345.3 (Pluto Rate) = 19 (error 0.8%)
- 19 degrees the moon orbit regresses per year and during 19 years this regression
creates the Metonic Cycle
- This equation simply is added to tenths of data which show Pluto effect on the
Earth moon motion – Pluto effect on the Earth moon motion is a doubtless fact
proved by tenths of data.
- The question here is that, how the motions create this interactions through great
distances?!
o The previous data pushes us to reach to 2 conclusions:
o (1st
) The planet moves almost during its day period a distance equal its
circumference exactly as Saturn and Jupiter told us
o (2nd
) The planets violate this rule under some geometrical necessaries and
because of this violation the planets have to create some interaction between
each other to perform the same result through this interaction
o But
o What's this same result? What’s the result Saturn want to do when it moves
a distance during its day = its circumference? What geometrical necessity is
found behind this behavior?!
- Please remember, we do this analysis to discover a 2nd
orbit for the moon motion,
so let's review the moon orbital triangle in following to remember our objective –
till next paper where we may find some answer for this question…

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The moon orbital triangle revision
Let's insert the moon orbital triangle and its data to be our discussion reference
z
Figure No. (1) (my figure)
Please Note
(1) The blue dotted arrow creates a point (Z) between F & S
SZ = 7665 km ZF = 2414 km
CZS = 77.8 degrees CZF =102.195 degrees
(2) The Green arrow creates a point (Y) after the point D
DY = 2513.7 km DYA= 118.92 degrees

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Let's Review The Moon Orbital Triangle Data
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373000 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- BS= (the moon Circumference) =10921 km
- BZ = = 18586 km
- BF = = 21000 km
- BD = DA = 43000 km
- BY = =47513.7 km
- BA = BC = 86000 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF = 88526.8 km
- CD =96150.9 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg)
(ACD = 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.92 deg) (BYC = 61.08 deg)
- (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees) and
- (CYA +0.6 deg = 119.5 deg where 119.5 x 0.99 = 118.3 deg (Neptune A. T)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees

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References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
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