Another Force Effect On The Earth Moon Motion (II)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Another Force Effect On The Earth Moon Motion (II)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo – Egypt – 1st
November 2020
Abstract
Paper Question
- If there's 2nd
force effects on the moon motion, and this force effect is seen clearly
on the Point (A) in the moon orbital triangle without which the moon orbital
triangle geometrical structure can't be created which proves that, this Point (A) is a
pillar in the moon orbital triangle geometry…. Let's ask
- How this (2nd
force) reaches to this point (A) to effect on the moon motion, if this
force has no any other effect in the moon orbital motion can be discovered?
- This 2nd
force is originated vertically, means it’s a vertical effect found on the
moon orbital motion (the moon orbital triangle)
- How to prove that?
- Because the moon has a vertical motion in its revolution around the Earth which is
a motion specific for the moon and no any other planet has such similar motion,
because all solar planets are prevented from the vertical overturning around the sun
but the moon has an option for a vertical motion to some extent but not to overturn
neither around the Earth nor around the sun…
- What proves are available for this claim?
- The moon orbit regression (19 degrees) per year is a proof for the moon vertical
motion in its revolution around the Earth.
i.e.
- I claim that, the moon orbit regression is a result of the moon vertical motion in its
revolution around the Earth. And the moon vertical motion is a result of this 2nd
force effect on the moon orbital motion (whose effect is seen on the Point (A) in
the moon orbital triangle), where this 2nd
force effects vertically on the moon
orbital motion…, this paper tries to prove this claim
References
Another Force Effect On The Earth Moon Motion
https://www.academia.edu/44412677/Another_Force_Effect_On_The_Earth_Moon_Motion
or
https://www.slideshare.net/Gergesfrancis/another-force-effect-on-the-earth-moon-motion

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1- The Moon Vertical Motion
1-1 The Moon Vertical Motion Definition 1-3 The Vertical Motion Origin
1-2 The Moon Vertical Motion Proves
1-1 The Moon Vertical Motion Definition
- What does that mean "A vertical motion of the moon in its revolution around
the Earth"?
- What means " A Vertical Motion"? how to discover that??
- Let's suppose the moon moves some vertical motion, what we will see in this case?
How to know that, the moon move a vertical motion??
- Because in this case, the moon doesn't do its usual displacement through its orbit,
because the moon moves in a vertical motion, it doesn't consume a displacement,
means, the moon will be stay in its position in its orbit…!
- Did we have see that before? Yes many times,
- When the moon reaches to the top points in perigee or apogee points, the moon
stay in this points long time without clear explanation – let's uses some data to
explain this idea
o During 28th
, 29th
and 30th
January 2020, the moon stayed between the
heights (404425 km, 405333km, 405111 km)
o During 26th
, 27th
and 28th
February 2020, the moon stayed between the
heights (406278 km, 405788km, 404278 km)
o During 10th
& 11th
March 2020, the moon stayed in perigee radius between
the depths (357235 km, 357602 km)
- Many other examples we have seen in the tests of (Gerges Equation for the moon
orbital motion)
- It's a strange feature, because we have seen that, the moon moved in one day from
a height point to another passing (4000 km) (for example moves from 404000 km
to 400000 km on one day only) but suddenly we have seen that, the moon stopped
at perigee radius top point or apogee radius to point and stayed in this point for
long days without clear reason –
- This behavior was so strange because we know that, the moon moves daily by the
angle (0.98562 degrees) which causes the moon to move from point to another,
and this angle is provided for the moon motion every day, so how the moon stops
such suddenly in its point without its usual displacement or sometimes without any
displacement?! How that can be possible?
- Because the moon moves (during this period) in its vertical motion, and this
motion consumes the daily angle (0.98562 degrees) but not in the usual horizontal
motion, instead, in a vertical motion…
- Can we describe this moon vertical motion? let's draw it in following

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The Moon Vertical Description
- The blue ball is the moon, the red arrow refers to the moon descending motion
direction from apogee (r=0.406 mkm) to perigee (r=0.363 mkm), the blue arrows
refers to the moon ascending motion direction from perigee (r=0.363 mkm) to
apogee (r= 0.406 mkm)
- The green arrows shows the displacement,
Let's discuss this figure in following:
- The moon basic motion is seen in 2 arrows (red and blue), showing that, it’s a
vertical motion done by the moon from perigee to apogee and vice versa
- In this vertical motion the moon consumes its daily angle of motion (0.985 deg)
- The green arrow shows a very small displacement can be done by the moon during
this vertical motion –
- This figure explains easily the moon data at perigee and apogee top points
- For example this data
o During 28th
, 29th
and 30th
January 2020, the moon stayed between the
heights (404425 km, 405333km, 405111 km)
o During 26th
, 27th
and 28th
February 2020, the moon stayed between the
heights (406278 km, 405788km, 404278 km)
o During 10th
& 11th
March 2020, the moon stayed in perigee radius between
the depths (357235 km, 357602 km)
- Many other similar data are found, because this is a feature of the moon motion. to
prove this claim we have to prove that, the moon uses (really) its daily motion
angle (0.985 degrees) in this vertical motion, it's very important proof for this
claim which we should consider in the proves discussion
Note Please
- As result of the moon motion analysis, I may claim, the moon motion is some
complex motion, I mean, a motion is consisted of many other motions, so, this
figure which explains the moon vertical motion can't explain the moon real
motion, but it explains one feature of the moon real motion… that means… we
have to find a similar to this figure in the moon real motion but not alone as I draw

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it here, but we will find this figure interacted with many other forms of motions
and these motions together will produce one general curve of the moon motion of
which this figure explains one feature….
- So, the displacement which is seen in the green arrows are done, but not obligatory
to be on apogee radius as I draw, but can be done on perigee radius also… but
please note, there's a moon motion cycle is done based on the displacement which
is done on the apogee radius (specifically) we should discuss that in this paper,
now the question will be (The displacement which is done in perigee radius can be
used as similar to the displacement done on apogee radius for this specific cycle?)
where both are done by vertical motion?? ….many other questions we should
discuss in this paper

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The Idea Summary
- Let's here summarize the main idea which we try to prove…
The Moon Orbital Triangle
- We have discussed this triangle before deeply
- The 2nd
force effects on the point (A) as we see,
- The point (A) is a proof that, there's 2nd
force effects on the moon motion, because
this point (A) is far from apogee point with 43000 km out of the moon orbit,
where Earth effect on the moon is limited to the apogee point… and as we see the
moon orbital triangle depends on this point (A) to be created, and without this
point (A) the orbital triangle can't be found – i.e. surely there's 2nd
force effects on
the moon motion and this 2nd
force effect is seen on the point (A).
- The question is, how this 2nd
force can reach to this point (A)? by what trajectory?
Because we don't see any effect of it except this point (A), so the question is, by
what trajectory this force moves to reach to the point (A)??
- My answer is that, this force is An Vertical Effect
i.e.
- This moon orbital triangle is seen (horizontally) because the moon motion
revolving around the Earth is a horizontal motion, and we don't consider that the
moon moves vertically (as all other planets move horizontally revolving around
the sun), because of that, this triangle can't show the vertical effect because it's
drawn by a horizontal point of view…
- The vertical effect on the point (A) which caused by the 2nd
force is perpendicular
on the page.
- And the moon moves 2 motions (one horizontal which is the triangle plain) and
(one vertical which is perpendicular on the triangle plain), 2 different motions are
done by the moon in its revolution around the Earth.
- The moon vertical motion causes the moon orbit to be regressed 19 degrees yearly
- Let's discuss this claim proves in following

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1-2 The Moon Vertical Motion Proves
I-Data
(1)
1270 degrees = 1290 days x 0.98562 degrees
(2)
1270 days = 346.6 days x 3.66
(3)
2644 mkm = 1270 days x 2.082 mkm (Mars velocity daily) ,
also
1437.4 mkm = 1270 days x 1.1318 mkm (Jupiter velocity daily)
(4)
1290 degrees = 1.79 deg x 720.7 = 687 days x 1.87 degrees (1.87 deg =1.3 x 1.44)
(5)
1290 degrees = 13.18deg x 97.8 deg = 1.44 deg x 895
(6)
5.1 degrees =1.44 degrees +3.66 degrees
(but 1.44 = 1.8 deg x 0.8 deg) and (5.1 deg = 3.66 x 1.932)
Old Equations
(O1)
(6939.75 days /27.3 days) = (1290 degrees /5.075 degrees)
(O2)
1290 days = 354.39 x3.66 = 27.3 x 2x 23.6

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II-Discussion
Equation No. (1)
Equation (O1)
(6939.75 days /27.3 days) = (1290 degrees /5.075 degrees)
- We remember this equation discussion, it told us that, the angle 1290 degrees is
relative to the moon orbital inclination (5.1 deg) by the same rate as Metonic Cycle
Period (6939.75 days) is relative to the moon sidereal motion (27.3 days), that told
us the value 1290 degrees is related to Metonic Cycle, where I claim that, Metonic
Cycle is a cycle found by the moon vertical motion – that's why we discus it here
- Because the moon orbit regress per year 19 degrees which causes change in the
eclipse calendar for 19 days, so 1 degree = 1 day for the moon orbit
Equation No. (1) (continued)
- The question was, when the moon moves a vertical motion, does the moon uses its
daily angle (0.98562 degrees) for this vertical motion, because it doesn't use for the
usual displacement through its orbit?
- Equation No. (1) tells that, during 1290 days the total degrees are 1270 degrees, if
the moon uses its daily angle value in its vertical motion, the next question is (dos
the moon use this result 1270 degrees in any process?)
Equation No. (2)
1270 days = 346.6 days (the nodal year) x 3.66 (= Earth diameter/ moon diameter)
- The rate 3.66 controls almost all data between the Earth and moon, for example
(365.25 days = 27.3 days x (3.66)2
),
- Also, (the sun diameter /the moon orbital radius at total solar eclipse) =3.66
- Jupiter Circumference = Saturn diameter x 3.66
- Shortly the rate 3.66 shows the geometrical mechanism of effect between Earth
and the moon structure data,
- Equation No (2) tells that, The Modal year is created as a function of this value
1270 days by the rate (3.66), but this is a rate between Earth diameter and the
moon diameter which can't be changed, that means, the nodal year depends on this
value (continuously)
i.e.
- The Nodal Year Is Created Because Of Metonic Cycle Motion

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Equation No. (3)
2644 mkm = 1270 days x 2.082 mkm (Mars velocity daily) ,
- Mars during 1270 days moves a distance accurately = Mars Uranus Distance, why
this is specific information? Because
1. Mars Motion is interacted with the moon motion, and that tells us, Mars
motion defines its periods based on the moon motion periods, that means,
this period 1270 days is defined by the moon motion but used by Mars
Motion to create its distance to Uranus
2. This explanation is supported by many old data (687 days =27.3 days x
25.2, where Mars axial tilt =25.2 degrees). Also (13.18 deg moon motion
daily /0.526 deg Mars motion daily =25.2), the interaction between Mars
and the moon motions effected greatly on Mars motion.
Let's see the equation second part,
also
1433.5 mkm = 1270 days x 1.1318 mkm (Jupiter velocity daily)
- It's similar equation, Saturn orbital distance is defined by Jupiter motion during
this same period 1270 days, how this equation is created??
- We accepted that, the three inner planets (Mercury, Venus and Mars) unify their
motions in one force to effect by it on the moon motion (on the Point A in the
moon orbital triangle) where this effect shows the 2nd
force effects on the moon
orbital motion, but because Jupiter is the inner planets parent and their source of
energy they do this effect through Jupiter, and because of that a very deep
relationship is found between Jupiter and the Earth moon as we have discussed
before frequently in all data of Jupiter and of the moon – almost both data is crated
to be suitable for one another
- This deep relationship between the moon and Jupiter effects greatly on Saturn
which is created by Jupiter effect, where Saturn is created after the moon creation,
and because of that many of the moon and mars data is used by Saturn…
- The equation tells that, Saturn orbital distance is defined before its creation by
Jupiter velocity and the moon metonic cycle period (1290 days or 1270 degrees)

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Equation No. (4)
(Part I)
1290 degrees = 1.79 deg x 720.7
(Part II)
1290 degrees = 687 days x 1.87 degrees (1.87 deg =1.3 x 1.44)
Let's discuss (Part I)
- 1.8 degrees = Neptune orbital inclination, and 720.7 mkm = Mercury Jupiter
distance,
- We know that 1 mkm = 1 degree
- Equation no. (4) (Part I) tells that, the Metonic Cycle degrees (1290 deg) depends
on 2 factors (Neptune orbital inclination) and (Mercury Jupiter Distance)…
- Why??
- 1.44 deg=1.8 deg (Neptune orbital inclination)x0.8 deg (Uranus orbital inclination)
- 1.44 degrees = the moon orbit regression per a month, this equation told us, the
moon orbital regression depends on Neptune and Uranus orbital inclinations
- Neptune inclination is the 1st
factor in Equation No. (4), but why use 720.7mkm?
because Jupiter is the inner planets energy source- let's remember that
o One light beam with supposed velocity (1.16 mkm/sec) travels during
4222.6 seconds a distance =4900 mkm = Jupiter orbital circumference, but
this distance is seen by us as 720 mkm x 2π, why?? because of Lorentz
length contraction phenomenon with rate (1.0725) –
o i.e. 720.7 mkm expresses the whole energy sent from Jupiter to the inner
planets,
- Equation No. (4) tells that 1290 degrees (Metonic Cycle degrees) express the
whole energy of the inner planets
Let's discuss (Part II)
1290 degrees = 687 days (Mars orbital period) x 1.87 degrees (1.87 deg =1.3 x 1.44)
(19. degrees = Mars orbital inclination error 1.4% with the value 1.87)
- this equation part tells again Mars performs (1290 degrees) by its own data (its
orbital period and its orbital inclination), Mars is almost a partner in Metonic Cycle
with the moon motion,

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Equation No. (5)
1290 degrees = 13.18deg x 97.8 deg
13.18 degrees = the moon daily motion degrees
97.8 degrees = Uranus Axial Tilt
- This is our basic equation in this discussion
- Metonic Cycle is a cycle found by a light motion, travels from Jupiter to Uranus
(2088 mkm) by light known velocity (0.3 mkm) consuming 6939.75 seconds, and
because light motion for 1 second causes Planet motion for 1 solar day, because of
that, this period 6939.75 seconds is transferred to the moon with the value 6939.75
days
- Metonic Cycle degrees (1290 degrees) is defined based on 2 values, the moon
daily motion degrees (13.18 deg) and Uranus axial tilt (97.8 degrees)
- 97.8 mkm x 71 = 6939.75 mkm, that means , the value 97.8 mkm (degrees) is
created by a contraction done for the value 6939.75 mkm
- How to explain this equation?
- The inner planets use Jupiter to practice the unified effect they try to practice on
the moon motion, but Jupiter sent this request to Uranus as energy in a light beam
form, this light beam (consumes the period 6939.75 seconds creating Metonic
Cycle) then Uranus through Metonic Cycle practices this effect which the three
planets tray to practice on the moon motion
- That explains, why the 2nd
force effects on the moon motion is perpendicular on its
orbit plain, because….
o Uranus axial tilt is perpendicular on the moon axial tilt (97.8 dh -6.7 deg
=91.1 degrees) (the 1.1 degrees is consumed in the moon angular diameter)
o Uranus axial tilt is perpendicular on Mercury orbital inclination, where 97.8
degrees (Uranus axial tilt) = 90 deg + 7 deg (Mercury orbital inclination)
+0.8 deg (Uranus orbital inclination)
o Uranus is on straight line with Venus because, 180.8 degrees = 177.4 deg
(Venus axial tilt) +3.4 deg (Venus orbital inclination),
o But what is Uranus relationship with this value 180.8 degrees? It's Uranus
orbital inclination where 0.8 deg +90 deg +90 deg = 180.8 degrees
i.e.
o Venus axial tilt and orbital inclination, and also Mercury orbital inclination
and the Earth moon axial tilt all these data are created based on Uranus
Axial Tilt…
o The previous investigation explains that Uranus effect is a vertical effect on
the inner planets, which tells us why the motion is vertical motion…

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More Data
- 12.19 degrees (= 13.18 degrees -0.985 degrees)
But
- 12.19 degrees +90 = 102.19 degrees
And
Equation No. (I)
- 102.19 degrees x 0.8 degrees (Uranus orbital inclination) = 82 =41 degrees x 2
- 41 degrees = The Planets Orbital Inclination Total
And
- 2 x 1433.5 = 2872.5 mkm (Uranus orbital distance), because it = double Saturn
orbital distance, but Saturn orbital distance (1433.5 mkm) = the real motion
distance done by all planets per solar day (Because 1433.5 mkm = 17.75 mkm x
511/2π),
i.e.
- Uranus orbital distance (2872.5 mkm) needs the solar system to move for 2 days
- Equation No. (I) tells that, the moon motion is created by a collective effect made
by all planets, it's a general motion found in the solar system by done by the moon,
that tells us, Metonic Cycle is so specific Cycle in the solar system because it's
produced by a vertical motion and also by a collective effect of all planets together
Please Note
- Uranus effect on all solar planets to prevent them to move any overturning motion
around the sun, and that means, Uranus prevented any planet to move a vertical
motion
- And because of that, no other planet can give the moon this chance to move its
vertical motion, it's an option made by Uranus only and can't be provided by any
other planet.
- That explains why Jupiter sent this light beam (0.3 mkm/sec during 6939.75
second) to Uranus, by which the 3 inner planets try to practice their unified effect
on the moon motion, because the vertical motion can provide only by Uranus..
- As we have discussed before, Jupiter prevents Uranus effect on the horizontal level
but Uranus can effect vertically, and because Earth gravity force effects on the
moon horizontally and strongly, that prevented Jupiter to provide any help to the
moon at the horizontal level, that's why Jupiter sent the light beam to Uranus to be
a call of help from Uranus to support the moon motion

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References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

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