Does The Moon Orbit Regression Prove The Earth Displacement?

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Does The Moon Orbit Regression Prove The Earth Displacement?
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo – Egypt –4th
November 2020
Abstract
Paper hypothesis
The Moon Orbit Regression 19 Degrees Yearly Depends On Earth Displacement
1 Km Per Solar Day
The Hypothesis Explanation
- The Earth Moon distances aren't changed and the moon orbit regresses 19 degrees
per year…
- Based on this data … we may conclude the following:
- Earth moves a specific motion as a result of the moon orbit regression (or the
moon orbit regression is done based on this Earth specific motion)
- The moon orbit regression is a translation motion and can't be considered as a
cyclic motion that because it doesn't return to its start point, on the contrary, it's a
translation motion moves from point to another new point and doesn't return back
- The Earth day displacement must be a translation motion and not a cyclic one
because it's a result or reason for the moon orbit regression, which is a translation
motion also…
- The moon orbit regression causes Metonic Cycle, but Metonic Cycle is a cyclic
motion repeats its trajectory once each 19 sidereal years, and this cycle depends on
the moon orbit regression which is a translation motion and that means, Metonic
Cycle is a cyclic motion but must contains a translation motion because it depends
on a translation motion (The Moon Orbit Regression)
[
Paper Objective
- The paper tries to analyze the moon orbit regression and to prove the Earth daily
displacement as a result or reason for the moon orbit regression..

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1- Introduction
- How does the Moon orbit regress 19 Degrees Per Year? let's consider this
question deeply as possible
Let's imagine
- The moon moves its orbital motion revolving around Earth, and we follow the
moon motion and by Chalk we make marks for the moon orbital motion around
Earth… then the moon completed its orbital motion around Earth
- So we want to make the moon orbit to regress 19 degrees on the horizontal level,
and then to start again the moon orbital motion revolving around The Earth…
- I have tried to draw this event in these 2 figures
- The right circle has no regression of the moon orbit around Earth, but the left circle
has an angle 19 degrees with the horizontal level ….
- The question is ripe now ….
- Suppose Earth doesn’t revolve around the sun, and Earth is a fixed point in the
space….
- After the moon orbit regresses with 19 degrees per year, can Earth still be in its
same point in space, and the distances between the Earth and Moon be equal their
values before the moon orbit regression??
- I suppose that, if Earth doesn't move from its point in Space, the distances can't be
equal because of the orbit regression ….. but if the distances are still equal that
means the Earth must have some motion as a result of the moon orbit regression
- What we try to do here?
- I try to prove that, Earth must have a specific motion done because of the moon
orbit regression otherwise the Earth moon distances must be changed
- The moon orbit regression tells us that, Earth does some displacement because of
the moon regression, and if we can discover and prove this Earth displacement we
will have a real progress in our understanding of the Earth and Moon motion
interactions…
- This paper analyzes the moon orbit regression to prove The Earth displacement as
a result of (or reason for) the Moon Orbit Regression.
E
E

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2 – The Moon Orbit Regression Analysis
2-1 How can the Earth save its position in the space
2-2 The Moon Orbit Regression Analysis
2-3 The Earth Daily Displacement (The proves discussion)
2-1 How Can The Earth Save Its Position In The Space?
As shown in the figure
- The red circle has zero degree on the horizontal line
- The black circle has 19 degrees on the circle line (The angle θ = 19 degrees)
- As we expected, the circles centers aren't the same one point …
i.e.
- The circles can't have the same one center ….
- Based on that,
- Earth position in the space must be changed with the moon regression 19 degrees
per year
- Otherwise the Earth moon distances must be changed…
- The moon orbit regression is a treasure because it tells us that, the Earth changes
its position in the space because of the moon orbit regression
But
- Because The Earth revolves around the sun and rotates around its axis, this motion
which the Earth does because of the moon orbit regression is hidden behind the
Earth different motions –
- Again I need to confirm on the previous conclusion which is
- The planet motion is consisted of many different motions, but we don't see these
different motions distinguished from each other, on the contrary, we see all these
motions in one complex motion done by a planet – so to consider the planet
motion is some simple motion found by one force in one direction, such
consideration makes the planet motion analysis is a simple useless process because
the planet motion is a very complex one and created by interaction between many
different motions which are done for different jobs defined to be done by this
planet, because of that the planet motion needs a deep analysis as possible

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- Now another question is ripe to be asked… let's provide it here
- The previous geometrical explanation tells us that, the moon orbit regression must
cause some motion or displacement for Earth as a result, otherwise the distances
between The Earth and Moon will be changed…. The question is
- What’s this displacement, the Earth does for the moon orbit regression?
And how to prove this displacement?
- My answer is the following
- Earth moves 1 km per solar day vertically on its position, it's Earth daily
displacement.
- That means,
- Earth orbital distance is decreased through the history
- Specifically, Earth during 8211 years moved 3 million km from its original
position in the space, this displacement is a vertical displacement, and that means,
Earth orbital distance was 153 million km since 8211 years, and during this period
each solar day the Earth moves 1 km vertically toward the sun
- How do I know that?
- It's a hypothesis, I have built based on the 2737 years phenomenon which we have
discussed frequently before… where the cycle 2737 years is repeated almost 3
times through the history (total period 8211 km) and the Earth Aphelion =152.1
mkm, which tells that, Earth orbital distance was almost 153 mkm – that makes 3
millions solar days were needed for a distance = 3 millions km, i.e. 1 km = 1 day
- We need strongly this conclusion (1 km =1 day), because this conclusion will
create some consistency for the planets data analysis with our understanding for
the solar system motion - I want to say that (1 km) is Not a measurement made by
human, but a unit of the universe measurement, as all time units (day, hour, minute
or second) these units are NOT created by human, it's NOT True, because there's
astronomical motion for each period as (365.25 days, 27.3 days…etc) these
periods are defined by astronomical motions, and similar to that the time units and
the unit 1 km,
- Why this conclusion is correct? Why does creature sleep when the sun is absent? I
want to say that, the solar system motions effect on our daily life, and if our tools
are in conflict with the solar system measurements that will create unusual
difficulties for the human ordinary life and because of that the units which are used
so frequently almost defined by the solar system motions because they are in
consistency with its motion …
- Now let's return to our question …. How to prove this displacement of The Earth?!
But before to answer this question let's try to analyze more deeply the moon orbit
regression in following ….

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2-2 The Moon Orbit Regression Analysis
The Moon Orbit Regression Features:
- The moon orbit regression is a translation motion, it's NOT a cycle, and NOT a
motion done in 2 directions or in a circle, it's a translation motion, because the
moon orbit regresses always and doesn't precede… It's one direction motion
(regression) i.e. it can't be considered as a cycle it's a translation motion as a train
moves from a city to another city and not return back to the first one…
- This feature still causes more puzzles… because….
- The moon Cycle Metonic (6939.75 days) depends on the moon orbit regression
and in the moon cycle Metonic, the moon doesn't pass by the same point 2 times
during 19 years … BUT the moon will pass this same trajectory again after 19
years….. Because of that it's a cycle and we know it as Metonic Cycle… That's
NOT done for the moon orbit regression, on the contrary, the moon orbit
regression is done in one direction and never reverses its direction, It simply
regresses always …..
- So we have 2 different kind of motions depend on each other ….! One translation
motion and one cycle motion…!
- This situation is similar to a ruler motion depends on motor motion – or – vice
versa – a motor motion depends on a ruler motion but the ruler moves in one
direction and doesn't return back, how to create such motions??
- Note please, if Earth does a displacement 1 km vertically per a solar day, that will
create another translation motion because Earth doesn't return back but does this
motion in one direction – because of that – Earth displacement (If real) can be a
suitable result for the moon orbit regression
Question No. 1
- How to create these motions depending on one another?! We have the moon orbit
regression (19 degrees per year) and Earth daily displacement (365.25 km per
year) and Metonic Cycle (19 sidereal years)… how these 3 motions can be done
based on each other??
Question No. 2
- How to find these 3 motions in the moon orbital triangle? We have simply 3
values (19 degrees), (1 km) and (6939.75 days) how to find these values in the
moon orbital triangle?
Question No. 3
- What force causes the moon orbit regression? Is this force vertical or horizontal
force?

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Some Values are found in the moon orbital triangle
I-Data
I have added the line (CS) for more better analysis
Let's start our analysis
- EB = Perigee radius = 363000 km
- ES = total solar eclipse radius = EC = 373000 km
- ED = Apogee radius = 406000 km (405500 km)
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- EC = (Saturn circumference) = 373000 km
- SB= (the moon Circumference) =10921 km
- CS = = 86693 km
- CF= (the moon daily displacement) =88000 km
- CD = = 95930 km
- CB= AB = 86000 km
THE ANGLES
- BCS = 7.25 degrees Angle E = 13.33 degrees
- BCF = 12.195 degrees ECB =76.7 degrees
- BCD= 26.3 degrees
- BCA = 45 degrees Angle C =121.7 degrees
- CSB = 82.75 degrees CSF = 97.25 degrees
- CFB = 77.8 degrees CFD = 102.195 degrees
- CDF= 63.7 degrees CDA= 116.3 degrees
- ECD= 103 degrees DCF = 19 degrees
The Required Data
Angle C =121.7 degrees
DCF = 19 degrees
BCF = 12.195 degrees

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The Discussion
Equation No. (1)
6939.75 days (Metonic Cycle Period) = (180 /π) x 121.12 degrees
(The difference between 121.12 degrees and Angle C = 0.55 degrees)
Let's remember this old equation
An Old Equation No. (A)
6585.36 days (Saros Cycle Period) = (180 /π) x 115 degrees
(Saros shift =115 degrees)
- We know that Saros and Metonic are complementary cycles…
- The equations show that, they use the same methods to define their values, and
because of that, I consider the angle (C=121.6 degrees) as the basic angle of
Metonic Cycle, because it's equivalent to the value 115 (Saros shift angle)
- I want to say that, Metonic Cycle period is representative in the moon orbital
triangle clearly in the angle (C ), because it uses the same method used by Saros
shift angle to define the Cycle period days
- Please Note, because the moon orbit regresses 19 degrees per year and that causes
change in the eclipse calendar = 19 days, so we conclude that 1 day = 1 degree, i.e.
These degrees in the previous equation express also the same number of days…
- The previous explanation tells us clearly that we have found Metonic Cycle period
(6939.75 days) in the moon orbital triangle…
- Please Note, our angle is (121.67 degrees) and the Equation angle is (121.123
degrees) and that means there's a difference = 0.55 degrees (this difference isn't an
error…it's the puzzle which we can’t solve yet… let's remember it….
o Uranus Axial Tilt Is Perpendicular On The Moon Axial Tilt Where (97.8
degrees – 6.7 degrees = 91.1 degrees)
o The moon angular diameter is equivalent to = 0.5 degree
o So the rest is (91.1 degrees – 0.5 degree) = 90.6 degrees
o If the perpendicular line BC expresses the perpendicular line from Uranus
axial tilt on the moon axial tilt, so the perpendicular angle will be changed
from 90 degrees to 90.6 degrees and by that the C angle 121.67 degrees will
be 121.123 degrees, means our triangle value will be = the equation value
o But we can't do that, because all other angles and dimensions will be
changed by this change and make error reach to 1% and that causes fear for
me to do this change in the triangle, although I believe perfectly that, Uranus
effect on the moon perigee radius but this conclusion still needs more
analysis.

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Equation No. (2)
(121.67 degrees /19 degrees) = 6.4 = (153.6 hours /24 hours)
Pluto day period =153.3 hours
- Equation no. (2) tells that, the 2 angles (121.6 and 19 degrees) have a rate = the
rate between Pluto and Earth day periods! Why this is useful data??
- Pluto surely effect on or effected by the Earth moon motion! for that reason Pluto
move per solar day a distance = 406000 km = Apogee Radius …. Also
- (1/Pluto velocity per solar day) = The Earth Moon Velocity Per Solar Day
- Equation no (2) tells us that, some complex relationship is found here- something
unexpected is done in the moon orbital motion related to Pluto motion, but
why? and how?! This equation provides so limited data and we need more deep
analysis to see what's happening behind…
Please Note
1. Angle (E) =13.33 degrees = (13.18 deg the moon motion degrees daily) / 0.985626
degrees ( the moon original motion degrees daily)- so this angle expresses the
moon motion angles daily in complex form
2. Earth orbital period (365.25 days) = the moon orbital period (27.3 days) x 13.33,

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2-3 The Earth Daily Displacement (The proves discussion)
(1st
Point) how to know that Earth displacement daily =1 km vertically?
- Let's suppose that, the planets positions are defined based on some series of
numbers ….
By this series …
- Mercury Position Number will be 11 so its distance will be 55 million km
(1+2+3+4+5+6+7+8+9+10+11 = 55 million km) (-2.9 mkm)
- Venus Position Number will be 15 so its distance will be 105 million km
(1+2+3+4+5+6+7+8+9+10+11+12+13+14+15 = 105 million km) (-3.2 mkm)
- Earth Position Number will be 17 so its distance will be 153 million km
(1+2+3+4+5+6+7+…..+15 +16+17 = 153 million km) (3.6 mkm)
- Mars Position Number will be 21 so its distance will be 231 million km
(1+2+3+4+5+6+7+…….19+20+ 21 = 231 million km) (3.1 mkm)
- Jupiter Position Number will be 39 so its distance will be 780 million km
(1+2+3+4+5+6+7+8…….37+38+39 = 780 million km) (1.4 mkm)
- Saturn Position Number will be 53 so its distance will be 1431 million km
(1+2+3+4+5+6+…….51+52+53 = 1431 million km) (-2.5 mkm)
- Uranus Position Number will be 75 so its distance will be 2850 million km
(1+2+3+4+5+6+7+8+…….73+74+75 = 2850 million km) (-22.5 mkm)
- Neptune Position Number will be 94 so its distance will be 4465 million km
(1+2+3+4+5+6+7+…….92+93+94 = 4465 million km) (-30.1 mkm)
- Pluto Position Number will be 108 so its distance will be 4465 million km
(1+2+3+4+5+6…….106+107+108 = 5886 million km) (-20 mkm)
How can this hypothesis be truth?
- Venus and Mercury moves far from the sun a distance 3 million
- Earth and Mars moves near to the sun 3 million km
- Jupiter near to the sun 1.4 million km
- The rest planets move far from the sun…..
A Comment
- The 4 inner planets move an equal distance (3 million km), although Mercury and
Venus move to be far But Earth & Mars move to be near to the sun, I suppose that
the equal distance shows a real displacement
- Also, the cycles of 2737 year passed by Earth (3 million days) and (3 mkm) means
1 km per solar day…. Which supporting the number (3 mkm) of Earth motion.

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Please Note
- The previous series gives us some light about what's happened during the solar
system history…..
- Also…. This series of numbers tells us that , Mars Migration is done based on
some geometrical structure, i.e. Mars migration was not a random motion done by
no geometrical calculations, on the contrary, this motion is done based on series of
numbers (geometrical development), that means, the solar system is creates based
on geometrical calculations and these calculations provide a capacity for different
motions to be done in the solar system, so Mars migration was one option provided
by the solar system geometrical structure defined with the solar system creation…
As a factory sold a car and created an agency for maintenance, so when the car
has defect the driver will drive it to this agency and not to any other place…
Noticeable ….
- Jupiter moves toward the sun (1.4 mkm, very near to its orbital inclination 1.3 deg)
- Saturn moves Far from the sun (2.5 mkm, equal orbital inclination 2.5 deg)

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(2nd
Point) Earth Displacement Description
- How this Earth Translation can be descried, let's try to do that in following….
- The figure may help our investigation to define how The
Earth makes its daily displacement…
- Let's remember our old model …
- Because Earth Mass = the 4 inner planets masses total
(error 1%)…
- By The double production experiment, 2 equal masses
particles (electron and positron) can be produced by
Gamma ray (1.2 Mev)
- I suppose that, the 5 inner planets are created by some
great Gamma Ray (or any suitable electromagnetic ray),
where Earth is the great electron and the 4 inner planets
are the great positron…
- The great Electron means (Earth atom nucleus has a
positive charge and negative charge moves around)
- The great positron means (the 4 inner planets atom nucleus has a negative charge
and positive charge moves around)
- The 5 inner planets attract each other by electric charges, and because of that, the
difference in their masses (1%) is used as energy to save the 5 inner planets in their
orbits around the sun (based on this hypothesis no sun gravity is required to cause
the 5 inner planets motions)
- Based on this description, the figure tells us, how Earth does its displacement..
Let's explain that …..
o When the moon be in the full moon phase, the Earth be between Venus and
the moon, Venus and the moon charges are (positive) and Earth charge is
(negative), so some electric field is created between Earth and Venus causes
Venus to attract Earth… and
o Earth attracts the moon by the electric charges attraction
Now let's suppose that
o Venus is found on a higher point vertically than Earth…means, Each planet
is found on stair or step, i.e. the planets are found on stairs horizontally
relative to each other .. so Venus is higher than Earth and Earth is higher
than Mars and Mars is higher than Jupiter …. (Stairs or Steps)
o i.e. Venus is above Earth and attracts it to a higher point (vertically), Earth
does this same effect on the moon when it be in the full moon phase …. By
that a vertical motion can be done for Earth and its moon

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o Note Please, Venus attracts the Earth and moon to higher point, but the
moon moves around Earth in its orbit by Earth gravity on it, i.e. Venus
vertical effect causes the moon orbit to be declined and created orbital
inclination =5.1 degrees, I want to say that, the planet orbital inclination is a
proof for some vertical motion effect on this planet motion orbit….
What useful results we get from this description?
- The description shows that, vertical motions can be done by Earth and its moon
(when the moon be in full moon phase)
- When the moon be in the waning phase, the moon will be between Venus and
Earth and because its positive charge is similar to Venus positive charge that
causes a repulsion between them but still the attraction is found between the moon
and Earth and by that, the moon will force to move toward Earth which causes the
moon to move a descending motion….
- That shows the moon vertical motion, because we know that the moon moves
vertically to apogee and then return back to perigee to consume (43000 km +43000
km) =86000 km of its daily displacement =88000 km, this process means the
moon motion should be to apogee and to perigee – it's a cycle motion and not
translation one – on the contrary – Earth daily displacement is a translation motion
done in one direction and not return back
- But the moon orbit regression is a translation motion and can't be considered as
cycle that because the orbit doesn't precede but always regresses
- What's conclusion we can get here??
- The Moon Orbit Regression Must Be Done Based On The Earth Displacement
Because They Are Similar Motions… Where the moon motion vertically is done
as side effect for the Earth displacement
- But … Note please…. The moon in its vertical motion moves daily to a new point
of space because of the Earth daily displacement (1 km)
- The next question is, how can Earth daily displacement produce the moon orbit
regression?!
- Before to answer, we need to prove that Earth daily displacement is real one and
produced by Venus effect on Earth motion!

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(3rd
Point) Why does Earth motion distance define the moon orbital radiuses?
(Earth Motion On The Moon Orbit Structure)
Let's consider this question in following
- The moon orbital circumference at apogee radius (r=0.406 mkm) = Earth motion
distance per a solar day =2.58 mkm, (error 1%)
- If we try to use Venus daily distance (3.02 mkm) in place of Earth we will each to
that the moon apogee will be (r= 0.48 mkm), which is so far from Earth
- If we try to use Mars daily distance (2.082 mkm) in place of Earth we will each to
that the moon perigee will be (r= 0.32 mkm), which is so near to Earth where the
moon perigee radius (r= 0.363 mkm)
- That means, the moon orbital circumference (at apogee) = Earth motion distance
per day, this equality can't be created by any pure coincidence… because it's a
selective data… the planet motion which is equivalent to the moon orbit radiuses
Let's ask
- Why the moon orbital radiuses (perigee and apogee) are defined based on the
Earth motion distance daily?! How to explain that??
- We have 2 values (perigee –apogee distance =43000 km) and the Earth daily
motion distance =2.58 mkm let's use them in the following right triangle…
- Ab = 86000 km = 43000 km
- Ac = 2.58 mkm = Earth motion distance daily
- The angle (c) = 0.9573 degrees
Equation No. (3)
- During 365.25 days, 0.9573 deg x 365.25 days = 349.68 degrees
- 360 deg. – 349.68 deg. = 2 x 5.15 deg. (5.1 deg = The Moon Orbital Inclination)
- How to understand this data?? The moon orbital inclination is crated as a function
based on these 2 distances (43000 km and 2.85 mkm)
- Why the equation uses number (2) because the moon orbital triangle is built on
the distance 86000 km and not 43000 km, so if the moon doesn't move beyond
apogee point, it has no effect on the fact that the point (A) is the main pillar on
which the moon orbital triangle is built and will be including in any data express
this moon orbital triangle (and motion) (please review the moon orbital triangle)
- If we use the double value (0.9573 x 2) it will be = 1.91 deg (Note Please 1.9
degrees = Mars orbital inclination) And

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- 25.2 deg (Mars Axial Tilt) = 1.9 deg x 13.18 deg (the moon daily motion = 13.18
degrees)…
Let's ask again
- Why does Earth motion distance per a solar day define the moon orbit points
"perigee and apogee"? why I ask this question??
- Because the Earth moon distances should be defined (as we know) based on the
Earth gravity and centrifugation, and that means, whatsoever the Earth motion
distance daily shouldn't effect on the Earth moon distances (the moon orbital
radiuses) – but the data tells something different …. Where Earth daily motion
distance defines the earth moon distances! And we need to know why? and how ??
- Specifically why 0.406 mkm (Apogee point) and 0.363 mkm (Perigee point) are
defined because of the Earth motion distance daily? The question doesn't interest
for the distance difference (43000 km) but interest for both points 0.363 mkm and
0.406 mkm….
Let's see the following equations
Equation No. (4)
(2.58 mkm /0.406 mkm) = (152.1/24)
153.3 hours = Pluto Day Period, but 24 hours = Earth Day Period
- Equation No. (4) tells that, The apogee radius (r= 0.406 mkm) is defined based on
some interaction between Pluto & Earth Days Periods, which shows some
interaction found between Earth and Pluto motions
- But how this interaction is found between Pluto and Earth Motions? Because
the distance between them is so great? Please review Equation No. 2 which
proves this same meaning…
Equation No. (5)
(2.58 mkm /0.363 mkm) = (170/24)
- 170 mkm =Mercury Mars Distance, This value is used here as 170 hours,
proportional with Earth day period…. This equation typically is similar to the
previous one
- Please remember, to use the distance value as time value, it's usual using for
Mercury and Mars motions, we remember that, Mercury moves during its rotation
period (58.66 days) a distance =243 mkm and Mars move during the Venus day
(116.75 days) this same distance = 243 mkm where Venus rotation period =243
days…(i.e. the distance value using as time period it's usual used with them)

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- The Equations no (4 and 5) tell us that, the moon orbital basic 2 radiuses are
defined based on a relationship between Earth & Pluto on one side and Earth &
Mars on the other side…. Noticeable Mars and Pluto were migrated from their
original points
- We know that, the moon is created after Mars & Pluto Migration, and because of
that the moon is created with specific dimensions to cover the negative results of
the planets migration….
- I wish I can explain the geometrical structure design of the solar system… the
solar system is a wonderful machine, when it has some defect, the machine itself
knows how to repair this defect and then to get recovery
i.e.
- The planets migration was some great earthquake in the solar system and could
destroy it, but the rest planets worked so hardly to save the group.. and it's saved
till now because of this great wonderful cooperation… that's what we try to
discover because no planet behaves alone as independent player but all of them
work as one wonderful team and because of that the solar group still in life
- The words are beautiful but helps a little……!
- Because the distances between the planets prevent to accept this beautiful
meaning… the distance still cause a great difficulty to discover by what force a
planet as (Pluto) can effect on the Earth moon motion?! the data proved this
fact…. (For example,
o (1) Pluto moves during a solar day a distance = 0.406 mkm = apogee radius,
o (2) Equation No. 4 tells that Earth motion distance daily (2.58mkm) divided
by apogee radius (r=0.406 mkm) = the rate between Pluto and Earth days
periods?!
o (3) (1/ Pluto velocity daily) = the Earth moon velocity daily
o (4) Earth Velocity Daily = Pluto Velocity Daily x 2π
o (5) Pluto orbital distance = (2π)2
x Earth orbital distance
o (6) Pluto orbital Period = 2π3
x 1461 days (=365+365+365+366)
- The data proves this idea clearly, but how to overcome the distance?! I claim some
light motion is accompanying with the planet motion, and the light motion can do
this effect…. But the geometrical mechanism by which this process is done still
needs more analysis…

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More Discussion:
- We have concluded that, the moon radiuses (perigee and apogee) are defined by
effect of interaction between Earth & Pluto one side and Earth & Mars on the other
side …
- Why does these 2 planets effect on the Earth motion distance daily? Or specifically
why these 2 planets effect on the Earth orbital distance?
(1) Mars Effect On Earth Orbital Distance?
2.082 mkm =2.58 mkm x 0.8
- 2.082 mkm = Mars daily motion distance
- 2.58 mkm = Earth daily motion distance
- 0.8 degrees = Uranus Orbital Inclination
Notice No. (1)
- The deep interaction between Mars and Moon motions causes Mars to effect on
the moon and on its distance to the sun, because of that, Mars can effect on
earth orbital distance through its effect on the moon motion data
- That explains the previous equation
- We may note that, Uranus orbital inclination defines the rate between Mars and
Earth motion distances daily –
- Uranus effect on the moon motion is supposed strongly regardless the distance
between them
- Because of Uranus effect on Venus Data Creation and on the moon motion,
because of that we may expect also a great effect of Uranus on Earth and Mars
motions as the equation shows clearly…
(2) Pluto Effect On Earth Orbital Distance?
149.6 mkm = 0.406 mkm Pluto velocity daily x 365.25 days
Pluto during 365.25 days moves a distance =149.6 mkm = Earth orbital distance
Notice No. (2)
- The basic connection between Earth and Pluto is 500 seconds this value is sent
from Pluto to Earth and by this period of time the light defines earth orbital
distance from the sun, where light known velocity needs 500 seconds to pass
from the sun to Earth (149.6 mkm)

I do this research
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17
- This period 500 seconds is produced by the distance 580 mkm which Pluto
moves during 1433.5 days but light with supposed velocity 1.16 mkm/sec
passes this distance during 500 seconds
- The previous data shows how Pluto effect on the Earth and its Moon motions,
the mechanism still needs more analysis, but all ways to solve this question
should use the previous data because it's the most possible way to find
connection between Earth and Pluto
Also
- Because we believe that, there's an effect of Uranus on the Earth moon motion,
that helps this claim greatly because of the deep interaction between Uranus
and Pluto motions –which help us to imagine that – Pluto may effect on the
moon motion through Uranus effect – the mechanism still needs more analysis.

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The moon orbital triangle revision (CBS)
- The triangle CBS, its perimeter = 183614 km
- But
- 183614 degrees = 360 x 511 degrees
- 511 degrees = The Planets Axial Tilts Total
Equation No. (6)
183614 degrees = 360 x 511 degrees
- How to understand
- Each 1 km = 1 degree, and 1 degree = 1 day (Earth moves a displacement 1 km
vertically per day)…. So we conclude that 1 km =1 degree
- Each solar day 1 degree is consumed from this 183614 degrees
- But
- Each 360 degrees of this 183614 degrees = 1 degree of the planets axial tilts total
(511 degrees)
- The triangle CBS shows the Earth vertical displacement (1 km) …. Note please
this is very important data because it's the only one proof for 1 km =1 degree and
by that 1 km Earth moves vertically per solar day….
Equation No. (7)
183614 kmx 2π =1.16 million km (error 0.5%)
- Equation No. (7) tells that, the value 183614 km is the circle diameter in a circle
the light travels around its circumference, we remember that (Planet Motion
Depends On Light Motion) and (light moves around the circle circumference but
the planet moves along this same circle diameter)…
- That means the value 183614 km is the distance a planet move as a result of a light
beam moves 1.16 mkm during 1 second
- I wish the light motion is seen behind the planet motion clearly

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Equation No. (8)
- 183614 km x sin (28.6 degrees ) = 88000 km (Earth displacement per day)
- 28.66 x 0.99 = 28.3 degrees (= Neptune Axial Tilt)
- Equation No. (8) tells that, the moon motion distance daily depends on light
motion because it depends on the value 183614 km which is created by the motion
of light beam with supposed velocity 1.16 mkm/sec
Equation No. (8)
- 5 million km = 183614 km x 27.3
- 5 million km = (152.1 mkm – 147.1 mkm), means the Earth motion free space
depends on this same value (183614 km) in a function of the moon orbital period
27.3 days..

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References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

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