This document summarizes the synthesis of 1-bromo-2-naphthol from 2-naphthol. It involves selectively brominating 2-naphthol using sodium bromide and oxone. 2-Naphthol, sodium bromide, and oxone are ground together and reacted overnight. Ethyl acetate is then used to extract the crude 1-bromo-2-naphthol product, which is a dark brown solid. The theoretical and practical yields are calculated and the percentage yield is reported.

1. SYNTHESIS OF 1-BROMO -2-
NAPHTHOL FROM
2-NAPHTHOL
Prepared By
PUSHPA K
Ⅱ M.Sc. Ⅳ Semester
Department of Studies and Research in Organic Chemistry
Tumkur University, Tumakuru

2. AIM: To prepare 1-bromo-2-naphthol from
2-naphthol
PRINCIPLE: Selective bromination of aromatic
compounds is an important reaction in organic
synthesis. Direct treatment of aromatic compounds
with molecular bromine normally results in a mixture
of mono , di and poly substituted products. In addition
, direct bromination of activated aromatic compound
by bromine generates hydrogen bromide which is
corrosive, toxic & pollutes the environment. To
overcome these difficulties numerous methods have
been proposed to increase the selectivity.

3. 1 –BROMO-2-NAPHTHOL
CHEMICALS REQUIRED; APPARATUS REQUIRED;
2 NAPHTHOL
SODIUM BROMIDE
OXONE
ETHYL ACETATE
MORTOR & PESTLE
BEAKER
FILTERING FUNNEL
FILTER PAPPER

4. PROCEDURE
0.5 g of 2-naphthol ,0.34 g of NaBr & 1.05 g of oxone were placed in a
mortor and pestle.
The reagent were ground together until they become a fine powder . Then
transfer the reaction media into a plastic reagent bottle & stir for over night
Ethyl acetate was added (5ml) to the container and shaken vigorously.
The ethyl acetate layer was filtered into 100ml conical flask & resulting dark
brown red solution was reduced to a solid by evaporation.
The resulting crude 1-bromo-2-naphthol is dark brown solid. Record the
yield of crude product.

5. Reaction
Calculation
Compound
2-naphthol
NaBr
Oxone
Amount
0.5g
0.34g
1.05g
Mol wt
144.17
102.89
617.74
Moles
0.0034
0.0034
0.0017
Eq wt
1
1
0.5

6. MECHANISM

7. THEORETICAL YIELD:
144.17g of 2-naphthol forms 223.07g of 1-bromo-2-
naphthol
0.5g of 2-naphthol forms “x” g of 1-bromo-2-naphthol
X= 0.5*223.07/144.17
X=…………………g
Practical yield=…………………g
Percentage yield=practical yield/theoretical yield* 100
Percentage yield= ……………………%

8. REPORT
NAME &
STRUCTURE OF
COMPOUND
THEORETI
CAL YIELD
PRACTICAL
YIELD
PERCENTAGE
YIELD
MELTINNG
POINT

9. THANK YOU