Obj. 39 Similar Right Triangles
The student is able to (I can):
• Use geometric mean to find segment lengths in right
triangles
• Apply similarity relationships in right triangles to solve
problems.
geometric
mean

A proportion with the following pattern:
a x
=
x b
or x 2 = ab

or

x = ab

Example: Find the geometric mean of 5 and
20.

5
x
=
x 20
x 2 = 100
x = 10
Thm 8-1-1

The altitude to the hypotenuse of a right
triangle forms two triangles that are
similar to each other and to the original
I
triangle.
90˚-∠M

90˚-∠M
M

T

E

M

M
T

I

E

I
T
E

I

∆MIT ~ ∆IET ~ ∆MEI
Because the triangles are similar, we can
set up proportions between the sides:
MI IE ME
=
=
, etc.
I
IT ET EI
M

T

E

M

M
T

I

E

I
T
E

I

∆MIT ~ ∆IET ~ ∆MEI
Cor. 8-1-2

The length of the altitude to the
hypotenuse is the geometric mean of the
lengths of the two segments.
E
b
H

h

T x A

y
c

x h
=
h y

or

a

h2 = xy
Cor. 8-1-3

The length of a leg of a right triangle is the
geometric mean of the lengths of the
hypotenuse and the segment of the
hypotenuse adjacent to that leg.
E
b
H

h

a

T x A

y
c

x a
=
a c

or

a2 = xc

y b
=
b c

or

b 2 = yc
When you are setting up these problems,
remember you are basically setting up
similar triangles.
Example
1. Find x, y, and z.

x
6

9

y

z

9 6
=
6 x
9x = 36
x=4

9
z
=
z 9+4
z 2 = 117
z = 3 13

4
y
=
y 9+4
y 2 = 52
y = 2 13

Obj. 39 Similar Right Triangles

  • 1.
    Obj. 39 SimilarRight Triangles The student is able to (I can): • Use geometric mean to find segment lengths in right triangles • Apply similarity relationships in right triangles to solve problems.
  • 2.
    geometric mean A proportion withthe following pattern: a x = x b or x 2 = ab or x = ab Example: Find the geometric mean of 5 and 20. 5 x = x 20 x 2 = 100 x = 10
  • 3.
    Thm 8-1-1 The altitudeto the hypotenuse of a right triangle forms two triangles that are similar to each other and to the original I triangle. 90˚-∠M 90˚-∠M M T E M M T I E I T E I ∆MIT ~ ∆IET ~ ∆MEI
  • 4.
    Because the trianglesare similar, we can set up proportions between the sides: MI IE ME = = , etc. I IT ET EI M T E M M T I E I T E I ∆MIT ~ ∆IET ~ ∆MEI
  • 5.
    Cor. 8-1-2 The lengthof the altitude to the hypotenuse is the geometric mean of the lengths of the two segments. E b H h T x A y c x h = h y or a h2 = xy
  • 6.
    Cor. 8-1-3 The lengthof a leg of a right triangle is the geometric mean of the lengths of the hypotenuse and the segment of the hypotenuse adjacent to that leg. E b H h a T x A y c x a = a c or a2 = xc y b = b c or b 2 = yc
  • 7.
    When you aresetting up these problems, remember you are basically setting up similar triangles. Example 1. Find x, y, and z. x 6 9 y z 9 6 = 6 x 9x = 36 x=4 9 z = z 9+4 z 2 = 117 z = 3 13 4 y = y 9+4 y 2 = 52 y = 2 13