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Motion laws of newton 2

Motion laws of newton 2

Rajat manchanda

Rajat manchanda

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- 1. Newton’s Laws of MotionI. Law of Inertia II. F=ma III. Action-Reaction
- 2. Newton’s Laws of Motion 1st Law – Inertia 2nd Law – F=ma 3rd Law – Action-Reaction
- 3. 2nd Law
- 4. 2nd Law The net force of an object is equal to the object’s mass times its acceleration, or F=ma.
- 5. 2nd Law (F = m x a) How much force is needed to accelerate a 1400 kilogram car 2 meters per second/per second? Write the formula F = m x a Fill in given numbers and units F = 1400 kg x 2 m/s/s Solve for the unknown 2800 kg m/s/s or 2800 N
- 6. 2nd Law One newton is equal to the force required to accelerate one kilogram of mass at one meter/second/second. N = kg m/s/s
- 7. Gravity • F = m a • Fg = m g – g is the acceleration due to gravity – G is 9.8 m/s/s for everything. • Everything accelerates at the same rate when it is falling • Fg = Force of gravity on an objects is the object’s weight
- 8. Newton’s 2nd Law proves that different masses accelerate to the earth at the same rate, but with different forces. • We know that objects with different masses accelerate to the ground at the same rate. • However, because of the 2nd Law we know that they don’t hit the ground with the same force. F = ma 98 N = 10 kg x 9.8 m/s/s F = ma 9.8 N = 1 kg x 9.8 m/s/s
- 9. Check Your Understanding 1. What acceleration will result when a 12 N net force applied to a 3 kg object? A 6 kg object? 2. A net force of 16 N causes a mass to accelerate at a rate of 5 m/s2. Determine the mass. 3. How much force is needed to accelerate a 66 kg skier 1 m/sec/sec? 4. What is the force on a 1000 kg elevator that is falling freely at 9.8 m/sec/sec?
- 10. Check Your Understanding 1. What acceleration will result when a 12 N net force applied to a 3 kg object? 12 N = 3 kg x 4 m/s/s 2. A net force of 16 N causes a mass to accelerate at a rate of 5 m/s2. Determine the mass. 16 N = 3.2 kg x 5 m/s/s 3. How much force is needed to accelerate a 66 kg skier 1 m/sec/sec? 66 kg-m/sec/sec or 66 N 4. What is the force on a 1000 kg elevator that is falling freely at 9.8 m/sec/sec? 9800 kg-m/sec/sec or 9800 N