Topic : Parabola
 Definition: A parabola is a set of all points in a plane
that are equidistant from a fixed line and a
fixed point (not on the line) in the plane.
'Para' means 'for'
'Bola' means 'throwing'
Parabola means shape describe
when we throw a ball in the air.
 The fixed line is called directrix of the parabola and fixed point f is called
focus.
 Latus rectum is a line segment perpendicular to the axis of parabola
through the focus and whose end points lie on the parabola.
Key Terms
 A point of intersection of a conic with its axis is
called vertex.
 The line passing through the focus and
perpendicular to the directrix is called axis.
 The constant ratio is called eccentricity denoted
with the letter e.
Deriving standard equation of a parabola
Latus rectum is a line
segment perpendicular to
the axis of parabola
through the focus and
whose end points lie on the
parabola.
Length of latus rectum = 4a
Types of parabola : 1) Right-open parabola
Vertex: (0,0)
Focus: (a,0)
Axis: Y=0
Equation of directrix: x = -a
Length of latus rectum = 4a
𝒚𝟐 = 𝟒𝒂𝒙
y
2) Find the equation of the parabola
with focus (2,0), directrix x=-2.
𝑦2
= 12𝑥
1)
2) Left-open parabola
Vertex: (0,0)
Focus: (-a,0)
Axis: Y=0
Equation of directrix: x = a
Length of latus rectum = 4a
𝒚𝟐 = −𝟒𝒂𝒙
2) Find the equation of the parabola
with vertex (0,0) and directrix x=8.
1) 𝑦2
= 15𝑥
3) Open-upwards parabola
Vertex: (0,0)
Focus: (0,a)
Axis: X=0
Equation of directrix: y = -a
Length of latus rectum = 4a
𝒙𝟐 = 𝟒𝒂𝒚
2) Find the equation of the parabola
with vertex (0,0) and directrix y=-9.
1) 𝑥2
= 5𝑦
4) Open-downward parabola
Vertex: (0,0)
Focus: (0,-a)
Axis: X=0
Equation of directrix: y = a
Length of latus rectum = 4a
𝒙𝟐
= −𝟒𝒂𝒚
Applications
 The parabola has many important applications, from a
parabolic antenna or parabolic microphone to
automobile headlight reflectors and the design of
ballistic missiles.
 It is frequently used in physics, engineering, and many
other areas.
Parabola with 𝒚𝟐
term Parabola with 𝒙𝟐 term
Symmetrical about X-axis. Symmetrical about Y-axis.
Axis is along the X-axis. Axis is along the Y-axis.
It open right handed when co-
efficient of ‘x’ is positive and
left handed when co-efficient
of ‘x’ is negative.
It opens upwards if co-
efficient of ‘y’ is positive and
downwards if co-efficient of
‘y’ is negative.
 Indian track and field athlete Neeraj Chopra, who
competes in the javelin throw, won a gold medal
at Tokyo Olympics. He is the first track and field
athlete to win a gold medal for India at the
Olympics.
 Based on above information, answer the following
1. Name the shape of paths followed by javelin.
2. If the equation of such a curve is given by 𝑥2
= −16𝑦, then
write the coordinate of foci.
3. Write the equation of directrix and length of semi-latus rectum.
Case Study
Maths PPT on parabola Class 11.pptx
Maths PPT on parabola Class 11.pptx
Maths PPT on parabola Class 11.pptx

Maths PPT on parabola Class 11.pptx

  • 2.
  • 3.
     Definition: Aparabola is a set of all points in a plane that are equidistant from a fixed line and a fixed point (not on the line) in the plane. 'Para' means 'for' 'Bola' means 'throwing' Parabola means shape describe when we throw a ball in the air.
  • 4.
     The fixedline is called directrix of the parabola and fixed point f is called focus.  Latus rectum is a line segment perpendicular to the axis of parabola through the focus and whose end points lie on the parabola. Key Terms  A point of intersection of a conic with its axis is called vertex.  The line passing through the focus and perpendicular to the directrix is called axis.  The constant ratio is called eccentricity denoted with the letter e.
  • 5.
  • 6.
    Latus rectum isa line segment perpendicular to the axis of parabola through the focus and whose end points lie on the parabola. Length of latus rectum = 4a
  • 8.
    Types of parabola: 1) Right-open parabola Vertex: (0,0) Focus: (a,0) Axis: Y=0 Equation of directrix: x = -a Length of latus rectum = 4a 𝒚𝟐 = 𝟒𝒂𝒙
  • 9.
    y 2) Find theequation of the parabola with focus (2,0), directrix x=-2. 𝑦2 = 12𝑥 1)
  • 10.
    2) Left-open parabola Vertex:(0,0) Focus: (-a,0) Axis: Y=0 Equation of directrix: x = a Length of latus rectum = 4a 𝒚𝟐 = −𝟒𝒂𝒙
  • 11.
    2) Find theequation of the parabola with vertex (0,0) and directrix x=8. 1) 𝑦2 = 15𝑥
  • 12.
    3) Open-upwards parabola Vertex:(0,0) Focus: (0,a) Axis: X=0 Equation of directrix: y = -a Length of latus rectum = 4a 𝒙𝟐 = 𝟒𝒂𝒚
  • 13.
    2) Find theequation of the parabola with vertex (0,0) and directrix y=-9. 1) 𝑥2 = 5𝑦
  • 14.
    4) Open-downward parabola Vertex:(0,0) Focus: (0,-a) Axis: X=0 Equation of directrix: y = a Length of latus rectum = 4a 𝒙𝟐 = −𝟒𝒂𝒚
  • 16.
    Applications  The parabolahas many important applications, from a parabolic antenna or parabolic microphone to automobile headlight reflectors and the design of ballistic missiles.  It is frequently used in physics, engineering, and many other areas.
  • 17.
    Parabola with 𝒚𝟐 termParabola with 𝒙𝟐 term Symmetrical about X-axis. Symmetrical about Y-axis. Axis is along the X-axis. Axis is along the Y-axis. It open right handed when co- efficient of ‘x’ is positive and left handed when co-efficient of ‘x’ is negative. It opens upwards if co- efficient of ‘y’ is positive and downwards if co-efficient of ‘y’ is negative.
  • 18.
     Indian trackand field athlete Neeraj Chopra, who competes in the javelin throw, won a gold medal at Tokyo Olympics. He is the first track and field athlete to win a gold medal for India at the Olympics.  Based on above information, answer the following 1. Name the shape of paths followed by javelin. 2. If the equation of such a curve is given by 𝑥2 = −16𝑦, then write the coordinate of foci. 3. Write the equation of directrix and length of semi-latus rectum. Case Study