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• illustrate situations that involves a joint variation. the
following variations: (a) joint ; (b) combined.
• translate into variation statement a relationship between
two quantities
• Solve for the missing variables in a given joint variation
If z varies jointly as x and y, then
z= kxy
or equivalently
𝒁
𝒙𝒚
= 𝒌.
The constant k is called the constant of
variation.
Y varies directly to
two or more
quantities
A= 𝒌𝒃𝒄𝟑
A= kbh
Z varies jointly with the square
of x and cube of y.
M varies jointly with s and p.
Find k.
y =kxz
y=6 x=10 z=8
y= kxz
6 = k(10)(8) 6 =80k k= 6
80
Find y. x= 4 z=40
y= kxz
y = (4)(40)
y =
1
(3)(4)
k =
3
40
( )
40
3
y = 12
Find k.
y=3 x=2 z=24
𝑧 = 𝑘𝑥2
𝑦
24= (2) (3)k 24=12k k = 2
2
𝑧 = 𝑘𝑥2
𝑦
Find z.
x= 3 y=5
z = (2) (3)
z =
2
(2)(9)(5)
k = 2
z = 90
𝑧 = 𝑘𝑥2
𝑦
(5)
The variable z varies
jointly with x and y.
Also, z = -75 when x
=3 and y = -5. Then
find z when x = 2 and
y = 6.
The area of a rectangle
varies jointly as the length
and the width, and whose A
= 72 sq. cm when l = 12 cm
and w = 2cm. Find the are
of the rectangle whose
length is 15cm and width is
3cm.
Find an equation of
variation in which y
varies jointly as x and z
and y = 45 when x = 18
and z = 10. Find y when
x = 20 and x = 30.
Page 95
Illustrate situations that involves
combined variation.
Translate variation statement into a
relationship involving combined
variation between two quantities .
Solve for the missing variables in a given
combined variation.
The idea of joint variation can be extended because in many situations direct and inverse
variations are combined in the same equations.
If z varies directly as x and inversely as y. The equation is
𝒛 =
𝒌𝒙
𝒚
 If z varies jointly as x and y and inversely as t . The equation is
𝒛 =
𝒌𝒙𝒚
𝒕
𝑝 =
𝑘𝑥𝑦
𝑧
𝑎 =
𝑘𝑝
𝑞
𝑎 =
𝑘𝑏𝑐
𝑑2
Find k.
150 =
𝑘(5)
2
z=150 x=5 y=2 𝒛 =
𝒌𝒙
𝒚
5k= 300 k =
300
5
k =60
Find z.
x= 6 y=10
k =60
𝑧 =
𝑘𝑥
𝑦
𝑧 =
(60)(6)
10
𝑧 =
360
10
𝑧 = 36
Suppose f varies
directly as g and f
caries inversely as h.
Find g when f = 18
and h = - 3, if g = 24
when h – 2 and f = 6.
Y varies directly as x
and inversely as the
square of z. y = 20
when x = 50 and z = 5.
Find y when x = 3 and
z = 6.
If z varies directly as x
and inversely as the
square of y. If z = 4
when x = 200 and y =
5, find z when x = 80
and y = 2.
E varies jointly as p
and q and inversely as
the square of r. If e =
18 when p = 8 and q =
12 and r = 4. Find e
when p = 9, q = 10 and
r = 3.
Express each formula in words. In each
formula, k is the constant of variation.
Equation/
Formula
Words
1. 𝐿 = 𝑘𝑚𝑛
1. 𝐸 = 𝑘𝑎𝑏2
1. 𝑀 = 𝑘𝑎2
𝑟
1. 𝑁 = 𝑘𝑎2𝑏2
1. 𝑅 = 𝑘𝑎√𝑑

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Joint and Combined variation grade 9.pptx

  • 1. • illustrate situations that involves a joint variation. the following variations: (a) joint ; (b) combined. • translate into variation statement a relationship between two quantities • Solve for the missing variables in a given joint variation
  • 2. If z varies jointly as x and y, then z= kxy or equivalently 𝒁 𝒙𝒚 = 𝒌. The constant k is called the constant of variation.
  • 3. Y varies directly to two or more quantities
  • 5. Z varies jointly with the square of x and cube of y. M varies jointly with s and p.
  • 6. Find k. y =kxz y=6 x=10 z=8 y= kxz 6 = k(10)(8) 6 =80k k= 6 80
  • 7. Find y. x= 4 z=40 y= kxz y = (4)(40) y = 1 (3)(4) k = 3 40 ( ) 40 3 y = 12
  • 8. Find k. y=3 x=2 z=24 𝑧 = 𝑘𝑥2 𝑦 24= (2) (3)k 24=12k k = 2 2 𝑧 = 𝑘𝑥2 𝑦
  • 9. Find z. x= 3 y=5 z = (2) (3) z = 2 (2)(9)(5) k = 2 z = 90 𝑧 = 𝑘𝑥2 𝑦 (5)
  • 10. The variable z varies jointly with x and y. Also, z = -75 when x =3 and y = -5. Then find z when x = 2 and y = 6.
  • 11. The area of a rectangle varies jointly as the length and the width, and whose A = 72 sq. cm when l = 12 cm and w = 2cm. Find the are of the rectangle whose length is 15cm and width is 3cm.
  • 12. Find an equation of variation in which y varies jointly as x and z and y = 45 when x = 18 and z = 10. Find y when x = 20 and x = 30.
  • 14.
  • 15.
  • 16. Illustrate situations that involves combined variation. Translate variation statement into a relationship involving combined variation between two quantities . Solve for the missing variables in a given combined variation.
  • 17. The idea of joint variation can be extended because in many situations direct and inverse variations are combined in the same equations. If z varies directly as x and inversely as y. The equation is 𝒛 = 𝒌𝒙 𝒚  If z varies jointly as x and y and inversely as t . The equation is 𝒛 = 𝒌𝒙𝒚 𝒕
  • 20. Find k. 150 = 𝑘(5) 2 z=150 x=5 y=2 𝒛 = 𝒌𝒙 𝒚 5k= 300 k = 300 5 k =60
  • 21. Find z. x= 6 y=10 k =60 𝑧 = 𝑘𝑥 𝑦 𝑧 = (60)(6) 10 𝑧 = 360 10 𝑧 = 36
  • 22. Suppose f varies directly as g and f caries inversely as h. Find g when f = 18 and h = - 3, if g = 24 when h – 2 and f = 6.
  • 23. Y varies directly as x and inversely as the square of z. y = 20 when x = 50 and z = 5. Find y when x = 3 and z = 6.
  • 24. If z varies directly as x and inversely as the square of y. If z = 4 when x = 200 and y = 5, find z when x = 80 and y = 2.
  • 25. E varies jointly as p and q and inversely as the square of r. If e = 18 when p = 8 and q = 12 and r = 4. Find e when p = 9, q = 10 and r = 3.
  • 26. Express each formula in words. In each formula, k is the constant of variation. Equation/ Formula Words 1. 𝐿 = 𝑘𝑚𝑛 1. 𝐸 = 𝑘𝑎𝑏2 1. 𝑀 = 𝑘𝑎2 𝑟 1. 𝑁 = 𝑘𝑎2𝑏2 1. 𝑅 = 𝑘𝑎√𝑑