ISOMETRIC
PROJECTIONS
    AND
 ISOMETRIC
  DRAWING
Introduction
Orthographic view shows only two dimensions in
any particular view. This makes it difficult to
interpret them and only technically trained person
can interpret the meaning of these orthographic
views.
A non-technical person Can not imagine the shape
of the object from orthographic projections.
Whereas, pictorial projections can be easily
understood even by persons Without any technical
training because such views show all the three
Dimensions Of an object in the same view.
But pictorial view does not show the true shape
and size of any principal surface of An object and
it does not show the hidden portions.
Pictorial projections are easy to imagine so these
are used in sales literature.
 Principle of Projection :

  If straight lines are drawn from various points
 of an object to meet a plane then it is said that
 object is Projected on that plane.
These straight lines from the object to the
 plane are called projectors.
The figure formed by joining the points at
 which the projectors meet the plane is called
 Projection of that object.
Types of Projection:
I) Orthographic Projection
II) Pictorial Projection

Pictorial Projection :
The projection in which the length , height
And depth are shown in one view is
called Pictorial Projection.

Types of Pictorial Projection:
I) Axonometric
II) Oblique
III) Perspective
Axonometric Projection:
When projection is obtained on plane inclined to
all the three principal planes, then It is called
Axonometric projection.
Types of Axonometric projection:
sometric
Dimetric
Trimetric
Isometric Projection :
The projection is obtained on a plane which is
equally inclined to all the three principal planes.
Isometric Projections and Isometric drawings are
represented on the plane paper or sheet by drawing
isometric axes, isometric lines and isometric planes.
When a cube is kept in particular position then it
gives isometric axes, isometric lines and isometric
planes.
Particular position : When cube is resting on H.P.
on corner G and diagonal EC is Perpendicular to
                        A
V.P.
              B                      D


                         E C

              F                      H

                   30o         30o
               M          G          N   Base Line
Isometric Axes :
The three lines CB,CD and CG meeting at the point
C and making angle of 120 degree with each other
are called isometric axes.
Isometric lines:
The lines parallel to isometric axes are called
isometric lines.
Isometric planes:
The planes represented by faces of cube are called
isometric planes.
Similarly any planes parallel to these planes are also
called isometric planes.
Isometric drawing or isometric view:
The pictorial view drawn with true scale is called
Isometric drawing or isometric view.


Isometric projection:
The pictorial view drawn with the use of isometric
scale is called Isometric projection.
F.V.   L.H.S.V.


                  X



T.V.
Aim:- Figure-1, shows the F.V. & T.V. of a simple
     vertical rectangular plane of size LH. Draw its
     isometric view, for (a) R.H.S.V. & (b) L.H.S.V.
                  a’                      b’




                                          H
                d’           L            c’
                            F.V.
                 a                       b
                 d         T.V.          c
                          Figure-1
MN, is the base line for isometric axes.
PQ, is the isometric axis (vertical) for Fig.1(a)

PR, is the isometric axis ( horizontal),for R.H.S.V. for
Fig.1(a) at 30º with base line MN.
                             Q
         A
                               Note:- The diagonal line
 R                             a’c’ in ortho. View
                      B
                               increases in its iso. View
        D
                               (Fig.1-a), as AC (known
                      H



               L
                               as, non isometric line)
       X              C
M                                                        N
            Figure-1(a)      P
MN, is the base line for isometric axes.
PQ, is the isometric axis (vertical) for Fig.1(b)

PS, is the isometric axis ( horizontal),for L.H.S.V. for
Fig.1(b) at 30º with base line MN.
                               Q
                                                    B
Note:- The diagonal line
a’c’ in ortho. View                                        S
decreases in its iso. View           A
(Fig. 1-b), as AC (known                            C
as, non isometric line)             H        L
                                     D             X
  M                                        Figure-1(b)         N
                               P
Figure shows the Top View of a rectangular plane of
100 x 70. Draw its isometric view i) for R.H.S.V & ii)
for L.H.S.V.
             a                                b




                                                   70
            d                                  c
                           100
                           T.V.
A
     70           10
                     0
D
                         B

 X            C
                  30°        30°

ISOMETRIC VIEW OF THE HORIZONTAL
RECTANGULAR PLANE (100 X 70) for its
R.H.S.V.
B
                            100
                                          C
                   A
                       70
                                  D       X
           30°         30°

ISOMETRIC VIEW OF THE HORIZONTAL
RECTANGULAR PLANE (100 X 70) for its
L.H.S.V.
c’
d’       c’
                     M1
              C2              C3
               d’                  N2



a’       b’   M2                   b’ C1
                    C4
                         N1
                                   X
a    b         a’
ISOMETRIC VIEW OF SIMPLE PLANES
Aim:-Figure shows the F.V.of a cut
     geometric plane.Draw its Isometric
     view . (i)For R.H.S.V. & (ii)For L.H.S.V.
                 ?
                        b’            c’
          a’


                30°                   d’




                                       H
                                  R

           g’           L   f’        e’
                        F.V.
?
                                                      b’            c’
Darken the required arc FD                 a’

with center C2                                                      d’
                                                30°




                                                                     H
                                                                R

                                           g’          L   f’        e’
A          L
      ?                                  -: Solution :-
          B
                                        AB=a’ b’ ED=EF=R
H




    30°       R
               2         C              Now,     only        the
          R                             Quadrant of a circle
G                        D R
                              1

                              C2
                                         (L.H.S. upward), is to
           F         C3                 be drawn using Four
X                        E              center method.
           C1
                         C4
                   (i)            30°
?
           b’            c’
a’


     30°                 d’




                          H
                     R

g’          L   f’        e’
                                               L       C

                                          ?    B       D
                                     A
                                         30°           E



                                 H
                                                   F

                                     G
                                                           X
                               30°             (ii)
Aim:-Figure shows the T.V. of a cut geometric
  plane. Draw its Isometric,       (i)For R.H.S.V.
                                & (ii) For L.H.S.V.
    b       ?        c       d
                                       e
                                 R

                                       f
D




        30° j                    i
                D1




          45°                    45°
    a     L1     k           h    L2   g
                         L

                     T.V.
?
    b                       c      d             e
                                                                BC=bc= ?    ED=EF=R
                                         R
                                                            AK=ak=L1         GH=gh=L2
D



                                                 f
        30°        j                     i           Draw, J I // AG ( at a distance of D1 )
                       D1



               45°                     45°

    a         L1       k
                             L
                                   h     L2      g         Note :- (1) MJ=KM=D1, as
                            T.V.
                                             B                         angle jka=45
                                                      ?            (2) Angle JKA &
       D
                                                           C           Angle IHG are not
       30°                                                    D        45 in isometric.
A    45° J M
  L
   1
          D1                                                     R    E
       K          N
        L     H     I
               L 45°                                             F
                2
X                   G
          (i)
                                                          30°
?
    b                       c      d          e
                                                         BC=bc= ?
                                         R
                                                       AK=ak=L1
D



                                              f
        30°        j                     i      Draw, J I // AG ( at a distance of D1 )
                       D1




               45°                     45°

    a         L1       k
                             L
                                   h     L2   g        Note :-
                                          (1) MJ=KM=D1, as
                             E
                            T.V.
                                                angle jka=45
                       D           F         (2) Angle JKA &
               ?
                   C
                                   I 45° G        R
                                                Angle IHG are
                                N               not 45 in
                                        L2
B                                 H             isometric.
                        J M
                                                  D1


                 D 30°         K L
                        45° 1
                           L
                       A                    X

                            30°                   (ii)
C2’
F.V.                    C2


       C1’

             C1
T.V.
d
4           3
e           c
                               3’
                     d’
1 a                            c’
          b 2   4’

                e’                                  3
                               2’
                          b’                d
                     a’                             c
                                    4
                1’

                                    e               2
                                                b
                                            a
                                        1
C2’         C3’
                                         c’
                              M1
             C4’    C2 d’                N2
                                    C3


T.V.                M2                   b’
                              C4         C1

                               N1        X
                         a’



F.V.
Draw the Iso.View of a
                                   regular Pentagonal plane
X     a’     b’      c’       Y
                                   of 40mm sides, with one
        e’    d’
    90°                            side normal to V.P. & the
      s      d        r            plane is in H.P.
      e
             g
40




                      c
                                           R
      a                            D
      p          b    q                           C

          2D          S                    G              Q
                          E
                              40                      B
                                       A                  X
                                           P   3D
O’                  Draw the Iso.View of a
                               Pentagonal Pyramid, having




                     60
                               base sides 40mm, axis 60mm
X    a’    g’ b’    c’       Y long,when its base is in
        e’     d’              H.P.with a side of it normal
              d                to V.P.
     e                                    O




                                                 60
          O g       c
40




                                           R
     a                             D
                                                  C
              b
                                           G
           2D            S                                Q
                             E
                             40                       B
                                       A                  X
                                               3D
Aim:- Figure shows the orthographic
projections of a cut simple block. Draw its
appropriate Pictorial ( Isometric ) view,
giving the dimensions.



NOTE: The appropriate Isometric will
      be,considering its R.H.S.V.
( which is not given & is to be added as a
        missed view).
A

                                   a




                         55




                                                      15 20
                   B          b         c         d
            55                          60
           R.H.S.V.                    F.V.
Normally, dotted lines         30
are not drawn in Iso.
                         20
View,          unless              1          2
specifically required




                                                      55
to reveal the object                    3                     T.V.
perfectly.
          Figure              15              15
20           30   ISOMETRIC
                                                                         VIEW
                                                             1




                                                                      20
  55

            a




                             15 20




                                               40
                                                                 A
       b        c        d                               a            2
                60
                F.V.
        30




                                                                                   35
  20




        1            2               15                   3
                                          b         c                          B
                             55



                3
                                         15
                                              30
       15   T.V. 15                                       d               55
                                                     15
                                     X
NOTE:- IN R.H.S.MISSED VIEW, THE AREAS, A & B ARE
         SEEN AND IS DRAWN IN ITS CORROSPONDING
         SPACE
Figure shows Front View
and Top View of a machine
parts. Sketch its isometric
view & dimension it.
SQ.HOLE OF 20
R25

      C
                 B        30°
           A                    D




                 20
70




                 30
          20

          F.V.
                     b2



                                     20 10 20
      a
                     c
                     b1
10




                 70             20
          T.V.
ISOMETRIC VIEW
SQ.HOLE OF 20
                        a



       25
                                 10
                 C
     95                               c
                                 B
                  A         20         30°       b2
                                      b1


                             20
                 30
            25                               D
                 20
                      11
                        5
                                      20              50
       X
Aim:- Figure shows the F.V. & T.V. of a machine
      component.
                     Figure




                                                  20
  Draw its




                                                R3
                                                  0
                15
   pictorial
                                   F.V.
(ISOMETRIC)                               20
 view, giving

                              15
                30

                      30
     the
 dimensions.                  R10
                15




                                                      20
                               120         40
                                   T.V.
Note 1:- The machine component is splitted
   into four different parts, for its iso.
   sketching, with bottom base part as first
   drawn.
Note 2:-The circularity or part of that of
  Ortho.View, is to be drawn in Iso view as an
  ellipse or part of that using “four center
  method”,as explained earlier.
Note 3:- Such components may be drawn in
  iso., by area (plane)wise w.r.t F.V, T.V &
  S.V directions. Never prefer “box method”
  for such components.
20
                                 Split-II       Solution




                     60
                                                See, Note 2
                                      20




                                                  20
 Split-III
             15                                R3
                                                  0

                                             20 Split-IV
                                        65




                                               15
ISOMETRIC                       R1
                                  0
   VIEW                    30
                     30               120      Split-I
       See, Note 2         15
ISOMETRIC SCALE
                                                        70
(To be used for isometric projections) )
                                                 e 60
                                              in
                                           ° l 50
                                        45
                                    ( on 40
                                 TH
                                G 30                                     e)
                             EN                                       lin
                            L    20                                0°
                        A
                          L
                                                              (o n3
                     TU      10                       60 TH √3)
                  A
                    C                     P             N G √2 /
                         0                   40 C LE BY
                      -5                          R I ED
                  -10             20           ET C
                                         OM EDU
                                       IS (R
                      Q
               B       45°
                 30°               90°
         A
                                  BASE LINE
III. A
The Front View of the Top Face of a Cube having
edges “e” (with one of the body diagonal line, normal
               D              to V.P. ) is to be treated
                              as ISOMETRIC of the
                              Top Face of the Cube
                 d’           (with a side parallel to
                              V.P.)
A      30° 45° m’            C All the edges Top face
a’           M               c’
                               edges, base face edges
                               and 4 vertical edges of
              b’               the cube are reduced in
                               its isometric view, in
 a’d’= f (AD)                  the stated condition.
               B
Cos 30º = a’m’/a’d’ ----- (1)
     Cos 45º = a’m’/AD ----- (2)
     From (1) & (2)
     a’m’ = a’d’ cos30º = AD cos45º
                 D
                                 i.e. a’d’ = AD cos45º/cos 30
                     d’
                                           e x 1/ 2
                                         =
A       30° 45° m’        C                 3/2
a’            M           c’
                                 i.e. a’d’ = AD x   2/3
                b’
                               i.e. ISOMETRIC LENGTH =
 a’d’= f (AD)
                 B             (0.815 x ACTUAL LENGTH)
Aim:- Sketch shows the Orthographic
views of a machine component. Draw
its appropriate Isometric view, using
“splitting the object into pieces”
techniques. Give the dimensions on
the ISOMETRIC VIEW drawn.
90
     20     50      R40     Sketch



          40 20
          30
            20
                    φ40
             T.V.
10




             30           R.H.S.V.
                     80   (missed view)
                          may be added
                          here in height
                    20



                          & depth range
             F.V.
Dimensions
                          20
must be         C




                               10
given on the
Isometric                 25




                                      50




                                                  30
view, which                                            30
are not                                                            20
                                             50             40
shown here.                                                      B
                                                  20
     80
     20
                                                            Ø30
70




                                                            R4 0

               R15
                          25           20
     90                             80x80
                20




                     25
                           A        square                           D
Exercise
Figure shows the Orthographic
views of a machine component.
Draw its Isometric view.

Give the dimensions as per
aligned system.
Ø30                 R30
         c

                                    25         60
                                                              B




                                         15
                        35
         40
                              15




                                                                  60
         b
         a              20                    A
             10




         40                                   120
         80
      L.H.S.V.                       FRONT VIEW
                     FIGURE
             NOTE:- The front view areas are A & B,
                    while the side view areas are a, b & c.
Solution
                                      ø30

                                                             R30

                             20                         B




                                        60
                25
                                                c
                     15                                 20
           35




       15               40
      20




                                  b
            10




                     a
                   40                  A          120
                 80
ISOMETRIC                                                X
   VIEW
F.V.   L.H.S.V.
c1’
34
           60


                     25




L= 60 mm
H= 25 mm
D= 34 mm         X
Isometric projections for engineering students

Isometric projections for engineering students

  • 1.
    ISOMETRIC PROJECTIONS AND ISOMETRIC DRAWING
  • 2.
    Introduction Orthographic view showsonly two dimensions in any particular view. This makes it difficult to interpret them and only technically trained person can interpret the meaning of these orthographic views. A non-technical person Can not imagine the shape of the object from orthographic projections. Whereas, pictorial projections can be easily understood even by persons Without any technical training because such views show all the three Dimensions Of an object in the same view.
  • 3.
    But pictorial viewdoes not show the true shape and size of any principal surface of An object and it does not show the hidden portions. Pictorial projections are easy to imagine so these are used in sales literature.
  • 4.
     Principle ofProjection : If straight lines are drawn from various points of an object to meet a plane then it is said that object is Projected on that plane. These straight lines from the object to the plane are called projectors. The figure formed by joining the points at which the projectors meet the plane is called Projection of that object.
  • 5.
    Types of Projection: I)Orthographic Projection II) Pictorial Projection Pictorial Projection : The projection in which the length , height And depth are shown in one view is called Pictorial Projection. Types of Pictorial Projection: I) Axonometric II) Oblique III) Perspective
  • 6.
    Axonometric Projection: When projectionis obtained on plane inclined to all the three principal planes, then It is called Axonometric projection. Types of Axonometric projection: sometric Dimetric Trimetric
  • 7.
    Isometric Projection : Theprojection is obtained on a plane which is equally inclined to all the three principal planes. Isometric Projections and Isometric drawings are represented on the plane paper or sheet by drawing isometric axes, isometric lines and isometric planes.
  • 8.
    When a cubeis kept in particular position then it gives isometric axes, isometric lines and isometric planes. Particular position : When cube is resting on H.P. on corner G and diagonal EC is Perpendicular to A V.P. B D E C F H 30o 30o M G N Base Line
  • 9.
    Isometric Axes : Thethree lines CB,CD and CG meeting at the point C and making angle of 120 degree with each other are called isometric axes. Isometric lines: The lines parallel to isometric axes are called isometric lines. Isometric planes: The planes represented by faces of cube are called isometric planes. Similarly any planes parallel to these planes are also called isometric planes.
  • 10.
    Isometric drawing orisometric view: The pictorial view drawn with true scale is called Isometric drawing or isometric view. Isometric projection: The pictorial view drawn with the use of isometric scale is called Isometric projection.
  • 11.
    F.V. L.H.S.V. X T.V.
  • 12.
    Aim:- Figure-1, showsthe F.V. & T.V. of a simple vertical rectangular plane of size LH. Draw its isometric view, for (a) R.H.S.V. & (b) L.H.S.V. a’ b’ H d’ L c’ F.V. a b d T.V. c Figure-1
  • 13.
    MN, is thebase line for isometric axes. PQ, is the isometric axis (vertical) for Fig.1(a) PR, is the isometric axis ( horizontal),for R.H.S.V. for Fig.1(a) at 30º with base line MN. Q A Note:- The diagonal line R a’c’ in ortho. View B increases in its iso. View D (Fig.1-a), as AC (known H L as, non isometric line) X C M N Figure-1(a) P
  • 14.
    MN, is thebase line for isometric axes. PQ, is the isometric axis (vertical) for Fig.1(b) PS, is the isometric axis ( horizontal),for L.H.S.V. for Fig.1(b) at 30º with base line MN. Q B Note:- The diagonal line a’c’ in ortho. View S decreases in its iso. View A (Fig. 1-b), as AC (known C as, non isometric line) H L D X M Figure-1(b) N P
  • 15.
    Figure shows theTop View of a rectangular plane of 100 x 70. Draw its isometric view i) for R.H.S.V & ii) for L.H.S.V. a b 70 d c 100 T.V.
  • 16.
    A 70 10 0 D B X C 30° 30° ISOMETRIC VIEW OF THE HORIZONTAL RECTANGULAR PLANE (100 X 70) for its R.H.S.V.
  • 17.
    B 100 C A 70 D X 30° 30° ISOMETRIC VIEW OF THE HORIZONTAL RECTANGULAR PLANE (100 X 70) for its L.H.S.V.
  • 18.
    c’ d’ c’ M1 C2 C3 d’ N2 a’ b’ M2 b’ C1 C4 N1 X a b a’
  • 19.
    ISOMETRIC VIEW OFSIMPLE PLANES Aim:-Figure shows the F.V.of a cut geometric plane.Draw its Isometric view . (i)For R.H.S.V. & (ii)For L.H.S.V. ? b’ c’ a’ 30° d’ H R g’ L f’ e’ F.V.
  • 20.
    ? b’ c’ Darken the required arc FD a’ with center C2 d’ 30° H R g’ L f’ e’ A L ? -: Solution :- B AB=a’ b’ ED=EF=R H 30° R 2 C Now, only the R Quadrant of a circle G D R 1 C2 (L.H.S. upward), is to F C3 be drawn using Four X E center method. C1 C4 (i) 30°
  • 21.
    ? b’ c’ a’ 30° d’ H R g’ L f’ e’ L C ? B D A 30° E H F G X 30° (ii)
  • 22.
    Aim:-Figure shows theT.V. of a cut geometric plane. Draw its Isometric, (i)For R.H.S.V. & (ii) For L.H.S.V. b ? c d e R f D 30° j i D1 45° 45° a L1 k h L2 g L T.V.
  • 23.
    ? b c d e BC=bc= ? ED=EF=R R AK=ak=L1 GH=gh=L2 D f 30° j i Draw, J I // AG ( at a distance of D1 ) D1 45° 45° a L1 k L h L2 g Note :- (1) MJ=KM=D1, as T.V. B angle jka=45 ? (2) Angle JKA & D C Angle IHG are not 30° D 45 in isometric. A 45° J M L 1 D1 R E K N L H I L 45° F 2 X G (i) 30°
  • 24.
    ? b c d e BC=bc= ? R AK=ak=L1 D f 30° j i Draw, J I // AG ( at a distance of D1 ) D1 45° 45° a L1 k L h L2 g Note :- (1) MJ=KM=D1, as E T.V. angle jka=45 D F (2) Angle JKA & ? C I 45° G R Angle IHG are N not 45 in L2 B H isometric. J M D1 D 30° K L 45° 1 L A X 30° (ii)
  • 25.
    C2’ F.V. C2 C1’ C1 T.V.
  • 26.
    d 4 3 e c 3’ d’ 1 a c’ b 2 4’ e’ 3 2’ b’ d a’ c 4 1’ e 2 b a 1
  • 27.
    C2’ C3’ c’ M1 C4’ C2 d’ N2 C3 T.V. M2 b’ C4 C1 N1 X a’ F.V.
  • 38.
    Draw the Iso.Viewof a regular Pentagonal plane X a’ b’ c’ Y of 40mm sides, with one e’ d’ 90° side normal to V.P. & the s d r plane is in H.P. e g 40 c R a D p b q C 2D S G Q E 40 B A X P 3D
  • 39.
    O’ Draw the Iso.View of a Pentagonal Pyramid, having 60 base sides 40mm, axis 60mm X a’ g’ b’ c’ Y long,when its base is in e’ d’ H.P.with a side of it normal d to V.P. e O 60 O g c 40 R a D C b G 2D S Q E 40 B A X 3D
  • 40.
    Aim:- Figure showsthe orthographic projections of a cut simple block. Draw its appropriate Pictorial ( Isometric ) view, giving the dimensions. NOTE: The appropriate Isometric will be,considering its R.H.S.V. ( which is not given & is to be added as a missed view).
  • 41.
    A a 55 15 20 B b c d 55 60 R.H.S.V. F.V. Normally, dotted lines 30 are not drawn in Iso. 20 View, unless 1 2 specifically required 55 to reveal the object 3 T.V. perfectly. Figure 15 15
  • 42.
    20 30 ISOMETRIC VIEW 1 20 55 a 15 20 40 A b c d a 2 60 F.V. 30 35 20 1 2 15 3 b c B 55 3 15 30 15 T.V. 15 d 55 15 X NOTE:- IN R.H.S.MISSED VIEW, THE AREAS, A & B ARE SEEN AND IS DRAWN IN ITS CORROSPONDING SPACE
  • 43.
    Figure shows FrontView and Top View of a machine parts. Sketch its isometric view & dimension it.
  • 44.
    SQ.HOLE OF 20 R25 C B 30° A D 20 70 30 20 F.V. b2 20 10 20 a c b1 10 70 20 T.V.
  • 45.
    ISOMETRIC VIEW SQ.HOLE OF20 a 25 10 C 95 c B A 20 30° b2 b1 20 30 25 D 20 11 5 20 50 X
  • 46.
    Aim:- Figure showsthe F.V. & T.V. of a machine component. Figure 20 Draw its R3 0 15 pictorial F.V. (ISOMETRIC) 20 view, giving 15 30 30 the dimensions. R10 15 20 120 40 T.V.
  • 47.
    Note 1:- Themachine component is splitted into four different parts, for its iso. sketching, with bottom base part as first drawn. Note 2:-The circularity or part of that of Ortho.View, is to be drawn in Iso view as an ellipse or part of that using “four center method”,as explained earlier. Note 3:- Such components may be drawn in iso., by area (plane)wise w.r.t F.V, T.V & S.V directions. Never prefer “box method” for such components.
  • 48.
    20 Split-II Solution 60 See, Note 2 20 20 Split-III 15 R3 0 20 Split-IV 65 15 ISOMETRIC R1 0 VIEW 30 30 120 Split-I See, Note 2 15
  • 49.
    ISOMETRIC SCALE 70 (To be used for isometric projections) ) e 60 in ° l 50 45 ( on 40 TH G 30 e) EN lin L 20 0° A L (o n3 TU 10 60 TH √3) A C P N G √2 / 0 40 C LE BY -5 R I ED -10 20 ET C OM EDU IS (R Q B 45° 30° 90° A BASE LINE
  • 50.
    III. A The FrontView of the Top Face of a Cube having edges “e” (with one of the body diagonal line, normal D to V.P. ) is to be treated as ISOMETRIC of the Top Face of the Cube d’ (with a side parallel to V.P.) A 30° 45° m’ C All the edges Top face a’ M c’ edges, base face edges and 4 vertical edges of b’ the cube are reduced in its isometric view, in a’d’= f (AD) the stated condition. B
  • 51.
    Cos 30º =a’m’/a’d’ ----- (1) Cos 45º = a’m’/AD ----- (2) From (1) & (2) a’m’ = a’d’ cos30º = AD cos45º D i.e. a’d’ = AD cos45º/cos 30 d’ e x 1/ 2 = A 30° 45° m’ C 3/2 a’ M c’ i.e. a’d’ = AD x 2/3 b’ i.e. ISOMETRIC LENGTH = a’d’= f (AD) B (0.815 x ACTUAL LENGTH)
  • 52.
    Aim:- Sketch showsthe Orthographic views of a machine component. Draw its appropriate Isometric view, using “splitting the object into pieces” techniques. Give the dimensions on the ISOMETRIC VIEW drawn.
  • 53.
    90 20 50 R40 Sketch 40 20 30 20 φ40 T.V. 10 30 R.H.S.V. 80 (missed view) may be added here in height 20 & depth range F.V.
  • 54.
    Dimensions 20 must be C 10 given on the Isometric 25 50 30 view, which 30 are not 20 50 40 shown here. B 20 80 20 Ø30 70 R4 0 R15 25 20 90 80x80 20 25 A square D
  • 55.
    Exercise Figure shows theOrthographic views of a machine component. Draw its Isometric view. Give the dimensions as per aligned system.
  • 56.
    Ø30 R30 c 25 60 B 15 35 40 15 60 b a 20 A 10 40 120 80 L.H.S.V. FRONT VIEW FIGURE NOTE:- The front view areas are A & B, while the side view areas are a, b & c.
  • 57.
    Solution ø30 R30 20 B 60 25 c 15 20 35 15 40 20 b 10 a 40 A 120 80 ISOMETRIC X VIEW
  • 58.
    F.V. L.H.S.V.
  • 59.
  • 61.
    34 60 25 L= 60 mm H= 25 mm D= 34 mm X