SlideShare a Scribd company logo
SECTION 2-4
Writing Proofs
ESSENTIAL QUESTIONS
➤How do you analyze figures to identify and use
postulates about points, lines, and planes?
➤How do you analyze and construct viable arguments in
proofs?
VOCABULARY
1. Postulate:
2. Axiom:
3. Proof:
4. Flow Proof:
5. Deductive Argument:
VOCABULARY
1. Postulate: A statement that is accepted to be true
without proof
2. Axiom:
3. Proof:
4. Flow Proof:
5. Deductive Argument:
VOCABULARY
1. Postulate: A statement that is accepted to be true
without proof
2. Axiom: Another name for a postulate
3. Proof:
4. Flow Proof:
5. Deductive Argument:
VOCABULARY
1. Postulate: A statement that is accepted to be true
without proof
2. Axiom: Another name for a postulate
3. Proof: A logical argument made up of statements that
are supported by another statement that is accepted as
true
4. Flow Proof:
5. Deductive Argument:
VOCABULARY
1. Postulate: A statement that is accepted to be true
without proof
2. Axiom: Another name for a postulate
3. Proof: A logical argument made up of statements that
are supported by another statement that is accepted as
true
4. Flow Proof: Uses statements in boxes with arrows to
show the logical progression of an argument
5. Deductive Argument:
VOCABULARY
1. Postulate: A statement that is accepted to be true
without proof
2. Axiom: Another name for a postulate
3. Proof: A logical argument made up of statements that
are supported by another statement that is accepted as
true
4. Flow Proof:
A logical chain of statements
that link the given to what you are trying to prove
Uses statements in boxes with arrows to
show the logical progression of an argument
5. Deductive Argument:
VOCABULARY
6. Algebraic Proof:
7. Theorem:
8. Paragraph Proof:
9. Informal Proof:
VOCABULARY
6. Algebraic Proof: When a series of algebraic steps are
used to solve problems and justify steps.
7. Theorem:
8. Paragraph Proof:
9. Informal Proof:
VOCABULARY
6. Algebraic Proof: When a series of algebraic steps are
used to solve problems and justify steps.
7. Theorem:
8. Paragraph Proof:
9. Informal Proof:
A statement or conjecture that has been
proven true
VOCABULARY
6. Algebraic Proof: When a series of algebraic steps are
used to solve problems and justify steps.
7. Theorem:
8. Paragraph Proof: When a paragraph is written to
logically explain why a given conjecture is true
9. Informal Proof:
A statement or conjecture that has been
proven true
VOCABULARY
6. Algebraic Proof: When a series of algebraic steps are
used to solve problems and justify steps.
7. Theorem:
8. Paragraph Proof: When a paragraph is written to
logically explain why a given conjecture is true
9. Informal Proof:
A statement or conjecture that has been
proven true
Another name for a paragraph proof
as it allows for free writing to provide the logical
explanation
HARKENING BACK TO CHAPTER 1
Old ideas about points, lines, and planes are now postulates!
HARKENING BACK TO CHAPTER 1
Old ideas about points, lines, and planes are now postulates!
2.1: Through any two points, there is exactly one line.
HARKENING BACK TO CHAPTER 1
Old ideas about points, lines, and planes are now postulates!
2.1: Through any two points, there is exactly one line.
2.2: Through any three noncollinear points, there is exactly one
plane.
HARKENING BACK TO CHAPTER 1
Old ideas about points, lines, and planes are now postulates!
2.1: Through any two points, there is exactly one line.
2.2: Through any three noncollinear points, there is exactly one
plane.
2.3: A line contains at least two points.
HARKENING BACK TO CHAPTER 1
Old ideas about points, lines, and planes are now postulates!
2.1: Through any two points, there is exactly one line.
2.2: Through any three noncollinear points, there is exactly one
plane.
2.3: A line contains at least two points.
2.4: A plane contains at least three noncollinear points.
HARKENING BACK TO CHAPTER 1
Old ideas about points, lines, and planes are now postulates!
2.1: Through any two points, there is exactly one line.
2.2: Through any three noncollinear points, there is exactly one
plane.
2.3: A line contains at least two points.
2.4: A plane contains at least three noncollinear points.
2.5: If two points lie in a plane, then the entire line containing
those points lies in the plane.
HARKENING BACK TO CHAPTER 1
Old ideas about points, lines, and planes are now postulates!
HARKENING BACK TO CHAPTER 1
Old ideas about points, lines, and planes are now postulates!
2.6: If two lines intersect, then their intersection is exactly one
point.
HARKENING BACK TO CHAPTER 1
Old ideas about points, lines, and planes are now postulates!
2.6: If two lines intersect, then their intersection is exactly one
point.
2.7: If two planes intersect, then their intersection is a line.
EXAMPLE 1
Determine whether the statement is always, sometimes, or
never true.
a. Points E and F are contained by exactly one line.
b. There is exactly one plane that contains points A, B, and C.
EXAMPLE 1
Determine whether the statement is always, sometimes, or
never true.
a. Points E and F are contained by exactly one line.
Always true
b. There is exactly one plane that contains points A, B, and C.
EXAMPLE 1
Determine whether the statement is always, sometimes, or
never true.
a. Points E and F are contained by exactly one line.
Always true
Only one line can be drawn through any two points
b. There is exactly one plane that contains points A, B, and C.
EXAMPLE 1
Determine whether the statement is always, sometimes, or
never true.
a. Points E and F are contained by exactly one line.
Always true
Only one line can be drawn through any two points
b. There is exactly one plane that contains points A, B, and C.
Sometimes true
EXAMPLE 1
Determine whether the statement is always, sometimes, or
never true.
a. Points E and F are contained by exactly one line.
Always true
Only one line can be drawn through any two points
b. There is exactly one plane that contains points A, B, and C.
Sometimes true
If the three points are collinear, then an infinite number
planes can be drawn. If they are noncollinear, then it is true.
EXAMPLE 1
Determine whether the statement is always, sometimes, or
never true.
c. Planes R and T intersect at point P.
EXAMPLE 1
Determine whether the statement is always, sometimes, or
never true.
c. Planes R and T intersect at point P.
Never true
EXAMPLE 1
Determine whether the statement is always, sometimes, or
never true.
c. Planes R and T intersect at point P.
Never true
Two planes intersect in a line
EXAMPLE 2
Given that AC intersects CD, write a paragraph proof to show
that A, C, and D determine a plane.
EXAMPLE 2
Given that AC intersects CD, write a paragraph proof to show
that A, C, and D determine a plane.
The two lines intersect, so they must intersect at point
C because two lines intersect in exactly one point.
EXAMPLE 2
Given that AC intersects CD, write a paragraph proof to show
that A, C, and D determine a plane.
The two lines intersect, so they must intersect at point
C because two lines intersect in exactly one point.
Points A and D are on different lines, so A, C, and D
are noncollinear by definition of noncollinear.
EXAMPLE 2
Given that AC intersects CD, write a paragraph proof to show
that A, C, and D determine a plane.
The two lines intersect, so they must intersect at point
C because two lines intersect in exactly one point.
Points A and D are on different lines, so A, C, and D
are noncollinear by definition of noncollinear.
Points A, C, and D determine a plane because three
noncollinear points determine exactly one plane.
EXAMPLE 3
Given that M is the midpoint of XY, write a paragraph proof to
show that XM ≅ MY.
EXAMPLE 3
If M is the midpoint of XY, then by the definition of midpoint,
XM = MY. Since they have the same measure, we know that,
by the definition of congruence, XM ≅ MY.
Given that M is the midpoint of XY, write a paragraph proof to
show that XM ≅ MY.
EXAMPLE 3
If M is the midpoint of XY, then by the definition of midpoint,
XM = MY. Since they have the same measure, we know that,
by the definition of congruence, XM ≅ MY.
Theorem 2.1 (Midpoint Theorem):
Given that M is the midpoint of XY, write a paragraph proof to
show that XM ≅ MY.
EXAMPLE 3
If M is the midpoint of XY, then by the definition of midpoint,
XM = MY. Since they have the same measure, we know that,
by the definition of congruence, XM ≅ MY.
Theorem 2.1 (Midpoint Theorem): If M is the midpoint of
XY, then XM ≅ MY.
Given that M is the midpoint of XY, write a paragraph proof to
show that XM ≅ MY.
PROPERTIES OF REAL NUMBERS
PROPERTIES OF REAL NUMBERS
PROPERTIES OF REAL NUMBERS
Addition Property of Equality:
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality:
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality:
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality: If a = b, then a × c = b × c
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality: If a = b, then a × c = b × c
Division Property of Equality:
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality: If a = b, then a × c = b × c
Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality: If a = b, then a × c = b × c
Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c
Reflexive Property of Equality:
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality: If a = b, then a × c = b × c
Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c
Reflexive Property of Equality: a = a
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality: If a = b, then a × c = b × c
Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c
Reflexive Property of Equality: a = a
Symmetric Property of Equality:
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality: If a = b, then a × c = b × c
Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c
Reflexive Property of Equality: a = a
Symmetric Property of Equality: If a = b, then b = a
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality: If a = b, then a × c = b × c
Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c
Reflexive Property of Equality: a = a
Symmetric Property of Equality: If a = b, then b = a
Transitive Property of Equality:
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality: If a = b, then a × c = b × c
Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c
Reflexive Property of Equality: a = a
Symmetric Property of Equality: If a = b, then b = a
Transitive Property of Equality: If a = b and b = c, then a = c
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality: If a = b, then a × c = b × c
Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c
Reflexive Property of Equality: a = a
Symmetric Property of Equality: If a = b, then b = a
Transitive Property of Equality: If a = b and b = c, then a = c
Substitution Property of Equality:
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality: If a = b, then a × c = b × c
Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c
Reflexive Property of Equality: a = a
Symmetric Property of Equality: If a = b, then b = a
Transitive Property of Equality: If a = b and b = c, then a = c
Substitution Property of Equality:
If a = b, then a may be replaced by b in
any equation/expression
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality: If a = b, then a × c = b × c
Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c
Reflexive Property of Equality: a = a
Symmetric Property of Equality: If a = b, then b = a
Transitive Property of Equality: If a = b and b = c, then a = c
Substitution Property of Equality:
If a = b, then a may be replaced by b in
any equation/expression
Distributive Property:
PROPERTIES OF REAL NUMBERS
Addition Property of Equality: If a = b, then a + c = b + c
Subtraction Property of Equality: If a = b, then a − c = b − c
Multiplication Property of Equality: If a = b, then a × c = b × c
Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c
Reflexive Property of Equality: a = a
Symmetric Property of Equality: If a = b, then b = a
Transitive Property of Equality: If a = b and b = c, then a = c
Substitution Property of Equality:
If a = b, then a may be replaced by b in
any equation/expression
Distributive Property: a(b + c) = ab + ac
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
Given
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
10 − 6a − 4a − 28 = 92
Given
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
10 − 6a − 4a − 28 = 92
Given
Distributive Property
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
10 − 6a − 4a − 28 = 92
−10a −18 = 92
Given
Distributive Property
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
10 − 6a − 4a − 28 = 92
−10a −18 = 92
Given
Distributive Property
Substitution Property
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
10 − 6a − 4a − 28 = 92
−10a −18 = 92
+18 +18
Given
Distributive Property
Substitution Property
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
10 − 6a − 4a − 28 = 92
−10a −18 = 92
+18 +18
Given
Distributive Property
Substitution Property
Addition Property
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
10 − 6a − 4a − 28 = 92
−10a −18 = 92
+18 +18
−10a = 110
Given
Distributive Property
Substitution Property
Addition Property
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
10 − 6a − 4a − 28 = 92
−10a −18 = 92
+18 +18
−10a = 110
Given
Distributive Property
Substitution Property
Addition Property
Substitution Property
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
10 − 6a − 4a − 28 = 92
−10a −18 = 92
+18 +18
−10a = 110
−10 −10
Given
Distributive Property
Substitution Property
Addition Property
Substitution Property
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
10 − 6a − 4a − 28 = 92
−10a −18 = 92
+18 +18
−10a = 110
−10 −10
Given
Distributive Property
Substitution Property
Addition Property
Substitution Property
Division Property
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
10 − 6a − 4a − 28 = 92
−10a −18 = 92
+18 +18
−10a = 110
−10 −10
a = −11
Given
Distributive Property
Substitution Property
Addition Property
Substitution Property
Division Property
EXAMPLE 4
2(5− 3a)− 4(a + 7)= 92
Solve. Write a justification for each step.
10 − 6a − 4a − 28 = 92
−10a −18 = 92
+18 +18
−10a = 110
−10 −10
a = −11
Given
Distributive Property
Substitution Property
Addition Property
Substitution Property
Division Property
Substitution Property
EXAMPLE 5
If the distance d an object travels can be given by
, the time t that the object travels is given by
. . Write an algebraic proof to verify this conjecture.
d = 20t + 5
t =
d − 5
20
EXAMPLE 5
d = 20t + 5
If the distance d an object travels can be given by
, the time t that the object travels is given by
. . Write an algebraic proof to verify this conjecture.
d = 20t + 5
t =
d − 5
20
EXAMPLE 5
d = 20t + 5 Given
If the distance d an object travels can be given by
, the time t that the object travels is given by
. . Write an algebraic proof to verify this conjecture.
d = 20t + 5
t =
d − 5
20
EXAMPLE 5
d = 20t + 5
d − 5+ 20t
Given
If the distance d an object travels can be given by
, the time t that the object travels is given by
. . Write an algebraic proof to verify this conjecture.
d = 20t + 5
t =
d − 5
20
EXAMPLE 5
d = 20t + 5
d − 5+ 20t
Given
Subtraction Property
If the distance d an object travels can be given by
, the time t that the object travels is given by
. . Write an algebraic proof to verify this conjecture.
d = 20t + 5
t =
d − 5
20
EXAMPLE 5
d = 20t + 5
d − 5+ 20t
d − 5
20
= t
Given
Subtraction Property
If the distance d an object travels can be given by
, the time t that the object travels is given by
. . Write an algebraic proof to verify this conjecture.
d = 20t + 5
t =
d − 5
20
EXAMPLE 5
d = 20t + 5
d − 5+ 20t
d − 5
20
= t
Given
Subtraction Property
Division Property
If the distance d an object travels can be given by
, the time t that the object travels is given by
. . Write an algebraic proof to verify this conjecture.
d = 20t + 5
t =
d − 5
20
EXAMPLE 5
d = 20t + 5
d − 5+ 20t
d − 5
20
= t
Given
Subtraction Property
Division Property
If the distance d an object travels can be given by
, the time t that the object travels is given by
. . Write an algebraic proof to verify this conjecture.
d = 20t + 5
t =
d − 5
20
t =
d − 5
20
EXAMPLE 5
d = 20t + 5
d − 5+ 20t
d − 5
20
= t
Given
Subtraction Property
Division Property
If the distance d an object travels can be given by
, the time t that the object travels is given by
. . Write an algebraic proof to verify this conjecture.
d = 20t + 5
t =
d − 5
20
t =
d − 5
20
Symmetric Property

More Related Content

What's hot

Subsets of a line & Different Kinds of Angles
Subsets of a line & Different Kinds of AnglesSubsets of a line & Different Kinds of Angles
Subsets of a line & Different Kinds of Angles
Jhon Paul Lagumbay
 
Points, Lines and Planes
Points, Lines and PlanesPoints, Lines and Planes
Points, Lines and Planes
ranzzley
 
Conditional and biconditional statements
Conditional and biconditional statementsConditional and biconditional statements
Conditional and biconditional statements
Dannah Paquibot
 
1 5
1 51 5
2.2 definitions and biconditionals
2.2 definitions and biconditionals2.2 definitions and biconditionals
2.2 definitions and biconditionals
Huron School District
 
1.2 points, lines and planes
1.2 points, lines and planes1.2 points, lines and planes
1.2 points, lines and planes
Sunshine Silvania
 
Language of Geometry
Language of GeometryLanguage of Geometry
Language of Geometry
Jhon Paul Lagumbay
 
Math 7 geometry 01 undefined terms rev 2
Math 7 geometry 01   undefined terms rev 2Math 7 geometry 01   undefined terms rev 2
Math 7 geometry 01 undefined terms rev 2
Gilbert Joseph Abueg
 
Points, Lines, Rays & Planes
Points, Lines, Rays & PlanesPoints, Lines, Rays & Planes
Points, Lines, Rays & Planes
MOISD MSTC
 
Key concepts of geometry
Key concepts of geometryKey concepts of geometry
Key concepts of geometry
salvie alvaro
 
Text 10.5 similar congruent polygons
Text 10.5 similar congruent polygonsText 10.5 similar congruent polygons
Text 10.5 similar congruent polygons
Annisa Fathia
 
2.1 terms
2.1 terms2.1 terms
2.1 terms
tommy34g
 
GEOMETRY: POINTS, LINES. PLANE
GEOMETRY: POINTS, LINES. PLANEGEOMETRY: POINTS, LINES. PLANE
GEOMETRY: POINTS, LINES. PLANE
M, Michelle Jeannite
 
Topic 1. points, line and plane
Topic 1. points, line and planeTopic 1. points, line and plane
Topic 1. points, line and plane
Alex Morron
 
Building Blocks Of Geometry
Building Blocks Of GeometryBuilding Blocks Of Geometry
Building Blocks Of Geometry
acavis
 
1 4 segments, rays, parallel lines and planes
1 4 segments, rays, parallel lines and planes1 4 segments, rays, parallel lines and planes
1 4 segments, rays, parallel lines and planes
Huron School District
 
1.3.2B Introduction to Proof
1.3.2B Introduction to Proof1.3.2B Introduction to Proof
1.3.2B Introduction to Proof
smiller5
 

What's hot (17)

Subsets of a line & Different Kinds of Angles
Subsets of a line & Different Kinds of AnglesSubsets of a line & Different Kinds of Angles
Subsets of a line & Different Kinds of Angles
 
Points, Lines and Planes
Points, Lines and PlanesPoints, Lines and Planes
Points, Lines and Planes
 
Conditional and biconditional statements
Conditional and biconditional statementsConditional and biconditional statements
Conditional and biconditional statements
 
1 5
1 51 5
1 5
 
2.2 definitions and biconditionals
2.2 definitions and biconditionals2.2 definitions and biconditionals
2.2 definitions and biconditionals
 
1.2 points, lines and planes
1.2 points, lines and planes1.2 points, lines and planes
1.2 points, lines and planes
 
Language of Geometry
Language of GeometryLanguage of Geometry
Language of Geometry
 
Math 7 geometry 01 undefined terms rev 2
Math 7 geometry 01   undefined terms rev 2Math 7 geometry 01   undefined terms rev 2
Math 7 geometry 01 undefined terms rev 2
 
Points, Lines, Rays & Planes
Points, Lines, Rays & PlanesPoints, Lines, Rays & Planes
Points, Lines, Rays & Planes
 
Key concepts of geometry
Key concepts of geometryKey concepts of geometry
Key concepts of geometry
 
Text 10.5 similar congruent polygons
Text 10.5 similar congruent polygonsText 10.5 similar congruent polygons
Text 10.5 similar congruent polygons
 
2.1 terms
2.1 terms2.1 terms
2.1 terms
 
GEOMETRY: POINTS, LINES. PLANE
GEOMETRY: POINTS, LINES. PLANEGEOMETRY: POINTS, LINES. PLANE
GEOMETRY: POINTS, LINES. PLANE
 
Topic 1. points, line and plane
Topic 1. points, line and planeTopic 1. points, line and plane
Topic 1. points, line and plane
 
Building Blocks Of Geometry
Building Blocks Of GeometryBuilding Blocks Of Geometry
Building Blocks Of Geometry
 
1 4 segments, rays, parallel lines and planes
1 4 segments, rays, parallel lines and planes1 4 segments, rays, parallel lines and planes
1 4 segments, rays, parallel lines and planes
 
1.3.2B Introduction to Proof
1.3.2B Introduction to Proof1.3.2B Introduction to Proof
1.3.2B Introduction to Proof
 

Similar to Geometry Section 2-4

Geometry Section 1-1
Geometry Section 1-1Geometry Section 1-1
Geometry Section 1-1
Jimbo Lamb
 
11 x1 t07 01 angle theorems (2013)
11 x1 t07 01 angle theorems (2013)11 x1 t07 01 angle theorems (2013)
11 x1 t07 01 angle theorems (2013)
Nigel Simmons
 
Geometry Section 2-9
Geometry Section 2-9Geometry Section 2-9
Geometry Section 2-9
Jimbo Lamb
 
Ac1.5cMorePracticeProblems
Ac1.5cMorePracticeProblemsAc1.5cMorePracticeProblems
Ac1.5cMorePracticeProblems
Wissahickon High School, Ambler, PA 19002
 
01 Fundamentals of Geometry
01 Fundamentals of Geometry01 Fundamentals of Geometry
01 Fundamentals of Geometry
Andreo Ayuro
 
Conditional statements dkjfoafoiej
Conditional statements dkjfoafoiejConditional statements dkjfoafoiej
Conditional statements dkjfoafoiej
mzzbarnes
 
Mathematical System-defined and undefined terms.pptx
Mathematical System-defined and undefined terms.pptxMathematical System-defined and undefined terms.pptx
Mathematical System-defined and undefined terms.pptx
bernadethvillanueva1
 
Q3W6 SAS ,APRIL 2024 education S-PPT.pptx
Q3W6   SAS ,APRIL 2024 education S-PPT.pptxQ3W6   SAS ,APRIL 2024 education S-PPT.pptx
Q3W6 SAS ,APRIL 2024 education S-PPT.pptx
goodtechpro3245
 
Ac1.5bPracticeProblems
Ac1.5bPracticeProblemsAc1.5bPracticeProblems
Presentation1.pptx
Presentation1.pptxPresentation1.pptx
Presentation1.pptx
PradeeshSAI
 
Geometry Section 2-1
Geometry Section 2-1Geometry Section 2-1
Geometry Section 2-1
Jimbo Lamb
 
Proof in Mathematics
Proof in MathematicsProof in Mathematics
Proof in Mathematics
mscartersmaths
 
3.5 Proving Lines Parallel
3.5 Proving Lines Parallel3.5 Proving Lines Parallel
3.5 Proving Lines Parallel
smiller5
 
Math 8 – proofing (direct and indirect)
Math 8 – proofing (direct and indirect)Math 8 – proofing (direct and indirect)
Math 8 – proofing (direct and indirect)
Rebekah Andrea Fullido
 
Euclid geometry
Euclid geometryEuclid geometry
Euclid geometry
Simran Khirbat
 
Project in math
Project in mathProject in math
Project in math
raprap10
 
AI Lecture 6 (logical agents)
AI Lecture 6 (logical agents)AI Lecture 6 (logical agents)
AI Lecture 6 (logical agents)
Tajim Md. Niamat Ullah Akhund
 
mathematicalsystem-230306101746-6d7ce447.pptx
mathematicalsystem-230306101746-6d7ce447.pptxmathematicalsystem-230306101746-6d7ce447.pptx
mathematicalsystem-230306101746-6d7ce447.pptx
2z9s6rsqpn
 
Capital RationingThe availability of funds effects the capital b.docx
Capital RationingThe availability of funds effects the capital b.docxCapital RationingThe availability of funds effects the capital b.docx
Capital RationingThe availability of funds effects the capital b.docx
humphrieskalyn
 
Geometry 201 unit 2.1
Geometry 201 unit 2.1Geometry 201 unit 2.1
Geometry 201 unit 2.1
Mark Ryder
 

Similar to Geometry Section 2-4 (20)

Geometry Section 1-1
Geometry Section 1-1Geometry Section 1-1
Geometry Section 1-1
 
11 x1 t07 01 angle theorems (2013)
11 x1 t07 01 angle theorems (2013)11 x1 t07 01 angle theorems (2013)
11 x1 t07 01 angle theorems (2013)
 
Geometry Section 2-9
Geometry Section 2-9Geometry Section 2-9
Geometry Section 2-9
 
Ac1.5cMorePracticeProblems
Ac1.5cMorePracticeProblemsAc1.5cMorePracticeProblems
Ac1.5cMorePracticeProblems
 
01 Fundamentals of Geometry
01 Fundamentals of Geometry01 Fundamentals of Geometry
01 Fundamentals of Geometry
 
Conditional statements dkjfoafoiej
Conditional statements dkjfoafoiejConditional statements dkjfoafoiej
Conditional statements dkjfoafoiej
 
Mathematical System-defined and undefined terms.pptx
Mathematical System-defined and undefined terms.pptxMathematical System-defined and undefined terms.pptx
Mathematical System-defined and undefined terms.pptx
 
Q3W6 SAS ,APRIL 2024 education S-PPT.pptx
Q3W6   SAS ,APRIL 2024 education S-PPT.pptxQ3W6   SAS ,APRIL 2024 education S-PPT.pptx
Q3W6 SAS ,APRIL 2024 education S-PPT.pptx
 
Ac1.5bPracticeProblems
Ac1.5bPracticeProblemsAc1.5bPracticeProblems
Ac1.5bPracticeProblems
 
Presentation1.pptx
Presentation1.pptxPresentation1.pptx
Presentation1.pptx
 
Geometry Section 2-1
Geometry Section 2-1Geometry Section 2-1
Geometry Section 2-1
 
Proof in Mathematics
Proof in MathematicsProof in Mathematics
Proof in Mathematics
 
3.5 Proving Lines Parallel
3.5 Proving Lines Parallel3.5 Proving Lines Parallel
3.5 Proving Lines Parallel
 
Math 8 – proofing (direct and indirect)
Math 8 – proofing (direct and indirect)Math 8 – proofing (direct and indirect)
Math 8 – proofing (direct and indirect)
 
Euclid geometry
Euclid geometryEuclid geometry
Euclid geometry
 
Project in math
Project in mathProject in math
Project in math
 
AI Lecture 6 (logical agents)
AI Lecture 6 (logical agents)AI Lecture 6 (logical agents)
AI Lecture 6 (logical agents)
 
mathematicalsystem-230306101746-6d7ce447.pptx
mathematicalsystem-230306101746-6d7ce447.pptxmathematicalsystem-230306101746-6d7ce447.pptx
mathematicalsystem-230306101746-6d7ce447.pptx
 
Capital RationingThe availability of funds effects the capital b.docx
Capital RationingThe availability of funds effects the capital b.docxCapital RationingThe availability of funds effects the capital b.docx
Capital RationingThe availability of funds effects the capital b.docx
 
Geometry 201 unit 2.1
Geometry 201 unit 2.1Geometry 201 unit 2.1
Geometry 201 unit 2.1
 

More from Jimbo Lamb

Geometry Section 1-5
Geometry Section 1-5Geometry Section 1-5
Geometry Section 1-5
Jimbo Lamb
 
Geometry Section 1-4
Geometry Section 1-4Geometry Section 1-4
Geometry Section 1-4
Jimbo Lamb
 
Geometry Section 1-3
Geometry Section 1-3Geometry Section 1-3
Geometry Section 1-3
Jimbo Lamb
 
Geometry Section 1-2
Geometry Section 1-2Geometry Section 1-2
Geometry Section 1-2
Jimbo Lamb
 
Geometry Section 1-2
Geometry Section 1-2Geometry Section 1-2
Geometry Section 1-2
Jimbo Lamb
 
Algebra 2 Section 5-3
Algebra 2 Section 5-3Algebra 2 Section 5-3
Algebra 2 Section 5-3
Jimbo Lamb
 
Algebra 2 Section 5-2
Algebra 2 Section 5-2Algebra 2 Section 5-2
Algebra 2 Section 5-2
Jimbo Lamb
 
Algebra 2 Section 5-1
Algebra 2 Section 5-1Algebra 2 Section 5-1
Algebra 2 Section 5-1
Jimbo Lamb
 
Algebra 2 Section 4-9
Algebra 2 Section 4-9Algebra 2 Section 4-9
Algebra 2 Section 4-9
Jimbo Lamb
 
Algebra 2 Section 4-8
Algebra 2 Section 4-8Algebra 2 Section 4-8
Algebra 2 Section 4-8
Jimbo Lamb
 
Algebra 2 Section 4-6
Algebra 2 Section 4-6Algebra 2 Section 4-6
Algebra 2 Section 4-6
Jimbo Lamb
 
Geometry Section 6-6
Geometry Section 6-6Geometry Section 6-6
Geometry Section 6-6
Jimbo Lamb
 
Geometry Section 6-5
Geometry Section 6-5Geometry Section 6-5
Geometry Section 6-5
Jimbo Lamb
 
Geometry Section 6-4
Geometry Section 6-4Geometry Section 6-4
Geometry Section 6-4
Jimbo Lamb
 
Geometry Section 6-3
Geometry Section 6-3Geometry Section 6-3
Geometry Section 6-3
Jimbo Lamb
 
Geometry Section 6-2
Geometry Section 6-2Geometry Section 6-2
Geometry Section 6-2
Jimbo Lamb
 
Geometry Section 6-1
Geometry Section 6-1Geometry Section 6-1
Geometry Section 6-1
Jimbo Lamb
 
Algebra 2 Section 4-5
Algebra 2 Section 4-5Algebra 2 Section 4-5
Algebra 2 Section 4-5
Jimbo Lamb
 
Algebra 2 Section 4-4
Algebra 2 Section 4-4Algebra 2 Section 4-4
Algebra 2 Section 4-4
Jimbo Lamb
 
Algebra 2 Section 4-2
Algebra 2 Section 4-2Algebra 2 Section 4-2
Algebra 2 Section 4-2
Jimbo Lamb
 

More from Jimbo Lamb (20)

Geometry Section 1-5
Geometry Section 1-5Geometry Section 1-5
Geometry Section 1-5
 
Geometry Section 1-4
Geometry Section 1-4Geometry Section 1-4
Geometry Section 1-4
 
Geometry Section 1-3
Geometry Section 1-3Geometry Section 1-3
Geometry Section 1-3
 
Geometry Section 1-2
Geometry Section 1-2Geometry Section 1-2
Geometry Section 1-2
 
Geometry Section 1-2
Geometry Section 1-2Geometry Section 1-2
Geometry Section 1-2
 
Algebra 2 Section 5-3
Algebra 2 Section 5-3Algebra 2 Section 5-3
Algebra 2 Section 5-3
 
Algebra 2 Section 5-2
Algebra 2 Section 5-2Algebra 2 Section 5-2
Algebra 2 Section 5-2
 
Algebra 2 Section 5-1
Algebra 2 Section 5-1Algebra 2 Section 5-1
Algebra 2 Section 5-1
 
Algebra 2 Section 4-9
Algebra 2 Section 4-9Algebra 2 Section 4-9
Algebra 2 Section 4-9
 
Algebra 2 Section 4-8
Algebra 2 Section 4-8Algebra 2 Section 4-8
Algebra 2 Section 4-8
 
Algebra 2 Section 4-6
Algebra 2 Section 4-6Algebra 2 Section 4-6
Algebra 2 Section 4-6
 
Geometry Section 6-6
Geometry Section 6-6Geometry Section 6-6
Geometry Section 6-6
 
Geometry Section 6-5
Geometry Section 6-5Geometry Section 6-5
Geometry Section 6-5
 
Geometry Section 6-4
Geometry Section 6-4Geometry Section 6-4
Geometry Section 6-4
 
Geometry Section 6-3
Geometry Section 6-3Geometry Section 6-3
Geometry Section 6-3
 
Geometry Section 6-2
Geometry Section 6-2Geometry Section 6-2
Geometry Section 6-2
 
Geometry Section 6-1
Geometry Section 6-1Geometry Section 6-1
Geometry Section 6-1
 
Algebra 2 Section 4-5
Algebra 2 Section 4-5Algebra 2 Section 4-5
Algebra 2 Section 4-5
 
Algebra 2 Section 4-4
Algebra 2 Section 4-4Algebra 2 Section 4-4
Algebra 2 Section 4-4
 
Algebra 2 Section 4-2
Algebra 2 Section 4-2Algebra 2 Section 4-2
Algebra 2 Section 4-2
 

Recently uploaded

Lapbook sobre os Regimes Totalitários.pdf
Lapbook sobre os Regimes Totalitários.pdfLapbook sobre os Regimes Totalitários.pdf
Lapbook sobre os Regimes Totalitários.pdf
Jean Carlos Nunes Paixão
 
A Survey of Techniques for Maximizing LLM Performance.pptx
A Survey of Techniques for Maximizing LLM Performance.pptxA Survey of Techniques for Maximizing LLM Performance.pptx
A Survey of Techniques for Maximizing LLM Performance.pptx
thanhdowork
 
What is the purpose of studying mathematics.pptx
What is the purpose of studying mathematics.pptxWhat is the purpose of studying mathematics.pptx
What is the purpose of studying mathematics.pptx
christianmathematics
 
বাংলাদেশ অর্থনৈতিক সমীক্ষা (Economic Review) ২০২৪ UJS App.pdf
বাংলাদেশ অর্থনৈতিক সমীক্ষা (Economic Review) ২০২৪ UJS App.pdfবাংলাদেশ অর্থনৈতিক সমীক্ষা (Economic Review) ২০২৪ UJS App.pdf
বাংলাদেশ অর্থনৈতিক সমীক্ষা (Economic Review) ২০২৪ UJS App.pdf
eBook.com.bd (প্রয়োজনীয় বাংলা বই)
 
Pride Month Slides 2024 David Douglas School District
Pride Month Slides 2024 David Douglas School DistrictPride Month Slides 2024 David Douglas School District
Pride Month Slides 2024 David Douglas School District
David Douglas School District
 
World environment day ppt For 5 June 2024
World environment day ppt For 5 June 2024World environment day ppt For 5 June 2024
World environment day ppt For 5 June 2024
ak6969907
 
How to Fix the Import Error in the Odoo 17
How to Fix the Import Error in the Odoo 17How to Fix the Import Error in the Odoo 17
How to Fix the Import Error in the Odoo 17
Celine George
 
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
IreneSebastianRueco1
 
Advantages and Disadvantages of CMS from an SEO Perspective
Advantages and Disadvantages of CMS from an SEO PerspectiveAdvantages and Disadvantages of CMS from an SEO Perspective
Advantages and Disadvantages of CMS from an SEO Perspective
Krisztián Száraz
 
clinical examination of hip joint (1).pdf
clinical examination of hip joint (1).pdfclinical examination of hip joint (1).pdf
clinical examination of hip joint (1).pdf
Priyankaranawat4
 
PCOS corelations and management through Ayurveda.
PCOS corelations and management through Ayurveda.PCOS corelations and management through Ayurveda.
PCOS corelations and management through Ayurveda.
Dr. Shivangi Singh Parihar
 
The Diamonds of 2023-2024 in the IGRA collection
The Diamonds of 2023-2024 in the IGRA collectionThe Diamonds of 2023-2024 in the IGRA collection
The Diamonds of 2023-2024 in the IGRA collection
Israel Genealogy Research Association
 
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
National Information Standards Organization (NISO)
 
Introduction to AI for Nonprofits with Tapp Network
Introduction to AI for Nonprofits with Tapp NetworkIntroduction to AI for Nonprofits with Tapp Network
Introduction to AI for Nonprofits with Tapp Network
TechSoup
 
Digital Artifact 1 - 10VCD Environments Unit
Digital Artifact 1 - 10VCD Environments UnitDigital Artifact 1 - 10VCD Environments Unit
Digital Artifact 1 - 10VCD Environments Unit
chanes7
 
Top five deadliest dog breeds in America
Top five deadliest dog breeds in AmericaTop five deadliest dog breeds in America
Top five deadliest dog breeds in America
Bisnar Chase Personal Injury Attorneys
 
Azure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHatAzure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
Scholarhat
 
How to Manage Your Lost Opportunities in Odoo 17 CRM
How to Manage Your Lost Opportunities in Odoo 17 CRMHow to Manage Your Lost Opportunities in Odoo 17 CRM
How to Manage Your Lost Opportunities in Odoo 17 CRM
Celine George
 
How to Add Chatter in the odoo 17 ERP Module
How to Add Chatter in the odoo 17 ERP ModuleHow to Add Chatter in the odoo 17 ERP Module
How to Add Chatter in the odoo 17 ERP Module
Celine George
 
Group Presentation 2 Economics.Ariana Buscigliopptx
Group Presentation 2 Economics.Ariana BuscigliopptxGroup Presentation 2 Economics.Ariana Buscigliopptx
Group Presentation 2 Economics.Ariana Buscigliopptx
ArianaBusciglio
 

Recently uploaded (20)

Lapbook sobre os Regimes Totalitários.pdf
Lapbook sobre os Regimes Totalitários.pdfLapbook sobre os Regimes Totalitários.pdf
Lapbook sobre os Regimes Totalitários.pdf
 
A Survey of Techniques for Maximizing LLM Performance.pptx
A Survey of Techniques for Maximizing LLM Performance.pptxA Survey of Techniques for Maximizing LLM Performance.pptx
A Survey of Techniques for Maximizing LLM Performance.pptx
 
What is the purpose of studying mathematics.pptx
What is the purpose of studying mathematics.pptxWhat is the purpose of studying mathematics.pptx
What is the purpose of studying mathematics.pptx
 
বাংলাদেশ অর্থনৈতিক সমীক্ষা (Economic Review) ২০২৪ UJS App.pdf
বাংলাদেশ অর্থনৈতিক সমীক্ষা (Economic Review) ২০২৪ UJS App.pdfবাংলাদেশ অর্থনৈতিক সমীক্ষা (Economic Review) ২০২৪ UJS App.pdf
বাংলাদেশ অর্থনৈতিক সমীক্ষা (Economic Review) ২০২৪ UJS App.pdf
 
Pride Month Slides 2024 David Douglas School District
Pride Month Slides 2024 David Douglas School DistrictPride Month Slides 2024 David Douglas School District
Pride Month Slides 2024 David Douglas School District
 
World environment day ppt For 5 June 2024
World environment day ppt For 5 June 2024World environment day ppt For 5 June 2024
World environment day ppt For 5 June 2024
 
How to Fix the Import Error in the Odoo 17
How to Fix the Import Error in the Odoo 17How to Fix the Import Error in the Odoo 17
How to Fix the Import Error in the Odoo 17
 
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
 
Advantages and Disadvantages of CMS from an SEO Perspective
Advantages and Disadvantages of CMS from an SEO PerspectiveAdvantages and Disadvantages of CMS from an SEO Perspective
Advantages and Disadvantages of CMS from an SEO Perspective
 
clinical examination of hip joint (1).pdf
clinical examination of hip joint (1).pdfclinical examination of hip joint (1).pdf
clinical examination of hip joint (1).pdf
 
PCOS corelations and management through Ayurveda.
PCOS corelations and management through Ayurveda.PCOS corelations and management through Ayurveda.
PCOS corelations and management through Ayurveda.
 
The Diamonds of 2023-2024 in the IGRA collection
The Diamonds of 2023-2024 in the IGRA collectionThe Diamonds of 2023-2024 in the IGRA collection
The Diamonds of 2023-2024 in the IGRA collection
 
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
 
Introduction to AI for Nonprofits with Tapp Network
Introduction to AI for Nonprofits with Tapp NetworkIntroduction to AI for Nonprofits with Tapp Network
Introduction to AI for Nonprofits with Tapp Network
 
Digital Artifact 1 - 10VCD Environments Unit
Digital Artifact 1 - 10VCD Environments UnitDigital Artifact 1 - 10VCD Environments Unit
Digital Artifact 1 - 10VCD Environments Unit
 
Top five deadliest dog breeds in America
Top five deadliest dog breeds in AmericaTop five deadliest dog breeds in America
Top five deadliest dog breeds in America
 
Azure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHatAzure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
 
How to Manage Your Lost Opportunities in Odoo 17 CRM
How to Manage Your Lost Opportunities in Odoo 17 CRMHow to Manage Your Lost Opportunities in Odoo 17 CRM
How to Manage Your Lost Opportunities in Odoo 17 CRM
 
How to Add Chatter in the odoo 17 ERP Module
How to Add Chatter in the odoo 17 ERP ModuleHow to Add Chatter in the odoo 17 ERP Module
How to Add Chatter in the odoo 17 ERP Module
 
Group Presentation 2 Economics.Ariana Buscigliopptx
Group Presentation 2 Economics.Ariana BuscigliopptxGroup Presentation 2 Economics.Ariana Buscigliopptx
Group Presentation 2 Economics.Ariana Buscigliopptx
 

Geometry Section 2-4

  • 2. ESSENTIAL QUESTIONS ➤How do you analyze figures to identify and use postulates about points, lines, and planes? ➤How do you analyze and construct viable arguments in proofs?
  • 3. VOCABULARY 1. Postulate: 2. Axiom: 3. Proof: 4. Flow Proof: 5. Deductive Argument:
  • 4. VOCABULARY 1. Postulate: A statement that is accepted to be true without proof 2. Axiom: 3. Proof: 4. Flow Proof: 5. Deductive Argument:
  • 5. VOCABULARY 1. Postulate: A statement that is accepted to be true without proof 2. Axiom: Another name for a postulate 3. Proof: 4. Flow Proof: 5. Deductive Argument:
  • 6. VOCABULARY 1. Postulate: A statement that is accepted to be true without proof 2. Axiom: Another name for a postulate 3. Proof: A logical argument made up of statements that are supported by another statement that is accepted as true 4. Flow Proof: 5. Deductive Argument:
  • 7. VOCABULARY 1. Postulate: A statement that is accepted to be true without proof 2. Axiom: Another name for a postulate 3. Proof: A logical argument made up of statements that are supported by another statement that is accepted as true 4. Flow Proof: Uses statements in boxes with arrows to show the logical progression of an argument 5. Deductive Argument:
  • 8. VOCABULARY 1. Postulate: A statement that is accepted to be true without proof 2. Axiom: Another name for a postulate 3. Proof: A logical argument made up of statements that are supported by another statement that is accepted as true 4. Flow Proof: A logical chain of statements that link the given to what you are trying to prove Uses statements in boxes with arrows to show the logical progression of an argument 5. Deductive Argument:
  • 9. VOCABULARY 6. Algebraic Proof: 7. Theorem: 8. Paragraph Proof: 9. Informal Proof:
  • 10. VOCABULARY 6. Algebraic Proof: When a series of algebraic steps are used to solve problems and justify steps. 7. Theorem: 8. Paragraph Proof: 9. Informal Proof:
  • 11. VOCABULARY 6. Algebraic Proof: When a series of algebraic steps are used to solve problems and justify steps. 7. Theorem: 8. Paragraph Proof: 9. Informal Proof: A statement or conjecture that has been proven true
  • 12. VOCABULARY 6. Algebraic Proof: When a series of algebraic steps are used to solve problems and justify steps. 7. Theorem: 8. Paragraph Proof: When a paragraph is written to logically explain why a given conjecture is true 9. Informal Proof: A statement or conjecture that has been proven true
  • 13. VOCABULARY 6. Algebraic Proof: When a series of algebraic steps are used to solve problems and justify steps. 7. Theorem: 8. Paragraph Proof: When a paragraph is written to logically explain why a given conjecture is true 9. Informal Proof: A statement or conjecture that has been proven true Another name for a paragraph proof as it allows for free writing to provide the logical explanation
  • 14. HARKENING BACK TO CHAPTER 1 Old ideas about points, lines, and planes are now postulates!
  • 15. HARKENING BACK TO CHAPTER 1 Old ideas about points, lines, and planes are now postulates! 2.1: Through any two points, there is exactly one line.
  • 16. HARKENING BACK TO CHAPTER 1 Old ideas about points, lines, and planes are now postulates! 2.1: Through any two points, there is exactly one line. 2.2: Through any three noncollinear points, there is exactly one plane.
  • 17. HARKENING BACK TO CHAPTER 1 Old ideas about points, lines, and planes are now postulates! 2.1: Through any two points, there is exactly one line. 2.2: Through any three noncollinear points, there is exactly one plane. 2.3: A line contains at least two points.
  • 18. HARKENING BACK TO CHAPTER 1 Old ideas about points, lines, and planes are now postulates! 2.1: Through any two points, there is exactly one line. 2.2: Through any three noncollinear points, there is exactly one plane. 2.3: A line contains at least two points. 2.4: A plane contains at least three noncollinear points.
  • 19. HARKENING BACK TO CHAPTER 1 Old ideas about points, lines, and planes are now postulates! 2.1: Through any two points, there is exactly one line. 2.2: Through any three noncollinear points, there is exactly one plane. 2.3: A line contains at least two points. 2.4: A plane contains at least three noncollinear points. 2.5: If two points lie in a plane, then the entire line containing those points lies in the plane.
  • 20. HARKENING BACK TO CHAPTER 1 Old ideas about points, lines, and planes are now postulates!
  • 21. HARKENING BACK TO CHAPTER 1 Old ideas about points, lines, and planes are now postulates! 2.6: If two lines intersect, then their intersection is exactly one point.
  • 22. HARKENING BACK TO CHAPTER 1 Old ideas about points, lines, and planes are now postulates! 2.6: If two lines intersect, then their intersection is exactly one point. 2.7: If two planes intersect, then their intersection is a line.
  • 23. EXAMPLE 1 Determine whether the statement is always, sometimes, or never true. a. Points E and F are contained by exactly one line. b. There is exactly one plane that contains points A, B, and C.
  • 24. EXAMPLE 1 Determine whether the statement is always, sometimes, or never true. a. Points E and F are contained by exactly one line. Always true b. There is exactly one plane that contains points A, B, and C.
  • 25. EXAMPLE 1 Determine whether the statement is always, sometimes, or never true. a. Points E and F are contained by exactly one line. Always true Only one line can be drawn through any two points b. There is exactly one plane that contains points A, B, and C.
  • 26. EXAMPLE 1 Determine whether the statement is always, sometimes, or never true. a. Points E and F are contained by exactly one line. Always true Only one line can be drawn through any two points b. There is exactly one plane that contains points A, B, and C. Sometimes true
  • 27. EXAMPLE 1 Determine whether the statement is always, sometimes, or never true. a. Points E and F are contained by exactly one line. Always true Only one line can be drawn through any two points b. There is exactly one plane that contains points A, B, and C. Sometimes true If the three points are collinear, then an infinite number planes can be drawn. If they are noncollinear, then it is true.
  • 28. EXAMPLE 1 Determine whether the statement is always, sometimes, or never true. c. Planes R and T intersect at point P.
  • 29. EXAMPLE 1 Determine whether the statement is always, sometimes, or never true. c. Planes R and T intersect at point P. Never true
  • 30. EXAMPLE 1 Determine whether the statement is always, sometimes, or never true. c. Planes R and T intersect at point P. Never true Two planes intersect in a line
  • 31. EXAMPLE 2 Given that AC intersects CD, write a paragraph proof to show that A, C, and D determine a plane.
  • 32. EXAMPLE 2 Given that AC intersects CD, write a paragraph proof to show that A, C, and D determine a plane. The two lines intersect, so they must intersect at point C because two lines intersect in exactly one point.
  • 33. EXAMPLE 2 Given that AC intersects CD, write a paragraph proof to show that A, C, and D determine a plane. The two lines intersect, so they must intersect at point C because two lines intersect in exactly one point. Points A and D are on different lines, so A, C, and D are noncollinear by definition of noncollinear.
  • 34. EXAMPLE 2 Given that AC intersects CD, write a paragraph proof to show that A, C, and D determine a plane. The two lines intersect, so they must intersect at point C because two lines intersect in exactly one point. Points A and D are on different lines, so A, C, and D are noncollinear by definition of noncollinear. Points A, C, and D determine a plane because three noncollinear points determine exactly one plane.
  • 35. EXAMPLE 3 Given that M is the midpoint of XY, write a paragraph proof to show that XM ≅ MY.
  • 36. EXAMPLE 3 If M is the midpoint of XY, then by the definition of midpoint, XM = MY. Since they have the same measure, we know that, by the definition of congruence, XM ≅ MY. Given that M is the midpoint of XY, write a paragraph proof to show that XM ≅ MY.
  • 37. EXAMPLE 3 If M is the midpoint of XY, then by the definition of midpoint, XM = MY. Since they have the same measure, we know that, by the definition of congruence, XM ≅ MY. Theorem 2.1 (Midpoint Theorem): Given that M is the midpoint of XY, write a paragraph proof to show that XM ≅ MY.
  • 38. EXAMPLE 3 If M is the midpoint of XY, then by the definition of midpoint, XM = MY. Since they have the same measure, we know that, by the definition of congruence, XM ≅ MY. Theorem 2.1 (Midpoint Theorem): If M is the midpoint of XY, then XM ≅ MY. Given that M is the midpoint of XY, write a paragraph proof to show that XM ≅ MY.
  • 41. PROPERTIES OF REAL NUMBERS Addition Property of Equality:
  • 42. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c
  • 43. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality:
  • 44. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c
  • 45. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality:
  • 46. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality: If a = b, then a × c = b × c
  • 47. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality: If a = b, then a × c = b × c Division Property of Equality:
  • 48. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality: If a = b, then a × c = b × c Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c
  • 49. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality: If a = b, then a × c = b × c Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c Reflexive Property of Equality:
  • 50. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality: If a = b, then a × c = b × c Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c Reflexive Property of Equality: a = a
  • 51. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality: If a = b, then a × c = b × c Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c Reflexive Property of Equality: a = a Symmetric Property of Equality:
  • 52. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality: If a = b, then a × c = b × c Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c Reflexive Property of Equality: a = a Symmetric Property of Equality: If a = b, then b = a
  • 53. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality: If a = b, then a × c = b × c Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c Reflexive Property of Equality: a = a Symmetric Property of Equality: If a = b, then b = a Transitive Property of Equality:
  • 54. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality: If a = b, then a × c = b × c Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c Reflexive Property of Equality: a = a Symmetric Property of Equality: If a = b, then b = a Transitive Property of Equality: If a = b and b = c, then a = c
  • 55. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality: If a = b, then a × c = b × c Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c Reflexive Property of Equality: a = a Symmetric Property of Equality: If a = b, then b = a Transitive Property of Equality: If a = b and b = c, then a = c Substitution Property of Equality:
  • 56. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality: If a = b, then a × c = b × c Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c Reflexive Property of Equality: a = a Symmetric Property of Equality: If a = b, then b = a Transitive Property of Equality: If a = b and b = c, then a = c Substitution Property of Equality: If a = b, then a may be replaced by b in any equation/expression
  • 57. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality: If a = b, then a × c = b × c Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c Reflexive Property of Equality: a = a Symmetric Property of Equality: If a = b, then b = a Transitive Property of Equality: If a = b and b = c, then a = c Substitution Property of Equality: If a = b, then a may be replaced by b in any equation/expression Distributive Property:
  • 58. PROPERTIES OF REAL NUMBERS Addition Property of Equality: If a = b, then a + c = b + c Subtraction Property of Equality: If a = b, then a − c = b − c Multiplication Property of Equality: If a = b, then a × c = b × c Division Property of Equality: If a = b and c ≠ 0, then a ÷ c = b ÷ c Reflexive Property of Equality: a = a Symmetric Property of Equality: If a = b, then b = a Transitive Property of Equality: If a = b and b = c, then a = c Substitution Property of Equality: If a = b, then a may be replaced by b in any equation/expression Distributive Property: a(b + c) = ab + ac
  • 59. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step.
  • 60. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step. Given
  • 61. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step. 10 − 6a − 4a − 28 = 92 Given
  • 62. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step. 10 − 6a − 4a − 28 = 92 Given Distributive Property
  • 63. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step. 10 − 6a − 4a − 28 = 92 −10a −18 = 92 Given Distributive Property
  • 64. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step. 10 − 6a − 4a − 28 = 92 −10a −18 = 92 Given Distributive Property Substitution Property
  • 65. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step. 10 − 6a − 4a − 28 = 92 −10a −18 = 92 +18 +18 Given Distributive Property Substitution Property
  • 66. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step. 10 − 6a − 4a − 28 = 92 −10a −18 = 92 +18 +18 Given Distributive Property Substitution Property Addition Property
  • 67. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step. 10 − 6a − 4a − 28 = 92 −10a −18 = 92 +18 +18 −10a = 110 Given Distributive Property Substitution Property Addition Property
  • 68. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step. 10 − 6a − 4a − 28 = 92 −10a −18 = 92 +18 +18 −10a = 110 Given Distributive Property Substitution Property Addition Property Substitution Property
  • 69. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step. 10 − 6a − 4a − 28 = 92 −10a −18 = 92 +18 +18 −10a = 110 −10 −10 Given Distributive Property Substitution Property Addition Property Substitution Property
  • 70. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step. 10 − 6a − 4a − 28 = 92 −10a −18 = 92 +18 +18 −10a = 110 −10 −10 Given Distributive Property Substitution Property Addition Property Substitution Property Division Property
  • 71. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step. 10 − 6a − 4a − 28 = 92 −10a −18 = 92 +18 +18 −10a = 110 −10 −10 a = −11 Given Distributive Property Substitution Property Addition Property Substitution Property Division Property
  • 72. EXAMPLE 4 2(5− 3a)− 4(a + 7)= 92 Solve. Write a justification for each step. 10 − 6a − 4a − 28 = 92 −10a −18 = 92 +18 +18 −10a = 110 −10 −10 a = −11 Given Distributive Property Substitution Property Addition Property Substitution Property Division Property Substitution Property
  • 73. EXAMPLE 5 If the distance d an object travels can be given by , the time t that the object travels is given by . . Write an algebraic proof to verify this conjecture. d = 20t + 5 t = d − 5 20
  • 74. EXAMPLE 5 d = 20t + 5 If the distance d an object travels can be given by , the time t that the object travels is given by . . Write an algebraic proof to verify this conjecture. d = 20t + 5 t = d − 5 20
  • 75. EXAMPLE 5 d = 20t + 5 Given If the distance d an object travels can be given by , the time t that the object travels is given by . . Write an algebraic proof to verify this conjecture. d = 20t + 5 t = d − 5 20
  • 76. EXAMPLE 5 d = 20t + 5 d − 5+ 20t Given If the distance d an object travels can be given by , the time t that the object travels is given by . . Write an algebraic proof to verify this conjecture. d = 20t + 5 t = d − 5 20
  • 77. EXAMPLE 5 d = 20t + 5 d − 5+ 20t Given Subtraction Property If the distance d an object travels can be given by , the time t that the object travels is given by . . Write an algebraic proof to verify this conjecture. d = 20t + 5 t = d − 5 20
  • 78. EXAMPLE 5 d = 20t + 5 d − 5+ 20t d − 5 20 = t Given Subtraction Property If the distance d an object travels can be given by , the time t that the object travels is given by . . Write an algebraic proof to verify this conjecture. d = 20t + 5 t = d − 5 20
  • 79. EXAMPLE 5 d = 20t + 5 d − 5+ 20t d − 5 20 = t Given Subtraction Property Division Property If the distance d an object travels can be given by , the time t that the object travels is given by . . Write an algebraic proof to verify this conjecture. d = 20t + 5 t = d − 5 20
  • 80. EXAMPLE 5 d = 20t + 5 d − 5+ 20t d − 5 20 = t Given Subtraction Property Division Property If the distance d an object travels can be given by , the time t that the object travels is given by . . Write an algebraic proof to verify this conjecture. d = 20t + 5 t = d − 5 20 t = d − 5 20
  • 81. EXAMPLE 5 d = 20t + 5 d − 5+ 20t d − 5 20 = t Given Subtraction Property Division Property If the distance d an object travels can be given by , the time t that the object travels is given by . . Write an algebraic proof to verify this conjecture. d = 20t + 5 t = d − 5 20 t = d − 5 20 Symmetric Property