CHAPTER 10
                          CIRCLES

Friday, May 11, 2012
SECTION 10-1
                       Circles and Circumference




Friday, May 11, 2012
ESSENTIAL QUESTIONS



                  How do you identify and use parts of circles?



                  How do you solve problems involving the
                  circumference of a circle?




Friday, May 11, 2012
VOCABULARY

     1. Circle:

     2. Center:

     3. Radius:



     4. Chord:

Friday, May 11, 2012
VOCABULARY

     1. Circle: The set of points that are all the same
        distance from a given point
     2. Center:

     3. Radius:



     4. Chord:

Friday, May 11, 2012
VOCABULARY

     1. Circle: The set of points that are all the same
        distance from a given point
     2. Center: The point that all of the points of a circle
        are equidistant from
     3. Radius:



     4. Chord:

Friday, May 11, 2012
VOCABULARY

     1. Circle: The set of points that are all the same
        distance from a given point
     2. Center: The point that all of the points of a circle
        are equidistant from
     3. Radius: A segment with one endpoint at the center
        and the other on the edge of the circle; also the
        distance from the center to the edge of the circle
     4. Chord:

Friday, May 11, 2012
VOCABULARY

     1. Circle: The set of points that are all the same
        distance from a given point
     2. Center: The point that all of the points of a circle
        are equidistant from
     3. Radius: A segment with one endpoint at the center
        and the other on the edge of the circle; also the
        distance from the center to the edge of the circle
     4. Chord: A segment with both endpoints on the
        edge of the circle
Friday, May 11, 2012
VOCABULARY

     5. Diameter:

     6. Congruent Circles:

     7. Concentric Circles:

     8. Circumference:
     9. Pi (π):
Friday, May 11, 2012
VOCABULARY

     5. Diameter: A special chord that passes through the
        center of a circle; twice the length of the radius
     6. Congruent Circles:

     7. Concentric Circles:

     8. Circumference:
     9. Pi (π):
Friday, May 11, 2012
VOCABULARY

     5. Diameter: A special chord that passes through the
        center of a circle; twice the length of the radius
     6. Congruent Circles: Two or more circles with
        congruent radii
     7. Concentric Circles:

     8. Circumference:
     9. Pi (π):
Friday, May 11, 2012
VOCABULARY

     5. Diameter: A special chord that passes through the
        center of a circle; twice the length of the radius
     6. Congruent Circles: Two or more circles with
        congruent radii
     7. Concentric Circles: Coplanar circles with the same
        center
     8. Circumference:
     9. Pi (π):
Friday, May 11, 2012
VOCABULARY

     5. Diameter: A special chord that passes through the
        center of a circle; twice the length of the radius
     6. Congruent Circles: Two or more circles with
        congruent radii
     7. Concentric Circles: Coplanar circles with the same
        center
     8. Circumference: The distance around a circle
     9. Pi (π):
Friday, May 11, 2012
VOCABULARY

     5. Diameter: A special chord that passes through the
        center of a circle; twice the length of the radius
     6. Congruent Circles: Two or more circles with
        congruent radii
     7. Concentric Circles: Coplanar circles with the same
        center
     8. Circumference: The distance around a circle
     9. Pi (π): The irrational number found from the ratio
      of circumference to the diameter
Friday, May 11, 2012
VOCABULARY

        10. Inscribed:



        11. Circumscribed:




Friday, May 11, 2012
VOCABULARY

        10. Inscribed: A polygon inside a circle where all of
          the vertices of the polygon are on the circle


        11. Circumscribed:




Friday, May 11, 2012
VOCABULARY

        10. Inscribed: A polygon inside a circle where all of
          the vertices of the polygon are on the circle


        11. Circumscribed: A circle that is around a polygon
          that is inscribed




Friday, May 11, 2012
EXAMPLE 1

     a. Name the circle


     b. Identify a radius



     c. Identify a chord       d. Name the diameter


Friday, May 11, 2012
EXAMPLE 1

     a. Name the circle
         Circle C or ⊙C

     b. Identify a radius



     c. Identify a chord       d. Name the diameter


Friday, May 11, 2012
EXAMPLE 1

     a. Name the circle
         Circle C or ⊙C

     b. Identify a radius
                 AC or CD

     c. Identify a chord       d. Name the diameter


Friday, May 11, 2012
EXAMPLE 1

     a. Name the circle
         Circle C or ⊙C

     b. Identify a radius
                 AC or CD

     c. Identify a chord       d. Name the diameter

                EB
Friday, May 11, 2012
EXAMPLE 1

     a. Name the circle
         Circle C or ⊙C

     b. Identify a radius
                 AC or CD

     c. Identify a chord       d. Name the diameter

                EB                AD
Friday, May 11, 2012
EXAMPLE 2
                       If JT = 24 in, what is KM?




Friday, May 11, 2012
EXAMPLE 2
                          If JT = 24 in, what is KM?

                       JT = KL




Friday, May 11, 2012
EXAMPLE 2
                            If JT = 24 in, what is KM?

                        JT = KL
                       KL = 24 in




Friday, May 11, 2012
EXAMPLE 2
                               If JT = 24 in, what is KM?

                           JT = KL
                         KL = 24 in
                       KM is half of KL




Friday, May 11, 2012
EXAMPLE 2
                               If JT = 24 in, what is KM?

                           JT = KL
                         KL = 24 in
                       KM is half of KL
                         KM = 12 in



Friday, May 11, 2012
EXAMPLE 3

               The diameter of ⊙L is 22 cm and the diameter of
                      ⊙P is 16 cm. MN = 5 cm. Find LP.




Friday, May 11, 2012
EXAMPLE 3

               The diameter of ⊙L is 22 cm and the diameter of
                      ⊙P is 16 cm. MN = 5 cm. Find LP.
                                      22
                                LN =
                                       2




Friday, May 11, 2012
EXAMPLE 3

               The diameter of ⊙L is 22 cm and the diameter of
                      ⊙P is 16 cm. MN = 5 cm. Find LP.
                                      22
                                LN =     =11
                                       2




Friday, May 11, 2012
EXAMPLE 3

               The diameter of ⊙L is 22 cm and the diameter of
                      ⊙P is 16 cm. MN = 5 cm. Find LP.
                                      22              16
                                LN =     =11     MP =
                                       2               2




Friday, May 11, 2012
EXAMPLE 3

               The diameter of ⊙L is 22 cm and the diameter of
                      ⊙P is 16 cm. MN = 5 cm. Find LP.
                                      22              16
                                LN =     =11     MP = = 8
                                       2               2




Friday, May 11, 2012
EXAMPLE 3

               The diameter of ⊙L is 22 cm and the diameter of
                      ⊙P is 16 cm. MN = 5 cm. Find LP.
                                      22              16
                                LN =     =11     MP = = 8
                                       2               2

                                      LP = LN + MP − MN




Friday, May 11, 2012
EXAMPLE 3

               The diameter of ⊙L is 22 cm and the diameter of
                      ⊙P is 16 cm. MN = 5 cm. Find LP.
                                      22              16
                                LN =     =11     MP = = 8
                                       2               2

                                      LP = LN + MP − MN
                                         LP =11+ 8 − 5


Friday, May 11, 2012
EXAMPLE 3

               The diameter of ⊙L is 22 cm and the diameter of
                      ⊙P is 16 cm. MN = 5 cm. Find LP.
                                      22              16
                                LN =     =11     MP = = 8
                                       2               2

                                      LP = LN + MP − MN
                                         LP =11+ 8 − 5
                                          LP =14 cm

Friday, May 11, 2012
EXAMPLE 4

      Find the diameter and radius of a circle to the nearest
     hundredth if the circumference of the circle is 65.4 feet.




Friday, May 11, 2012
EXAMPLE 4

      Find the diameter and radius of a circle to the nearest
     hundredth if the circumference of the circle is 65.4 feet.

                              C = πd




Friday, May 11, 2012
EXAMPLE 4

      Find the diameter and radius of a circle to the nearest
     hundredth if the circumference of the circle is 65.4 feet.

                              C = πd
                             65.4 = π d




Friday, May 11, 2012
EXAMPLE 4

      Find the diameter and radius of a circle to the nearest
     hundredth if the circumference of the circle is 65.4 feet.

                              C = πd
                             65.4 = π d
                              π     π




Friday, May 11, 2012
EXAMPLE 4

      Find the diameter and radius of a circle to the nearest
     hundredth if the circumference of the circle is 65.4 feet.

                              C = πd
                             65.4 = π d
                              π     π
                           d ≈ 20.82 ft



Friday, May 11, 2012
EXAMPLE 4

      Find the diameter and radius of a circle to the nearest
     hundredth if the circumference of the circle is 65.4 feet.

                              C = πd
                             65.4 = π d
                              π     π
                           d ≈ 20.82 ft
                            r ≈10.41 ft

Friday, May 11, 2012
EXAMPLE 5

                       Find the exact circumference of ⊙R.
                                    BF = 3 2




Friday, May 11, 2012
EXAMPLE 5

                           Find the exact circumference of ⊙R.
                                        BF = 3 2

          (BR) + (RF ) = (BF )
                       2      2      2




Friday, May 11, 2012
EXAMPLE 5

                               Find the exact circumference of ⊙R.
                                            BF = 3 2

          (BR) + (RF ) = (BF )
                           2       2       2


                 r + r = (3 2 )
                       2       2       2




Friday, May 11, 2012
EXAMPLE 5

                                   Find the exact circumference of ⊙R.
                                                BF = 3 2

          (BR) + (RF ) = (BF )
                           2           2           2


                 r + r = (3 2 )
                       2           2           2


                       2r = (3 2 )
                               2           2




Friday, May 11, 2012
EXAMPLE 5

                                   Find the exact circumference of ⊙R.
                                                BF = 3 2

          (BR) + (RF ) = (BF )
                           2           2           2


                 r + r = (3 2 )
                       2           2           2


                       2r = (3 2 )
                               2           2


                               2r = 9(2)
                                   2




Friday, May 11, 2012
EXAMPLE 5

                                   Find the exact circumference of ⊙R.
                                                BF = 3 2

          (BR) + (RF ) = (BF )
                           2           2           2


                 r + r = (3 2 )
                       2           2           2


                       2r = (3 2 )
                               2           2


                               2r = 9(2)
                                   2


                                 r =9
                                  2




Friday, May 11, 2012
EXAMPLE 5

                                   Find the exact circumference of ⊙R.
                                                BF = 3 2

          (BR) + (RF ) = (BF )
                           2           2           2
                                                       r = 9
                                                       2

                 r + r = (3 2 )
                       2           2           2


                       2r = (3 2 )
                               2           2


                               2r = 9(2)
                                   2


                                 r =9
                                  2




Friday, May 11, 2012
EXAMPLE 5

                                   Find the exact circumference of ⊙R.
                                                BF = 3 2

          (BR) + (RF ) = (BF )
                           2           2           2
                                                       r = 9
                                                       2

                 r + r = (3 2 )
                       2           2           2
                                                        r =3
                       2r = (3 2 )
                               2           2


                               2r = 9(2)
                                   2


                                 r =9
                                  2




Friday, May 11, 2012
EXAMPLE 5

                                   Find the exact circumference of ⊙R.
                                                BF = 3 2

          (BR) + (RF ) = (BF )
                           2           2           2
                                                       r = 9
                                                        2

                 r + r = (3 2 )
                       2           2           2
                                                        r =3
                       2r = (3 2 )
                               2           2
                                                       C = 2π r
                               2r = 9(2)
                                   2


                                 r =9
                                  2




Friday, May 11, 2012
EXAMPLE 5

                                   Find the exact circumference of ⊙R.
                                                BF = 3 2

          (BR) + (RF ) = (BF )
                           2           2           2
                                                        r = 9
                                                         2

                 r + r = (3 2 )
                       2           2           2
                                                         r =3
                       2r = (3 2 )
                               2           2
                                                        C = 2π r
                               2r = 9(2)
                                   2
                                                       C = 2π (3)
                                 r =9
                                  2




Friday, May 11, 2012
EXAMPLE 5

                                   Find the exact circumference of ⊙R.
                                                BF = 3 2

          (BR) + (RF ) = (BF )
                           2           2           2
                                                        r = 9
                                                         2

                 r + r = (3 2 )
                       2           2           2
                                                         r =3
                       2r = (3 2 )
                               2           2
                                                        C = 2π r
                               2r = 9(2)
                                   2
                                                       C = 2π (3)
                                 r =9
                                  2
                                                        C = 6π

Friday, May 11, 2012
CHECK YOUR
                       UNDERSTANDING


                           p. 687 #1-9




Friday, May 11, 2012
PROBLEM SET




Friday, May 11, 2012
PROBLEM SET



                            p. 687 #11-41 odd, 71




                 “We don't know who we are until we see what
                        we can do.” - Martha Grimes
Friday, May 11, 2012

Geometry Section 10-1 1112

  • 1.
    CHAPTER 10 CIRCLES Friday, May 11, 2012
  • 2.
    SECTION 10-1 Circles and Circumference Friday, May 11, 2012
  • 3.
    ESSENTIAL QUESTIONS How do you identify and use parts of circles? How do you solve problems involving the circumference of a circle? Friday, May 11, 2012
  • 4.
    VOCABULARY 1. Circle: 2. Center: 3. Radius: 4. Chord: Friday, May 11, 2012
  • 5.
    VOCABULARY 1. Circle: The set of points that are all the same distance from a given point 2. Center: 3. Radius: 4. Chord: Friday, May 11, 2012
  • 6.
    VOCABULARY 1. Circle: The set of points that are all the same distance from a given point 2. Center: The point that all of the points of a circle are equidistant from 3. Radius: 4. Chord: Friday, May 11, 2012
  • 7.
    VOCABULARY 1. Circle: The set of points that are all the same distance from a given point 2. Center: The point that all of the points of a circle are equidistant from 3. Radius: A segment with one endpoint at the center and the other on the edge of the circle; also the distance from the center to the edge of the circle 4. Chord: Friday, May 11, 2012
  • 8.
    VOCABULARY 1. Circle: The set of points that are all the same distance from a given point 2. Center: The point that all of the points of a circle are equidistant from 3. Radius: A segment with one endpoint at the center and the other on the edge of the circle; also the distance from the center to the edge of the circle 4. Chord: A segment with both endpoints on the edge of the circle Friday, May 11, 2012
  • 9.
    VOCABULARY 5. Diameter: 6. Congruent Circles: 7. Concentric Circles: 8. Circumference: 9. Pi (π): Friday, May 11, 2012
  • 10.
    VOCABULARY 5. Diameter: A special chord that passes through the center of a circle; twice the length of the radius 6. Congruent Circles: 7. Concentric Circles: 8. Circumference: 9. Pi (π): Friday, May 11, 2012
  • 11.
    VOCABULARY 5. Diameter: A special chord that passes through the center of a circle; twice the length of the radius 6. Congruent Circles: Two or more circles with congruent radii 7. Concentric Circles: 8. Circumference: 9. Pi (π): Friday, May 11, 2012
  • 12.
    VOCABULARY 5. Diameter: A special chord that passes through the center of a circle; twice the length of the radius 6. Congruent Circles: Two or more circles with congruent radii 7. Concentric Circles: Coplanar circles with the same center 8. Circumference: 9. Pi (π): Friday, May 11, 2012
  • 13.
    VOCABULARY 5. Diameter: A special chord that passes through the center of a circle; twice the length of the radius 6. Congruent Circles: Two or more circles with congruent radii 7. Concentric Circles: Coplanar circles with the same center 8. Circumference: The distance around a circle 9. Pi (π): Friday, May 11, 2012
  • 14.
    VOCABULARY 5. Diameter: A special chord that passes through the center of a circle; twice the length of the radius 6. Congruent Circles: Two or more circles with congruent radii 7. Concentric Circles: Coplanar circles with the same center 8. Circumference: The distance around a circle 9. Pi (π): The irrational number found from the ratio of circumference to the diameter Friday, May 11, 2012
  • 15.
    VOCABULARY 10. Inscribed: 11. Circumscribed: Friday, May 11, 2012
  • 16.
    VOCABULARY 10. Inscribed: A polygon inside a circle where all of the vertices of the polygon are on the circle 11. Circumscribed: Friday, May 11, 2012
  • 17.
    VOCABULARY 10. Inscribed: A polygon inside a circle where all of the vertices of the polygon are on the circle 11. Circumscribed: A circle that is around a polygon that is inscribed Friday, May 11, 2012
  • 18.
    EXAMPLE 1 a. Name the circle b. Identify a radius c. Identify a chord d. Name the diameter Friday, May 11, 2012
  • 19.
    EXAMPLE 1 a. Name the circle Circle C or ⊙C b. Identify a radius c. Identify a chord d. Name the diameter Friday, May 11, 2012
  • 20.
    EXAMPLE 1 a. Name the circle Circle C or ⊙C b. Identify a radius AC or CD c. Identify a chord d. Name the diameter Friday, May 11, 2012
  • 21.
    EXAMPLE 1 a. Name the circle Circle C or ⊙C b. Identify a radius AC or CD c. Identify a chord d. Name the diameter EB Friday, May 11, 2012
  • 22.
    EXAMPLE 1 a. Name the circle Circle C or ⊙C b. Identify a radius AC or CD c. Identify a chord d. Name the diameter EB AD Friday, May 11, 2012
  • 23.
    EXAMPLE 2 If JT = 24 in, what is KM? Friday, May 11, 2012
  • 24.
    EXAMPLE 2 If JT = 24 in, what is KM? JT = KL Friday, May 11, 2012
  • 25.
    EXAMPLE 2 If JT = 24 in, what is KM? JT = KL KL = 24 in Friday, May 11, 2012
  • 26.
    EXAMPLE 2 If JT = 24 in, what is KM? JT = KL KL = 24 in KM is half of KL Friday, May 11, 2012
  • 27.
    EXAMPLE 2 If JT = 24 in, what is KM? JT = KL KL = 24 in KM is half of KL KM = 12 in Friday, May 11, 2012
  • 28.
    EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. Friday, May 11, 2012
  • 29.
    EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 LN = 2 Friday, May 11, 2012
  • 30.
    EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 LN = =11 2 Friday, May 11, 2012
  • 31.
    EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 16 LN = =11 MP = 2 2 Friday, May 11, 2012
  • 32.
    EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 16 LN = =11 MP = = 8 2 2 Friday, May 11, 2012
  • 33.
    EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 16 LN = =11 MP = = 8 2 2 LP = LN + MP − MN Friday, May 11, 2012
  • 34.
    EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 16 LN = =11 MP = = 8 2 2 LP = LN + MP − MN LP =11+ 8 − 5 Friday, May 11, 2012
  • 35.
    EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 16 LN = =11 MP = = 8 2 2 LP = LN + MP − MN LP =11+ 8 − 5 LP =14 cm Friday, May 11, 2012
  • 36.
    EXAMPLE 4 Find the diameter and radius of a circle to the nearest hundredth if the circumference of the circle is 65.4 feet. Friday, May 11, 2012
  • 37.
    EXAMPLE 4 Find the diameter and radius of a circle to the nearest hundredth if the circumference of the circle is 65.4 feet. C = πd Friday, May 11, 2012
  • 38.
    EXAMPLE 4 Find the diameter and radius of a circle to the nearest hundredth if the circumference of the circle is 65.4 feet. C = πd 65.4 = π d Friday, May 11, 2012
  • 39.
    EXAMPLE 4 Find the diameter and radius of a circle to the nearest hundredth if the circumference of the circle is 65.4 feet. C = πd 65.4 = π d π π Friday, May 11, 2012
  • 40.
    EXAMPLE 4 Find the diameter and radius of a circle to the nearest hundredth if the circumference of the circle is 65.4 feet. C = πd 65.4 = π d π π d ≈ 20.82 ft Friday, May 11, 2012
  • 41.
    EXAMPLE 4 Find the diameter and radius of a circle to the nearest hundredth if the circumference of the circle is 65.4 feet. C = πd 65.4 = π d π π d ≈ 20.82 ft r ≈10.41 ft Friday, May 11, 2012
  • 42.
    EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 Friday, May 11, 2012
  • 43.
    EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 Friday, May 11, 2012
  • 44.
    EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r + r = (3 2 ) 2 2 2 Friday, May 11, 2012
  • 45.
    EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r + r = (3 2 ) 2 2 2 2r = (3 2 ) 2 2 Friday, May 11, 2012
  • 46.
    EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r + r = (3 2 ) 2 2 2 2r = (3 2 ) 2 2 2r = 9(2) 2 Friday, May 11, 2012
  • 47.
    EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r + r = (3 2 ) 2 2 2 2r = (3 2 ) 2 2 2r = 9(2) 2 r =9 2 Friday, May 11, 2012
  • 48.
    EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r = 9 2 r + r = (3 2 ) 2 2 2 2r = (3 2 ) 2 2 2r = 9(2) 2 r =9 2 Friday, May 11, 2012
  • 49.
    EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r = 9 2 r + r = (3 2 ) 2 2 2 r =3 2r = (3 2 ) 2 2 2r = 9(2) 2 r =9 2 Friday, May 11, 2012
  • 50.
    EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r = 9 2 r + r = (3 2 ) 2 2 2 r =3 2r = (3 2 ) 2 2 C = 2π r 2r = 9(2) 2 r =9 2 Friday, May 11, 2012
  • 51.
    EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r = 9 2 r + r = (3 2 ) 2 2 2 r =3 2r = (3 2 ) 2 2 C = 2π r 2r = 9(2) 2 C = 2π (3) r =9 2 Friday, May 11, 2012
  • 52.
    EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r = 9 2 r + r = (3 2 ) 2 2 2 r =3 2r = (3 2 ) 2 2 C = 2π r 2r = 9(2) 2 C = 2π (3) r =9 2 C = 6π Friday, May 11, 2012
  • 53.
    CHECK YOUR UNDERSTANDING p. 687 #1-9 Friday, May 11, 2012
  • 54.
  • 55.
    PROBLEM SET p. 687 #11-41 odd, 71 “We don't know who we are until we see what we can do.” - Martha Grimes Friday, May 11, 2012