The document discusses the center of pressure and its importance in engineering. It addresses:
1) The relationship between (hp-h(dash)) and (h) and how they relate at different angles Θ.
2) Why the center of pressure is important for engineers, as it allows them to evenly balance lift on aircraft.
3) The difference between the center of pressure and center of gravity - the center of pressure is the point where lifting and drag forces act on a fluid, while the center of gravity is one of the forces that must be considered.
The continuity equation is important for describing the movement of fluids as they pass from a tube of greater diameter to one of smaller diameter. It is critical to keep in mind that the fluid has to be of constant density as well as being incompressible. The Bernoulli equation is an important expression relating pressure, height and velocity of a fluid at one point along its flow. The relationship between these fluid conditions along a streamline always equal the same constant along that streamline in an idealized system.
PLEASE NOTE THIS IS PART-1
By Referring or said Learning This Presentation You Can Clear Your Basics Fundamental Doubts about Fluid Mechanics. In this Presentation You Will Learn about Fluid Pressure, Pressure at Point, Pascal's Law, Types Of Pressure and Pressure Measurements.
The continuity equation is important for describing the movement of fluids as they pass from a tube of greater diameter to one of smaller diameter. It is critical to keep in mind that the fluid has to be of constant density as well as being incompressible. The Bernoulli equation is an important expression relating pressure, height and velocity of a fluid at one point along its flow. The relationship between these fluid conditions along a streamline always equal the same constant along that streamline in an idealized system.
PLEASE NOTE THIS IS PART-1
By Referring or said Learning This Presentation You Can Clear Your Basics Fundamental Doubts about Fluid Mechanics. In this Presentation You Will Learn about Fluid Pressure, Pressure at Point, Pascal's Law, Types Of Pressure and Pressure Measurements.
Abstract Today’s experiment objectives are to determine the st.docxannetnash8266
Abstract
Today’s experiment objectives are to determine the stress, deflection, and the strain of a simply supported beam under load. Moreover, experimentally verify the beam stress and flexure formulas. In this week’s experiment we had to use the MTS machine in order to apply a load to a simply supported beam and measure the deflection and strain that comes out from it. As a result from the graphs we plotted, we saw that whenever the load increases, the deflection and strain also increases. We used the strain to find the theoretical stress in our calculations, and we also used the moment, moment of inertia, and the neutral axis to find the experimental stress. We calculated the moment of inertia, which came out to be 0.05122 . Also, we found the neutral axis to be 0515 in , and the maximum deflection also came out to be 0.000013 in. The maximum load applied on the beam came out to be 40049.5 psi, which we calculated from the maximum stress.
Table of Contents
Abstract……………………………………………………………..………..2
Table of Contents……………………………………….……………………3
Introduction and Theory…………………………………………………….4-6
Procedure………………………………………………….……………….7-9
Summary of Important Results…………………...………………………..10-12
Sample Calculations and Error Analysis……………….………………….13
Discussion and Conclusion………………………………………………..14-15
References……………………………………..…………………………….16
Appendix……………………………………………………….……………17
Introduction and Theory
Engineers use beams to support loads over a span length. These beams are structural
members that are only loaded non-axially causing them to be subjected to bending. “A piece is said to be in bending if the forces act on a piece of material in such a way that they tend to induce compressive stresses over one part of a cross section of the piece and tensile stresses over
the remaining part” (Ref. 1). This definition of bending is illustrated below in Figure 1.
It can be seen from Figure 1 that the compressive force, C, and the tensile force, T, acting on the member are equal in magnitude because of equilibrium. Therefore, the compressive force and the tensile force form a force couple whose moment is equal to either the tensile force multiplied by the moment arm or the compressive force multiplied by the moment arm. The moment arm is denoted, e, in Figure 1.
This is why structural members usually carry the center of the load into the tensile, compressive, or transverse loads. A beam usually carries the load transversely. During today’s experiment the load will be forced onto the beam in a symmetric order. We also must know that any cross section of the beam there will be a shear force V and a moment M. When we see in the middle of the beam we realize that the shear force diagram is zero and the moment reaches its maximum constant value.
When a beam is cur in to slices we see that if we want the moment the internal forces must be equal to the moment on the outside. So, M must be equal to the internal forces applied.
Thought: By the Waves-Duality PrinciplePeter Anyebe
The principles discussed here do not describe anything new, they merely reconstruct what people do intuitively,
of which they may therefore not be aware
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Discussion by ahmad_jalal_for_center_of_pressure_
1. Discussion 6.4
Discussionby ahmad jalal hasan
1-draw the relation between (hp-h(dash)) and (h).
2-discuss the relations above and the result of calculating.
When the eualsto 𝛳 = 0 hppara,ℎ 𝑝 𝑡ℎ
− ℎ−
,h are all
equal, so we can observe that this case on th e plot will
seem to be like a vertical line because theres no varity
between values of the all (h) ,this for y axis , but for y axis
as it should be because the (h)s are equal so if subtract
them thuer result will be zero ,so we wont have values as
it shoul be , when the ϴ=90 the relationbetween values
of hpprac-h- and h proportional as it shown on the plot as a
curve line not like first case,, but our last case is when
ϴ=30 the relation here in the first two pointsis inversely
proportionaland in the second and above is directly
propotionalas it seems on the plot.
2. 3-Why is the centre of pressure important?
The center of pressure is the location where the forces of
lifting force and drag forces are exerted on the fluid . It is
very important for engineers to know the center of
pressure because it allowsthem for example to evenly
balancethe lift on aircraft and planes.
4- What is the differencebetweenCentre of pressure and
Centre of gravity?
the place where the resultant vector of all the forces
acting and exerting on the body can be considered to act.
inside or outside a body, that is The center of pressure is
that point,but the center of gravity is one of the forces
that has to be taken into account and should be
considered.
5- why centre of gravity is above the centre of pressure?
If we could say this questionmore clearly "Why is
the centre of pressure below the centre of gravity for a
vertically immersed body in a fluid" the concept is If the
centre of lifting of an object which immersed in a liquidis
above the centre of gravity then the equilibriumshould be
steady and the body will retain to its own orientation.
3. 6-What are the practicalapplication and uses of Centre of
pressure?
One of the very important application is for pitch stability
of an airplaneand flying machines. This is stabilityto the
nose up, nose down Direction in the airoplane.Thisis used
when you design for example a paper airplanes.inthe
airoplanethe locationof the tail and the nose will
represent the center of gravity while the wings are
the center of pressure .
Answers by Muhammed Fuad Rashid
Discussion
Q1