II MODULE
FLUID IN MOTION
By
SINY MARY LONA
●Continuity Equation:
●Rate of Flow of Discharge(Q)
●It is defined as Quantity of fluid flowing per second through a section of a pipe or channel.
● For an Incompressible fluid :Rate of flow is usually expressed as Volume of fluid flowing across the sec
●For Compressible Fluid : Rate of flow is usually expressed as weight of fluid flowing across the section
●For Liquid Q=m3/s.
●V1= Average Velocity at 1-1
●(rho)1= Density at section1-1
●A1= Area of Cross section 1-1
●Rate of flow at 1-1=(rho)1*A1*V1
●Rate of Flow at 2-2=(rho)2*A2*V2
●Law of Conservation of Mass:
●Rate of flow at 1-1=Rate of flow at 2-2
●(rho)1*A1*V1=(rho)2*A2*V2
●For incompressible fluid(rho)1=(rho)2
●A1*V1=A2*V2
●The Diameter of a pipe at 1 and 2 are at 10cm and 15cm respectively .Find Discharge through pipe if vel
●Solution: D1=10cm=0.1m A1=0.00785m2
● D2=15cm=0.15m A2=0.01766m2
●As per Rate of Discharge
●Q=A1*V1=0.00785*5=0.0392m3
/s
●As per Continuity Equation:Q=A1*V1=A2*V2
●0.00785*5=0.01766*V2
●V2=2.22m/s
●The Velocity at section 2 V2=2.22m/s
EXPLAIN THE CONCEPT
● THANK YOU

Continuity Equation

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    II MODULE FLUID INMOTION By SINY MARY LONA
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    ●Rate of Flowof Discharge(Q) ●It is defined as Quantity of fluid flowing per second through a section of a pipe or channel. ● For an Incompressible fluid :Rate of flow is usually expressed as Volume of fluid flowing across the sec ●For Compressible Fluid : Rate of flow is usually expressed as weight of fluid flowing across the section ●For Liquid Q=m3/s.
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    ●V1= Average Velocityat 1-1 ●(rho)1= Density at section1-1 ●A1= Area of Cross section 1-1 ●Rate of flow at 1-1=(rho)1*A1*V1 ●Rate of Flow at 2-2=(rho)2*A2*V2 ●Law of Conservation of Mass: ●Rate of flow at 1-1=Rate of flow at 2-2 ●(rho)1*A1*V1=(rho)2*A2*V2 ●For incompressible fluid(rho)1=(rho)2 ●A1*V1=A2*V2
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    ●The Diameter ofa pipe at 1 and 2 are at 10cm and 15cm respectively .Find Discharge through pipe if vel ●Solution: D1=10cm=0.1m A1=0.00785m2 ● D2=15cm=0.15m A2=0.01766m2 ●As per Rate of Discharge ●Q=A1*V1=0.00785*5=0.0392m3 /s ●As per Continuity Equation:Q=A1*V1=A2*V2 ●0.00785*5=0.01766*V2 ●V2=2.22m/s ●The Velocity at section 2 V2=2.22m/s
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