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AC Analysis of
BJT and MOSFET
Inverting Amplifiers
Assoc Prof Chang Chip Hong email: echchang@ntu.edu.sg
EE2002 Analog Electronics
EE2002 Analog Electronics
Lesson Objectives
AC Analysis of BJT and MOSFET Inverting Amplifiers 2
At the end of this lesson, you should be able to:
Draw small signal model for BJT and MOSFET
Calculate the small signal parameters of BJT and MOSFET
Construct AC equivalent circuit of BJT and MOSFET inverting amplifiers
Calculate the following performance characteristics of C-E and C-S amplifiers
Voltage gain
Input resistance
Output resistance
EE2002 Analog Electronics
Hybrid-Pi Model of BJT
AC Analysis of BJT and MOSFET Inverting Amplifiers 3
This hybrid-pi small-signal model is
the intrinsic low-frequency
representation of the BJT.
Small-signal parameters are
controlled by the Q-point and are
independent of geometry of BJT.
Transconductance:
Output resistance:
ic
gmvbe
ib
E
CB
vbe r r vce
40C
m C
T
I
g I
V
where 25 mV@25 CT
kT
V
q
Input resistance:
m
r
g
++
A CE A
o
C C
V V V
r
I I
if
EE2002 Analog Electronics
Equivalent Forms of Small-Signal
Model for BJT
AC Analysis of BJT and MOSFET Inverting Amplifiers 4
Voltage-controlled current source gmvbe can be transformed into current-controlled
current source.
gmvbe
ib
E
CB
vbe
r r
ic
ib
ib
E
CB
vbe r r
ic
Basic relationship ic= ib is useful
for both dc and ac analysis when
BJT is in forward-active region.
be b
m be m b b
ce
c b b
o
v i r
g v g i r i
v
i i i
r
+ +
EE2002 Analog Electronics
VCC
E
Q
RC
RE
C1
C2
C3
B
C
RB
RC
RI
vi
RL
RI
RB2
RB1
vi
Q
C
B
E RL
+
vo
1 2B B BR R R
The ac equivalent circuit is
constructed by assuming that all
capacitances have zero
impedance at signal frequency and
dc voltage source is ac ground.
Assume that Q-point has already
been calculated from DC analysis.
Hence, gm, r and ro of BJT can
be calculated.
AC Analysis of BJT and MOSFET Inverting Amplifiers 5
Small Signal Analysis of C-E Amplifier
with Fully Bypass RE
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 6
C-E Amplifier with Fully Bypass RE:
Voltage Gain
c o m be L
vt m L
b be be
v v g v R
A g R
v v v
Terminal voltage gain between
base and collector is:
Overall voltage gain from source vi
to output voltage vo across RL is:
o c b b
v vt
i b i i
v v v v
A A
v v v v
RI
vi RB ro RL
+
vo
B C
E
r
RC
gmvbe
+
vbe
0L C L
R r R R
B
v m L
I B
R r
A g R
R R r
B
R r
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 7
C-E Amplifier with Fully Bypass RE:
Input Resistance
C1
VCC
1 2B B BR R R
RI
RB2
vi
Q
RB1
RC C2
C3
RL
Rin
vx
ix
RE
x x B
x
in
x
B
v i R r
v
R
i
R r
RB r ro RL
+
vo
B C
E
RC
gmvbe
+
vbe
B
R r
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 8
C-E Amplifier with Fully Bypass RE:
Output Resistance
C1
0
x x
x m be
C o
x x
be x
C o
v v
i g v
R r
v v
v i
R r
VCC
RI
Q
RB2
RB1 C2
C3
RL
Rour
1 2B B BR R R
vxRB ro
RI
B C
E
r RC
gmvbe
+
vbe
ix
RE
RC
vi
1
1 1x
out C o
x C o
out C
v
R R r
i R r
R R if
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 9
C-E Amplifier with Fully Bypass RE:
Example
Problem: Find voltage gain, input
and output resistances.
Given: = 65, VA = 50 V
Find the Q-point from dc equivalent circuit:
3 3
100 10 0.7 66 16 10 ( 5) 0B BI I
3.71
65 241
66 245
B
C B
E B
I
I I
I I
5 10 k 241 CEV
+5 V
10 k
voRout
RC
C3
C1
Rin
vi
+
220 k
RB
100 k
RE
16 k
330
RI
5 V
RL
C2
+5 V
10 k
IC
VCE
+
IE
16 k
5 V
100 k VBE
+
IB
3.67 VCEV
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 10
AC Analysis of C-E Amplifier with
Fully Bypass RE
9.64 (223 10 220) 6.23 k
84.0
330 6.23 k
bein
v vt
I in be
vR
A A
R R v
40 241mg
65
6.64 k
9.64 m
r
50 3.67
223 k
241
or
100 k 6.64 k 6.23 kinR
223 k 10 k 9.57 koutR
330
vi
100k
ro
220k
+
vo
B C
E
r
10k
gmvbe
+
vbe
Rin
100k
223k
220k
B C
E
6.64k
10k
9.64mvbe9.64mvbe
Rout
100k
223k
330
B C
E
6.64k
10k
Small signal equivalent
EE2002 Analog Electronics
Small Signal Parameters of MOSFET
AC Analysis of BJT and MOSFET Inverting Amplifiers 11
Since gate is insulated from channel
by gate-oxide, input resistance = .
Small-signal parameters are
controlled by the Q-point.
MOSFET transconductance is
geometry dependent.
2
1
2
1
n
D GS TN DS
D
m n GS TN DS
GS Q pt
K
i v V v
i
g K V V V
v
n n OX
W
K C
L
where
+
gmvgs
ig
S
DG
vgs r
id
vds
+
2
2
1
1
D
m n D
GS TN
DS
o
D D
I
g K I
V V
V
r
I I
if
1
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 12
Small Signal Analysis of C-S
Amplifier with Fully Bypass RS
VDD
S
AC equivalent circuit is constructed by
assuming that all capacitances have zero
impedance at signal frequency and dc
voltage sources represent ac grounds. M
RD
RS
C1
C2
C3
G
D
RG
RD
RI
vi
RL
RI
RG2
RG1
vi
D
MG
S RL
+
vo
1 2G G GR R R
vo
The small signal parameters, gm and ro of
the MOSFET is calculated at the Q-point,
ID and VDS.
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 13
C-S Amplifier with Fully Bypass RS:
Voltage Gain
Terminal voltage gain between
gate and drain is:
Overall voltage gain from source vi
to output voltage vo across RL is:
RI
vi RG ro RL
+
vo
G D
S
RD
gmvgs
+
vgs
0L D LR r R R
m gs Ld
vt m L
g gs
g v Rv
A g R
v v
g go o
v vt
i g i i
G
m L
I G
v vv v
A A
v v v v
R
g R
R R
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 14
C-S Amplifier with Fully Bypass RS:
Input Resistance
RG2
M
RG1
RD
RS
C2
C3
RL
Rin
C1
RG ro RL
+
vo
G D
S
RD
gmvgs
+
vgs
1 2G G GR R R
VDD
RI
vi
x x G
x
in
x
G
v i R
v
R
i
R
vx
ix
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 15
C-S Amplifier with Fully Bypass RS:
Output Resistance
vi
VDD
C1
Since vgs = 0, gmvgs = 0.
RI
RG2
RG1 C2
Rour
RS
RD
RL
M
gmvgs
vxRG ro
RI
G D
S
RD
+
vgs
ix
C3
21 GG G
R R R
x x D o
x
out D o
x
out D
v i R r
v
R R r
i
R R if
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 16
C-S Amplifier with Fully Bypass RS:
Example
Problem: Find voltage gain, input and
output resistances.
Given: Kn = 500 A/V2, VTN = 1V,
= 0.0167 V 1
DC Analysis:
61
1
6
5 10
2 10
0.4
S
GS
D
DS
I
IV
V
V
5 , 2 , 250DS GS DV V V V I
2500
1
2
GSD VI (1)
3
110 20 10DS D IV I (2)
+10 V
20 k
C3
vo
+Rout
100 k
RL
RD
RG3
1 M
RG2 2 M
RG1 2 M
C2
C1
10 k
RI
Rin
vi
+10 V
20 k
RG3
1 M
RG2
2 M
RG1
2 M
vDS
+
+
vGS
I1
ID
IG
RD
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 17
C-S Amplifier with Fully Bypass RS:
Example
0.5 260 k 1 M 20 k 100 k 1 M
7.93
10 k 1 M
gsin
v vt
I in gs
m vR
A A
R R v
2 2 1inR M M M
2 500m
g
1
5
0.0167 260 k
250
or
10k
vi
2M
ro
100k
+
vo
G
D
S
1M
gmvgs
+
vgs
2M
20k
Rin
1M
260k
16.4k
G D
S
0.5mvgs
0.5mvgs
S
Rout
1M
260k
10k
G D
1M
20k
260 1 20 18.2outR k M k k
16.4 k1 M
Small Signal Equivalent Circuit:
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 18
C-E Amplifier with Unbypass RE:
Terminal Voltage Gain
VCC
RB2
RB1
RC
RE2 C3
RI
vi
RL
C2
C1
vo
RE1
Q
vi RB
RL
+
voRC
ro
B C
E
r
gmvbe
+
vbe
RI
RE1
ic
L C LR R R
1 1 11
c c L m be L m L
vt
b be e E be m be E m E
v i R g v R g R
A
v v i R v g v R g R
ie
1 2B B BR R R
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 19
C-E Amplifier with Unbypass RE:
Input Resistance
vi
RI
1
1
1
1
b b b E
b
in E
b
v i r i R
v
R r R
i
Rin
vb RB
RL
+
voRC
ro
B C
E
r
ib
+
vbe
RE1
( +1)ib
ib
Rin
in in BR R R
inR
RB
RL
+
voRC
ro
B C
E
r
gmvbe
+
vbe
RE1
1 2B B BR R R
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 20
C-E Amplifier with Unbypass RE:
Overall Voltage Gain
+
vbRin
RB = RB1 || RB2
RL
+
voRC
ro
B C
E
r
gmvbe
+
vbe
RE1
Rin
VCC
RB2
RB1
RC
RE2 C3
RI
vi
RL
C2
C1
vo
RE1
Q
o o b in
v vt
i b i I in
v v v R
A A
v v v R R
vi
RI
Rin
vi
RI
+
vbRin
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 21
C-E Amplifier with Unbypass RE:
Output Resistance
Rth
RC
ro
B C
E
r
gmvbe
+
vbe
RE1
vx
ix
Rout
1 2th I B BR R R R
ix
1
be e
th
x th E
th
r
v v
r R
r
i r R R
r R1e x th Ev i r R R
x m bex o ev g v r vi
current through ro
outR
RL
+
vo
RI
RB
RC
ro
B C
E
r
gmvbe
+
vbe
RE1
1 2B B BR R R
Rout
vi
EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 22
C-E Amplifier with Unbypass RE:
Output Resistance
1
1
x x m be o e
x m x th E o
th
x th E
v i g v r v
r
i g i r R R r
r R
i r R RRth
ro
B C
E
r
gmvbe
+
vbe
RE1
vx
ix
ix
out out CR R R
RC
Rout
11x
out m th E o
x th
v r
R g r R R r
i r R
outR

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Common Emitter circuit

  • 1. AC Analysis of BJT and MOSFET Inverting Amplifiers Assoc Prof Chang Chip Hong email: echchang@ntu.edu.sg EE2002 Analog Electronics
  • 2. EE2002 Analog Electronics Lesson Objectives AC Analysis of BJT and MOSFET Inverting Amplifiers 2 At the end of this lesson, you should be able to: Draw small signal model for BJT and MOSFET Calculate the small signal parameters of BJT and MOSFET Construct AC equivalent circuit of BJT and MOSFET inverting amplifiers Calculate the following performance characteristics of C-E and C-S amplifiers Voltage gain Input resistance Output resistance
  • 3. EE2002 Analog Electronics Hybrid-Pi Model of BJT AC Analysis of BJT and MOSFET Inverting Amplifiers 3 This hybrid-pi small-signal model is the intrinsic low-frequency representation of the BJT. Small-signal parameters are controlled by the Q-point and are independent of geometry of BJT. Transconductance: Output resistance: ic gmvbe ib E CB vbe r r vce 40C m C T I g I V where 25 mV@25 CT kT V q Input resistance: m r g ++ A CE A o C C V V V r I I if
  • 4. EE2002 Analog Electronics Equivalent Forms of Small-Signal Model for BJT AC Analysis of BJT and MOSFET Inverting Amplifiers 4 Voltage-controlled current source gmvbe can be transformed into current-controlled current source. gmvbe ib E CB vbe r r ic ib ib E CB vbe r r ic Basic relationship ic= ib is useful for both dc and ac analysis when BJT is in forward-active region. be b m be m b b ce c b b o v i r g v g i r i v i i i r + +
  • 5. EE2002 Analog Electronics VCC E Q RC RE C1 C2 C3 B C RB RC RI vi RL RI RB2 RB1 vi Q C B E RL + vo 1 2B B BR R R The ac equivalent circuit is constructed by assuming that all capacitances have zero impedance at signal frequency and dc voltage source is ac ground. Assume that Q-point has already been calculated from DC analysis. Hence, gm, r and ro of BJT can be calculated. AC Analysis of BJT and MOSFET Inverting Amplifiers 5 Small Signal Analysis of C-E Amplifier with Fully Bypass RE
  • 6. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 6 C-E Amplifier with Fully Bypass RE: Voltage Gain c o m be L vt m L b be be v v g v R A g R v v v Terminal voltage gain between base and collector is: Overall voltage gain from source vi to output voltage vo across RL is: o c b b v vt i b i i v v v v A A v v v v RI vi RB ro RL + vo B C E r RC gmvbe + vbe 0L C L R r R R B v m L I B R r A g R R R r B R r
  • 7. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 7 C-E Amplifier with Fully Bypass RE: Input Resistance C1 VCC 1 2B B BR R R RI RB2 vi Q RB1 RC C2 C3 RL Rin vx ix RE x x B x in x B v i R r v R i R r RB r ro RL + vo B C E RC gmvbe + vbe B R r
  • 8. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 8 C-E Amplifier with Fully Bypass RE: Output Resistance C1 0 x x x m be C o x x be x C o v v i g v R r v v v i R r VCC RI Q RB2 RB1 C2 C3 RL Rour 1 2B B BR R R vxRB ro RI B C E r RC gmvbe + vbe ix RE RC vi 1 1 1x out C o x C o out C v R R r i R r R R if
  • 9. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 9 C-E Amplifier with Fully Bypass RE: Example Problem: Find voltage gain, input and output resistances. Given: = 65, VA = 50 V Find the Q-point from dc equivalent circuit: 3 3 100 10 0.7 66 16 10 ( 5) 0B BI I 3.71 65 241 66 245 B C B E B I I I I I 5 10 k 241 CEV +5 V 10 k voRout RC C3 C1 Rin vi + 220 k RB 100 k RE 16 k 330 RI 5 V RL C2 +5 V 10 k IC VCE + IE 16 k 5 V 100 k VBE + IB 3.67 VCEV
  • 10. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 10 AC Analysis of C-E Amplifier with Fully Bypass RE 9.64 (223 10 220) 6.23 k 84.0 330 6.23 k bein v vt I in be vR A A R R v 40 241mg 65 6.64 k 9.64 m r 50 3.67 223 k 241 or 100 k 6.64 k 6.23 kinR 223 k 10 k 9.57 koutR 330 vi 100k ro 220k + vo B C E r 10k gmvbe + vbe Rin 100k 223k 220k B C E 6.64k 10k 9.64mvbe9.64mvbe Rout 100k 223k 330 B C E 6.64k 10k Small signal equivalent
  • 11. EE2002 Analog Electronics Small Signal Parameters of MOSFET AC Analysis of BJT and MOSFET Inverting Amplifiers 11 Since gate is insulated from channel by gate-oxide, input resistance = . Small-signal parameters are controlled by the Q-point. MOSFET transconductance is geometry dependent. 2 1 2 1 n D GS TN DS D m n GS TN DS GS Q pt K i v V v i g K V V V v n n OX W K C L where + gmvgs ig S DG vgs r id vds + 2 2 1 1 D m n D GS TN DS o D D I g K I V V V r I I if 1
  • 12. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 12 Small Signal Analysis of C-S Amplifier with Fully Bypass RS VDD S AC equivalent circuit is constructed by assuming that all capacitances have zero impedance at signal frequency and dc voltage sources represent ac grounds. M RD RS C1 C2 C3 G D RG RD RI vi RL RI RG2 RG1 vi D MG S RL + vo 1 2G G GR R R vo The small signal parameters, gm and ro of the MOSFET is calculated at the Q-point, ID and VDS.
  • 13. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 13 C-S Amplifier with Fully Bypass RS: Voltage Gain Terminal voltage gain between gate and drain is: Overall voltage gain from source vi to output voltage vo across RL is: RI vi RG ro RL + vo G D S RD gmvgs + vgs 0L D LR r R R m gs Ld vt m L g gs g v Rv A g R v v g go o v vt i g i i G m L I G v vv v A A v v v v R g R R R
  • 14. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 14 C-S Amplifier with Fully Bypass RS: Input Resistance RG2 M RG1 RD RS C2 C3 RL Rin C1 RG ro RL + vo G D S RD gmvgs + vgs 1 2G G GR R R VDD RI vi x x G x in x G v i R v R i R vx ix
  • 15. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 15 C-S Amplifier with Fully Bypass RS: Output Resistance vi VDD C1 Since vgs = 0, gmvgs = 0. RI RG2 RG1 C2 Rour RS RD RL M gmvgs vxRG ro RI G D S RD + vgs ix C3 21 GG G R R R x x D o x out D o x out D v i R r v R R r i R R if
  • 16. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 16 C-S Amplifier with Fully Bypass RS: Example Problem: Find voltage gain, input and output resistances. Given: Kn = 500 A/V2, VTN = 1V, = 0.0167 V 1 DC Analysis: 61 1 6 5 10 2 10 0.4 S GS D DS I IV V V 5 , 2 , 250DS GS DV V V V I 2500 1 2 GSD VI (1) 3 110 20 10DS D IV I (2) +10 V 20 k C3 vo +Rout 100 k RL RD RG3 1 M RG2 2 M RG1 2 M C2 C1 10 k RI Rin vi +10 V 20 k RG3 1 M RG2 2 M RG1 2 M vDS + + vGS I1 ID IG RD
  • 17. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 17 C-S Amplifier with Fully Bypass RS: Example 0.5 260 k 1 M 20 k 100 k 1 M 7.93 10 k 1 M gsin v vt I in gs m vR A A R R v 2 2 1inR M M M 2 500m g 1 5 0.0167 260 k 250 or 10k vi 2M ro 100k + vo G D S 1M gmvgs + vgs 2M 20k Rin 1M 260k 16.4k G D S 0.5mvgs 0.5mvgs S Rout 1M 260k 10k G D 1M 20k 260 1 20 18.2outR k M k k 16.4 k1 M Small Signal Equivalent Circuit:
  • 18. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 18 C-E Amplifier with Unbypass RE: Terminal Voltage Gain VCC RB2 RB1 RC RE2 C3 RI vi RL C2 C1 vo RE1 Q vi RB RL + voRC ro B C E r gmvbe + vbe RI RE1 ic L C LR R R 1 1 11 c c L m be L m L vt b be e E be m be E m E v i R g v R g R A v v i R v g v R g R ie 1 2B B BR R R
  • 19. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 19 C-E Amplifier with Unbypass RE: Input Resistance vi RI 1 1 1 1 b b b E b in E b v i r i R v R r R i Rin vb RB RL + voRC ro B C E r ib + vbe RE1 ( +1)ib ib Rin in in BR R R inR RB RL + voRC ro B C E r gmvbe + vbe RE1 1 2B B BR R R
  • 20. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 20 C-E Amplifier with Unbypass RE: Overall Voltage Gain + vbRin RB = RB1 || RB2 RL + voRC ro B C E r gmvbe + vbe RE1 Rin VCC RB2 RB1 RC RE2 C3 RI vi RL C2 C1 vo RE1 Q o o b in v vt i b i I in v v v R A A v v v R R vi RI Rin vi RI + vbRin
  • 21. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 21 C-E Amplifier with Unbypass RE: Output Resistance Rth RC ro B C E r gmvbe + vbe RE1 vx ix Rout 1 2th I B BR R R R ix 1 be e th x th E th r v v r R r i r R R r R1e x th Ev i r R R x m bex o ev g v r vi current through ro outR RL + vo RI RB RC ro B C E r gmvbe + vbe RE1 1 2B B BR R R Rout vi
  • 22. EE2002 Analog Electronics AC Analysis of BJT and MOSFET Inverting Amplifiers 22 C-E Amplifier with Unbypass RE: Output Resistance 1 1 x x m be o e x m x th E o th x th E v i g v r v r i g i r R R r r R i r R RRth ro B C E r gmvbe + vbe RE1 vx ix ix out out CR R R RC Rout 11x out m th E o x th v r R g r R R r i r R outR