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Circular 
MEASURES 
STANDARD 9
r 
Perimeter of a circle is 
2пr 
П ≈3.141
A 
B 
AB is part of the circle ,it is known as Arc
A 
B 
O 
The angle made by joining the end points of an arc to 
the center of the circle is called the central angle of 
an arc. 
Eg: angle AOB is the central angle of the arc AB
For an arc of central angle x°, 
arc length =2пr × x/360 
r = radius of the circle
If we draw regular polygons with more 
and more sides within the circle, their 
areas would get closer and closer to 
the area of the circle.
By joining the vertices of the polygon to the center 
of the circle, we can divide the polygon into 
triangles 
The area of the polygon is the sum of the 
areas of these triangles; and all these triangles 
are congruent. So we need only multiply the 
area of one triangle by the number of triangle.
To find the area of the 
Dtrriaawn gtlhee perpendicular from the center of the 
circle to a side of the polygon 
h 
s 
Area of the triangle is 
½ × s × h = 1/2sh
If the polygon has n sides, then 
its area is 
n × 1/2 × sh = ½ n s h 
n s is the sum of all sides of 
the polygon ie. Perimeter so we 
can denote p= ns 
Therefore , 
Area of the Polygon = 
½ ph
Thus as the number of sides of the 
polygon increases, in the area 
½ ph of the polygon, the perimeter gets 
closer and closer to the perimeter of 
the circle and the perpendicular 
distance h gets closer and closer to the 
radius of the circle. 
Thus 
area of the circle = ½ × perimeter of 
the circle 
× radius
Area of the circle =1/2 × 2п× radius (r)× radius 
= п푟2
Circular measures

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Circular measures

  • 2.
  • 3.
  • 4. r Perimeter of a circle is 2пr П ≈3.141
  • 5. A B AB is part of the circle ,it is known as Arc
  • 6. A B O The angle made by joining the end points of an arc to the center of the circle is called the central angle of an arc. Eg: angle AOB is the central angle of the arc AB
  • 7. For an arc of central angle x°, arc length =2пr × x/360 r = radius of the circle
  • 8. If we draw regular polygons with more and more sides within the circle, their areas would get closer and closer to the area of the circle.
  • 9. By joining the vertices of the polygon to the center of the circle, we can divide the polygon into triangles The area of the polygon is the sum of the areas of these triangles; and all these triangles are congruent. So we need only multiply the area of one triangle by the number of triangle.
  • 10. To find the area of the Dtrriaawn gtlhee perpendicular from the center of the circle to a side of the polygon h s Area of the triangle is ½ × s × h = 1/2sh
  • 11. If the polygon has n sides, then its area is n × 1/2 × sh = ½ n s h n s is the sum of all sides of the polygon ie. Perimeter so we can denote p= ns Therefore , Area of the Polygon = ½ ph
  • 12. Thus as the number of sides of the polygon increases, in the area ½ ph of the polygon, the perimeter gets closer and closer to the perimeter of the circle and the perpendicular distance h gets closer and closer to the radius of the circle. Thus area of the circle = ½ × perimeter of the circle × radius
  • 13. Area of the circle =1/2 × 2п× radius (r)× radius = п푟2