This document defines IPv4 addressing and network prefixes. It discusses IP address classes and ranges, public and private IP addresses, subnet masks, calculating network addresses, broadcasts and host ranges from a given IP address and prefix length. Examples are provided to illustrate how to determine the network address, broadcast address, and host range for a subnet. The document also discusses subnetting an IP network into multiple subnets.
IP Addressing and Subnetting
1. Write the default Masks for the Class A, Class B and Class C IP addresses.
2. How we can distinguish Class A, Class B, Class C, Class D and Class E IP addresses from each other. Write the range of first octet in decimal and Binary for all the 5 IP address classes.
3. Write the default subnet Masks for the following IP addresses:
4. Write down the three available ranges for assigning Private IP addresses recommended by IANA (Internet Assigned Number Authority).
5. A broadcast address is the one that addresses to all the hosts in any network. State that to create a broadcast address, all the bits of network ID portion or all the bits of host ID portion are set to 1? Write down the broadcast addresses of the networks to which the following IP addresses belong, write network addresses and ranges of their valid IP address too. (No subnetting).
6. Subnet Mask or Custom mask tells us that how many bits are used for Subnet ID portion and how many for host ID portion. Identify how many bits are used for sub netting in the following IP address using its subnet mask:
7. Extract the Network Addresses of the given IP addresses in question number 8, using the subnet masks given with them. (Remember that ANDing the IP address with the Mask extracts the network address from the given IP address).
8. Suppose you have a class C Network 208.94.115.0. Your task is to design a subnet scheme so that we can create 16 Network segments (subnets) within this Network. Each subnet should support 10-14 hosts.
9. Suppose you have a class C Network 220.94.115.0. Your task is to design a subnet scheme so that we can create 28 Network segments (subnets) within this Network. Each subnet should support hosts as given below.
• 2 Network Segment support 30 Hosts
• 4 Network Segment support 14 Hosts
• 8 Network Segment support 6 Hosts
• 14 Network Segment support 2 Hosts
This Presentation will give you about basic IPv4 and IPv6 addressing, Subnetting and NAT process. As much as possible the informations was tried to be summarized and a slideshow of visual weight was made. You can contact the e-mail address in the slide to get information about the yours issue or correct my any mistakes.
Complete understanding of subnet masking
also available on the youtube channal in three parts 1,2,3
link:-
https://www.youtube.com/channel/UC36lyOTi8w1EhQ-yZssjX1g?view_as=subscriber.
Here is the presentation for Network Layer Numericals from the book Andrew S. Tanenbaum (Computer Networks) and B A Forouzan ( Data Communication and Networking)
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1. Addressing the Network
IPv4
Group 4 :
Yuli Artika (3311201021)
Adithya Widi Maulana (3311201022)
Indita Brayudi (3311201023)
Ipan Handoko (3311201024)
Christ Yana (3311201025)
Robby Gusnaldy (3311201026)
2. Definition
IP v4
Alamat perangkat
untuk komunikasi antar network
4 byte atau 32 bit atau 4 octet
ex : 10101100000100000000010000010100
Dotted Decimal
ex : 172.16.4.20
Terdiri dari Network Portion(high-order bits) dan Host
Portion(low-order bits)
172.16.4.20
Network
Portion
Host
Portion
10. Definition
Kelas IP Range Porsi Default Subnet
A 1-127 N-H-H-H 255.0.0.0
B 128-191 N-N-H-H 255.255.0.0
C 192-223 N-N-N-H 255.255.255.0
D 224-239 NA(multicast)
E 240-255 NA(experimental)
N : Network
H : Host
17. Subnet Mask
Contoh : /24 = 24 bits pertama adalah network address, 8
bits adalah host
11111111.11111111.11111111.00000000
255.255.255.0
Contoh : /27 = 27 bits pertama adalah network address, 5
bits adalah host
11111111.11111111.11111111.11100000
255.255.255.(128+64+32+0+0+0+0+0) = 255.255.255.224
18. How to get the Network Address
Calculating Network, Host, Broadcast
172.16.20.0 /25
IP
Subnet Mask
Network Address
Broadcast
Host Min
Host Max
Range
19. How to get the Network Address
Langkah - Langkah :
1 . Ubah IP desimal menjadi IP biner
Desimal 172 16 20 0
Biner 10101100 00010000 00010100 00000000
Langkah - Langkah :
2. Terjemahkan subnet kedalam biner
/25
Biner 11111111 11111111 11111111 10000000
20. How to get the Network Address
Dengan melakukan operasi AND
172.16.20.0 /25
IP 10101100 00010000 00010100 00000000
Subnet Mask 11111111 11111111 11111111 10000000
Network
Address
Broadcast
Host Min
Host Max
Range
21. How to get the Network Address
Langkah - Langkah :
3. Lakukan Operasi AND
Operasi AND digunakan untuk mendapatkan Network Address
IP 10101100 00010000 00010100 00000000
Subnet 11111111 11111111 11111111 10000000
AND
Network
Address
10101100 00010000 00010100 00000000
172 16 20 0
22. How to get the Network Address
Calculating Network, Host, Broadcast
172.16.20.0 /25
IP 10101100 00010000 00010100 00000000
Subnet Mask 11111111 11111111 11111111 10000000
Network
Address
172 16 20 0
Broadcast
Host Min
Host Max
Range
23. How to get the Network Address
Langkah - Langkah :
4. Menghitung Broadcast
Network ID 10101100 00010000 00010100 00000000
Subnet 11111111 11111111 11111111 10000000
Broadcast
10101100 00010000 00010100 01111111
172 16 20 127
24. How to get the Network Address
Calculating Network, Host, Broadcast
172.16.20.0 /25
IP 10101100 00010000 00010100 00000000
Subnet Mask 11111111 11111111 11111111 10000000
Network
Address
172 16 20 0
Broadcast 172 16 20 127
Host Min
Host Max
Range
25. How to get the Network Address
Langkah - Langkah :
5. Menetukan Host Min
Rumus : Network ID + 1
Network ID 172 16 20 0
1
Host Min 172 16 20 1
26. How to get the Network Address
Calculating Network, Host, Broadcast
172.16.20.0 /25
IP 10101100 00010000 00010100 00000000
Subnet Mask 11111111 11111111 11111111 10000000
Network
Address
172 16 20 0
Broadcast 172 16 20 127
Host Min 172 16 20 1
Host Max
Range
27. How to get the Network Address
Langkah - Langkah :
6. Menetukan Host Max
Rumus : Broadcast - 1
Broadcast 172 16 20 127
1
Host Max 172 16 20 126
28. How to get the Network Address
Calculating Network, Host, Broadcast
172.16.20.0 /25
IP 10101100 00010000 00010100 00000000
Subnet Mask 11111111 11111111 11111111 10000000
Network
Address
172 16 20 0
Broadcast 172 16 20 127
Host Min 172 16 20 1
Host Max 172 16 20 126
Range
29. How to get the Network Address
Langkah - Langkah :
7. Menetukan Range
Rumus : Host Min – Host Max
Host Min 172 16 20 1
until
Host Max 172 16 20 126
Range 172.16.20.1 – 172.16.20.126
30. How to get the Network Address
Calculating Network, Host, Broadcast
172.16.20.0 /25
IP 10101100 00010000 00010100 00000000
Subnet Mask 11111111 11111111 11111111 10000000
Network
Address
172 16 20 0
Broadcast 172 16 20 127
Host Min 172 16 20 1
Host Max 172 16 20 126
Range 172.16.20.1 – 172.16.20.126
32. Subnetting
Soal 192.168.1.0 /24
-Membuat 3 buah subnet dari IP tersebut
Langkah – Langkah :
1. Gunakan rumus 2n
22 = 4 karena mendekati angka 3
/24 + 2 = /26
subnet yang akan dibuat nanti menjadi /26
subnet : 11111111 11111111 11111111 11000000
/26 = 64 host
33. Subnetting
Soal 192.168.1.0 /24
-Membuat 3 buah subnet dari IP tersebut
Network ID Range Broadcast
192.168.1.0 1-62 63
192.168.1.64 65-126 127
192.168.1.128 129-190 191
192.168.1.192 193-254 255