The document provides information on subnetting the IP address blocks 192.168.30.0/24, 192.168.50.0/23, and 192.168.0.0/22 to create two subnets (Subnet A and Subnet B) that satisfy specific host requirements. It asks the reader to determine the subnet calculations for Subnet A and Subnet B in each case, including the subnet specification, new IP mask, maximum subnets, number of IPs and hosts per subnet, subnet addresses, and host addresses. No subnet calculators are permitted.

1. Question 1: Given the IP address block of 192.168.30.0/24, design an IP addressing scheme that satisfies
the following requirements:
■ Subnet A has 100 hosts.
■ Subnet B has 50 hosts.
■ Subnet zero is used.
■ Create the smallest possible subnets that satisfy the
requirements for hosts.
■ No subnet calculators may be used.
1) Subnet Calculations for Subnet A is provided.
Subnet Specification Calculation
Number of bits in the subnet 25
New IP mask (binary) 1111 1111. 1111 1111 . 1111 1111 . 1000 0000
New IP mask (decimal) 255.255.255.128
Maximum number of usable subnets 2
(including the 0 subnet)
Number of IP per subnet 128
Number of usable hosts per subnet 126
IP subnetwork address 192.168.30.0
First IP host address 192.168.30.1
Last IP host address 192.168.30.126
Broadcast IP address 192.168.30.127
Next subnet IP address 192.168.30.128
Next subnet IP host address 192.168.30.129
Next subnet IP host last address 192.168.30.254
2) What is the Subnet Calculations for Subnet B
Subnet Specification Calculation
Number of bits in the subnet 26
New IP mask (binary) 1111 1111. 1111 1111 . 1111 1111 . 1100 0000
New IP mask (decimal) 255.255.255.192
Maximum number of usable subnets 4
(including the 0 subnet)
Number of IP per subnet 64
Number of usable hosts per subnet 62
IP subnetwork address 192.168.30.128
First IP host address 192.168.30.129
Last IP host address 192.168.30.158
Broadcast IP address 192.168.30.159
Next subnet IP address 192.168.30.160
Next subnet IP host address 192.168.30.161
Next subnet IP host last address 192.168.30.174

2. Question 2: Given the IP address block of 192.168.30.0/24, design an IP addressing scheme that satisfies
the following requirements:
■ Subnet A has 50 hosts.
■ Subnet B has 100 hosts.
■ Subnet zero is used.
■ Create the smallest possible subnets that satisfy the
requirements for hosts.
■ No subnet calculators may be used.
1) Subnet Calculations for Subnet A is provided.
Subnet Specification Calculation
Number of bits in the subnet 26
New IP mask (binary) 1111 1111. 1111 1111 . 1111 1111 . 1100 0000
New IP mask (decimal) 255.255.255.192
Maximum number of usable subnets 4
(including the 0 subnet)
Number of IP per subnet 64
Number of usable hosts per subnet 62
IP subnetwork address 192.168.30.128
First IP host address 192.168.30.129
Last IP host address 192.168.30.158
Broadcast IP address 192.168.30.159
Next subnet IP address 192.168.30.160
Next subnet IP host address 192.168.30.161
Next subnet IP host last address 192.168.30.174
2) What is the Subnet Calculations for Subnet B
Subnet Specification Calculation
Number of bits in the subnet 25
New IP mask (binary) 1111 1111. 1111 1111 . 1111 1111 . 1000 0000
New IP mask (decimal) 255.255.255.128
Maximum number of usable subnets 2
(including the 0 subnet)
Number of IP per subnet 128
Number of usable hosts per subnet 126
IP subnetwork address 192.168.30.0
First IP host address 192.168.30.1
Last IP host address 192.168.30.126
Broadcast IP address 192.168.30.127
Next subnet IP address 192.168.30.128
Next subnet IP host address 192.168.30.129
Next subnet IP host last address 192.168.30.254

3. Question 3: Given the IP address block of 192.168.50.0/23, design an IP addressing scheme that satisfies
the following requirements:
■ Subnet A has 200 hosts.
■ Subnet B has 50 hosts.
■ Subnet zero is used.
■ Create the smallest possible subnets that satisfy the
requirements for hosts.
■ No subnet calculators may be used.
1) Subnet Calculations for Subnet A is provided.
Subnet Specification Calculation
Number of bits in the subnet 24
New IP mask (binary) 1111 1111. 1111 1111 . 1111 1111 . 0000 0000
New IP mask (decimal) 255.255.255.0
Maximum number of usable subnets 2
(including the 0 subnet)
Number of IP per subnet 256
Number of usable hosts per subnet 254
IP subnetwork address 192.168.50.0
First IP host address 192.168.50.1
Last IP host address 192.168.50.254
Broadcast IP address 192.168.50.255
Next subnet IP address 192.168.51.0
Next subnet IP host address 192.168.51.1
Next subnet IP host last address 192.168.51.254
2) Subnet Calculations for Subnet A is provided.
Subnet Specification Calculation
Number of bits in the subnet 23
New IP mask (binary) 1111 1111. 1111 1111 . 1111 1111 . 1110 0000
New IP mask (decimal) 255.255.255.128
Maximum number of usable subnets 8
(including the 0 subnet)
Number of IP per subnet 64
Number of usable hosts per subnet 62
IP subnetwork address 192.168.51.0
First IP host address 192.168.51.1
Last IP host address 192.168.51.62
Broadcast IP address 192.168.51.63
Next subnet IP address 192.168.51.64
Next subnet IP host address 192.168.51.65
Next subnet IP host last address 192.168.51.126

4. Question 4: Given the IP address block of 192.168.0.0/22, design an IP addressing scheme that satisfies
the following requirements:
■ Subnet A has 500 hosts.
■ Subnet B has 200 hosts.
■ Subnet zero is used.
■ Create the smallest possible subnets that satisfy the
requirements for hosts.
■ No subnet calculators may be used.
1) Subnet Calculations for Subnet A is provided.
Subnet Specification Calculation
Number of bits in the subnet
New IP mask (binary)
New IP mask (decimal)
Maximum number of usable subnets
(including the 0 subnet)
Number of IP per subnet
Number of usable hosts per subnet
IP subnetwork address
First IP host address
Last IP host address
Broadcast IP address
Next subnet IP address
Next subnet IP host address
Next subnet IP host last address
2) Subnet Calculations for Subnet A is provided.
Subnet Specification Calculation
Number of bits in the subnet
New IP mask (binary)
New IP mask (decimal)
Maximum number of usable subnets
(including the 0 subnet)
Number of IP per subnet
Number of usable hosts per subnet
IP subnetwork address
First IP host address
Last IP host address
Broadcast IP address
Next subnet IP address
Next subnet IP host address
Next subnet IP host last address

5. Question 5: Given the IP address block of 192.168.64.0/25, design an IP addressing scheme that satisfies
the following requirements:
■ Subnet A has 50 hosts.
■ Subnet B has 20 hosts.
■ Subnet zero is used.
■ Create the smallest possible subnets that satisfy the
requirements for hosts.
■ No subnet calculators may be used.
1) Subnet Calculations for Subnet A is provided.
Subnet Specification Calculation
Number of bits in the subnet
New IP mask (binary)
New IP mask (decimal)
Maximum number of usable subnets
(including the 0 subnet)
Number of IP per subnet
Number of usable hosts per subnet
IP subnetwork address
First IP host address
Last IP host address
Broadcast IP address
Next subnet IP address
Next subnet IP host address
Next subnet IP host last address
2) Subnet Calculations for Subnet A is provided.
Subnet Specification Calculation
Number of bits in the subnet
New IP mask (binary)
New IP mask (decimal)
Maximum number of usable subnets
(including the 0 subnet)
Number of IP per subnet
Number of usable hosts per subnet
IP subnetwork address
First IP host address
Last IP host address
Broadcast IP address
Next subnet IP address
Next subnet IP host address
Next subnet IP host last address