The document outlines construction details for one-room and two-room buildings, including methods for concrete work and brickwork in foundations and walls using center line and separate wall methods. It provides calculations for quantities of concrete and brickwork required for various components of the structures. The specifications include dimensions and thicknesses for foundations and walls.

1. Prepared by:-
Er. Simarpreet Singh
A.P, Civil Engg.
ACET, Amritsar

2. TABLE OF CONTENTS
 One Room Building
 Concrete work in foundation (Center line and
separate wall method)
 Brickwork in footing (Center line and separate wall
method)
 Brickwork in walls (Center line and separate wall
method)
 Two Rooms Building
 Concrete work in foundation (Center line and
separate wall method)

4. 5m
4m
0.3m
0.3m
0.5m
0.6m
0.9m
0.4m
0.6m
3.5m
Section at A-A’ and B-B’
Thickness of footing and foundation is 30 cm each
A
A’
B B’
Plan

5. 0.9 m
5.3m
4.3 m
Total Center line = 5.3+5.3+4.3+4.3=19.2 m
Width = 0.9 m Total Qty of concrete in foundation= (19.2×0.9×0.3) cum
Center Line Method

6. 0.9 m
5.3m
6.2m
4.3 m
3.4 m
Separate Wall Method
Width = 0.9 m Total Qty of concrete in fdn= (2×6.2×0.9×0.3) + (2×3.4×0.9×0.3)cum
Long Wall = 5.3+0.9=6.2 m Short Wall = 4.3-0.9=3.4 m

7. 0.6 m
5.3m
4.3 m
Total Center line = 5.3+5.3+4.3+4.3=19.2 m
Width = 0.6 m Total Qty of brickwork in Ist footing= (19.2×0.6×0.3) cum
Center Line Method

8. 0.6 m
5.3m
5.9 m
4.3 m
3.7 m
Width = 0.6 m
Separate Wall Method
Long Wall = 5.3+0.6=5.9 m Short Wall = 4.3-0.6=3.7 m
Total Qty of brickwork in Ist footing= (2×5.9×0.6×0.3) + (2×3.7×0.6×0.3)cum

9. 5.3m
4.3 m
0.3 m
Total Center line = 5.3+5.3+4.3+4.3=19.2 m
Width = 0.3 m Total Qty of brickwork in walls= (19.2×0.3×3.5) cum
Center Line Method

10. 5.6 m
5.3m
4.3 m
4 m
0.3 m
Width = 0.3 m
Separate Wall Method
Long Wall = 5.3+0.3=5.6 m Short Wall = 4.3-0.3=4.0 m
Total Qty of brickwork in walls= (2×5.6×0.3×3.5) + (2×4.0×0.3×3.5)cum

12. 5m
4m
0.3m
0.3m
0.5m
0.6m
0.9m
0.4m
0.6m
3.5m
Section at A-A’ and B-B’
Thickness of footing and foundation is 30 cm each
A
A’
B B’
Plan

13. Center Line Method
Total Center line = 5.3+5.3+5.3+5.3+4.3+4.3+4.3=34.1 m
Width = 0.9 m Total Qty of concrete in fdn= (34.1×0.9×0.3)
5.3m 5.3m
4.3 m
0.9 m
Intermediate wall
– (2×0.9×(0.9/2) ×0.3)cum

14. Separate Wall Method
Long Wall = 5.3+5.3+0.9=11.5 m Short Wall = 4.3-0.9=3.4 m
Width = 0.9 m Total Qty of concrete in fdn= (2×11.5×0.9×0.3)
5.3m 5.3m
4.3 m
0.9 m
11.5 m
3.4m
Intermediate wall
+ (3×3.4×0.9×0.3)cum