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f(x) = ax2 + bx + c, where a   0
f(x) = ax2 + bx + c




        vertex




     Line of symmetry
f(x) = ax2 + bx + c                How do you find:
                                   y-intercept   (0, c)


                                   line of symmetry:




                                   vertex:


y-intercept                      vertex
                                          (      , f(     )   )
              Line of symmetry
Find the y-intercept, the equation of the axis of
symmetry, and the coordinates of the vertex for




y-intercept:        Line of symmetry:

(0, 2)

Vertex:            f(2) = 1(2)2 - 4(2) + 2
(2, -2 )               =4–8+2
                       = -2
Line of symmetry: x = 2
           Vertex: (2, -2)
           y- int: (0, 2)
x   f(x)
0    2
1    –1       (0, 2)

2    –2
3    –1
4    2
                             (2, –2)
Find the y-intercept, the equation of the axis of
symmetry, and the coordinates of the vertex for


                               6   3

y-intercept:        Line of symmetry:
                                        6
(0, 3)                                        3

Vertex:             f(3) = 1(3)2 – 6(3) + 3
(3, -6 )                = 9 – 18 + 3
                        = -6
Line of symmetry: x = 3
                           Vertex: (3, -6)
                           y- int: (0, 3)
x    x2 – 6x + 3    f(x)
                              (0, 3)
0                    3
1   12 – 6(1) + 3    –2
2   22 – 6(2) + 3    –5
3                    –6
6                    3


                                             (3, –6)
Find the maximum or a minimum value of


    a = -1


        =         =1


                       =

 Maximum value is 4 when x is 1

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Alg2 lesson 6-1

  • 1. f(x) = ax2 + bx + c, where a 0
  • 2. f(x) = ax2 + bx + c vertex Line of symmetry
  • 3. f(x) = ax2 + bx + c How do you find: y-intercept (0, c) line of symmetry: vertex: y-intercept vertex ( , f( ) ) Line of symmetry
  • 4. Find the y-intercept, the equation of the axis of symmetry, and the coordinates of the vertex for y-intercept: Line of symmetry: (0, 2) Vertex: f(2) = 1(2)2 - 4(2) + 2 (2, -2 ) =4–8+2 = -2
  • 5. Line of symmetry: x = 2 Vertex: (2, -2) y- int: (0, 2) x f(x) 0 2 1 –1 (0, 2) 2 –2 3 –1 4 2 (2, –2)
  • 6. Find the y-intercept, the equation of the axis of symmetry, and the coordinates of the vertex for 6 3 y-intercept: Line of symmetry: 6 (0, 3) 3 Vertex: f(3) = 1(3)2 – 6(3) + 3 (3, -6 ) = 9 – 18 + 3 = -6
  • 7. Line of symmetry: x = 3 Vertex: (3, -6) y- int: (0, 3) x x2 – 6x + 3 f(x) (0, 3) 0 3 1 12 – 6(1) + 3 –2 2 22 – 6(2) + 3 –5 3 –6 6 3 (3, –6)
  • 8. Find the maximum or a minimum value of a = -1 = =1 = Maximum value is 4 when x is 1