The document discusses various methods for factoring polynomials, including:
1. Greatest common factor (GCF)
2. Binomial square factoring
3. Difference of squares factoring
It provides examples demonstrating how to use these methods to factor polynomials by finding common factors between terms. Specific techniques for binomial square factoring are explained, such as recognizing if a trinomial is a perfect square.
Happy Math Humans (group h) of 8 - St. Basil
3 students of 8 - St. Basil representing the group Happy Math Humans, will show you how to factor different types of polynomials.
Happy Math Humans (group h) of 8 - St. Basil
3 students of 8 - St. Basil representing the group Happy Math Humans, will show you how to factor different types of polynomials.
Are you scared of that algebraic sums? Just view this presentation an you can learn about each and every algebraic identities. Just view this and Now take full marks in your tests..
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
Introduction to AI for Nonprofits with Tapp NetworkTechSoup
Dive into the world of AI! Experts Jon Hill and Tareq Monaur will guide you through AI's role in enhancing nonprofit websites and basic marketing strategies, making it easy to understand and apply.
Acetabularia Information For Class 9 .docxvaibhavrinwa19
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
Executive Directors Chat Leveraging AI for Diversity, Equity, and InclusionTechSoup
Let’s explore the intersection of technology and equity in the final session of our DEI series. Discover how AI tools, like ChatGPT, can be used to support and enhance your nonprofit's DEI initiatives. Participants will gain insights into practical AI applications and get tips for leveraging technology to advance their DEI goals.
A review of the growth of the Israel Genealogy Research Association Database Collection for the last 12 months. Our collection is now passed the 3 million mark and still growing. See which archives have contributed the most. See the different types of records we have, and which years have had records added. You can also see what we have for the future.
How to Make a Field invisible in Odoo 17Celine George
It is possible to hide or invisible some fields in odoo. Commonly using “invisible” attribute in the field definition to invisible the fields. This slide will show how to make a field invisible in odoo 17.
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...Dr. Vinod Kumar Kanvaria
Exploiting Artificial Intelligence for Empowering Researchers and Faculty,
International FDP on Fundamentals of Research in Social Sciences
at Integral University, Lucknow, 06.06.2024
By Dr. Vinod Kumar Kanvaria
Model Attribute Check Company Auto PropertyCeline George
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
Normal Labour/ Stages of Labour/ Mechanism of LabourWasim Ak
Normal labor is also termed spontaneous labor, defined as the natural physiological process through which the fetus, placenta, and membranes are expelled from the uterus through the birth canal at term (37 to 42 weeks
1.4 modern child centered education - mahatma gandhi-2.pptx
AA Section 11-3 Day 1
1. Section 11-3
Factoring Special Cases
Tuesday, March 3, 2009
2. Factoring:
Rewriting a polynomial as a product of factors
Tuesday, March 3, 2009
3. Factoring:
Rewriting a polynomial as a product of factors
1. Greatest Common Factor
Tuesday, March 3, 2009
4. Factoring:
Rewriting a polynomial as a product of factors
1. Greatest Common Factor
2. Binomial Square Factoring
Tuesday, March 3, 2009
5. Factoring:
Rewriting a polynomial as a product of factors
1. Greatest Common Factor
2. Binomial Square Factoring
3. Difference of Squares Factoring
Tuesday, March 3, 2009
6. Factoring:
Rewriting a polynomial as a product of factors
1. Greatest Common Factor
2. Binomial Square Factoring
3. Difference of Squares Factoring
4. Other Methods of Factoring
Tuesday, March 3, 2009
7. Factoring:
Rewriting a polynomial as a product of factors
1. Greatest Common Factor
2. Binomial Square Factoring
3. Difference of Squares Factoring
4. Other Methods of Factoring
There’s trial-and-error, too, but that just takes too long.
Tuesday, March 3, 2009
8. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
Tuesday, March 3, 2009
9. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4
Tuesday, March 3, 2009
10. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x
Tuesday, March 3, 2009
11. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x(
Tuesday, March 3, 2009
12. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x(3
Tuesday, March 3, 2009
13. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x(3x
Tuesday, March 3, 2009
14. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x(3x -
Tuesday, March 3, 2009
15. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x(3x - 1
Tuesday, March 3, 2009
16. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x(3x - 1)
Tuesday, March 3, 2009
17. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x(3x - 1) 5
Tuesday, March 3, 2009
18. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x(3x - 1) 5x
Tuesday, March 3, 2009
19. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x(3x - 1) 5xy
Tuesday, March 3, 2009
20. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x(3x - 1) 5xy(
Tuesday, March 3, 2009
21. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x(3x - 1) 5xy(3x2 + xy - 7y)
Tuesday, March 3, 2009
22. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x(3x - 1) 5xy(3x2 + xy - 7y)
All we did here was go through the numbers first, then the
variables in alphabetical order, finding factors that the terms
have in common.
Tuesday, March 3, 2009
23. Example 1: Factor.
a. 12x2 - 4x b. 15x3y + 5x2y2 - 35xy2
4x(3x - 1) 5xy(3x2 + xy - 7y)
All we did here was go through the numbers first, then the
variables in alphabetical order, finding factors that the terms
have in common.
To check your answer, re-distribute the GCF and see if you
get what you started with.
Tuesday, March 3, 2009
34. (x + 4) 2
(x + 4)(x + 4)
2 + 4x + 4x + 16
x
2 + 8x + 16
x
Tuesday, March 3, 2009
35. NOTICE
(x + 4) 2
First term:
Tuesday, March 3, 2009
36. NOTICE
(x + 4) 2
First term: x2
Tuesday, March 3, 2009
37. NOTICE
(x + 4) 2
First term: x2
What do you notice about it compared to what we
began with?
Tuesday, March 3, 2009
38. NOTICE
(x + 4) 2
First term: x2
What do you notice about it compared to what we
began with?
Middle term:
Tuesday, March 3, 2009
39. NOTICE
(x + 4) 2
First term: x2
What do you notice about it compared to what we
began with?
Middle term: 8x
Tuesday, March 3, 2009
40. NOTICE
(x + 4) 2
First term: x2
What do you notice about it compared to what we
began with?
Middle term: 8x
How does this compare with what we started out with?
Tuesday, March 3, 2009
41. NOTICE
(x + 4) 2
First term: x2
What do you notice about it compared to what we
began with?
Middle term: 8x
How does this compare with what we started out with?
Last term:
Tuesday, March 3, 2009
42. NOTICE
(x + 4) 2
First term: x2
What do you notice about it compared to what we
began with?
Middle term: 8x
How does this compare with what we started out with?
Last term: 16
Tuesday, March 3, 2009
43. NOTICE
(x + 4) 2
First term: x2
What do you notice about it compared to what we
began with?
Middle term: 8x
How does this compare with what we started out with?
Last term: 16
What’s happening?
Tuesday, March 3, 2009
44. A pattern emerges...
A perfect square trinomial will have the following things
occur:
Tuesday, March 3, 2009
45. A pattern emerges...
A perfect square trinomial will have the following things
occur:
1. The first term will be a perfect square.
Tuesday, March 3, 2009
46. A pattern emerges...
A perfect square trinomial will have the following things
occur:
1. The first term will be a perfect square.
2.The last term will be a perfect square.
Tuesday, March 3, 2009
47. A pattern emerges...
A perfect square trinomial will have the following things
occur:
1. The first term will be a perfect square.
2.The last term will be a perfect square.
3.The middle term will be 2 times the product of the square
roots of the first and last terms.
Tuesday, March 3, 2009
49. Example 2: Factor.
a. 9x2 + 12x + 4
Check to see if the first and last terms are perfect squares.
Tuesday, March 3, 2009
50. Example 2: Factor.
a. 9x2 + 12x + 4
Check to see if the first and last terms are perfect squares.
Tuesday, March 3, 2009
51. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x
Check to see if the first and last terms are perfect squares.
Tuesday, March 3, 2009
52. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x
Check to see if the first and last terms are perfect squares.
3x
Tuesday, March 3, 2009
53. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x
Check to see if the first and last terms are perfect squares.
3x
Tuesday, March 3, 2009
54. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x 2·2
Check to see if the first and last terms are perfect squares.
3x
Tuesday, March 3, 2009
55. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x 2·2
Check to see if the first and last terms are perfect squares.
3x 2
Tuesday, March 3, 2009
56. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x 2·2
Check to see if the first and last terms are perfect squares.
3x 2
Check to see if the middle term is 2 times the product of the
square roots of the first and last terms.
Tuesday, March 3, 2009
57. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x 2·2
Check to see if the first and last terms are perfect squares.
3x 2
Check to see if the middle term is 2 times the product of the
square roots of the first and last terms.
2(3x · 2)
Tuesday, March 3, 2009
58. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x 2·2
Check to see if the first and last terms are perfect squares.
3x 2
Check to see if the middle term is 2 times the product of the
square roots of the first and last terms.
2(3x · 2) = 2(6x)
Tuesday, March 3, 2009
59. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x 2·2
Check to see if the first and last terms are perfect squares.
3x 2
Check to see if the middle term is 2 times the product of the
square roots of the first and last terms.
2(3x · 2) = 2(6x) = 12x
Tuesday, March 3, 2009
60. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x 2·2
Check to see if the first and last terms are perfect squares.
3x 2
Check to see if the middle term is 2 times the product of the
square roots of the first and last terms.
2(3x · 2) = 2(6x) = 12x
Final Answer:
Tuesday, March 3, 2009
61. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x 2·2
Check to see if the first and last terms are perfect squares.
3x 2
Check to see if the middle term is 2 times the product of the
square roots of the first and last terms.
2(3x · 2) = 2(6x) = 12x
Final Answer:
(3x
Tuesday, March 3, 2009
62. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x 2·2
Check to see if the first and last terms are perfect squares.
3x 2
Check to see if the middle term is 2 times the product of the
square roots of the first and last terms.
2(3x · 2) = 2(6x) = 12x
Final Answer:
(3x 2)
Tuesday, March 3, 2009
63. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x 2·2
Check to see if the first and last terms are perfect squares.
3x 2
Check to see if the middle term is 2 times the product of the
square roots of the first and last terms.
2(3x · 2) = 2(6x) = 12x
Final Answer:
(3x + 2)
Tuesday, March 3, 2009
64. Example 2: Factor.
a. 9x2 + 12x + 4
3x · 3x 2·2
Check to see if the first and last terms are perfect squares.
3x 2
Check to see if the middle term is 2 times the product of the
square roots of the first and last terms.
2(3x · 2) = 2(6x) = 12x
Final Answer:
(3x + 2)2
Tuesday, March 3, 2009
65. Example 2: Factor.
b. x2 - 6x + 9 c. y2 - 20y + 100
d. x2 + 7x + 14
Tuesday, March 3, 2009
66. Example 2: Factor.
b. x2 - 6x + 9 c. y2 - 20y + 100
(x
d. x2 + 7x + 14
Tuesday, March 3, 2009
67. Example 2: Factor.
b. x2 - 6x + 9 c. y2 - 20y + 100
(x 3)
d. x2 + 7x + 14
Tuesday, March 3, 2009
68. Example 2: Factor.
b. x2 - 6x + 9 c. y2 - 20y + 100
(x - 3)
d. x2 + 7x + 14
Tuesday, March 3, 2009
69. Example 2: Factor.
b. x2 - 6x + 9 c. y2 - 20y + 100
(x - 3) 2
d. x2 + 7x + 14
Tuesday, March 3, 2009
70. Example 2: Factor.
b. x2 - 6x + 9 c. y2 - 20y + 100
(x - 3) 2 (y
d. x2 + 7x + 14
Tuesday, March 3, 2009
71. Example 2: Factor.
b. x2 - 6x + 9 c. y2 - 20y + 100
(x - 3) 2 (y -
d. x2 + 7x + 14
Tuesday, March 3, 2009
72. Example 2: Factor.
b. x2 - 6x + 9 c. y2 - 20y + 100
(x - 3) 2 (y - 10)
d. x2 + 7x + 14
Tuesday, March 3, 2009
73. Example 2: Factor.
b. x2 - 6x + 9 c. y2 - 20y + 100
(x - 3) 2 (y - 10)2
d. x2 + 7x + 14
Tuesday, March 3, 2009
74. Example 2: Factor.
b. x2 - 6x + 9 c. y2 - 20y + 100
(x - 3) 2 (y - 10)2
d. x2 + 7x + 14
(x
Tuesday, March 3, 2009
75. Example 2: Factor.
b. x2 - 6x + 9 c. y2 - 20y + 100
(x - 3) 2 (y - 10)2
d. x2 + 7x + 14
(x
14 is not a perfect square!
Cannot factor with this method.
Tuesday, March 3, 2009
79. Difference of Squares
Factoring
For all a and b,
a2 - b2 =
(a + b)(a - b)
Tuesday, March 3, 2009
80. Difference of two squares
This only works for the following conditions:
Tuesday, March 3, 2009
81. Difference of two squares
This only works for the following conditions:
1. You must have a binomial.
Tuesday, March 3, 2009
82. Difference of two squares
This only works for the following conditions:
1. You must have a binomial.
2.Both terms must be perfect squares.
Tuesday, March 3, 2009
83. Difference of two squares
This only works for the following conditions:
1. You must have a binomial.
2.Both terms must be perfect squares.
3.There must be subtraction!
Tuesday, March 3, 2009
91. Example 3: Factor.
a. 64x2 - 81
Check to see if the first and last terms are perfect squares.
Tuesday, March 3, 2009
92. Example 3: Factor.
a. 64x2 - 81
Check to see if the first and last terms are perfect squares.
Tuesday, March 3, 2009
93. Example 3: Factor.
a. 64x2 - 81
8x · 8x
Check to see if the first and last terms are perfect squares.
Tuesday, March 3, 2009
94. Example 3: Factor.
a. 64x2 - 81
8x · 8x
Check to see if the first and last terms are perfect squares.
Tuesday, March 3, 2009
95. Example 3: Factor.
a. 64x2 - 81
8x · 8x 9 · 9
Check to see if the first and last terms are perfect squares.
Tuesday, March 3, 2009
96. Example 3: Factor.
a. 64x2 - 81
8x · 8x 9 · 9
Check to see if the first and last terms are perfect squares.
Is it a subtraction problem?
Tuesday, March 3, 2009
97. Example 3: Factor.
a. 64x2 - 81
8x · 8x 9 · 9
Check to see if the first and last terms are perfect squares.
Is it a subtraction problem?
Answer:
Tuesday, March 3, 2009
98. Example 3: Factor.
a. 64x2 - 81
8x · 8x 9 · 9
Check to see if the first and last terms are perfect squares.
Is it a subtraction problem?
Answer:
(8x
Tuesday, March 3, 2009
99. Example 3: Factor.
a. 64x2 - 81
8x · 8x 9 · 9
Check to see if the first and last terms are perfect squares.
Is it a subtraction problem?
Answer:
(8x (8x
Tuesday, March 3, 2009
100. Example 3: Factor.
a. 64x2 - 81
8x · 8x 9 · 9
Check to see if the first and last terms are perfect squares.
Is it a subtraction problem?
Answer:
(8x 9)(8x
Tuesday, March 3, 2009
101. Example 3: Factor.
a. 64x2 - 81
8x · 8x 9 · 9
Check to see if the first and last terms are perfect squares.
Is it a subtraction problem?
Answer:
(8x 9)(8x 9)
Tuesday, March 3, 2009
102. Example 3: Factor.
a. 64x2 - 81
8x · 8x 9 · 9
Check to see if the first and last terms are perfect squares.
Is it a subtraction problem?
Answer:
(8x + 9)(8x 9)
Tuesday, March 3, 2009
103. Example 3: Factor.
a. 64x2 - 81
8x · 8x 9 · 9
Check to see if the first and last terms are perfect squares.
Is it a subtraction problem?
Answer:
(8x + 9)(8x - 9)
Tuesday, March 3, 2009
104. Example 3: Factor.
b. r2 - 121 c. y2 + 100
e. x4 - 16
d. 25x4y6 - 36z8
Tuesday, March 3, 2009
105. Example 3: Factor.
b. r2 - 121 c. y2 + 100
( )( )
e. x4 - 16
d. 25x4y6 - 36z8
Tuesday, March 3, 2009
106. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r )( r )
e. x4 - 16
d. 25x4y6 - 36z8
Tuesday, March 3, 2009
107. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r 11)( r 11)
e. x4 - 16
d. 25x4y6 - 36z8
Tuesday, March 3, 2009
108. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r +11)( r - 11)
e. x4 - 16
d. 25x4y6 - 36z8
Tuesday, March 3, 2009
109. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r +11)( r - 11) Cannot be factored
e. x4 - 16
d. 25x4y6 - 36z8
Tuesday, March 3, 2009
110. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r +11)( r - 11) Cannot be factored
Not a difference
e. x4 - 16
d. 25x4y6 - 36z8
Tuesday, March 3, 2009
111. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r +11)( r - 11) Cannot be factored
Not a difference
e. x4 - 16
d. 25x4y6 - 36z8
( )( )
Tuesday, March 3, 2009
112. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r +11)( r - 11) Cannot be factored
Not a difference
e. x4 - 16
d. 25x4y6 -36z8
(5x2y3 )(5x2y3 )
Tuesday, March 3, 2009
113. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r +11)( r - 11) Cannot be factored
Not a difference
e. x4 - 16
d. 25x4y6
- 36z8
(5x2y3 6z4)(5x2y3 6z4 )
Tuesday, March 3, 2009
114. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r +11)( r - 11) Cannot be factored
Not a difference
e. x4 - 16
d. 25x4y6
- 36z8
(5x2y3+ 6z4)(5x2y3 - 6z4 )
Tuesday, March 3, 2009
115. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r +11)( r - 11) Cannot be factored
Not a difference
e. x4 - 16
d. 25x4y6
- 36z8
(5x2y3+ 6z4)(5x2y3 - 6z4 ) ( )( )
Tuesday, March 3, 2009
116. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r +11)( r - 11) Cannot be factored
Not a difference
e. x4 - 16
d. 25x4y6
- 36z8
(5x2y3+ 6z4)(5x2y3 - 6z4 ) (x2 )( x2 )
Tuesday, March 3, 2009
117. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r +11)( r - 11) Cannot be factored
Not a difference
e. x4 - 16
d. 25x4y6
- 36z8
(5x2y3+ 6z4)(5x2y3 - 6z4 ) (x2 4)( x2 4 )
Tuesday, March 3, 2009
118. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r +11)( r - 11) Cannot be factored
Not a difference
e. x4 - 16
d. 25x4y6
- 36z8
(5x2y3+ 6z4)(5x2y3 - 6z4 ) (x2+ 4)( x2 - 4 )
Tuesday, March 3, 2009
119. Example 3: Factor.
b. r2 - 121 c. y2 + 100
(r +11)( r - 11) Cannot be factored
Not a difference
e. x4 - 16
d. 25x4y6
- 36z8
(5x2y3+ 6z4)(5x2y3 - 6z4 ) (x2+ 4)( x2 - 4 )
(x2 + 4)(x + 2)(x - 2)
Tuesday, March 3, 2009