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FACTORING POLYNOMIALS
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],So, the numerical value of the polynomial P(x)  when  x = -3  is:  P(-3) = -32
[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],[object Object],The  linear binomials  (x-2) y (x-1) are the  simplest factors   of  P(x)
[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],“ An integer root of a polynomial, is always a divisor of its constant term”
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],So, if the remainder of the division is zero,  then P(a)=0  and therefore “a” is a root of P(x).
[object Object],[object Object],(x 2  – 3x + 2) : (x – 2)
[object Object],[object Object],(x 2  – 3x + 2) : (x – 2) How?
(x 2  – 3x + 2) : (x – 2) We write this number here 2 1 -3 2
(x 2  – 3x + 2) : (x – 2) 2 1 -3 2 and then, we write the  coefficients of the polynomial
[object Object],As the remainder of  P(x) : (x-2)   is zero, “2” is a root of P(x), and therefore, the  linear binomial  (x-2) is a factor of the polynomial P(x) Now, we will look for another root in order to get a new factor, and so on… (x 2  – 3x + 2) : (x – 2) 2 1 -3 2 remainder of the division 1   -1   0 2  -2
[object Object],“ An integer root of a polynomial, is always a divisor of its constant term”
“ An integer root of a polynomial, is always a divisor of its constant term”  Example: Which  integer numbers   could be  roots of the polynomial P(x) = - 3x 5  + 4x 2  – 5x -3 ? Answer:  The divisors of the  constant term They are only  +1, -1, +3 y -3
It is time to use Ruffini’s rule to make the following divisions faster: P(x):(x-1) P(x):(x+1) P(x):(x-3) and P(x):(x+3) (  x-(-1) ) (  x-(3) )
[object Object],Roots 2,  -1 y 3 1 st  Factor: (x-2) 2 nd  Factor: (x+1) 3 th  Factor: (x-3)
[object Object],Possible integer roots :  +1, -1, +2,  -2, +3, -3, +6, -6 P(x) = x 3  -4x 2  + x + 6
No -6 No +6 No -3 (x-3) Yes +3 No -2 (x-2) Yes +2 (x+1) Yes -1 No +1 Factor Is it a root?  Yes/No Possible integer root
[object Object],P(x) = x 3  -4x 2  + x + 6 in its factored form P(x) = x 3  -4x 2  + x + 6 = (x+1)(x-2)(x-3) general form factored form
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
In a diagram form, we can say: P(x) Possible integer roots: Divisors of the constant term:  a, b, c… a is a  root b is not a root (x – a) is a factor
P(x) Possible integer roots: Divisors of the constant term:  a, b, c… a is a root b is not a root (x – a) is a factor If the remainder of the division is zero… P(x)  x-a 0  C(x) When the remainder of  the division is  zero… P(x)  x-a 0  C(x)
P(x) Possible integer roots: Divisors of the constant term:  a, b, c… a is a  root b is not a root (x – a) is a factor If the numerical value P(a) = 0 P(a) = 0
P(x) Possible integer roots: Divisors of the constant term:  a, b, c… a is a  root b is not a root (x – a) is a factor If “a” is a solution of the equation P(x) = 0
The factors will be: (x-a), (x-b), (x-c), etc… Therefore, if we know  every root of the polynomial P(x), so to speak,  a, b, c, etc…

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Factoring polynomials

  • 2.
  • 3.
  • 4.
  • 5.
  • 6.
  • 7.
  • 8.
  • 9.
  • 10.
  • 11.
  • 12.
  • 13.
  • 14. (x 2 – 3x + 2) : (x – 2) We write this number here 2 1 -3 2
  • 15. (x 2 – 3x + 2) : (x – 2) 2 1 -3 2 and then, we write the coefficients of the polynomial
  • 16.
  • 17.
  • 18. “ An integer root of a polynomial, is always a divisor of its constant term” Example: Which integer numbers could be roots of the polynomial P(x) = - 3x 5 + 4x 2 – 5x -3 ? Answer: The divisors of the constant term They are only +1, -1, +3 y -3
  • 19. It is time to use Ruffini’s rule to make the following divisions faster: P(x):(x-1) P(x):(x+1) P(x):(x-3) and P(x):(x+3) ( x-(-1) ) ( x-(3) )
  • 20.
  • 21.
  • 22. No -6 No +6 No -3 (x-3) Yes +3 No -2 (x-2) Yes +2 (x+1) Yes -1 No +1 Factor Is it a root? Yes/No Possible integer root
  • 23.
  • 24.
  • 25. In a diagram form, we can say: P(x) Possible integer roots: Divisors of the constant term: a, b, c… a is a root b is not a root (x – a) is a factor
  • 26. P(x) Possible integer roots: Divisors of the constant term: a, b, c… a is a root b is not a root (x – a) is a factor If the remainder of the division is zero… P(x) x-a 0 C(x) When the remainder of the division is zero… P(x) x-a 0 C(x)
  • 27. P(x) Possible integer roots: Divisors of the constant term: a, b, c… a is a root b is not a root (x – a) is a factor If the numerical value P(a) = 0 P(a) = 0
  • 28. P(x) Possible integer roots: Divisors of the constant term: a, b, c… a is a root b is not a root (x – a) is a factor If “a” is a solution of the equation P(x) = 0
  • 29. The factors will be: (x-a), (x-b), (x-c), etc… Therefore, if we know every root of the polynomial P(x), so to speak, a, b, c, etc…