4.1.5 RL Example 1
•
0 likes•187 views
An inductor with a resistance of 30Ω and inductance of 0.8H is connected to a 240V 50Hz supply. The document finds (a) the inductive reactance of 251.2Ω, (b) the impedance of 253Ω, (c) the current of 0.95A, and (d) the phase angle between the current and voltage of 83.2°. A phasor diagram is drawn showing the current lags the voltage by 83.2°.
Report
Share
Report
Share
Recommended
Electrical Circuit - CSE132
This document discusses key concepts related to electrical circuits including:
1) It defines average/active power, reactive power, and apparent power as well as the relationship between power, voltage, and current using mathematical equations.
2) It explains the significance of power factor as the ratio of real power to apparent power and how power delivered is affected by the power factor.
3) It describes how to use phasor and impedance diagrams to represent voltages, currents, and phase relationships in AC circuits and how to use them to calculate unknown values.
Calculation of voltage drop in power systems r1
Calculation of voltage drop in power systems - The value that matters is not obtained directly by Ohm's law formula.
Most Commonly Used Approximate Formula where neither “er” nor “es” is known is dV=[R.cos(phi)+X.sin(phi)] x I per phase.
PracticalPFC_1
This document presents the solution to a circuit analysis problem. It is given that the supply voltage is 240V, frequency is 60Hz, active power is 1.5kW, and current is 9.615A.
The document calculates the power factor, resistive and inductive components, and determines that the load is inductive. It then calculates the value of inductance as 50.31365mH.
Finally, it calculates the required capacitance of 80.761uF to compensate the power factor to unity.
8.1.6example2
The document provides an example of calculating the instantaneous value of a sine wave passing through zero at 30 degrees. It gives the amplitude as 15V, frequency as 50Hz, and time as 15ms. Through the calculations, it finds the instantaneous value to be -12.99V.
Sheet no 1
This document contains 20 multi-part math and physics problems related to functions, graphs, signals, thermostats, elasticity, and other applied calculus topics. The problems involve tasks like plotting graphs, finding values, determining relationships, and interpreting results.
13.8.2 Example 1
Three single-phase transformers are connected in a Y-Δ configuration to form a three-phase transformer bank supplying a 120 kVA, 230 V, 0.85 pf lag load. Calculations show the primary phase current is 17.39 A and since it is a Y connection, the primary line current is also 17.39 A.
Smith chart:A graphical representation.
The document discusses the Smith chart, which is a graphical tool used to solve transmission line problems. Some key points:
- The Smith chart was developed in 1939 and allows tedious transmission line calculations to be done graphically.
- It provides a mapping between the normalized impedance plane and the reflection coefficient plane. Circles of constant resistance and reactance are plotted, along with the reflection coefficient.
- Parameters like impedance, admittance, reflection coefficient, VSWR can all be plotted and derived from locations on the chart.
- Examples are given of using the Smith chart to determine input impedance, reflection coefficient, and stub matching of transmission lines with various termination impedances.
2009-2 기말고사문제(초고주파공학)
The document contains a past exam for a Microwave Engineering course. It includes 3 questions:
1) A design procedure question for a microstrip line power divider in 1-2 sentences.
2) A question involving the design and analysis of a quadrature hybrid circuit, including calculating scattered voltage waves from port excitations.
3) A brief explanation of the usage of scattering matrices in electromagnetic problems.
Recommended
Electrical Circuit - CSE132
This document discusses key concepts related to electrical circuits including:
1) It defines average/active power, reactive power, and apparent power as well as the relationship between power, voltage, and current using mathematical equations.
2) It explains the significance of power factor as the ratio of real power to apparent power and how power delivered is affected by the power factor.
3) It describes how to use phasor and impedance diagrams to represent voltages, currents, and phase relationships in AC circuits and how to use them to calculate unknown values.
Calculation of voltage drop in power systems r1
Calculation of voltage drop in power systems - The value that matters is not obtained directly by Ohm's law formula.
Most Commonly Used Approximate Formula where neither “er” nor “es” is known is dV=[R.cos(phi)+X.sin(phi)] x I per phase.
PracticalPFC_1
This document presents the solution to a circuit analysis problem. It is given that the supply voltage is 240V, frequency is 60Hz, active power is 1.5kW, and current is 9.615A.
The document calculates the power factor, resistive and inductive components, and determines that the load is inductive. It then calculates the value of inductance as 50.31365mH.
Finally, it calculates the required capacitance of 80.761uF to compensate the power factor to unity.
8.1.6example2
The document provides an example of calculating the instantaneous value of a sine wave passing through zero at 30 degrees. It gives the amplitude as 15V, frequency as 50Hz, and time as 15ms. Through the calculations, it finds the instantaneous value to be -12.99V.
Sheet no 1
This document contains 20 multi-part math and physics problems related to functions, graphs, signals, thermostats, elasticity, and other applied calculus topics. The problems involve tasks like plotting graphs, finding values, determining relationships, and interpreting results.
13.8.2 Example 1
Three single-phase transformers are connected in a Y-Δ configuration to form a three-phase transformer bank supplying a 120 kVA, 230 V, 0.85 pf lag load. Calculations show the primary phase current is 17.39 A and since it is a Y connection, the primary line current is also 17.39 A.
Smith chart:A graphical representation.
The document discusses the Smith chart, which is a graphical tool used to solve transmission line problems. Some key points:
- The Smith chart was developed in 1939 and allows tedious transmission line calculations to be done graphically.
- It provides a mapping between the normalized impedance plane and the reflection coefficient plane. Circles of constant resistance and reactance are plotted, along with the reflection coefficient.
- Parameters like impedance, admittance, reflection coefficient, VSWR can all be plotted and derived from locations on the chart.
- Examples are given of using the Smith chart to determine input impedance, reflection coefficient, and stub matching of transmission lines with various termination impedances.
2009-2 기말고사문제(초고주파공학)
The document contains a past exam for a Microwave Engineering course. It includes 3 questions:
1) A design procedure question for a microstrip line power divider in 1-2 sentences.
2) A question involving the design and analysis of a quadrature hybrid circuit, including calculating scattered voltage waves from port excitations.
3) A brief explanation of the usage of scattering matrices in electromagnetic problems.
matlab program for Smith chart
This document discusses using a Smith chart to analyze transmission line parameters. It provides examples to determine the voltage reflection coefficient, voltage standing wave ratio (VSWR), and impedance (Zx) from a load at a distance along a transmission line. The document first introduces the Smith chart and how it represents normalized impedance values graphically. It then provides an example problem and solution to calculate the reflection coefficient, VSWR, and Zx for a given transmission line and load impedance using both MATLAB formulas and the Smith chart.
4.2.2 Rc Phasor
The document describes a circuit diagram with a reference voltage (VR), a capacitor voltage (VC), and an applied voltage (V5). It asks the reader to find the value of the applied voltage and the phase angle between the current and the applied voltage based on the circuit.
Ohm's law for Class 10th
This table shows the relationship between voltage and current in a circuit. It lists voltage values from 0 to 12 volts in the first column and the corresponding current in amps in the second column. As the voltage increases, the current also increases in consistent increments of 0.5 amps.
Anexo iv calculo de sistema de puesta a tierra
This document calculates the grounding system for an electrical installation using the Dwight method. It provides calculations for both the horizontal and vertical components of the mesh grounding system. For the horizontal component, it calculates the resistance of the mesh, mutual interference resistance, conductor resistance, and total conductor resistance. Similarly, it performs these same calculations for the vertical component. It then calculates the total resistance of the grounding system mesh and notes that in practice the geometric layout would need to adapt to the terrain.
Smith chart basics
The Smith chart is a graphical tool used to analyze high frequency circuits. It represents all possible complex impedances in terms of the reflection coefficient. Circles of constant resistance and arcs of constant reactance intersect on the chart to indicate impedance values. The chart allows users to determine impedances, reflection coefficients, voltage standing wave ratios and other transmission line parameters through graphical techniques. It remains a popular tool decades after its original conception due to providing a clever way to visualize complex impedance functions.
Chapter I Moments
This document provides information about units of measurement, forces, moments, and calculating moments using two different methods. It discusses the conversion of various units like kgf, hp, bar, ton, and hectare. Forces are defined as vectors with magnitude, point of application, line of action, and direction. An example problem is given to calculate the moment at point O of a cantilever beam with a 10N force applied at angle Ø using the scalar product and vector product formulas. Both methods yield a net moment of 0 Nm, verifying the equivalence of the two approaches.
as400 built in function- %ELEM
This document discusses the %ELEM function in SAS, which returns the dimension of an array. It provides an example where %ELEM(arr1) returns the dimension of 100 for the array darr1, which was previously defined with dimensions of 100. The output displays the result of 100 from evaluating %ELEM(arr1).
L18 1 ph-ac
This document introduces phasors and their graphical representation. It discusses that a phasor can represent the magnitude and angular position of a sinusoidal quantity. It also describes that a phasor diagram can show the relative relationship of sine waves of the same frequency. The document outlines different forms to represent a phasor including rectangular, trigonometric, exponential and polar forms. It discusses operations that can be performed on phasors such as addition, subtraction, multiplication and division in both rectangular and polar forms. Finally, it describes how phasors can be graphically added and subtracted on a phasor diagram.
3D Smith Chart
The 3D Smith Chart program is a new Java tool for visualizing and designing active and passive microwave circuits. It generalizes the traditional 2D Smith chart onto the surface of a sphere, addressing limitations of the 2D chart. Key features include reading measurement files, plotting reflection coefficients for complex impedances, and aiding oscillator and amplifier design by visualizing infinite mismatch and stability circles. The tool aims to provide a complete graphical solution for microwave circuit measurement and design.
Loop alignment
The document discusses loop alignment techniques to eliminate loop carried dependencies and enable parallelization. It describes how adding an extra iteration and adjusting indices can align references to compute and use values in the same iteration. Alignment incurs overhead from conditionals and modulo operations. While alignment can eliminate dependencies for loops without recurrences, it may not work for loops with recurrences due to possible alignment conflicts between dependencies.
Gate ee 2008 with solutions
This document contains 20 multiple choice questions from a GATE EE exam. Each question is presented along with the question stem and 4 possible answer choices. The correct answer is indicated and a brief explanation of the solution is provided. The questions cover topics in circuits, signals and systems, random variables, matrices, communication systems, control systems, electronics, and power systems.
Intro to smithchart
The Smith Chart is a graphical tool developed in the 1930s to help solve radio frequency circuit problems. It displays impedances on a chart using a system of circles and arcs. Impedances are plotted based on their resistance (circle) and reactance (arc) values after normalizing to the system characteristic impedance. In this example, the Smith Chart is used to calculate the input impedance seen at the transmitter given the load impedance of an antenna and the electrical length of the transmission line connecting them.
Raicesdeecuaciones
The document contains results from applying different root finding algorithms - bisection, false position, secant, Newton-Raphson, and fixed point - to find the root of a function. It shows the iterations, estimates for the root at each iteration and the error compared to the previous iteration. The algorithms converge to a root near 0.42630275 after several iterations, with the error decreasing significantly in each successive step.
Sloof
This document summarizes the calculations for the dimensions and reinforcement of a sloped beam. The beam has a height of 0.5m and width of 0.18m. The required reinforcement is calculated to be 3 bars of 14mm diameter on the bottom of the beam. An iterative process is used to calculate the depth of the neutral axis as 35.36mm. The nominal moment capacity is calculated as 49451528 Nmm, which exceeds the required design moment of 21020000 Nmm. Therefore, the beam reinforcement is adequate.
EC6503 TLWG - Properties of Smith Chart
The Smith chart is a graphical tool developed by P.H. Smith at Bell Labs to help solve radio frequency transmission line problems. It displays the resistance and reactance of an impedance on a chart bounded by a unit circle. Circles of constant resistance and reactance are superimposed, allowing one to easily locate complex impedances and determine key parameters like voltage maxima and minima. The Smith chart represents an invaluable tool for simplifying transmission line design issues that are difficult to solve analytically.
P13 048
This document describes calculating torques and forces on a beam hinged at one end. It finds that for a 12m beam with a 400N tension and angles of 40 and 50 degrees, the weight on the beam is 671N. Equilibrium equations show the horizontal hinge force is 400N of tension and the vertical force is approximately 670N of weight.
Eet3082 binod kumar sahu lecturer_24
1. The document discusses numerical problems related to alternators, including:
2. Calculating the current and power factor of a star-connected alternator just before falling out of step given its synchronous impedance and rated current/power factor.
3. Determining the current and power factor of a star-connected turbo alternator if excitation is raised by 20% without changing prime mover input, given its reactance and original current/power factor.
4. Estimating the load power factor and power delivered by a star-connected alternator if its voltage regulation is zero, given its rating and synchronous reactance.
5. Finding the maximum active and reactive power values that can be delivered by a synchronous
The smith chart
The document describes how the Smith Chart maps impedances on the normalized complex impedance plane to the complex Γ plane. Vertical lines on the impedance plane representing constant resistance values r map to circles on the Γ plane, with centers located along the Γi = 0 line. Horizontal lines representing constant reactance values x also map to circles, with centers located along the Γr = 1 line. By mapping many such lines, the rectilinear grid of the impedance plane is distorted into the curvilinear grid of circles that make up the Smith Chart.
6161103 4.8 resultants of a force and couple system
1) The document discusses calculating the resultant force and moment on a rigid body from a system of individual forces and couples.
2) It provides equations to calculate the total resultant force, FR, total resultant moment, MR, and components of each.
3) Examples are given to demonstrate calculating the equivalent resultant force and moment at a point by summing the forces and moments of the individual components.
Solar LED street light, 20 w 40w
LED Solar street light, road light, 20w, 25w, 30w,40w for choice, www.luminhome.com. if need more information conatct: sales1@luminhome.com . Happy hear from you .
8713-Event-Information-kit-WEB_15 Sept
This document provides guidelines for event organisers in Liverpool City Council area. It covers key topics such as event management and approval process, community awareness and communications, accessibility, sustainability, transport, health, safety, risk management, temporary structures, volunteers, legal requirements and evaluation. It aims to assist event organisers in planning a safe and successful event and ensuring all necessary standards and approvals are met. Site maps and checklists are provided in attachments to help organisers navigate the application and planning process.
More Related Content
What's hot
matlab program for Smith chart
This document discusses using a Smith chart to analyze transmission line parameters. It provides examples to determine the voltage reflection coefficient, voltage standing wave ratio (VSWR), and impedance (Zx) from a load at a distance along a transmission line. The document first introduces the Smith chart and how it represents normalized impedance values graphically. It then provides an example problem and solution to calculate the reflection coefficient, VSWR, and Zx for a given transmission line and load impedance using both MATLAB formulas and the Smith chart.
4.2.2 Rc Phasor
The document describes a circuit diagram with a reference voltage (VR), a capacitor voltage (VC), and an applied voltage (V5). It asks the reader to find the value of the applied voltage and the phase angle between the current and the applied voltage based on the circuit.
Ohm's law for Class 10th
This table shows the relationship between voltage and current in a circuit. It lists voltage values from 0 to 12 volts in the first column and the corresponding current in amps in the second column. As the voltage increases, the current also increases in consistent increments of 0.5 amps.
Anexo iv calculo de sistema de puesta a tierra
This document calculates the grounding system for an electrical installation using the Dwight method. It provides calculations for both the horizontal and vertical components of the mesh grounding system. For the horizontal component, it calculates the resistance of the mesh, mutual interference resistance, conductor resistance, and total conductor resistance. Similarly, it performs these same calculations for the vertical component. It then calculates the total resistance of the grounding system mesh and notes that in practice the geometric layout would need to adapt to the terrain.
Smith chart basics
The Smith chart is a graphical tool used to analyze high frequency circuits. It represents all possible complex impedances in terms of the reflection coefficient. Circles of constant resistance and arcs of constant reactance intersect on the chart to indicate impedance values. The chart allows users to determine impedances, reflection coefficients, voltage standing wave ratios and other transmission line parameters through graphical techniques. It remains a popular tool decades after its original conception due to providing a clever way to visualize complex impedance functions.
Chapter I Moments
This document provides information about units of measurement, forces, moments, and calculating moments using two different methods. It discusses the conversion of various units like kgf, hp, bar, ton, and hectare. Forces are defined as vectors with magnitude, point of application, line of action, and direction. An example problem is given to calculate the moment at point O of a cantilever beam with a 10N force applied at angle Ø using the scalar product and vector product formulas. Both methods yield a net moment of 0 Nm, verifying the equivalence of the two approaches.
as400 built in function- %ELEM
This document discusses the %ELEM function in SAS, which returns the dimension of an array. It provides an example where %ELEM(arr1) returns the dimension of 100 for the array darr1, which was previously defined with dimensions of 100. The output displays the result of 100 from evaluating %ELEM(arr1).
L18 1 ph-ac
This document introduces phasors and their graphical representation. It discusses that a phasor can represent the magnitude and angular position of a sinusoidal quantity. It also describes that a phasor diagram can show the relative relationship of sine waves of the same frequency. The document outlines different forms to represent a phasor including rectangular, trigonometric, exponential and polar forms. It discusses operations that can be performed on phasors such as addition, subtraction, multiplication and division in both rectangular and polar forms. Finally, it describes how phasors can be graphically added and subtracted on a phasor diagram.
3D Smith Chart
The 3D Smith Chart program is a new Java tool for visualizing and designing active and passive microwave circuits. It generalizes the traditional 2D Smith chart onto the surface of a sphere, addressing limitations of the 2D chart. Key features include reading measurement files, plotting reflection coefficients for complex impedances, and aiding oscillator and amplifier design by visualizing infinite mismatch and stability circles. The tool aims to provide a complete graphical solution for microwave circuit measurement and design.
Loop alignment
The document discusses loop alignment techniques to eliminate loop carried dependencies and enable parallelization. It describes how adding an extra iteration and adjusting indices can align references to compute and use values in the same iteration. Alignment incurs overhead from conditionals and modulo operations. While alignment can eliminate dependencies for loops without recurrences, it may not work for loops with recurrences due to possible alignment conflicts between dependencies.
Gate ee 2008 with solutions
This document contains 20 multiple choice questions from a GATE EE exam. Each question is presented along with the question stem and 4 possible answer choices. The correct answer is indicated and a brief explanation of the solution is provided. The questions cover topics in circuits, signals and systems, random variables, matrices, communication systems, control systems, electronics, and power systems.
Intro to smithchart
The Smith Chart is a graphical tool developed in the 1930s to help solve radio frequency circuit problems. It displays impedances on a chart using a system of circles and arcs. Impedances are plotted based on their resistance (circle) and reactance (arc) values after normalizing to the system characteristic impedance. In this example, the Smith Chart is used to calculate the input impedance seen at the transmitter given the load impedance of an antenna and the electrical length of the transmission line connecting them.
Raicesdeecuaciones
The document contains results from applying different root finding algorithms - bisection, false position, secant, Newton-Raphson, and fixed point - to find the root of a function. It shows the iterations, estimates for the root at each iteration and the error compared to the previous iteration. The algorithms converge to a root near 0.42630275 after several iterations, with the error decreasing significantly in each successive step.
Sloof
This document summarizes the calculations for the dimensions and reinforcement of a sloped beam. The beam has a height of 0.5m and width of 0.18m. The required reinforcement is calculated to be 3 bars of 14mm diameter on the bottom of the beam. An iterative process is used to calculate the depth of the neutral axis as 35.36mm. The nominal moment capacity is calculated as 49451528 Nmm, which exceeds the required design moment of 21020000 Nmm. Therefore, the beam reinforcement is adequate.
EC6503 TLWG - Properties of Smith Chart
The Smith chart is a graphical tool developed by P.H. Smith at Bell Labs to help solve radio frequency transmission line problems. It displays the resistance and reactance of an impedance on a chart bounded by a unit circle. Circles of constant resistance and reactance are superimposed, allowing one to easily locate complex impedances and determine key parameters like voltage maxima and minima. The Smith chart represents an invaluable tool for simplifying transmission line design issues that are difficult to solve analytically.
P13 048
This document describes calculating torques and forces on a beam hinged at one end. It finds that for a 12m beam with a 400N tension and angles of 40 and 50 degrees, the weight on the beam is 671N. Equilibrium equations show the horizontal hinge force is 400N of tension and the vertical force is approximately 670N of weight.
Eet3082 binod kumar sahu lecturer_24
1. The document discusses numerical problems related to alternators, including:
2. Calculating the current and power factor of a star-connected alternator just before falling out of step given its synchronous impedance and rated current/power factor.
3. Determining the current and power factor of a star-connected turbo alternator if excitation is raised by 20% without changing prime mover input, given its reactance and original current/power factor.
4. Estimating the load power factor and power delivered by a star-connected alternator if its voltage regulation is zero, given its rating and synchronous reactance.
5. Finding the maximum active and reactive power values that can be delivered by a synchronous
The smith chart
The document describes how the Smith Chart maps impedances on the normalized complex impedance plane to the complex Γ plane. Vertical lines on the impedance plane representing constant resistance values r map to circles on the Γ plane, with centers located along the Γi = 0 line. Horizontal lines representing constant reactance values x also map to circles, with centers located along the Γr = 1 line. By mapping many such lines, the rectilinear grid of the impedance plane is distorted into the curvilinear grid of circles that make up the Smith Chart.
6161103 4.8 resultants of a force and couple system
1) The document discusses calculating the resultant force and moment on a rigid body from a system of individual forces and couples.
2) It provides equations to calculate the total resultant force, FR, total resultant moment, MR, and components of each.
3) Examples are given to demonstrate calculating the equivalent resultant force and moment at a point by summing the forces and moments of the individual components.
What's hot (19)
6161103 4.8 resultants of a force and couple system
6161103 4.8 resultants of a force and couple system
Viewers also liked
Solar LED street light, 20 w 40w
LED Solar street light, road light, 20w, 25w, 30w,40w for choice, www.luminhome.com. if need more information conatct: sales1@luminhome.com . Happy hear from you .
8713-Event-Information-kit-WEB_15 Sept
This document provides guidelines for event organisers in Liverpool City Council area. It covers key topics such as event management and approval process, community awareness and communications, accessibility, sustainability, transport, health, safety, risk management, temporary structures, volunteers, legal requirements and evaluation. It aims to assist event organisers in planning a safe and successful event and ensuring all necessary standards and approvals are met. Site maps and checklists are provided in attachments to help organisers navigate the application and planning process.
Control estadístico de calidad unad m
Este documento proporciona información sobre un servicio de asesoría y resolución de ejercicios de ciencias. Incluye instrucciones para dos actividades: la primera instruye el uso de un diagrama de Pareto para analizar los defectos más frecuentes en una línea de producción, y la segunda instruye el uso de gráficos de control para cuantificar defectos en un proceso de fabricación de baños de cerámica.
4.2.1 RC Circuits
This document discusses the relationship between voltage, current, and resistance in circuits. Voltage across a resistor (VR) equals current through the resistor (IR) multiplied by the resistance value (R). Additionally, voltage across a capacitor (VC) equals current through the capacitor (IC) multiplied by the capacitive reactance (XC).
3.3.2 F Type
This document discusses a structured cabling system that features waterproof coaxial connections for RG59 and RG6 cable types. The connections are color coded for easy identification of the cable type, with red for RG59, yellow for RG6 dual-shield, and blue for RG6 quad-shield cables. It also mentions a crimp plug for connecting RG6/U quad-shield coaxial cable.
alzheimer
conocer sobre esta enfermedad nos ayudara a saber como cuidar a nuestros pacientes con alzheimer, y algo muy importante que debo de recalcar que no cualquier persona puede ser responsable de el, debe tener ciertas características y tener sobre todo paciencia.
Human reproduction
Human reproduction involves the fertilization of an ovum by a sperm, which leads to the development of an embryo and eventual birth of a child. The stages include fertilization where a sperm fertilizes an ovum, development of the embryo as the zygote divides and multiplies into an embryo, and development of the fetus over nine weeks as all organs are formed and it grows in the uterus receiving oxygen and nourishment from the mother's placenta until birth.
Viewers also liked (8)
Similar to 4.1.5 RL Example 1
presentation_chapter_2_ac_networks_1516086872_20707.ppt
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb nnnnnnnnnnnnnnn jjjjjjjjjjjjjjjjjjjjjjbllllllllllll ttttttttttttttttt
EEE 3
This document contains a set of practice problems related to sinusoidal signals, phasors, and AC power analysis. It begins with definitions of terms like sinusoids, phasors, resistance, inductance, capacitance, and impedance. It then presents 35 problems involving concepts like phasor representations of signals, phase relationships between voltage and current in different circuit elements, power calculations, RMS values, and power factors. The document spans 24 pages and provides the questions, blank spaces for solutions, and sometimes diagrams related to circuit analysis.
12 seri rlc
1. The document discusses RLC series circuits. It defines impedance and explains that resonance occurs in a series RLC circuit when the frequency causes the voltages across the inductor and capacitor to become equal and opposite in phase.
2. It provides the equation for determining impedance in a RLC series circuit and discusses the relationships between source voltage, current, and impedance. It also examines the voltage across each component in relation to current.
3. Examples are given to calculate current as a function of time, phase difference, and capacitor voltage for various RLC series circuits operating at different frequencies. Diagrams are drawn to illustrate the phasor relationships.
Topic 2b ac_circuits_analysis
1) An AC generator with an RMS voltage of 110 V is connected in series with a 35-Ω resistor and 1-μF capacitor. To maintain a current of 1.2 A, the generator must operate at a frequency of 1.9 kHz.
2) An AC generator with an emf of 22.8 V at 353 rad/s is connected to a 17.3 H inductor. When the current is maximum, the emf is 22.8 V. When the emf is -11.4 V and increasing, the current is 4.11 A.
3) A series RLC circuit with a 148-Ω resistor, 1.50-μF capacitor
4.1.6 RL Example 2
A circuit contains a 50 ohm resistor connected in series with a 0.2H inductor that has 4 ohms of resistance. The circuit is powered by a 50Hz supply. A 25V drop is measured across the resistor. The current is found to be 0.5A. The inductor's reactance is calculated as 62.8 ohms. Using the required equations accounting for the resistor, inductor and their combined resistance, the total applied voltage is calculated to be 41.4V. The phase angle between the current and applied voltage is 49.3 degrees.
Ac wave forms theroy
This document provides information about AC waveforms including:
- Formulas for instantaneous voltage of a sine wave in terms of peak voltage and angle.
- Conversions between peak, RMS, and average voltages.
- Relationships between frequency and period.
- Calculations of power in resistive AC circuits using RMS voltages and currents.
- Examples of calculations including instantaneous voltage, peak voltage, frequency, and power dissipation.
rangkaian am dan fm
The document provides an overview of key topics in alternating current (AC) circuits covered in Chapter 31, including:
1) The use of phasors to describe sinusoidally varying quantities in AC circuits such as resistors, inductors, and capacitors.
2) Analyzing RLC series circuits driven by a sinusoidal voltage source using phasors.
3) Factors that determine the power in an AC circuit such as the current and voltage amplitudes and their phase relationship.
4) Resonance in RLC circuits and the effect of frequency on current.
5) Transformers and how they can change AC voltages and currents through electromagnetic induction.
Transmission lines
1) The document discusses transmission lines and their characteristics. It describes different types of transmission lines including coaxial lines, two-wire lines, and microstrip lines.
2) It presents the telegrapher's equations which model voltage and current on a transmission line as a function of position and time. These equations include parameters like inductance and capacitance per unit length.
3) Waves can propagate down transmission lines, maintaining their shape as they travel at a characteristic velocity. The wavelength depends on the wave velocity and frequency. Phasors are used to represent sinusoidal waves independent of time.
AC electricity
This document summarizes key concepts about alternating current (AC) circuits including resistors, inductors, and capacitors in AC circuits. It discusses the RLC series circuit, power in AC circuits, and resonance. It also covers transformers and how they are used for power transmission by stepping voltages up or down. Resonance occurs at the resonance frequency when the inductive reactance equals the capacitive reactance in a RLC series circuit, resulting in maximum current. Transformers use magnetic induction to change AC voltages efficiently for applications like power distribution.
AC.pptx
Alternating voltages and currents are easier to generate and distribute than direct currents. AC can be converted to DC using rectifiers when needed. AC quantities vary sinusoidally with time and can be analyzed using phasors. The opposition to AC flow in circuits is called reactance, which depends on the frequency and circuit elements. Resonance occurs in RLC circuits when the inductive and capacitive reactances are equal, resulting in maximum current flow. Circuit Q factor and bandwidth describe the frequency response around the resonant point.
Basic Electrical Engineering Module 1 Part 1
This document provides an overview of basic electrical engineering concepts including Ohm's Law, series and parallel circuits, and Kirchhoff's Laws. It defines Ohm's Law as stating that current is directly proportional to voltage and inversely proportional to resistance. Kirchhoff's Current Law and Voltage Law are introduced as the principles that the algebraic sum of currents at a junction is zero and the algebraic sum of voltages around a closed loop is also zero. An example circuit problem is worked through using these laws to solve for unknown currents.
Modeling of an RLC circuit
This presentation contains basics of RLC circuit. Also there is a model developed for a given RLC circuit problem. The solution of this model is also included with MATLAB code.
Network analysis-mcq-for-apgenco-aptranco-preparation
This document contains multiple choice questions and answers about electrical engineering concepts. It begins with 50 questions about topics like Thevenin's theorem, decibel calculations, filters, transmission lines, and more. Each question is followed by an explanation of the correct answer. The questions cover fundamental concepts and calculations in electrical engineering.
LISTRIK
1. Alternating current (AC) is an electric current that reverses direction and changes its magnitude continuously with time in contrast to direct current (DC), which flows only in one direction. AC is used in power transmission and domestic power lines.
2. The benefits of using AC include powering many household appliances and machines, street lighting, powering factory machines, and providing power grid security in homes.
3. In an AC circuit, impedance is calculated as the square root of resistance squared plus the difference between inductive and capacitive reactances squared. Impedance determines the current in the circuit.
Chapter32A.ppt
This document discusses AC circuits and their components. It covers:
- Calculating inductive and capacitive reactance for inductors and capacitors.
- Phase relationships in circuits with resistance, capacitance, and inductance. Voltage leads or lags current depending on the component.
- Impedance, effective current, power, and resonant frequency calculations for series RLC circuits. Resonance occurs when inductive and capacitive reactances cancel out.
AP PGECET Electrical Engineering 2016 question paper
This document provides instructions for a 120-question, 120-minute multiple choice exam. Each question has 4 answer choices marked A, B, C or D. Questions must be answered on the provided OMR answer sheet using a blue or black pen. The exam booklet and answer sheet should be returned to the invigilator before leaving the exam hall. No additional materials like calculators are allowed.
PROBLEMAS RESUELTOS (93) DE LABORATORIO N° 2 DE FÍSICA II - SEARS
This document discusses direct-current circuits and series-parallel resistor combinations. It contains several examples of calculating equivalent resistances and currents in circuits with series and parallel resistors. The key steps are to identify the resistor combinations, set up the appropriate series or parallel resistance formula, then execute the calculations and evaluate the results. Calculating power dissipation in resistors is also demonstrated.
MATERI LISTRIK BOLAK-BALIK (AC)
1. The document discusses alternating current (AC), which is an electric current that reverses direction and changes its magnitude continuously with time in contrast to direct current (DC), which flows only in one direction.
2. It provides definitions and examples of AC, including that it is used to power many household appliances as well as street lights, factory machines, and is distributed through electrical networks by utility companies.
3. Key concepts covered include effective voltage and current, inductive and capacitive reactance, impedance, power, and example calculations involving AC circuits.
Materi arus listrik bolak balik (ac)
1. The document discusses alternating current (AC), which is an electric current that reverses direction and changes its magnitude continuously with time in contrast to direct current (DC), which flows only in one direction.
2. It provides definitions and examples of AC, including that it is used to power most household appliances and generates sinusoidal waves. The benefits of AC include powering homes and industries.
3. Formulas are presented for calculating effective voltage and current, impedance, power, and other electrical characteristics of AC circuits containing resistors, inductors, and capacitors. Worked examples applying the formulas are also provided.
R-L-C circuit
This document section describes alternating current (AC) circuits containing a single circuit element: resistor, inductor, or capacitor, connected to an AC voltage source. For a resistive circuit, the current and voltage are in phase. For an inductive circuit, the current lags the voltage by 90 degrees. For a capacitive circuit, the current leads the voltage by 90 degrees. The document defines important concepts such as reactance, impedance, and phasor diagrams for analyzing AC circuits.
Similar to 4.1.5 RL Example 1 (20)
presentation_chapter_2_ac_networks_1516086872_20707.ppt
presentation_chapter_2_ac_networks_1516086872_20707.ppt
Network analysis-mcq-for-apgenco-aptranco-preparation
Network analysis-mcq-for-apgenco-aptranco-preparation
AP PGECET Electrical Engineering 2016 question paper
AP PGECET Electrical Engineering 2016 question paper
PROBLEMAS RESUELTOS (93) DE LABORATORIO N° 2 DE FÍSICA II - SEARS
PROBLEMAS RESUELTOS (93) DE LABORATORIO N° 2 DE FÍSICA II - SEARS
More from Talia Carbis
7.4.6 slip
This document describes how to calculate the rotor frequency of a two-pole, 50 Hz induction motor given the rotor speed of 2850 rpm. It shows that the slip speed is 3000 rpm, the slip percentage is 5%, and using the formula fs x %slip / 100, the rotor frequency is calculated to be 2.5 Hz.
4.2.1 Better Load
The document describes the circuits and loads for an electrical installation. It lists 19 circuits with various lighting, power outlet, motor, and appliance loads. It calculates the demand current in amps for each phase based on adding the full load or percentage of full load for each circuit based on rating and number of devices. The highest calculated demand is 153.25 amps on phase L2. With a 10% allowance for future additions, the total recommended maximum current is 168.575 amps.
4.1.13 Light Demand 3
This short document does not provide any substantive information to summarize in 3 sentences or less. It only notes that an explanation is not contained in a workbook, but provides no other context or details.
4.1.12 Light Demand 2 Table Part2
The document outlines the demand calculations for 19 different circuit load groups across 3 phases. It lists the load description, current allowance calculation method, and resulting demand current for each phase. The total demand current per phase is calculated at the bottom, with values of 143.8 amps for phase 1, 153.25 amps for phase 2, and 145.05 amps for phase 3.
4.1.11 Light Demand 2 Table
The document contains a table that calculates the current demand per phase for various circuit load groups in an electrical system. It lists 19 load groups categorized by letters A through D, describing each load. It shows the current allowance calculation method and resulting demand in amps for each phase. The total demand current calculated per phase is 143.8 amps for L1, 153.25 amps for L2, and 145.05 amps for L3.
4.1.10 Light Demand 2
This 3 sentence document provides instructions to refer to a specific table on a specific page of a particular standard for additional explanatory information not contained in the current workbook. The instructions direct the reader to Table C2 on page 359 of AS/NZA 3000:2007 for an explanation that is not included in the current document.
4.1.9 Light Demand 1
The document describes the functions of 19 electrical circuits in a building. It lists the types of equipment connected to each circuit such as fluorescent lighting, outlets, motors, and appliances. It also indicates which of the 3 electrical phases (L1, L2, L3) each circuit is connected to.
4.1.7 Example Domestic 3
The document calculates the electrical load of communal services in an apartment building. It shows that 24 lighting points will draw 240 watts and 6 10A sockets will draw up to 12A, for a total demand of 18A per phase. The total demand current per phase for communal services is 18A.
4.1.6 Example Domestic 2
The document calculates the electrical load and demand for 6 living units per phase. It lists the types of loads in each unit, the quantity and allowance per unit, and uses this to calculate the total demand current for phases L1, L2 and L3, which is 154.4 amps for each phase. The key loads included are lighting, power outlets, cooking ranges, air conditioners and hot water systems.
4.1.5 Example Domestic 1
This document discusses the number of living units per phase of a project. It calculates that for 18 total living units divided into 3 phases, there would be 6 living units per phase.
4.1.4 Step 2
This document summarizes the electrical load calculations for 11 circuits in a home. It lists the load type and description for each circuit, the current allowance per unit, and calculates the demand in amps for circuits 1-10. The largest demands are 17.7 amps for an air conditioner and 15 amps for an off-peak hot water system. The total calculated demand current for each phase is 40.7, 39.5, and 46.5 amps respectively.
4.1.3 Example Solution Three
The document calculates the electrical load and demand current for 11 circuits in a home. It groups the loads into categories like lighting, outlets, appliances, and assigns each a description, allowance, and demand calculation. The total demand current per phase is summarized at the bottom, with the highest draw of 46.5 amps on phase L3.
4.1.2 Example Three
The document outlines the functions and ratings of 12 electrical circuits. Circuit 1 provides power for 13 indoor lighting points. Circuit 10 powers an air conditioner rated at 23.6 amps per phase and can draw power from circuits L1, L2, and L3. Circuits 11a and 11b each power a controlled load hot water unit rated at 3.6 kW.
4.1.1 Example Single
This document calculates the total demand current for an electrical installation consisting of:
- 21 lighting points and 12 double sockets, contributing 5A and 15A respectively
- 15 single sockets contributing 10A
- A 6kW oven contributing 0.5A
- A 2.4kW water heater contributing 0.33A
The total demand current calculated is 45.83A.
5.4.4 LR Circuits
The document discusses the time constant and final current value for an RL circuit. It states that:
1) The time constant for the circuit is 0.17 seconds based on the given inductance and resistance values.
2) It will take approximately 0.85 seconds (5 time constants) for the current to reach its final value.
3) Using Ohm's law, the approximate final current after 0.85 seconds is 2 amps.
14.5.4 Example 1 Part 1
This document calculates the apparent power, power factor, and phase angle for a circuit. It finds that the apparent power is 2.308 kVA by multiplying the current of 9.615 by the voltage of 240. This apparent power is larger than the actual power of 1.5 kW, indicating a poor power factor of 0.65 or a 49.46 degree phase angle between the current and voltage.
14.1.2 TRA Power
Reactive power (Q) and true power (P) combine to form apparent power (S). Apparent power is the combination of true power, which is the usable energy in a circuit, and reactive power, which is stored energy that results from the combination of voltage and current out of phase.
14.5.8 Example 1 Part 5
This document calculates the true power, apparent power, and total current for a circuit. It determines that the true power is 1.5 kW, the apparent power is 1.5009 kVA, and the power factor is 0.99994. It then calculates that with an apparent power of 1.5009 kVA at 240 Volts, the total current would be 6.25 amps.
More from Talia Carbis (20)
Recently uploaded
MISS TEEN HYDERABAD 2024 - WINNER RYKA TANDON
In the dynamic city of Hyderabad, a youthful and outstandingly skilled person has as of late made waves on the national stage. Ryka Tandon, a 14-year-old understudy, has been honored with the prestigious title of Miss High Schooler India 2024 Victor, Pride of India, from the Dk Show. Her travels to this regarded position are a confirmation of her unflinching devotion, ability, and tireless endeavors. Despite her youthful age, Ryka has, as of now, accomplished momentous points of reference that recognize her as a guide of motivation and pride for her city and her nation. This article digs into the uncommon life and accomplishments of Ryka Tandon, investigating her foundation, achievements, and the qualities that make her a standout individual.
一比一原版美国俄亥俄大学毕业证（OU学位证）如何办理
原件一模一样【微信：WP101A】【美国俄亥俄大学毕业证（OU学位证）成绩单】【微信：WP101A】（留信学历认证永久存档查询）采用学校原版纸张、特殊工艺完全按照原版一比一制作（包括：隐形水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠，文字图案浮雕，激光镭射，紫外荧光，温感，复印防伪）行业标杆！精益求精，诚心合作，真诚制作！多年品质 ,按需精细制作，24小时接单,全套进口原装设备，十五年致力于帮助留学生解决难题，业务范围有加拿大、英国、澳洲、韩国、美国、新加坡，新西兰等学历材料，包您满意。
【业务选择办理准则】
一、工作未确定，回国需先给父母、亲戚朋友看下文凭的情况，办理一份就读学校的毕业证【微信：WP101A】文凭即可
二、回国进私企、外企、自己做生意的情况，这些单位是不查询毕业证真伪的，而且国内没有渠道去查询国外文凭的真假，也不需要提供真实教育部认证。鉴于此，办理一份毕业证【微信：WP101A】即可
三、进国企，银行，事业单位，考公务员等等，这些单位是必需要提供真实教育部认证的，办理教育部认证所需资料众多且烦琐，所有材料您都必须提供原件，我们凭借丰富的经验，快捷的绿色通道帮您快速整合材料，让您少走弯路。
留信网认证的作用:
1:该专业认证可证明留学生真实身份【微信：WP101A】
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
→ 【关于价格问题（保证一手价格）
我们所定的价格是非常合理的，而且我们现在做得单子大多数都是代理和回头客户介绍的所以一般现在有新的单子 我给客户的都是第一手的代理价格，因为我想坦诚对待大家 不想跟大家在价格方面浪费时间
对于老客户或者被老客户介绍过来的朋友，我们都会适当给一些优惠。
选择实体注册公司办理，更放心，更安全！我们的承诺：可来公司面谈，可签订合同，会陪同客户一起到教育部认证窗口递交认证材料，客户在教育部官方认证查询网站查询到认证通过结果后付款，不成功不收费！
办理美国俄亥俄大学毕业证（OU学位证）学位证【微信：WP101A 】外观非常精致，由特殊纸质材料制成，上面印有校徽、校名、毕业生姓名、专业等信息。
办理美国俄亥俄大学毕业证（OU学位证）学位证【微信：WP101A 】格式相对统一，各专业都有相应的模板。通常包括以下部分：
校徽：象征着学校的荣誉和传承。
校名:学校英文全称
授予学位：本部分将注明获得的具体学位名称。
毕业生姓名：这是最重要的信息之一，标志着该证书是由特定人员获得的。
颁发日期：这是毕业正式生效的时间，也代表着毕业生学业的结束。
其他信息：根据不同的专业和学位，可能会有一些特定的信息或章节。
办理美国俄亥俄大学毕业证（OU学位证）学位证【微信：WP101A 】价值很高，需要妥善保管。一般来说，应放置在安全、干燥、防潮的地方，避免长时间暴露在阳光下。如需使用，最好使用复印件而不是原件，以免丢失。
综上所述，办理美国俄亥俄大学毕业证（OU学位证）学位证【微信：WP101A 】是证明身份和学历的高价值文件。外观简单庄重，格式统一，包括重要的个人信息和发布日期。对持有人来说，妥善保管是非常重要的。
一比一原版塔夫斯大学毕业证Tufts成绩单一模一样
原件一模一样【微信：6496090】【塔夫斯大学毕业证Tufts学位证成绩单】【微信：6496090】（留信学历认证永久存档查询）采用学校原版纸张、特殊工艺完全按照原版一比一制作（包括：隐形水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠，文字图案浮雕，激光镭射，紫外荧光，温感，复印防伪）行业标杆！精益求精，诚心合作，真诚制作！多年品质 ,按需精细制作，24小时接单,全套进口原装设备，十五年致力于帮助留学生解决难题，业务范围有加拿大、英国、澳洲、韩国、美国、新加坡，新西兰等学历材料，包您满意。
【业务选择办理准则】
一、工作未确定，回国需先给父母、亲戚朋友看下文凭的情况，办理一份就读学校的毕业证【微信：6496090】文凭即可
二、回国进私企、外企、自己做生意的情况，这些单位是不查询毕业证真伪的，而且国内没有渠道去查询国外文凭的真假，也不需要提供真实教育部认证。鉴于此，办理一份毕业证【微信：6496090】即可
三、进国企，银行，事业单位，考公务员等等，这些单位是必需要提供真实教育部认证的，办理教育部认证所需资料众多且烦琐，所有材料您都必须提供原件，我们凭借丰富的经验，快捷的绿色通道帮您快速整合材料，让您少走弯路。
留信网认证的作用:
1:该专业认证可证明留学生真实身份【微信：6496090】
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
→ 【关于价格问题（保证一手价格）
我们所定的价格是非常合理的，而且我们现在做得单子大多数都是代理和回头客户介绍的所以一般现在有新的单子 我给客户的都是第一手的代理价格，因为我想坦诚对待大家 不想跟大家在价格方面浪费时间
对于老客户或者被老客户介绍过来的朋友，我们都会适当给一些优惠。
选择实体注册公司办理，更放心，更安全！我们的承诺：可来公司面谈，可签订合同，会陪同客户一起到教育部认证窗口递交认证材料，客户在教育部官方认证查询网站查询到认证通过结果后付款，不成功不收费！
办理塔夫斯大学毕业证Tufts学位证【微信：6496090 】外观非常精致，由特殊纸质材料制成，上面印有校徽、校名、毕业生姓名、专业等信息。
办理塔夫斯大学毕业证Tufts学位证【微信：6496090 】格式相对统一，各专业都有相应的模板。通常包括以下部分：
校徽：象征着学校的荣誉和传承。
校名:学校英文全称
授予学位：本部分将注明获得的具体学位名称。
毕业生姓名：这是最重要的信息之一，标志着该证书是由特定人员获得的。
颁发日期：这是毕业正式生效的时间，也代表着毕业生学业的结束。
其他信息：根据不同的专业和学位，可能会有一些特定的信息或章节。
办理塔夫斯大学毕业证Tufts学位证【微信：6496090 】价值很高，需要妥善保管。一般来说，应放置在安全、干燥、防潮的地方，避免长时间暴露在阳光下。如需使用，最好使用复印件而不是原件，以免丢失。
综上所述，办理塔夫斯大学毕业证Tufts学位证【微信：6496090 】是证明身份和学历的高价值文件。外观简单庄重，格式统一，包括重要的个人信息和发布日期。对持有人来说，妥善保管是非常重要的。
欧洲杯下注-欧洲杯下注买球网-欧洲杯下注买球网站|【网址🎉ac10.net🎉】
【网址🎉ac10.net🎉】欧洲杯下注是此世界知名网上博彩平台的特点是对英超、英冠以及英国的赛事准确率很高，赔率很少变动。欧洲杯下注平台的赔率一旦出现变动，其它英国和国外的赛事赔率都会因而出现变动，欧洲杯下注对业界的影响力可见一斑。
Navigating the World of Topsoil: A Guide to the Right Choice for Your Garden
Are you looking to improve your garden's health but unsure about which topsoil to choose? This PPT provides insights into selecting the right topsoil for your gardening needs. From understanding various types of topsoil to evaluating their benefits, this resource equips you with the essential knowledge to make an informed decision. Explore to learn more.
Click to know more - https://mulchpros.com/blog/navigating-the-world-of-topsoil-a-guide-to-the-right-choice-for-your-garden/
一比一原版(UoL毕业证)伦敦大学毕业证如何办理
UoL毕业证成绩单【微信95270640】国外文凭购买伦敦大学留信认证毕业证书印刷品《Q微信95270640》学历认证怎么做：原版仿制伦敦大学电子版成绩单毕业证认证《伦敦大学毕业证成绩单》、伦敦大学文凭证书成绩单复刻offer录取通知书、购买UoL圣力嘉学院本科毕业证、《伦敦大学毕业证办理UoL毕业证书哪里买》、伦敦大学 Offer在线办理UoL Offer伦敦大学Bachloer Degree。
【实体公司】办伦敦大学伦敦大学毕业证学历书学历认证学位证文凭认证办留信网认证办留服认证办教育部认证（网上可查实体公司专业可靠）
— — — 留学归国服务中心 — — -
【主营项目】
一.伦敦大学毕业证成绩单使馆认证教育部认证成绩单等！
二.真实使馆公证(即留学回国人员证明,不成功不收费)
三.真实教育部学历学位认证（教育部存档！教育部留服网站永久可查）
四.办理各国各大学文凭(一对一专业服务,可全程监控跟踪进度)
国外毕业证学位证成绩单办理流程：
1客户提供伦敦大学伦敦大学毕业证学历书办理信息：姓名生日专业学位毕业时间等（如信息不确定可以咨询顾问：我们有专业老师帮你查询）；
2开始安排制作毕业证成绩单电子图；
3毕业证成绩单电子版做好以后发送给您确认；
4毕业证成绩单电子版您确认信息无误之后安排制作成品；
5成品做好拍照或者视频给您确认；
6快递给客户（国内顺丰国外DHLUPS等快读邮寄）。
专业服务请勿犹豫联系我！本公司是留学创业和海归创业者们的桥梁。一次办理终生受用一步到位高效服务。详情请在线咨询办理,欢迎有诚意办理的客户咨询!洽谈。
招聘代理：本公司诚聘英国加拿大澳洲新西兰美国法国德国新加坡各地代理人员如果你有业余时间有兴趣就请联系我们咨询顾问：+微信:95270640山娃很高兴夏令营就设在附近一所小学山娃发现那所小学比自己的学校更大更美操场上还铺有塑胶跑道呢里面很多小朋友一班一班的快快乐乐原来城里娃都藏这儿来了怪不得平时见不到他们山娃恍然大悟起来吹拉弹唱琴棋书画山娃都不懂却什么都想学山娃怨自己太笨什么都不会斟酌再三山娃终于选定了学美术当听说每月要交元时父亲犹豫了山娃也说爸算了吧咱学校一学期才交元呢买图画书回家咱自己练父亲摸着山娃的小平头擤了擤鼻子很感动很无奈窄
Stag Elevators | Leading Home Elevator Company in India
Discover Stag Elevators, India's premier home elevator company, dedicated to delivering unmatched mobility solutions nationwide. Specializing in certified home elevators, lifts, and platform lifts, Stag Elevators leads with superior safety, quality, and innovation. Partnering with renowned Italian manufacturers ensures every product meets European safety standards and is TUV certified, offering affordability and utmost safety for homes of all sizes and types, from small houses to luxury residences.
快速办理(加拿大CBU毕业证书)卡普顿大学毕业证毕业完成信一模一样
学校原件一模一样【微信：741003700 】《(加拿大CBU毕业证书)卡普顿大学毕业证》【微信：741003700 】学位证，留信认证（真实可查，永久存档）原件一模一样纸张工艺/offer、雅思、外壳等材料/诚信可靠,可直接看成品样本，帮您解决无法毕业带来的各种难题！外壳，原版制作，诚信可靠，可直接看成品样本。行业标杆！精益求精，诚心合作，真诚制作！多年品质 ,按需精细制作，24小时接单,全套进口原装设备。十五年致力于帮助留学生解决难题，包您满意。
本公司拥有海外各大学样板无数，能完美还原。
1:1完美还原海外各大学毕业材料上的工艺：水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠。文字图案浮雕、激光镭射、紫外荧光、温感、复印防伪等防伪工艺。材料咨询办理、认证咨询办理请加学历顾问Q/微741003700
【主营项目】
一.毕业证【q微741003700】成绩单、使馆认证、教育部认证、雅思托福成绩单、学生卡等！
二.真实使馆公证(即留学回国人员证明,不成功不收费)
三.真实教育部学历学位认证（教育部存档！教育部留服网站永久可查）
四.办理各国各大学文凭(一对一专业服务,可全程监控跟踪进度)
如果您处于以下几种情况：
◇在校期间，因各种原因未能顺利毕业……拿不到官方毕业证【q/微741003700】
◇面对父母的压力，希望尽快拿到；
◇不清楚认证流程以及材料该如何准备；
◇回国时间很长，忘记办理；
◇回国马上就要找工作，办给用人单位看；
◇企事业单位必须要求办理的
◇需要报考公务员、购买免税车、落转户口
◇申请留学生创业基金
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
The Uttoxeter and Cheadle Voice Issue 123
Giving a voice to those in Uttoxeter and Cheadle, as well as the surrounding towns and villages.
欧洲杯赌钱-欧洲杯赌钱比赛投注-欧洲杯赌钱比赛投注官网|【网址🎉ac22.net🎉】
【网址🎉ac22.net🎉】欧洲杯赌钱是一家极具特色的欧洲主流博彩公司，对于自己所擅长的赛事往往把赔率值压得很低，掩饰平局是他们一贯的手法。例如，当伟德旗帜鲜明地支持客胜，降低客胜值，提升主胜值，而平局赔率却与欧洲杯赌钱、欧洲杯赌钱的态度较吻合时，这场比赛往往以平局收场。
美洲杯投注冠军赔率揭晓！谁将问鼎南美之王？|【网址🎉ac22.net🎉】
美洲杯，作为南美洲最具影响力的足球赛事，吸引着全球球迷的目光。而对于众多球迷而言，除了观赏精彩的比赛之外，美洲杯投注也是不可或缺的一部分。如何选择合适的球队，如何解读美洲杯投注冠军赔率，成为了球迷们热议的话题。
**美洲杯投注冠军赔率**
2024年的美洲杯，各支强队蓄势待发，争夺南美之王的荣耀。而各大博彩公司也纷纷发布了最新的美洲杯投注冠军赔率，为球迷们提供了参考依据。例如，巴西队作为卫冕冠军，实力依然强劲，赔率自然也处于领先位置。而阿根廷队、乌拉圭队等传统强队，也拥有不俗的实力和深厚的底蕴。此外，近年来涌现的强劲黑马，例如哥伦比亚队、厄瓜多尔队，也值得关注。
**如何解读美洲杯投注冠军赔率**
美洲杯投注冠军赔率，反映了各支球队夺冠的概率。赔率越低，球队夺冠的可能性越高。例如，巴西队的赔率可能为1.5，而哥伦比亚队的赔率可能为8.0。这意味着，巴西队夺冠的可能性远高于哥伦比亚队。
**美洲杯投注平台推荐**
想要体验美洲杯投注的乐趣，选择一个靠谱的平台至关重要。**[入口: ac99.net]** 提供丰富的投注选项，赔率优惠，操作便捷，是您美洲杯投注的不二之选。
**如何选择合适的球队**
在选择球队进行美洲杯投注时，除了参考赔率之外，还需要综合考虑以下因素：
* 球队近期的状态
* 球队阵容的整体实力
* 球队之间的历史战绩
* 球队的战术风格
* 球队的伤病情况
只有综合考虑这些因素，才能做出更加明智的投注决策。
**总结**
美洲杯投注，不仅能够增加比赛的观赏性，还能让球迷们体验紧张刺激的博彩乐趣。选择靠谱的平台，解读美洲杯投注冠军赔率，并综合考虑各个因素，才能在美洲杯投注中取得更好的收益。祝您在美洲杯投注中好运连连！
MISS RAIPUR 2024 - WINNER POONAM BHARTI.
Poonam Bharti, a guide of ability and diligence, has been chosen as the champ from Raipur for Mrs. India 2024, Pride of India, from the DK Show. Her journey to this prestigious title is a confirmation of her commitment, difficult work, and multifaceted gifts. At fair 23 a long time ago, Poonam has as of now made noteworthy strides in both her proficient and individual lives, encapsulating the soul of present-day Indian ladies who adjust different parts with beauty and competence. This article dives into Poonam Bharti’s foundation, achievements, and qualities that separated her as a meriting champion of this award.
2024欧洲杯比分投注-2024欧洲杯比分投注推荐-2024欧洲杯比分投注|【网址🎉ac99.net🎉】
2024欧洲杯比分投注堪称近年最强的在线博彩独角马公司，他创立于2012年，总部位于美国波士顿，是美国每日梦幻体育比赛和体育博彩的运营商。去年4月挂牌上市后股价一飞冲天，市值轻松超越凯萨娱乐，成为美国博彩业的亮点。2024欧洲杯比分投注也擅长与体坛或是电视媒体合作。2024欧洲杯比分投注宣布与ESPN建立合作伙伴关系，2024欧洲杯比分投注成为每日梦幻体育博彩的独家内容供应商，并成为从在线体彩链接的独家合作伙伴。
Recently uploaded (13)
Navigating the World of Topsoil: A Guide to the Right Choice for Your Garden
Navigating the World of Topsoil: A Guide to the Right Choice for Your Garden
Stag Elevators | Leading Home Elevator Company in India
Stag Elevators | Leading Home Elevator Company in India
2024欧洲杯比分投注-2024欧洲杯比分投注推荐-2024欧洲杯比分投注|【网址🎉ac99.net🎉】
2024欧洲杯比分投注-2024欧洲杯比分投注推荐-2024欧洲杯比分投注|【网址🎉ac99.net🎉】
4.1.5 RL Example 1
- 1. Example Question 1 An inductor has a resistance of 30Ω and an inductance of 0.8H. If itʼs connected across a 240V 50Hz supply, find: (a) Its inductive reactance (b) Its impedance (c) The current flowing through the inductor (d) The phase angle between the current and the applied voltage (e) Also, draw the phasor diagram for the current and voltage.
- 2. Z = impedance in ohms R = resistance in ohms XL = reactance in ohms
- 3. Known values: L = 0.8H R = 30Ω V = 240V f = 50Hz
- 4. (a) Equation XL = 2πfL = 6.28 x 50 x 0.8 Answer XL = 251.2 Ω
- 5. (b) Values: R = 30Ω XL = 251.2 Ω
- 6. Z = √(R² + XL²) Z = √(30² )+(251.2²) Z = √900 + 63101.44 Z = √64001.44 Answer Z = 253 Ω
- 7. (c) Values; Z = 253 Ω V = 240 V
- 8. V I = Z (Ohmʼs law) 240 I = 253 Answer I = 0.95 A
- 9. (d) Values: Z = 253 Ω R = 50 Ω
- 10. ∅ = cos¯¹ R Z
- 11. ∅ = cos¯¹ 30 253
- 12. ∅ = cos¯¹ 0.118577
- 13. Answer ∅ = 83.2°
- 14. Applied voltage (V) Current (I)
- 15. Applied voltage (V) ∅= Current (I)
- 16. Applied voltage (V) ∅ = 83.2⁰ Current (I)