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The Basics
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Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
The Basics
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x.
The Basics
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x.
The Basics
15 can be divided by 3
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x.
Hence 3 is a factor of 15
The Basics
15 can be divided by 3
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x.
Hence 3 is a factor of 15
Example A. List the factors and the multiples of 12.
The factors of 12:
The Basics
15 can be divided by 3
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x.
Hence 3 is a factor of 15
Example A. List the factors and the multiples of 12.
The factors of 12: 1,
The Basics
15 can be divided by 3
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x.
Hence 3 is a factor of 15
Example A. List the factors and the multiples of 12.
The factors of 12: 1, 2,
The Basics
15 can be divided by 3
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x.
Hence 3 is a factor of 15
Example A. List the factors and the multiples of 12.
The factors of 12: 1, 2, 3, 4, 6, and 12.
The Basics
15 can be divided by 3
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x. We also say that x is a multiple of y.
Hence 3 is a factor of 15
Example A. List the factors and the multiples of 12.
The factors of 12: 1, 2, 3, 4, 6, and 12.
The Basics
15 can be divided by 3
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x. We also say that x is a multiple of y.
Hence 3 is a factor of 15 and that 15 is a multiple of 3.
Example A. List the factors and the multiples of 12.
The factors of 12: 1, 2, 3, 4, 6, and 12.
The Basics
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x. We also say that x is a multiple of y.
Hence 3 is a factor of 15 and that 15 is a multiple of 3.
A number x is always the multiple and a factor of itself.
Example A. List the factors and the multiples of 12.
The factors of 12: 1, 2, 3, 4, 6, and 12.
The Basics
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x. We also say that x is a multiple of y.
Hence 3 is a factor of 15 and that 15 is a multiple of 3.
A number x is always the multiple and a factor of itself.
Example A. List the factors and the multiples of 12.
The factors of 12: 1, 2, 3, 4, 6, and 12.
The multiples of 12:
The Basics
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x. We also say that x is a multiple of y.
Hence 3 is a factor of 15 and that 15 is a multiple of 3.
A number x is always the multiple and a factor of itself.
Example A. List the factors and the multiples of 12.
The factors of 12: 1, 2, 3, 4, 6, and 12.
The multiples of 12: 12=1x12,
The Basics
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x. We also say that x is a multiple of y.
Hence 3 is a factor of 15 and that 15 is a multiple of 3.
A number x is always the multiple and a factor of itself.
Example A. List the factors and the multiples of 12.
The factors of 12: 1, 2, 3, 4, 6, and 12.
The multiples of 12: 12=1x12, 24=2x12, 36=3x12, 48, 60, etc…
The Basics
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x. We also say that x is a multiple of y.
Hence 3 is a factor of 15 and that 15 is a multiple of 3.
A number x is always the multiple and a factor of itself.
Example A. List the factors and the multiples of 12.
The factors of 12: 1, 2, 3, 4, 6, and 12.
The multiples of 12: 12=1x12, 24=2x12, 36=3x12, 48, 60, etc…
The Basics
Your Turn: List the factors and the multiples of 18.
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x. We also say that x is a multiple of y.
Hence 3 is a factor of 15 and that 15 is a multiple of 3.
A number x is always the multiple and a factor of itself.
Example A. List the factors and the multiples of 12.
The factors of 12: 1, 2, 3, 4, 6, and 12.
The multiples of 12: 12=1x12, 24=2x12, 36=3x12, 48, 60, etc…
The Basics
A prime number is a natural number that can not be divided
evenly into smaller numbers (except as 1’s), that is to say,
a prime number only has 1 and itself as factors.
Your Turn: List the factors and the multiples of 18.
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x. We also say that x is a multiple of y.
Hence 3 is a factor of 15 and that 15 is a multiple of 3.
A number x is always the multiple and a factor of itself.
Example A. List the factors and the multiples of 12.
The factors of 12: 1, 2, 3, 4, 6, and 12.
The multiples of 12: 12=1x12, 24=2x12, 36=3x12, 48, 60, etc…
The Basics
A prime number is a natural number that can not be divided
evenly into smaller numbers (except as 1’s), that is to say,
a prime number only has 1 and itself as factors.
The numbers 2, 3, 5, 7, (not 9), 11, 13,… are prime numbers.
Your Turn: List the factors and the multiples of 18.
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x. We also say that x is a multiple of y.
Hence 3 is a factor of 15 and that 15 is a multiple of 3.
A number x is always the multiple and a factor of itself.
Example A. List the factors and the multiples of 12.
The factors of 12: 1, 2, 3, 4, 6, and 12.
The multiples of 12: 12=1x12, 24=2x12, 36=3x12, 48, 60, etc…
The Basics
A prime number is a natural number that can not be divided
evenly into smaller numbers (except as 1’s), that is to say,
a prime number only has 1 and itself as factors.
The numbers 2, 3, 5, 7, (not 9), 11, 13,… are prime numbers.
Even numbers are not prime so prime numbers must be odd
(except for 2).
Your Turn: List the factors and the multiples of 18.
Whole numbers 1, 2, 3, 4,.. are called natural numbers because
they are used to count whole items like chickens and cows.
If x and y are two natural numbers and x can be divided by y,
we say y is a factor of x. We also say that x is a multiple of y.
Hence 3 is a factor of 15 and that 15 is a multiple of 3.
A number x is always the multiple and a factor of itself.
Example A. List the factors and the multiples of 12.
The factors of 12: 1, 2, 3, 4, 6, and 12.
The multiples of 12: 12=1x12, 24=2x12, 36=3x12, 48, 60, etc…
The Basics
A prime number is a natural number that can not be divided
evenly into smaller numbers (except as 1’s), that is to say,
a prime number only has 1 and itself as factors.
The numbers 2, 3, 5, 7, (not 9), 11, 13,… are prime numbers.
Even numbers are not prime so prime numbers must be odd
(except for 2). The number 1 is not a prime number.
Your Turn: List the factors and the multiples of 18.
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*...
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6 = 3*4 = 2*2*3.
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete
if all the factors are prime numbers.
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete
if all the factors are prime numbers. Hence 12=2*2*3 is factored
completely,
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete
if all the factors are prime numbers. Hence 12=2*2*3 is factored
completely, 12=2*6 is not complete because 6 is not prime.
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete
if all the factors are prime numbers. Hence 12=2*2*3 is factored
completely, 12=2*6 is not complete because 6 is not prime.
Just as in chemistry that every chemical is a group of bonded
elements, every number is the product of a group of prime
numbers.
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete
if all the factors are prime numbers. Hence 12=2*2*3 is factored
completely, 12=2*6 is not complete because 6 is not prime.
Just as in chemistry that every chemical is a group of bonded
elements, every number is the product of a group of prime
numbers.
Exponents
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete
if all the factors are prime numbers. Hence 12=2*2*3 is factored
completely, 12=2*6 is not complete because 6 is not prime.
Just as in chemistry that every chemical is a group of bonded
elements, every number is the product of a group of prime
numbers.
Exponents
To simplify writing repetitive multiplication, we write 22 for 2*2,
we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on.
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete
if all the factors are prime numbers. Hence 12=2*2*3 is factored
completely, 12=2*6 is not complete because 6 is not prime.
Just as in chemistry that every chemical is a group of bonded
elements, every number is the product of a group of prime
numbers.
Exponents
To simplify writing repetitive multiplication, we write 22 for 2*2,
we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on.
We write x*x*x…*x as xN where N is the number of x’s
multiplying to itself.
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete
if all the factors are prime numbers. Hence 12=2*2*3 is factored
completely, 12=2*6 is not complete because 6 is not prime.
Just as in chemistry that every chemical is a group of bonded
elements, every number is the product of a group of prime
numbers.
Exponents
To simplify writing repetitive multiplication, we write 22 for 2*2,
we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on.
We write x*x*x…*x as xN where N is the number of x’s
multiplying to itself. N is called the exponent or the power of xN.
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete
if all the factors are prime numbers. Hence 12=2*2*3 is factored
completely, 12=2*6 is not complete because 6 is not prime.
Just as in chemistry that every chemical is a group of bonded
elements, every number is the product of a group of prime
numbers.
Exponents
To simplify writing repetitive multiplication, we write 22 for 2*2,
we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on.
Example B. Calculate.
32 =
43 =
We write x*x*x…*x as xN where N is the number of x’s
multiplying to itself. N is called the exponent or the power of xN.
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete
if all the factors are prime numbers. Hence 12=2*2*3 is factored
completely, 12=2*6 is not complete because 6 is not prime.
Just as in chemistry that every chemical is a group of bonded
elements, every number is the product of a group of prime
numbers.
Exponents
To simplify writing repetitive multiplication, we write 22 for 2*2,
we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on.
Example B. Calculate.
32 = 3*3 = 9 (note that 3*2 = 6)
43 =
We write x*x*x…*x as xN where N is the number of x’s
multiplying to itself. N is called the exponent or the power of xN.
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete
if all the factors are prime numbers. Hence 12=2*2*3 is factored
completely, 12=2*6 is not complete because 6 is not prime.
Just as in chemistry that every chemical is a group of bonded
elements, every number is the product of a group of prime
numbers.
Exponents
To simplify writing repetitive multiplication, we write 22 for 2*2,
we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on.
Example B. Calculate.
32 = 3*3 = 9 (note that 3*2 = 6)
43 = 4*4*4
We write x*x*x…*x as xN where N is the number of x’s
multiplying to itself. N is called the exponent or the power of xN.
The Basics
To factor a number x means to break down x as a product,
i.e. to write x as a*b*c*... e.g. 12 can be factored as
12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete
if all the factors are prime numbers. Hence 12=2*2*3 is factored
completely, 12=2*6 is not complete because 6 is not prime.
Just as in chemistry that every chemical is a group of bonded
elements, every number is the product of a group of prime
numbers.
Exponents
To simplify writing repetitive multiplication, we write 22 for 2*2,
we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on.
Example B. Calculate.
32 = 3*3 = 9 (note that 3*2 = 6)
43 = 4*4*4 = 64 (note that 4*3 = 12)
We write x*x*x…*x as xN where N is the number of x’s
multiplying to itself. N is called the exponent or the power of xN.
The Basics
Your Turn:
Calculate 24, 34, 44,
and 2*4, 3*4, 4*4
Numbers that are factored completely may be written
using the exponential notation.
The Basics
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 =
The Basics
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3
The Basics
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3 = 22*3,
The Basics
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3 = 22*3,
200 =
The Basics
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3 = 22*3,
200 = 8*25
The Basics
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3 = 22*3,
200 = 8*25 = 2*2*2*5*5
The Basics
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3 = 22*3,
200 = 8*25 = 2*2*2*5*5 = 23*52.
The Basics
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3 = 22*3,
200 = 8*25 = 2*2*2*5*5 = 23*52.
The Basics
Each number has a unique form when its completely factored
into prime factors and arranged in order.
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3 = 22*3,
200 = 8*25 = 2*2*2*5*5 = 23*52.
The Basics
Each number has a unique form when its completely factored
into prime factors and arranged in order. This is analogous to
chemistry where each chemical has a unique chemical
composition of basic elements such as H20 for water.
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3 = 22*3,
200 = 8*25 = 2*2*2*5*5 = 23*52.
The Basics
Each number has a unique form when its completely factored
into prime factors and arranged in order. This is analogous to
chemistry where each chemical has a unique chemical
composition of basic elements such as H20 for water.
Larger numbers may be factored using a vertical format.
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3 = 22*3,
200 = 8*25 = 2*2*2*5*5 = 23*52.
The Basics
Each number has a unique form when its completely factored
into prime factors and arranged in order. This is analogous to
chemistry where each chemical has a unique chemical
composition of basic elements such as H20 for water.
Larger numbers may be factored using a vertical format.
Example C. Factor 144 completely. (Vertical format)
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3 = 22*3,
200 = 8*25 = 2*2*2*5*5 = 23*52.
The Basics
Each number has a unique form when its completely factored
into prime factors and arranged in order. This is analogous to
chemistry where each chemical has a unique chemical
composition of basic elements such as H20 for water.
Larger numbers may be factored using a vertical format.
Example C. Factor 144 completely. (Vertical format)
144
12 12
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3 = 22*3,
200 = 8*25 = 2*2*2*5*5 = 23*52.
The Basics
Each number has a unique form when its completely factored
into prime factors and arranged in order. This is analogous to
chemistry where each chemical has a unique chemical
composition of basic elements such as H20 for water.
Larger numbers may be factored using a vertical format.
Example C. Factor 144 completely. (Vertical format)
144
12 12
3 4 3 4
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3 = 22*3,
200 = 8*25 = 2*2*2*5*5 = 23*52.
The Basics
Each number has a unique form when its completely factored
into prime factors and arranged in order. This is analogous to
chemistry where each chemical has a unique chemical
composition of basic elements such as H20 for water.
Larger numbers may be factored using a vertical format.
Example C. Factor 144 completely. (Vertical format)
144
12 12
3 4 3 4
2 22 2
Numbers that are factored completely may be written
using the exponential notation.
Hence, factored completely, 12 = 2*2*3 = 22*3,
200 = 8*25 = 2*2*2*5*5 = 23*52.
The Basics
Each number has a unique form when its completely factored
into prime factors and arranged in order. This is analogous to
chemistry where each chemical has a unique chemical
composition of basic elements such as H20 for water.
Larger numbers may be factored using a vertical format.
Example C. Factor 144 completely. (Vertical format)
144
12 12
3 4 3 4
2 22 2
Gather all the prime numbers at
the end of the branches we have
144 = 3*3*2*2*2*2 = 3224.
Note that we obtain the same answer
regardless how we factor at each step.
Your Turn: Factor 72 completely.
Basic Laws
Of the four arithmetic operations +, – , *, and ÷,
+, and * behave nicer than – or ÷.
Basic Laws
Of the four arithmetic operations +, – , *, and ÷,
+, and * behave nicer than – or ÷. We often take advantage
of the this nice “behavior” of the addition and multiplication
operations to get short cuts.
Basic Laws
Of the four arithmetic operations +, – , *, and ÷,
+, and * behave nicer than – or ÷. We often take advantage
of the this nice “behavior” of the addition and multiplication
operations to get short cuts. However, be sure you don’t
mistakenly apply these short cuts to – and ÷.
Associative Law for Addition and Multiplication
Basic Laws
Of the four arithmetic operations +, – , *, and ÷,
+, and * behave nicer than – or ÷. We often take advantage
of the this nice “behavior” of the addition and multiplication
operations to get short cuts. However, be sure you don’t
mistakenly apply these short cuts to – and ÷.
Associative Law for Addition and Multiplication
( a + b ) + c = a + ( b + c )
( a * b ) * c = a * ( b * c )
Note: We are to perform the operations inside the “( )” first.
Basic Laws
Of the four arithmetic operations +, – , *, and ÷,
+, and * behave nicer than – or ÷. We often take advantage
of the this nice “behavior” of the addition and multiplication
operations to get short cuts. However, be sure you don’t
mistakenly apply these short cuts to – and ÷.
Associative Law for Addition and Multiplication
( a + b ) + c = a + ( b + c )
( a * b ) * c = a * ( b * c )
Note: We are to perform the operations inside the “( )” first.
For example, (1 + 2) + 3
1 + (2 + 3)
Basic Laws
Of the four arithmetic operations +, – , *, and ÷,
+, and * behave nicer than – or ÷. We often take advantage
of the this nice “behavior” of the addition and multiplication
operations to get short cuts. However, be sure you don’t
mistakenly apply these short cuts to – and ÷.
Associative Law for Addition and Multiplication
( a + b ) + c = a + ( b + c )
( a * b ) * c = a * ( b * c )
Note: We are to perform the operations inside the “( )” first.
For example, (1 + 2) + 3 = 3 + 3 = 6,
1 + (2 + 3)
Basic Laws
Of the four arithmetic operations +, – , *, and ÷,
+, and * behave nicer than – or ÷. We often take advantage
of the this nice “behavior” of the addition and multiplication
operations to get short cuts. However, be sure you don’t
mistakenly apply these short cuts to – and ÷.
Associative Law for Addition and Multiplication
( a + b ) + c = a + ( b + c )
( a * b ) * c = a * ( b * c )
Note: We are to perform the operations inside the “( )” first.
For example, (1 + 2) + 3 = 3 + 3 = 6,
1 + (2 + 3) = 1 + 5 = 6.
Basic Laws
Of the four arithmetic operations +, – , *, and ÷,
+, and * behave nicer than – or ÷. We often take advantage
of the this nice “behavior” of the addition and multiplication
operations to get short cuts. However, be sure you don’t
mistakenly apply these short cuts to – and ÷.
Associative Law for Addition and Multiplication
( a + b ) + c = a + ( b + c )
( a * b ) * c = a * ( b * c )
Note: We are to perform the operations inside the “( )” first.
For example, (1 + 2) + 3 = 3 + 3 = 6, which is the same as
1 + (2 + 3) = 1 + 5 = 6.
Basic Laws
Of the four arithmetic operations +, – , *, and ÷,
+, and * behave nicer than – or ÷. We often take advantage
of the this nice “behavior” of the addition and multiplication
operations to get short cuts. However, be sure you don’t
mistakenly apply these short cuts to – and ÷.
So if you want to
total the money in
your pockets,
it does not matter
which two pockets
you add first.
Associative Law for Addition and Multiplication
( a + b ) + c = a + ( b + c )
( a * b ) * c = a * ( b * c )
Note: We are to perform the operations inside the “( )” first.
For example, (1 + 2) + 3 = 3 + 3 = 6, which is the same as
1 + (2 + 3) = 1 + 5 = 6.
Subtraction and division are not associative.
Basic Laws
Of the four arithmetic operations +, – , *, and ÷,
+, and * behave nicer than – or ÷. We often take advantage
of the this nice “behavior” of the addition and multiplication
operations to get short cuts. However, be sure you don’t
mistakenly apply these short cuts to – and ÷.
So if you want to
total the money in
your pockets,
it does not matter
which two pockets
you add first.
Associative Law for Addition and Multiplication
( a + b ) + c = a + ( b + c )
( a * b ) * c = a * ( b * c )
Note: We are to perform the operations inside the “( )” first.
For example, (1 + 2) + 3 = 3 + 3 = 6, which is the same as
1 + (2 + 3) = 1 + 5 = 6.
Subtraction and division are not associative.
For example, ( 3 – 2 ) – 1
3 – ( 2 – 1 )
Basic Laws
Of the four arithmetic operations +, – , *, and ÷,
+, and * behave nicer than – or ÷. We often take advantage
of the this nice “behavior” of the addition and multiplication
operations to get short cuts. However, be sure you don’t
mistakenly apply these short cuts to – and ÷.
So if you want to
total the money in
your pockets,
it does not matter
which two pockets
you add first.
Associative Law for Addition and Multiplication
( a + b ) + c = a + ( b + c )
( a * b ) * c = a * ( b * c )
Note: We are to perform the operations inside the “( )” first.
For example, (1 + 2) + 3 = 3 + 3 = 6, which is the same as
1 + (2 + 3) = 1 + 5 = 6.
Subtraction and division are not associative.
For example, ( 3 – 2 ) – 1 = 0
3 – ( 2 – 1 )
Basic Laws
Of the four arithmetic operations +, – , *, and ÷,
+, and * behave nicer than – or ÷. We often take advantage
of the this nice “behavior” of the addition and multiplication
operations to get short cuts. However, be sure you don’t
mistakenly apply these short cuts to – and ÷.
So if you want to
total the money in
your pockets,
it does not matter
which two pockets
you add first.
Associative Law for Addition and Multiplication
( a + b ) + c = a + ( b + c )
( a * b ) * c = a * ( b * c )
Note: We are to perform the operations inside the “( )” first.
For example, (1 + 2) + 3 = 3 + 3 = 6, which is the same as
1 + (2 + 3) = 1 + 5 = 6.
Subtraction and division are not associative.
For example, ( 3 – 2 ) – 1 = 0 is different from
3 – ( 2 – 1 ) = 2.
Basic Laws
Of the four arithmetic operations +, – , *, and ÷,
+, and * behave nicer than – or ÷. We often take advantage
of the this nice “behavior” of the addition and multiplication
operations to get short cuts. However, be sure you don’t
mistakenly apply these short cuts to – and ÷.
So if you want to
total the money in
your pockets,
it does not matter
which two pockets
you add first.
Basic Laws
Commutative Law for Addition and Multiplication
Commutative Law for Addition and Multiplication
a + b = b + a
a * b = b * a
Basic Laws
Commutative Law for Addition and Multiplication
a + b = b + a
a * b = b * a
For example, 3*4 = 4*3 = 12.
Basic Laws
Commutative Law for Addition and Multiplication
a + b = b + a
a * b = b * a
For example, 3*4 = 4*3 = 12.
Subtraction and division don't satisfy commutative laws.
Basic Laws
Commutative Law for Addition and Multiplication
a + b = b + a
a * b = b * a
For example, 3*4 = 4*3 = 12.
Subtraction and division don't satisfy commutative laws.
For example: 2  1  1  2.
Basic Laws
Commutative Law for Addition and Multiplication
a + b = b + a
a * b = b * a
For example, 3*4 = 4*3 = 12.
Subtraction and division don't satisfy commutative laws.
For example: 2  1  1  2.
From the above laws, we get the following important facts.
Basic Laws
Commutative Law for Addition and Multiplication
a + b = b + a
a * b = b * a
For example, 3*4 = 4*3 = 12.
Subtraction and division don't satisfy commutative laws.
For example: 2  1  1  2.
From the above laws, we get the following important facts.
When adding, the order of addition doesn’t matter.
Basic Laws
Commutative Law for Addition and Multiplication
a + b = b + a
a * b = b * a
For example, 3*4 = 4*3 = 12.
Subtraction and division don't satisfy commutative laws.
For example: 2  1  1  2.
From the above laws, we get the following important facts.
When adding, the order of addition doesn’t matter.
Hence to take advantages of this when adding a list numbers,
it's easier to add the ones that add to multiples of 10 first.
Basic Laws
Commutative Law for Addition and Multiplication
a + b = b + a
a * b = b * a
For example, 3*4 = 4*3 = 12.
Subtraction and division don't satisfy commutative laws.
For example: 2  1  1  2.
From the above laws, we get the following important facts.
When adding, the order of addition doesn’t matter.
Hence to take advantages of this when adding a list numbers,
it's easier to add the ones that add to multiples of 10 first.
Example D.
14 + 3 + 16 + 8 + 35 + 15
Basic Laws
Commutative Law for Addition and Multiplication
a + b = b + a
a * b = b * a
For example, 3*4 = 4*3 = 12.
Subtraction and division don't satisfy commutative laws.
For example: 2  1  1  2.
From the above laws, we get the following important facts.
When adding, the order of addition doesn’t matter.
Hence to take advantages of this when adding a list numbers,
it's easier to add the ones that add to multiples of 10 first.
Example D.
14 + 3 + 16 + 8 + 35 + 15
= 30
Basic Laws
Commutative Law for Addition and Multiplication
a + b = b + a
a * b = b * a
For example, 3*4 = 4*3 = 12.
Subtraction and division don't satisfy commutative laws.
For example: 2  1  1  2.
From the above laws, we get the following important facts.
When adding, the order of addition doesn’t matter.
Hence to take advantages of this when adding a list numbers,
it's easier to add the ones that add to multiples of 10 first.
Example D.
14 + 3 + 16 + 8 + 35 + 15
= 30 + 50
Basic Laws
Commutative Law for Addition and Multiplication
a + b = b + a
a * b = b * a
For example, 3*4 = 4*3 = 12.
Subtraction and division don't satisfy commutative laws.
For example: 2  1  1  2.
From the above laws, we get the following important facts.
When adding, the order of addition doesn’t matter.
Hence to take advantages of this when adding a list numbers,
it's easier to add the ones that add to multiples of 10 first.
Example D.
14 + 3 + 16 + 8 + 35 + 15
= 30 + 11 + 50
Basic Laws
Commutative Law for Addition and Multiplication
a + b = b + a
a * b = b * a
For example, 3*4 = 4*3 = 12.
Subtraction and division don't satisfy commutative laws.
For example: 2  1  1  2.
From the above laws, we get the following important facts.
When adding, the order of addition doesn’t matter.
Hence to take advantages of this when adding a list numbers,
it's easier to add the ones that add to multiples of 10 first.
Example D.
14 + 3 + 16 + 8 + 35 + 15
= 30 + 11 + 50 = 91
Basic Laws
Basic Laws
When multiplying, the order of multiplication doesn’t
matter.
Basic Laws
When multiplying, the order of multiplication doesn’t
matter.
When multiplying many numbers, always multiply them in
pairs first.
Basic Laws
When multiplying, the order of multiplication doesn’t
matter.
When multiplying many numbers, always multiply them in
pairs first. This is useful for raising exponents.
Basic Laws
When multiplying, the order of multiplication doesn’t
matter.
Example E.
36
When multiplying many numbers, always multiply them in
pairs first. This is useful for raising exponents.
Basic Laws
When multiplying, the order of multiplication doesn’t
matter.
Example E.
36 = 3*3*3*3*3*3
When multiplying many numbers, always multiply them in
pairs first. This is useful for raising exponents.
Basic Laws
When multiplying, the order of multiplication doesn’t
matter.
Example E.
36 = 3*3*3*3*3*3
= 9 * 9 * 9
When multiplying many numbers, always multiply them in
pairs first. This is useful for raising exponents.
Basic Laws
When multiplying, the order of multiplication doesn’t
matter.
Example E.
36 = 3*3*3*3*3*3
= 9 * 9 * 9
= 81 * 9 = 729
When multiplying many numbers, always multiply them in
pairs first. This is useful for raising exponents.
Basic Laws
When multiplying, the order of multiplication doesn’t
matter.
Example E.
36 = 3*3*3*3*3*3
= 9 * 9 * 9
= 81 * 9 = 729
When multiplying many numbers, always multiply them in
pairs first. This is useful for raising exponents.
Because the order of the additions (or multiplications) may be
scrambled, this offers a strategy to check our answers–
do it in two different ways.
Basic Laws
When multiplying, the order of multiplication doesn’t
matter.
Example E.
36 = 3*3*3*3*3*3
= 9 * 9 * 9
= 81 * 9 = 729
When multiplying many numbers, always multiply them in
pairs first. This is useful for raising exponents.
Because the order of the additions (or multiplications) may be
scrambled, this offers a strategy to check our answers–
do it in two different ways.
If both yield the same answer, it’s likely the answer is correct.
Basic Laws
When multiplying, the order of multiplication doesn’t
matter.
Example E.
36 = 3*3*3*3*3*3
= 9 * 9 * 9
= 81 * 9 = 729
When multiplying many numbers, always multiply them in
pairs first. This is useful for raising exponents.
Because the order of the additions (or multiplications) may be
scrambled, this offers a strategy to check our answers–
do it in two different ways.
If both yield the same answer, it’s likely the answer is correct.
If the two outcomes are different, then some thing went wrong,
find it and correct it.
Basic Laws
The Distributive Law
Basic Laws
The are two $10–bills and three $5–bills in a box.
The Distributive Law
Basic Laws
The are two $10–bills and three $5–bills in a box. So there is
the total of 2x10=20 plus 3x5=15, or $35, in the box which is
recorded as (20+15) = 35.
The Distributive Law
Basic Laws
The are two $10–bills and three $5–bills in a box. So there is
the total of 2x10=20 plus 3x5=15, or $35, in the box which is
recorded as (20+15) = 35.
Suppose we have 4 of these boxes, there are two methods to
find their total:
The Distributive Law
Basic Laws
The are two $10–bills and three $5–bills in a box. So there is
the total of 2x10=20 plus 3x5=15, or $35, in the box which is
recorded as (20+15) = 35.
Suppose we have 4 of these boxes, there are two methods to
find their total:
I. Each box has $35 so 4 boxes have 4x35=$140 in total.
The Distributive Law
Basic Laws
The are two $10–bills and three $5–bills in a box. So there is
the total of 2x10=20 plus 3x5=15, or $35, in the box which is
recorded as (20+15) = 35.
Suppose we have 4 of these boxes, there are two methods to
find their total:
I. Each box has $35 so 4 boxes have 4x35=$140 in total.
The Distributive Law
Recording these with symbols:
4(20+15) = 4(35)
= 140
Basic Laws
The are two $10–bills and three $5–bills in a box. So there is
the total of 2x10=20 plus 3x5=15, or $35, in the box which is
recorded as (20+15) = 35.
Suppose we have 4 of these boxes, there are two methods to
find their total:
I. Each box has $35 so 4 boxes have 4x35=$140 in total.
II. Unpack the boxes, there are 4x20=$80 from the $10-bills,
and 4x15=$60 from the $5-bills, which total to $140.
The Distributive Law
Recording these with symbols:
4(20+15) = 4(35)
= 140
Basic Laws
The are two $10–bills and three $5–bills in a box. So there is
the total of 2x10=20 plus 3x5=15, or $35, in the box which is
recorded as (20+15) = 35.
Suppose we have 4 of these boxes, there are two methods to
find their total:
I. Each box has $35 so 4 boxes have 4x35=$140 in total.
II. Unpack the boxes, there are 4x20=$80 from the $10-bills,
and 4x15=$60 from the $5-bills, which total to $140.
The Distributive Law
Recording these with symbols:
4(20+15) = 4(35)
or 4(20+15) = 4(20) + 4(15)
= 140
Basic Laws
The are two $10–bills and three $5–bills in a box. So there is
the total of 2x10=20 plus 3x5=15, or $35, in the box which is
recorded as (20+15) = 35.
Suppose we have 4 of these boxes, there are two methods to
find their total:
I. Each box has $35 so 4 boxes have 4x35=$140 in total.
II. Unpack the boxes, there are 4x20=$80 from the $10-bills,
and 4x15=$60 from the $5-bills, which total to $140.
The Distributive Law
Recording these with symbols: The point here is that
these two ways of
totaling always yield
the same result,
not which is easier.
4(20+15) = 4(35)
or 4(20+15) = 4(20) + 4(15)
= 140
Basic Laws
The are two $10–bills and three $5–bills in a box. So there is
the total of 2x10=20 plus 3x5=15, or $35, in the box which is
recorded as (20+15) = 35.
Suppose we have 4 of these boxes, there are two methods to
find their total:
I. Each box has $35 so 4 boxes have 4x35=$140 in total.
II. Unpack the boxes, there are 4x20=$80 from the $10-bills,
and 4x15=$60 from the $5-bills, which total to $140.
The Distributive Law
Recording these with symbols: The point here is that
these two ways of
totaling always yield
the same result,
not which is easier.
4(20+15) = 4(35)
or 4(20+15) = 4(20) + 4(15)
= 140
The fact that these two ways are “identical" and that there are
two forms associated with the two ways is important.
Let’s redo this in symbols.
Basic Laws
The are two $10–bills and three $5–bills in a box. So there is
the total of 2x10=20 plus 3x5=15, or $35, in the box which is
recorded as (20+15) = 35.
Suppose we have 4 of these boxes, there are two methods to
find their total:
I. Each box has $35 so 4 boxes have 4x35=$140 in total.
II. Unpack the boxes, there are 4x20=$80 from the $10-bills,
and 4x15=$60 from the $5-bills, which total to $140.
The Distributive Law
Recording these with symbols: The point here is that
these two ways of
totaling always yield
the same result,
not which is easier.
4(20+15) = 4(35)
or 4(20+15) = 4(20) + 4(15)
= 140
The fact that these two ways are identical and that
there two forms associated with the two ways is important.
Let’s redo this in symbols.
Basic Laws
The are two $10–bills and three $5–bills in a box. So there is
the total of 2x10=20 plus 3x5=15, or $35, in the box which is
recorded as (20+15) = 35.
Suppose we have 4 of these boxes, there are two methods to
find their total:
I. Each box has $35 so 4 boxes have 4x35=$140 in total.
II. Unpack the boxes, there are 4x20=$80 from the $10-bills,
and 4x15=$60 from the $5-bills, which total to $140.
The Distributive Law
Recording these with symbols: The point here is that
these two ways of
totaling always yield
the same result,
not which is easier.
4(20+15) = 4(35)
or 4(20+15) = 4(20) + 4(15)
= 140
The fact that these two ways are identical and that
there two forms associated with the two ways is important.
Let’s redo this in symbols.
Basic Laws
The Distributive Law
Basic Laws
There are two $10–bills and three $5–bills in a box.
The Distributive Law
Basic Laws
There are two $10–bills and three $5–bills in a box.
Using the letter T to represent a $10–bill and F for a $5–bill,
we may represent this box as (2T + 3F).
The Distributive Law
Basic Laws
There are two $10–bills and three $5–bills in a box.
Using the letter T to represent a $10–bill and F for a $5–bill,
we may represent this box as (2T + 3F).
If we have four of these boxes, we may record them as
4(2T + 3F).
The Distributive Law
Basic Laws
There are two $10–bills and three $5–bills in a box.
Using the letter T to represent a $10–bill and F for a $5–bill,
we may represent this box as (2T + 3F).
If we have four of these boxes, we may record them as
4(2T + 3F). We open all the boxes and take out all the bills,
there are 4 sets of 2T’s or 8T’s
The Distributive Law
Basic Laws
There are two $10–bills and three $5–bills in a box.
Using the letter T to represent a $10–bill and F for a $5–bill,
we may represent this box as (2T + 3F).
If we have four of these boxes, we may record them as
4(2T + 3F). We open all the boxes and take out all the bills,
there are 4 sets of 2T’s or 8T’s and 4 sets of 3F’s or 12F’s.
The Distributive Law
Basic Laws
There are two $10–bills and three $5–bills in a box.
Using the letter T to represent a $10–bill and F for a $5–bill,
we may represent this box as (2T + 3F).
If we have four of these boxes, we may record them as
4(2T + 3F). We open all the boxes and take out all the bills,
there are 4 sets of 2T’s or 8T’s and 4 sets of 3F’s or 12F’s.
We track this unpacking or expanding procedure, as
4(2T + 3F) = 4*2T + 4*3F = 8T + 12F
The Distributive Law
Basic Laws
There are two $10–bills and three $5–bills in a box.
Using the letter T to represent a $10–bill and F for a $5–bill,
we may represent this box as (2T + 3F).
If we have four of these boxes, we may record them as
4(2T + 3F). We open all the boxes and take out all the bills,
there are 4 sets of 2T’s or 8T’s and 4 sets of 3F’s or 12F’s.
We track this unpacking or expanding procedure, as
4(2T + 3F) = 4*2T + 4*3F = 8T + 12F
The Distributive Law
Expressing this operation in symbol we have the
Distributive Law : a*(b ± c) = a*b ± a*c
Basic Laws
There are two $10–bills and three $5–bills in a box.
Using the letter T to represent a $10–bill and F for a $5–bill,
we may represent this box as (2T + 3F).
If we have four of these boxes, we may record them as
4(2T + 3F). We open all the boxes and take out all the bills,
there are 4 sets of 2T’s or 8T’s and 4 sets of 3F’s or 12F’s.
We track this unpacking or expanding procedure, as
4(2T + 3F) = 4*2T + 4*3F = 8T + 12F
The Distributive Law
Expressing this operation in symbol we have the
Distributive Law : a*(b ± c) = a*b ± a*c
The “packed” form is
the factored form.
the factored form.
Basic Laws
There are two $10–bills and three $5–bills in a box.
Using the letter T to represent a $10–bill and F for a $5–bill,
we may represent this box as (2T + 3F).
If we have four of these boxes, we may record them as
4(2T + 3F). We open all the boxes and take out all the bills,
there are 4 sets of 2T’s or 8T’s and 4 sets of 3F’s or 12F’s.
We track this unpacking or expanding procedure, as
4(2T + 3F) = 4*2T + 4*3F = 8T + 12F
The Distributive Law
Expressing this operation in symbol we have the
Distributive Law : a*(b ± c) = a*b ± a*c
The “packed” form is
the factored form.
The “unpacked” form is
the expanded form.
the factored form. the expanded form.
Example E. A. A fruit basket contains 4 apples and 6
bananas, using A for “an apple” and B for "a banana“ write the
expression for a fruit basket,
Basic Laws
Example E. A. A fruit basket contains 4 apples and 6
bananas, using A for “an apple” and B for "a banana“ write the
expression for a fruit basket,
Basic Laws
The basket may be written as (4A + 6B).
Example E. A. A fruit basket contains 4 apples and 6
bananas, using A for “an apple” and B for "a banana“ write the
expression for a fruit basket, then write the expression for
5 such baskets.
Basic Laws
The basket may be written as (4A + 6B).
Example E. A. A fruit basket contains 4 apples and 6
bananas, using A for “an apple” and B for "a banana“ write the
expression for a fruit basket, then write the expression for
5 such baskets.
Basic Laws
The basket may be written as (4A + 6B).
Five baskets are 5(4A + 6B)
Example E. A. A fruit basket contains 4 apples and 6
bananas, using A for “an apple” and B for "a banana“ write the
expression for a fruit basket, then write the expression for
5 such baskets. Expand the expression,
how many apples and bananas do we have?
Basic Laws
The basket may be written as (4A + 6B).
Five baskets are 5(4A + 6B)
Example E. A. A fruit basket contains 4 apples and 6
bananas, using A for “an apple” and B for "a banana“ write the
expression for a fruit basket, then write the expression for
5 such baskets. Expand the expression,
how many apples and bananas do we have?
Basic Laws
The basket may be written as (4A + 6B).
Five baskets are 5(4A + 6B), distribute the 5 and expand,
5(4A + 6B) = 5*4A + 5*6B
Example E. A. A fruit basket contains 4 apples and 6
bananas, using A for “an apple” and B for "a banana“ write the
expression for a fruit basket, then write the expression for
5 such baskets. Expand the expression,
how many apples and bananas do we have?
Basic Laws
The basket may be written as (4A + 6B).
Five baskets are 5(4A + 6B), distribute the 5 and expand,
5(4A + 6B) = 5*4A + 5*6B = 20A + 30B
so that we have 20 apples and 30 bananas.
Example E. A. A fruit basket contains 4 apples and 6
bananas, using A for “an apple” and B for "a banana“ write the
expression for a fruit basket, then write the expression for
5 such baskets. Expand the expression,
how many apples and bananas do we have?
Basic Laws
B. We unpack six fruit boxes and obtain 48 apples and
30 bananas. Record this amount using A and B
(i.e. the expanded form),
The basket may be written as (4A + 6B).
Five baskets are 5(4A + 6B), distribute the 5 and expand,
5(4A + 6B) = 5*4A + 5*6B = 20A + 30B
so that we have 20 apples and 30 bananas.
Example E. A. A fruit basket contains 4 apples and 6
bananas, using A for “an apple” and B for "a banana“ write the
expression for a fruit basket, then write the expression for
5 such baskets. Expand the expression,
how many apples and bananas do we have?
Basic Laws
B. We unpack six fruit boxes and obtain 48 apples and
30 bananas. Record this amount using A and B
(i.e. the expanded form),
The basket may be written as (4A + 6B).
Five baskets are 5(4A + 6B), distribute the 5 and expand,
5(4A + 6B) = 5*4A + 5*6B = 20A + 30B
so that we have 20 apples and 30 bananas.
The fruits may be recorded as 48A + 30B
Example E. A. A fruit basket contains 4 apples and 6
bananas, using A for “an apple” and B for "a banana“ write the
expression for a fruit basket, then write the expression for
5 such baskets. Expand the expression,
how many apples and bananas do we have?
Basic Laws
B. We unpack six fruit boxes and obtain 48 apples and
30 bananas. Record this amount using A and B
(i.e. the expanded form), then write it in the factored form
(i.e. as 6 packed boxes). What were in each box?
The basket may be written as (4A + 6B).
Five baskets are 5(4A + 6B), distribute the 5 and expand,
5(4A + 6B) = 5*4A + 5*6B = 20A + 30B
so that we have 20 apples and 30 bananas.
The fruits may be recorded as 48A + 30B
Example E. A. A fruit basket contains 4 apples and 6
bananas, using A for “an apple” and B for "a banana“ write the
expression for a fruit basket, then write the expression for
5 such baskets. Expand the expression,
how many apples and bananas do we have?
Basic Laws
B. We unpack six fruit boxes and obtain 48 apples and
30 bananas. Record this amount using A and B
(i.e. the expanded form), then write it in the factored form
(i.e. as 6 packed boxes). What were in each box?
The basket may be written as (4A + 6B).
Five baskets are 5(4A + 6B), distribute the 5 and expand,
5(4A + 6B) = 5*4A + 5*6B = 20A + 30B
so that we have 20 apples and 30 bananas.
The fruits may be recorded as 48A + 30B, packed in six
baskets, so each has 48/6 = 8 apples and 30/6 = 5 bananas,
Example E. A. A fruit basket contains 4 apples and 6
bananas, using A for “an apple” and B for "a banana“ write the
expression for a fruit basket, then write the expression for
5 such baskets. Expand the expression,
how many apples and bananas do we have?
Basic Laws
B. We unpack six fruit boxes and obtain 48 apples and
30 bananas. Record this amount using A and B
(i.e. the expanded form), then write it in the factored form
(i.e. as 6 packed boxes). What were in each box?
The basket may be written as (4A + 6B).
Five baskets are 5(4A + 6B), distribute the 5 and expand,
5(4A + 6B) = 5*4A + 5*6B = 20A + 30B
so that we have 20 apples and 30 bananas.
The fruits may be recorded as 48A + 30B, packed in six
baskets, so each has 48/6 = 8 apples and 30/6 = 5 bananas,
hence 48A + 30B = 6(8A + 5B) in the factored form.
Exercise A.
Do the following problems two ways.
* Add the following by summing the multiples of 10 first.
* Add by adding in the order.
to find the correct answer.
1. 3 + 5 + 7 2. 8 + 6 + 2 3. 1 + 8 + 9
4. 3 + 5 + 15 5. 9 + 14 + 6 6. 22 + 5 + 8
7. 16 + 5 + 4 + 3 8. 4 + 13 + 5 + 7
9. 19 + 7 + 1 + 3 10. 4 + 5 + 17 + 3
11. 23 + 5 + 17 + 3 12. 22 + 5 + 13 + 28
13. 35 + 6 + 15 + 7 + 14 14. 42 + 5 + 18 + 12
15. 21 + 16 + 19 + 7 + 44 16. 53 + 5 + 18 + 27 + 22
17. 155 + 16 + 25 + 7 + 344 18. 428 + 3 + 32 + 227 + 22
Basic Laws
Basic Laws
19. List the all the factors and the first 4 multiples of the
following numbers. 6, 9, 10, 15, 16, 24, 30, 36, 42, 56, 60.
B. Calculate.
1. 33 2. 42 3. 52 4. 53 5. 62 6. 63 7. 72
8. 82 9. 92 10. 102 11. 103 12. 104 13. 105
14. 1002 15. 1003 16. 1004 17. 112 18. 122
20. Factor completely and arrange the factors from smallest to
the largest in the exponential notation: 4, 8, 12, 16, 18, 24,
27, 32, 36, 45, 48, 56, 60, 63, 72, 75, 81, 120.
21. 3 * 5 * 4 * 2 22. 6 * 5 * 4 * 3 23. 6 * 15 * 3 * 2
24. 7 * 5 * 5 * 4 25. 6 * 7 * 4 * 3 26. 9 * 3 * 4 * 4
27. 2 * 25 * 3 * 4 * 2 28. 3 * 2 * 3 * 3 * 2 * 4
29. 3 * 5 * 2 * 5 * 2 * 4 30. 4 * 2 * 3 * 15 * 8 * 4
31. 24 32. 25 33. 26 34. 27 35. 28
36. 29 37. 210 38. 34 39. 35 40. 36
C. Multiply in two ways to find the correct answer.
Basic Laws
D. Packing and unpacking problems.
21. 3 * 5 * 4 * 2
The Basics
Factor 72 completely:
72 = 2*2*2*3*3
72
6 12
2 3 3 4
2 2
The factors of 18: 1, 2, 3, 6, 9, and 18.
The multiples of 18: 18=1x18, 36=2x18, 54=3x18, 72, 90, etc…
Answers to “Your Turn”:
Calculate 24 = 16, 34 = 9*9 = 81, 44 = 16*16 =256
and 2*4 = 8, 3*4 = 12, 4*4 = 16

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1 f1 prime numbers and factors

  • 1. The Basics Back to 123a-Home
  • 2. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. The Basics
  • 3. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. The Basics
  • 4. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. The Basics 15 can be divided by 3
  • 5. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. Hence 3 is a factor of 15 The Basics 15 can be divided by 3
  • 6. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. Hence 3 is a factor of 15 Example A. List the factors and the multiples of 12. The factors of 12: The Basics 15 can be divided by 3
  • 7. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. Hence 3 is a factor of 15 Example A. List the factors and the multiples of 12. The factors of 12: 1, The Basics 15 can be divided by 3
  • 8. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. Hence 3 is a factor of 15 Example A. List the factors and the multiples of 12. The factors of 12: 1, 2, The Basics 15 can be divided by 3
  • 9. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. Hence 3 is a factor of 15 Example A. List the factors and the multiples of 12. The factors of 12: 1, 2, 3, 4, 6, and 12. The Basics 15 can be divided by 3
  • 10. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. We also say that x is a multiple of y. Hence 3 is a factor of 15 Example A. List the factors and the multiples of 12. The factors of 12: 1, 2, 3, 4, 6, and 12. The Basics 15 can be divided by 3
  • 11. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. We also say that x is a multiple of y. Hence 3 is a factor of 15 and that 15 is a multiple of 3. Example A. List the factors and the multiples of 12. The factors of 12: 1, 2, 3, 4, 6, and 12. The Basics
  • 12. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. We also say that x is a multiple of y. Hence 3 is a factor of 15 and that 15 is a multiple of 3. A number x is always the multiple and a factor of itself. Example A. List the factors and the multiples of 12. The factors of 12: 1, 2, 3, 4, 6, and 12. The Basics
  • 13. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. We also say that x is a multiple of y. Hence 3 is a factor of 15 and that 15 is a multiple of 3. A number x is always the multiple and a factor of itself. Example A. List the factors and the multiples of 12. The factors of 12: 1, 2, 3, 4, 6, and 12. The multiples of 12: The Basics
  • 14. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. We also say that x is a multiple of y. Hence 3 is a factor of 15 and that 15 is a multiple of 3. A number x is always the multiple and a factor of itself. Example A. List the factors and the multiples of 12. The factors of 12: 1, 2, 3, 4, 6, and 12. The multiples of 12: 12=1x12, The Basics
  • 15. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. We also say that x is a multiple of y. Hence 3 is a factor of 15 and that 15 is a multiple of 3. A number x is always the multiple and a factor of itself. Example A. List the factors and the multiples of 12. The factors of 12: 1, 2, 3, 4, 6, and 12. The multiples of 12: 12=1x12, 24=2x12, 36=3x12, 48, 60, etc… The Basics
  • 16. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. We also say that x is a multiple of y. Hence 3 is a factor of 15 and that 15 is a multiple of 3. A number x is always the multiple and a factor of itself. Example A. List the factors and the multiples of 12. The factors of 12: 1, 2, 3, 4, 6, and 12. The multiples of 12: 12=1x12, 24=2x12, 36=3x12, 48, 60, etc… The Basics Your Turn: List the factors and the multiples of 18.
  • 17. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. We also say that x is a multiple of y. Hence 3 is a factor of 15 and that 15 is a multiple of 3. A number x is always the multiple and a factor of itself. Example A. List the factors and the multiples of 12. The factors of 12: 1, 2, 3, 4, 6, and 12. The multiples of 12: 12=1x12, 24=2x12, 36=3x12, 48, 60, etc… The Basics A prime number is a natural number that can not be divided evenly into smaller numbers (except as 1’s), that is to say, a prime number only has 1 and itself as factors. Your Turn: List the factors and the multiples of 18.
  • 18. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. We also say that x is a multiple of y. Hence 3 is a factor of 15 and that 15 is a multiple of 3. A number x is always the multiple and a factor of itself. Example A. List the factors and the multiples of 12. The factors of 12: 1, 2, 3, 4, 6, and 12. The multiples of 12: 12=1x12, 24=2x12, 36=3x12, 48, 60, etc… The Basics A prime number is a natural number that can not be divided evenly into smaller numbers (except as 1’s), that is to say, a prime number only has 1 and itself as factors. The numbers 2, 3, 5, 7, (not 9), 11, 13,… are prime numbers. Your Turn: List the factors and the multiples of 18.
  • 19. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. We also say that x is a multiple of y. Hence 3 is a factor of 15 and that 15 is a multiple of 3. A number x is always the multiple and a factor of itself. Example A. List the factors and the multiples of 12. The factors of 12: 1, 2, 3, 4, 6, and 12. The multiples of 12: 12=1x12, 24=2x12, 36=3x12, 48, 60, etc… The Basics A prime number is a natural number that can not be divided evenly into smaller numbers (except as 1’s), that is to say, a prime number only has 1 and itself as factors. The numbers 2, 3, 5, 7, (not 9), 11, 13,… are prime numbers. Even numbers are not prime so prime numbers must be odd (except for 2). Your Turn: List the factors and the multiples of 18.
  • 20. Whole numbers 1, 2, 3, 4,.. are called natural numbers because they are used to count whole items like chickens and cows. If x and y are two natural numbers and x can be divided by y, we say y is a factor of x. We also say that x is a multiple of y. Hence 3 is a factor of 15 and that 15 is a multiple of 3. A number x is always the multiple and a factor of itself. Example A. List the factors and the multiples of 12. The factors of 12: 1, 2, 3, 4, 6, and 12. The multiples of 12: 12=1x12, 24=2x12, 36=3x12, 48, 60, etc… The Basics A prime number is a natural number that can not be divided evenly into smaller numbers (except as 1’s), that is to say, a prime number only has 1 and itself as factors. The numbers 2, 3, 5, 7, (not 9), 11, 13,… are prime numbers. Even numbers are not prime so prime numbers must be odd (except for 2). The number 1 is not a prime number. Your Turn: List the factors and the multiples of 18.
  • 21. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... The Basics
  • 22. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 The Basics
  • 23. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 = 3*4 = 2*2*3. The Basics
  • 24. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete if all the factors are prime numbers. The Basics
  • 25. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete if all the factors are prime numbers. Hence 12=2*2*3 is factored completely, The Basics
  • 26. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete if all the factors are prime numbers. Hence 12=2*2*3 is factored completely, 12=2*6 is not complete because 6 is not prime. The Basics
  • 27. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete if all the factors are prime numbers. Hence 12=2*2*3 is factored completely, 12=2*6 is not complete because 6 is not prime. Just as in chemistry that every chemical is a group of bonded elements, every number is the product of a group of prime numbers. The Basics
  • 28. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete if all the factors are prime numbers. Hence 12=2*2*3 is factored completely, 12=2*6 is not complete because 6 is not prime. Just as in chemistry that every chemical is a group of bonded elements, every number is the product of a group of prime numbers. Exponents The Basics
  • 29. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete if all the factors are prime numbers. Hence 12=2*2*3 is factored completely, 12=2*6 is not complete because 6 is not prime. Just as in chemistry that every chemical is a group of bonded elements, every number is the product of a group of prime numbers. Exponents To simplify writing repetitive multiplication, we write 22 for 2*2, we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on. The Basics
  • 30. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete if all the factors are prime numbers. Hence 12=2*2*3 is factored completely, 12=2*6 is not complete because 6 is not prime. Just as in chemistry that every chemical is a group of bonded elements, every number is the product of a group of prime numbers. Exponents To simplify writing repetitive multiplication, we write 22 for 2*2, we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on. We write x*x*x…*x as xN where N is the number of x’s multiplying to itself. The Basics
  • 31. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete if all the factors are prime numbers. Hence 12=2*2*3 is factored completely, 12=2*6 is not complete because 6 is not prime. Just as in chemistry that every chemical is a group of bonded elements, every number is the product of a group of prime numbers. Exponents To simplify writing repetitive multiplication, we write 22 for 2*2, we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on. We write x*x*x…*x as xN where N is the number of x’s multiplying to itself. N is called the exponent or the power of xN. The Basics
  • 32. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete if all the factors are prime numbers. Hence 12=2*2*3 is factored completely, 12=2*6 is not complete because 6 is not prime. Just as in chemistry that every chemical is a group of bonded elements, every number is the product of a group of prime numbers. Exponents To simplify writing repetitive multiplication, we write 22 for 2*2, we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on. Example B. Calculate. 32 = 43 = We write x*x*x…*x as xN where N is the number of x’s multiplying to itself. N is called the exponent or the power of xN. The Basics
  • 33. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete if all the factors are prime numbers. Hence 12=2*2*3 is factored completely, 12=2*6 is not complete because 6 is not prime. Just as in chemistry that every chemical is a group of bonded elements, every number is the product of a group of prime numbers. Exponents To simplify writing repetitive multiplication, we write 22 for 2*2, we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on. Example B. Calculate. 32 = 3*3 = 9 (note that 3*2 = 6) 43 = We write x*x*x…*x as xN where N is the number of x’s multiplying to itself. N is called the exponent or the power of xN. The Basics
  • 34. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete if all the factors are prime numbers. Hence 12=2*2*3 is factored completely, 12=2*6 is not complete because 6 is not prime. Just as in chemistry that every chemical is a group of bonded elements, every number is the product of a group of prime numbers. Exponents To simplify writing repetitive multiplication, we write 22 for 2*2, we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on. Example B. Calculate. 32 = 3*3 = 9 (note that 3*2 = 6) 43 = 4*4*4 We write x*x*x…*x as xN where N is the number of x’s multiplying to itself. N is called the exponent or the power of xN. The Basics
  • 35. To factor a number x means to break down x as a product, i.e. to write x as a*b*c*... e.g. 12 can be factored as 12 = 2*6 = 3*4 = 2*2*3. We say the factorization is complete if all the factors are prime numbers. Hence 12=2*2*3 is factored completely, 12=2*6 is not complete because 6 is not prime. Just as in chemistry that every chemical is a group of bonded elements, every number is the product of a group of prime numbers. Exponents To simplify writing repetitive multiplication, we write 22 for 2*2, we write 23 for 2*2*2, we write 24 for 2*2*2*2 and so on. Example B. Calculate. 32 = 3*3 = 9 (note that 3*2 = 6) 43 = 4*4*4 = 64 (note that 4*3 = 12) We write x*x*x…*x as xN where N is the number of x’s multiplying to itself. N is called the exponent or the power of xN. The Basics Your Turn: Calculate 24, 34, 44, and 2*4, 3*4, 4*4
  • 36. Numbers that are factored completely may be written using the exponential notation. The Basics
  • 37. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = The Basics
  • 38. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 The Basics
  • 39. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 = 22*3, The Basics
  • 40. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 = 22*3, 200 = The Basics
  • 41. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 = 22*3, 200 = 8*25 The Basics
  • 42. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 = 22*3, 200 = 8*25 = 2*2*2*5*5 The Basics
  • 43. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 = 22*3, 200 = 8*25 = 2*2*2*5*5 = 23*52. The Basics
  • 44. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 = 22*3, 200 = 8*25 = 2*2*2*5*5 = 23*52. The Basics Each number has a unique form when its completely factored into prime factors and arranged in order.
  • 45. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 = 22*3, 200 = 8*25 = 2*2*2*5*5 = 23*52. The Basics Each number has a unique form when its completely factored into prime factors and arranged in order. This is analogous to chemistry where each chemical has a unique chemical composition of basic elements such as H20 for water.
  • 46. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 = 22*3, 200 = 8*25 = 2*2*2*5*5 = 23*52. The Basics Each number has a unique form when its completely factored into prime factors and arranged in order. This is analogous to chemistry where each chemical has a unique chemical composition of basic elements such as H20 for water. Larger numbers may be factored using a vertical format.
  • 47. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 = 22*3, 200 = 8*25 = 2*2*2*5*5 = 23*52. The Basics Each number has a unique form when its completely factored into prime factors and arranged in order. This is analogous to chemistry where each chemical has a unique chemical composition of basic elements such as H20 for water. Larger numbers may be factored using a vertical format. Example C. Factor 144 completely. (Vertical format)
  • 48. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 = 22*3, 200 = 8*25 = 2*2*2*5*5 = 23*52. The Basics Each number has a unique form when its completely factored into prime factors and arranged in order. This is analogous to chemistry where each chemical has a unique chemical composition of basic elements such as H20 for water. Larger numbers may be factored using a vertical format. Example C. Factor 144 completely. (Vertical format) 144 12 12
  • 49. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 = 22*3, 200 = 8*25 = 2*2*2*5*5 = 23*52. The Basics Each number has a unique form when its completely factored into prime factors and arranged in order. This is analogous to chemistry where each chemical has a unique chemical composition of basic elements such as H20 for water. Larger numbers may be factored using a vertical format. Example C. Factor 144 completely. (Vertical format) 144 12 12 3 4 3 4
  • 50. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 = 22*3, 200 = 8*25 = 2*2*2*5*5 = 23*52. The Basics Each number has a unique form when its completely factored into prime factors and arranged in order. This is analogous to chemistry where each chemical has a unique chemical composition of basic elements such as H20 for water. Larger numbers may be factored using a vertical format. Example C. Factor 144 completely. (Vertical format) 144 12 12 3 4 3 4 2 22 2
  • 51. Numbers that are factored completely may be written using the exponential notation. Hence, factored completely, 12 = 2*2*3 = 22*3, 200 = 8*25 = 2*2*2*5*5 = 23*52. The Basics Each number has a unique form when its completely factored into prime factors and arranged in order. This is analogous to chemistry where each chemical has a unique chemical composition of basic elements such as H20 for water. Larger numbers may be factored using a vertical format. Example C. Factor 144 completely. (Vertical format) 144 12 12 3 4 3 4 2 22 2 Gather all the prime numbers at the end of the branches we have 144 = 3*3*2*2*2*2 = 3224. Note that we obtain the same answer regardless how we factor at each step. Your Turn: Factor 72 completely.
  • 52. Basic Laws Of the four arithmetic operations +, – , *, and ÷, +, and * behave nicer than – or ÷.
  • 53. Basic Laws Of the four arithmetic operations +, – , *, and ÷, +, and * behave nicer than – or ÷. We often take advantage of the this nice “behavior” of the addition and multiplication operations to get short cuts.
  • 54. Basic Laws Of the four arithmetic operations +, – , *, and ÷, +, and * behave nicer than – or ÷. We often take advantage of the this nice “behavior” of the addition and multiplication operations to get short cuts. However, be sure you don’t mistakenly apply these short cuts to – and ÷.
  • 55. Associative Law for Addition and Multiplication Basic Laws Of the four arithmetic operations +, – , *, and ÷, +, and * behave nicer than – or ÷. We often take advantage of the this nice “behavior” of the addition and multiplication operations to get short cuts. However, be sure you don’t mistakenly apply these short cuts to – and ÷.
  • 56. Associative Law for Addition and Multiplication ( a + b ) + c = a + ( b + c ) ( a * b ) * c = a * ( b * c ) Note: We are to perform the operations inside the “( )” first. Basic Laws Of the four arithmetic operations +, – , *, and ÷, +, and * behave nicer than – or ÷. We often take advantage of the this nice “behavior” of the addition and multiplication operations to get short cuts. However, be sure you don’t mistakenly apply these short cuts to – and ÷.
  • 57. Associative Law for Addition and Multiplication ( a + b ) + c = a + ( b + c ) ( a * b ) * c = a * ( b * c ) Note: We are to perform the operations inside the “( )” first. For example, (1 + 2) + 3 1 + (2 + 3) Basic Laws Of the four arithmetic operations +, – , *, and ÷, +, and * behave nicer than – or ÷. We often take advantage of the this nice “behavior” of the addition and multiplication operations to get short cuts. However, be sure you don’t mistakenly apply these short cuts to – and ÷.
  • 58. Associative Law for Addition and Multiplication ( a + b ) + c = a + ( b + c ) ( a * b ) * c = a * ( b * c ) Note: We are to perform the operations inside the “( )” first. For example, (1 + 2) + 3 = 3 + 3 = 6, 1 + (2 + 3) Basic Laws Of the four arithmetic operations +, – , *, and ÷, +, and * behave nicer than – or ÷. We often take advantage of the this nice “behavior” of the addition and multiplication operations to get short cuts. However, be sure you don’t mistakenly apply these short cuts to – and ÷.
  • 59. Associative Law for Addition and Multiplication ( a + b ) + c = a + ( b + c ) ( a * b ) * c = a * ( b * c ) Note: We are to perform the operations inside the “( )” first. For example, (1 + 2) + 3 = 3 + 3 = 6, 1 + (2 + 3) = 1 + 5 = 6. Basic Laws Of the four arithmetic operations +, – , *, and ÷, +, and * behave nicer than – or ÷. We often take advantage of the this nice “behavior” of the addition and multiplication operations to get short cuts. However, be sure you don’t mistakenly apply these short cuts to – and ÷.
  • 60. Associative Law for Addition and Multiplication ( a + b ) + c = a + ( b + c ) ( a * b ) * c = a * ( b * c ) Note: We are to perform the operations inside the “( )” first. For example, (1 + 2) + 3 = 3 + 3 = 6, which is the same as 1 + (2 + 3) = 1 + 5 = 6. Basic Laws Of the four arithmetic operations +, – , *, and ÷, +, and * behave nicer than – or ÷. We often take advantage of the this nice “behavior” of the addition and multiplication operations to get short cuts. However, be sure you don’t mistakenly apply these short cuts to – and ÷. So if you want to total the money in your pockets, it does not matter which two pockets you add first.
  • 61. Associative Law for Addition and Multiplication ( a + b ) + c = a + ( b + c ) ( a * b ) * c = a * ( b * c ) Note: We are to perform the operations inside the “( )” first. For example, (1 + 2) + 3 = 3 + 3 = 6, which is the same as 1 + (2 + 3) = 1 + 5 = 6. Subtraction and division are not associative. Basic Laws Of the four arithmetic operations +, – , *, and ÷, +, and * behave nicer than – or ÷. We often take advantage of the this nice “behavior” of the addition and multiplication operations to get short cuts. However, be sure you don’t mistakenly apply these short cuts to – and ÷. So if you want to total the money in your pockets, it does not matter which two pockets you add first.
  • 62. Associative Law for Addition and Multiplication ( a + b ) + c = a + ( b + c ) ( a * b ) * c = a * ( b * c ) Note: We are to perform the operations inside the “( )” first. For example, (1 + 2) + 3 = 3 + 3 = 6, which is the same as 1 + (2 + 3) = 1 + 5 = 6. Subtraction and division are not associative. For example, ( 3 – 2 ) – 1 3 – ( 2 – 1 ) Basic Laws Of the four arithmetic operations +, – , *, and ÷, +, and * behave nicer than – or ÷. We often take advantage of the this nice “behavior” of the addition and multiplication operations to get short cuts. However, be sure you don’t mistakenly apply these short cuts to – and ÷. So if you want to total the money in your pockets, it does not matter which two pockets you add first.
  • 63. Associative Law for Addition and Multiplication ( a + b ) + c = a + ( b + c ) ( a * b ) * c = a * ( b * c ) Note: We are to perform the operations inside the “( )” first. For example, (1 + 2) + 3 = 3 + 3 = 6, which is the same as 1 + (2 + 3) = 1 + 5 = 6. Subtraction and division are not associative. For example, ( 3 – 2 ) – 1 = 0 3 – ( 2 – 1 ) Basic Laws Of the four arithmetic operations +, – , *, and ÷, +, and * behave nicer than – or ÷. We often take advantage of the this nice “behavior” of the addition and multiplication operations to get short cuts. However, be sure you don’t mistakenly apply these short cuts to – and ÷. So if you want to total the money in your pockets, it does not matter which two pockets you add first.
  • 64. Associative Law for Addition and Multiplication ( a + b ) + c = a + ( b + c ) ( a * b ) * c = a * ( b * c ) Note: We are to perform the operations inside the “( )” first. For example, (1 + 2) + 3 = 3 + 3 = 6, which is the same as 1 + (2 + 3) = 1 + 5 = 6. Subtraction and division are not associative. For example, ( 3 – 2 ) – 1 = 0 is different from 3 – ( 2 – 1 ) = 2. Basic Laws Of the four arithmetic operations +, – , *, and ÷, +, and * behave nicer than – or ÷. We often take advantage of the this nice “behavior” of the addition and multiplication operations to get short cuts. However, be sure you don’t mistakenly apply these short cuts to – and ÷. So if you want to total the money in your pockets, it does not matter which two pockets you add first.
  • 65. Basic Laws Commutative Law for Addition and Multiplication
  • 66. Commutative Law for Addition and Multiplication a + b = b + a a * b = b * a Basic Laws
  • 67. Commutative Law for Addition and Multiplication a + b = b + a a * b = b * a For example, 3*4 = 4*3 = 12. Basic Laws
  • 68. Commutative Law for Addition and Multiplication a + b = b + a a * b = b * a For example, 3*4 = 4*3 = 12. Subtraction and division don't satisfy commutative laws. Basic Laws
  • 69. Commutative Law for Addition and Multiplication a + b = b + a a * b = b * a For example, 3*4 = 4*3 = 12. Subtraction and division don't satisfy commutative laws. For example: 2  1  1  2. Basic Laws
  • 70. Commutative Law for Addition and Multiplication a + b = b + a a * b = b * a For example, 3*4 = 4*3 = 12. Subtraction and division don't satisfy commutative laws. For example: 2  1  1  2. From the above laws, we get the following important facts. Basic Laws
  • 71. Commutative Law for Addition and Multiplication a + b = b + a a * b = b * a For example, 3*4 = 4*3 = 12. Subtraction and division don't satisfy commutative laws. For example: 2  1  1  2. From the above laws, we get the following important facts. When adding, the order of addition doesn’t matter. Basic Laws
  • 72. Commutative Law for Addition and Multiplication a + b = b + a a * b = b * a For example, 3*4 = 4*3 = 12. Subtraction and division don't satisfy commutative laws. For example: 2  1  1  2. From the above laws, we get the following important facts. When adding, the order of addition doesn’t matter. Hence to take advantages of this when adding a list numbers, it's easier to add the ones that add to multiples of 10 first. Basic Laws
  • 73. Commutative Law for Addition and Multiplication a + b = b + a a * b = b * a For example, 3*4 = 4*3 = 12. Subtraction and division don't satisfy commutative laws. For example: 2  1  1  2. From the above laws, we get the following important facts. When adding, the order of addition doesn’t matter. Hence to take advantages of this when adding a list numbers, it's easier to add the ones that add to multiples of 10 first. Example D. 14 + 3 + 16 + 8 + 35 + 15 Basic Laws
  • 74. Commutative Law for Addition and Multiplication a + b = b + a a * b = b * a For example, 3*4 = 4*3 = 12. Subtraction and division don't satisfy commutative laws. For example: 2  1  1  2. From the above laws, we get the following important facts. When adding, the order of addition doesn’t matter. Hence to take advantages of this when adding a list numbers, it's easier to add the ones that add to multiples of 10 first. Example D. 14 + 3 + 16 + 8 + 35 + 15 = 30 Basic Laws
  • 75. Commutative Law for Addition and Multiplication a + b = b + a a * b = b * a For example, 3*4 = 4*3 = 12. Subtraction and division don't satisfy commutative laws. For example: 2  1  1  2. From the above laws, we get the following important facts. When adding, the order of addition doesn’t matter. Hence to take advantages of this when adding a list numbers, it's easier to add the ones that add to multiples of 10 first. Example D. 14 + 3 + 16 + 8 + 35 + 15 = 30 + 50 Basic Laws
  • 76. Commutative Law for Addition and Multiplication a + b = b + a a * b = b * a For example, 3*4 = 4*3 = 12. Subtraction and division don't satisfy commutative laws. For example: 2  1  1  2. From the above laws, we get the following important facts. When adding, the order of addition doesn’t matter. Hence to take advantages of this when adding a list numbers, it's easier to add the ones that add to multiples of 10 first. Example D. 14 + 3 + 16 + 8 + 35 + 15 = 30 + 11 + 50 Basic Laws
  • 77. Commutative Law for Addition and Multiplication a + b = b + a a * b = b * a For example, 3*4 = 4*3 = 12. Subtraction and division don't satisfy commutative laws. For example: 2  1  1  2. From the above laws, we get the following important facts. When adding, the order of addition doesn’t matter. Hence to take advantages of this when adding a list numbers, it's easier to add the ones that add to multiples of 10 first. Example D. 14 + 3 + 16 + 8 + 35 + 15 = 30 + 11 + 50 = 91 Basic Laws
  • 78. Basic Laws When multiplying, the order of multiplication doesn’t matter.
  • 79. Basic Laws When multiplying, the order of multiplication doesn’t matter. When multiplying many numbers, always multiply them in pairs first.
  • 80. Basic Laws When multiplying, the order of multiplication doesn’t matter. When multiplying many numbers, always multiply them in pairs first. This is useful for raising exponents.
  • 81. Basic Laws When multiplying, the order of multiplication doesn’t matter. Example E. 36 When multiplying many numbers, always multiply them in pairs first. This is useful for raising exponents.
  • 82. Basic Laws When multiplying, the order of multiplication doesn’t matter. Example E. 36 = 3*3*3*3*3*3 When multiplying many numbers, always multiply them in pairs first. This is useful for raising exponents.
  • 83. Basic Laws When multiplying, the order of multiplication doesn’t matter. Example E. 36 = 3*3*3*3*3*3 = 9 * 9 * 9 When multiplying many numbers, always multiply them in pairs first. This is useful for raising exponents.
  • 84. Basic Laws When multiplying, the order of multiplication doesn’t matter. Example E. 36 = 3*3*3*3*3*3 = 9 * 9 * 9 = 81 * 9 = 729 When multiplying many numbers, always multiply them in pairs first. This is useful for raising exponents.
  • 85. Basic Laws When multiplying, the order of multiplication doesn’t matter. Example E. 36 = 3*3*3*3*3*3 = 9 * 9 * 9 = 81 * 9 = 729 When multiplying many numbers, always multiply them in pairs first. This is useful for raising exponents. Because the order of the additions (or multiplications) may be scrambled, this offers a strategy to check our answers– do it in two different ways.
  • 86. Basic Laws When multiplying, the order of multiplication doesn’t matter. Example E. 36 = 3*3*3*3*3*3 = 9 * 9 * 9 = 81 * 9 = 729 When multiplying many numbers, always multiply them in pairs first. This is useful for raising exponents. Because the order of the additions (or multiplications) may be scrambled, this offers a strategy to check our answers– do it in two different ways. If both yield the same answer, it’s likely the answer is correct.
  • 87. Basic Laws When multiplying, the order of multiplication doesn’t matter. Example E. 36 = 3*3*3*3*3*3 = 9 * 9 * 9 = 81 * 9 = 729 When multiplying many numbers, always multiply them in pairs first. This is useful for raising exponents. Because the order of the additions (or multiplications) may be scrambled, this offers a strategy to check our answers– do it in two different ways. If both yield the same answer, it’s likely the answer is correct. If the two outcomes are different, then some thing went wrong, find it and correct it.
  • 89. Basic Laws The are two $10–bills and three $5–bills in a box. The Distributive Law
  • 90. Basic Laws The are two $10–bills and three $5–bills in a box. So there is the total of 2x10=20 plus 3x5=15, or $35, in the box which is recorded as (20+15) = 35. The Distributive Law
  • 91. Basic Laws The are two $10–bills and three $5–bills in a box. So there is the total of 2x10=20 plus 3x5=15, or $35, in the box which is recorded as (20+15) = 35. Suppose we have 4 of these boxes, there are two methods to find their total: The Distributive Law
  • 92. Basic Laws The are two $10–bills and three $5–bills in a box. So there is the total of 2x10=20 plus 3x5=15, or $35, in the box which is recorded as (20+15) = 35. Suppose we have 4 of these boxes, there are two methods to find their total: I. Each box has $35 so 4 boxes have 4x35=$140 in total. The Distributive Law
  • 93. Basic Laws The are two $10–bills and three $5–bills in a box. So there is the total of 2x10=20 plus 3x5=15, or $35, in the box which is recorded as (20+15) = 35. Suppose we have 4 of these boxes, there are two methods to find their total: I. Each box has $35 so 4 boxes have 4x35=$140 in total. The Distributive Law Recording these with symbols: 4(20+15) = 4(35) = 140
  • 94. Basic Laws The are two $10–bills and three $5–bills in a box. So there is the total of 2x10=20 plus 3x5=15, or $35, in the box which is recorded as (20+15) = 35. Suppose we have 4 of these boxes, there are two methods to find their total: I. Each box has $35 so 4 boxes have 4x35=$140 in total. II. Unpack the boxes, there are 4x20=$80 from the $10-bills, and 4x15=$60 from the $5-bills, which total to $140. The Distributive Law Recording these with symbols: 4(20+15) = 4(35) = 140
  • 95. Basic Laws The are two $10–bills and three $5–bills in a box. So there is the total of 2x10=20 plus 3x5=15, or $35, in the box which is recorded as (20+15) = 35. Suppose we have 4 of these boxes, there are two methods to find their total: I. Each box has $35 so 4 boxes have 4x35=$140 in total. II. Unpack the boxes, there are 4x20=$80 from the $10-bills, and 4x15=$60 from the $5-bills, which total to $140. The Distributive Law Recording these with symbols: 4(20+15) = 4(35) or 4(20+15) = 4(20) + 4(15) = 140
  • 96. Basic Laws The are two $10–bills and three $5–bills in a box. So there is the total of 2x10=20 plus 3x5=15, or $35, in the box which is recorded as (20+15) = 35. Suppose we have 4 of these boxes, there are two methods to find their total: I. Each box has $35 so 4 boxes have 4x35=$140 in total. II. Unpack the boxes, there are 4x20=$80 from the $10-bills, and 4x15=$60 from the $5-bills, which total to $140. The Distributive Law Recording these with symbols: The point here is that these two ways of totaling always yield the same result, not which is easier. 4(20+15) = 4(35) or 4(20+15) = 4(20) + 4(15) = 140
  • 97. Basic Laws The are two $10–bills and three $5–bills in a box. So there is the total of 2x10=20 plus 3x5=15, or $35, in the box which is recorded as (20+15) = 35. Suppose we have 4 of these boxes, there are two methods to find their total: I. Each box has $35 so 4 boxes have 4x35=$140 in total. II. Unpack the boxes, there are 4x20=$80 from the $10-bills, and 4x15=$60 from the $5-bills, which total to $140. The Distributive Law Recording these with symbols: The point here is that these two ways of totaling always yield the same result, not which is easier. 4(20+15) = 4(35) or 4(20+15) = 4(20) + 4(15) = 140 The fact that these two ways are “identical" and that there are two forms associated with the two ways is important. Let’s redo this in symbols.
  • 98. Basic Laws The are two $10–bills and three $5–bills in a box. So there is the total of 2x10=20 plus 3x5=15, or $35, in the box which is recorded as (20+15) = 35. Suppose we have 4 of these boxes, there are two methods to find their total: I. Each box has $35 so 4 boxes have 4x35=$140 in total. II. Unpack the boxes, there are 4x20=$80 from the $10-bills, and 4x15=$60 from the $5-bills, which total to $140. The Distributive Law Recording these with symbols: The point here is that these two ways of totaling always yield the same result, not which is easier. 4(20+15) = 4(35) or 4(20+15) = 4(20) + 4(15) = 140 The fact that these two ways are identical and that there two forms associated with the two ways is important. Let’s redo this in symbols.
  • 99. Basic Laws The are two $10–bills and three $5–bills in a box. So there is the total of 2x10=20 plus 3x5=15, or $35, in the box which is recorded as (20+15) = 35. Suppose we have 4 of these boxes, there are two methods to find their total: I. Each box has $35 so 4 boxes have 4x35=$140 in total. II. Unpack the boxes, there are 4x20=$80 from the $10-bills, and 4x15=$60 from the $5-bills, which total to $140. The Distributive Law Recording these with symbols: The point here is that these two ways of totaling always yield the same result, not which is easier. 4(20+15) = 4(35) or 4(20+15) = 4(20) + 4(15) = 140 The fact that these two ways are identical and that there two forms associated with the two ways is important. Let’s redo this in symbols.
  • 101. Basic Laws There are two $10–bills and three $5–bills in a box. The Distributive Law
  • 102. Basic Laws There are two $10–bills and three $5–bills in a box. Using the letter T to represent a $10–bill and F for a $5–bill, we may represent this box as (2T + 3F). The Distributive Law
  • 103. Basic Laws There are two $10–bills and three $5–bills in a box. Using the letter T to represent a $10–bill and F for a $5–bill, we may represent this box as (2T + 3F). If we have four of these boxes, we may record them as 4(2T + 3F). The Distributive Law
  • 104. Basic Laws There are two $10–bills and three $5–bills in a box. Using the letter T to represent a $10–bill and F for a $5–bill, we may represent this box as (2T + 3F). If we have four of these boxes, we may record them as 4(2T + 3F). We open all the boxes and take out all the bills, there are 4 sets of 2T’s or 8T’s The Distributive Law
  • 105. Basic Laws There are two $10–bills and three $5–bills in a box. Using the letter T to represent a $10–bill and F for a $5–bill, we may represent this box as (2T + 3F). If we have four of these boxes, we may record them as 4(2T + 3F). We open all the boxes and take out all the bills, there are 4 sets of 2T’s or 8T’s and 4 sets of 3F’s or 12F’s. The Distributive Law
  • 106. Basic Laws There are two $10–bills and three $5–bills in a box. Using the letter T to represent a $10–bill and F for a $5–bill, we may represent this box as (2T + 3F). If we have four of these boxes, we may record them as 4(2T + 3F). We open all the boxes and take out all the bills, there are 4 sets of 2T’s or 8T’s and 4 sets of 3F’s or 12F’s. We track this unpacking or expanding procedure, as 4(2T + 3F) = 4*2T + 4*3F = 8T + 12F The Distributive Law
  • 107. Basic Laws There are two $10–bills and three $5–bills in a box. Using the letter T to represent a $10–bill and F for a $5–bill, we may represent this box as (2T + 3F). If we have four of these boxes, we may record them as 4(2T + 3F). We open all the boxes and take out all the bills, there are 4 sets of 2T’s or 8T’s and 4 sets of 3F’s or 12F’s. We track this unpacking or expanding procedure, as 4(2T + 3F) = 4*2T + 4*3F = 8T + 12F The Distributive Law Expressing this operation in symbol we have the Distributive Law : a*(b ± c) = a*b ± a*c
  • 108. Basic Laws There are two $10–bills and three $5–bills in a box. Using the letter T to represent a $10–bill and F for a $5–bill, we may represent this box as (2T + 3F). If we have four of these boxes, we may record them as 4(2T + 3F). We open all the boxes and take out all the bills, there are 4 sets of 2T’s or 8T’s and 4 sets of 3F’s or 12F’s. We track this unpacking or expanding procedure, as 4(2T + 3F) = 4*2T + 4*3F = 8T + 12F The Distributive Law Expressing this operation in symbol we have the Distributive Law : a*(b ± c) = a*b ± a*c The “packed” form is the factored form. the factored form.
  • 109. Basic Laws There are two $10–bills and three $5–bills in a box. Using the letter T to represent a $10–bill and F for a $5–bill, we may represent this box as (2T + 3F). If we have four of these boxes, we may record them as 4(2T + 3F). We open all the boxes and take out all the bills, there are 4 sets of 2T’s or 8T’s and 4 sets of 3F’s or 12F’s. We track this unpacking or expanding procedure, as 4(2T + 3F) = 4*2T + 4*3F = 8T + 12F The Distributive Law Expressing this operation in symbol we have the Distributive Law : a*(b ± c) = a*b ± a*c The “packed” form is the factored form. The “unpacked” form is the expanded form. the factored form. the expanded form.
  • 110. Example E. A. A fruit basket contains 4 apples and 6 bananas, using A for “an apple” and B for "a banana“ write the expression for a fruit basket, Basic Laws
  • 111. Example E. A. A fruit basket contains 4 apples and 6 bananas, using A for “an apple” and B for "a banana“ write the expression for a fruit basket, Basic Laws The basket may be written as (4A + 6B).
  • 112. Example E. A. A fruit basket contains 4 apples and 6 bananas, using A for “an apple” and B for "a banana“ write the expression for a fruit basket, then write the expression for 5 such baskets. Basic Laws The basket may be written as (4A + 6B).
  • 113. Example E. A. A fruit basket contains 4 apples and 6 bananas, using A for “an apple” and B for "a banana“ write the expression for a fruit basket, then write the expression for 5 such baskets. Basic Laws The basket may be written as (4A + 6B). Five baskets are 5(4A + 6B)
  • 114. Example E. A. A fruit basket contains 4 apples and 6 bananas, using A for “an apple” and B for "a banana“ write the expression for a fruit basket, then write the expression for 5 such baskets. Expand the expression, how many apples and bananas do we have? Basic Laws The basket may be written as (4A + 6B). Five baskets are 5(4A + 6B)
  • 115. Example E. A. A fruit basket contains 4 apples and 6 bananas, using A for “an apple” and B for "a banana“ write the expression for a fruit basket, then write the expression for 5 such baskets. Expand the expression, how many apples and bananas do we have? Basic Laws The basket may be written as (4A + 6B). Five baskets are 5(4A + 6B), distribute the 5 and expand, 5(4A + 6B) = 5*4A + 5*6B
  • 116. Example E. A. A fruit basket contains 4 apples and 6 bananas, using A for “an apple” and B for "a banana“ write the expression for a fruit basket, then write the expression for 5 such baskets. Expand the expression, how many apples and bananas do we have? Basic Laws The basket may be written as (4A + 6B). Five baskets are 5(4A + 6B), distribute the 5 and expand, 5(4A + 6B) = 5*4A + 5*6B = 20A + 30B so that we have 20 apples and 30 bananas.
  • 117. Example E. A. A fruit basket contains 4 apples and 6 bananas, using A for “an apple” and B for "a banana“ write the expression for a fruit basket, then write the expression for 5 such baskets. Expand the expression, how many apples and bananas do we have? Basic Laws B. We unpack six fruit boxes and obtain 48 apples and 30 bananas. Record this amount using A and B (i.e. the expanded form), The basket may be written as (4A + 6B). Five baskets are 5(4A + 6B), distribute the 5 and expand, 5(4A + 6B) = 5*4A + 5*6B = 20A + 30B so that we have 20 apples and 30 bananas.
  • 118. Example E. A. A fruit basket contains 4 apples and 6 bananas, using A for “an apple” and B for "a banana“ write the expression for a fruit basket, then write the expression for 5 such baskets. Expand the expression, how many apples and bananas do we have? Basic Laws B. We unpack six fruit boxes and obtain 48 apples and 30 bananas. Record this amount using A and B (i.e. the expanded form), The basket may be written as (4A + 6B). Five baskets are 5(4A + 6B), distribute the 5 and expand, 5(4A + 6B) = 5*4A + 5*6B = 20A + 30B so that we have 20 apples and 30 bananas. The fruits may be recorded as 48A + 30B
  • 119. Example E. A. A fruit basket contains 4 apples and 6 bananas, using A for “an apple” and B for "a banana“ write the expression for a fruit basket, then write the expression for 5 such baskets. Expand the expression, how many apples and bananas do we have? Basic Laws B. We unpack six fruit boxes and obtain 48 apples and 30 bananas. Record this amount using A and B (i.e. the expanded form), then write it in the factored form (i.e. as 6 packed boxes). What were in each box? The basket may be written as (4A + 6B). Five baskets are 5(4A + 6B), distribute the 5 and expand, 5(4A + 6B) = 5*4A + 5*6B = 20A + 30B so that we have 20 apples and 30 bananas. The fruits may be recorded as 48A + 30B
  • 120. Example E. A. A fruit basket contains 4 apples and 6 bananas, using A for “an apple” and B for "a banana“ write the expression for a fruit basket, then write the expression for 5 such baskets. Expand the expression, how many apples and bananas do we have? Basic Laws B. We unpack six fruit boxes and obtain 48 apples and 30 bananas. Record this amount using A and B (i.e. the expanded form), then write it in the factored form (i.e. as 6 packed boxes). What were in each box? The basket may be written as (4A + 6B). Five baskets are 5(4A + 6B), distribute the 5 and expand, 5(4A + 6B) = 5*4A + 5*6B = 20A + 30B so that we have 20 apples and 30 bananas. The fruits may be recorded as 48A + 30B, packed in six baskets, so each has 48/6 = 8 apples and 30/6 = 5 bananas,
  • 121. Example E. A. A fruit basket contains 4 apples and 6 bananas, using A for “an apple” and B for "a banana“ write the expression for a fruit basket, then write the expression for 5 such baskets. Expand the expression, how many apples and bananas do we have? Basic Laws B. We unpack six fruit boxes and obtain 48 apples and 30 bananas. Record this amount using A and B (i.e. the expanded form), then write it in the factored form (i.e. as 6 packed boxes). What were in each box? The basket may be written as (4A + 6B). Five baskets are 5(4A + 6B), distribute the 5 and expand, 5(4A + 6B) = 5*4A + 5*6B = 20A + 30B so that we have 20 apples and 30 bananas. The fruits may be recorded as 48A + 30B, packed in six baskets, so each has 48/6 = 8 apples and 30/6 = 5 bananas, hence 48A + 30B = 6(8A + 5B) in the factored form.
  • 122. Exercise A. Do the following problems two ways. * Add the following by summing the multiples of 10 first. * Add by adding in the order. to find the correct answer. 1. 3 + 5 + 7 2. 8 + 6 + 2 3. 1 + 8 + 9 4. 3 + 5 + 15 5. 9 + 14 + 6 6. 22 + 5 + 8 7. 16 + 5 + 4 + 3 8. 4 + 13 + 5 + 7 9. 19 + 7 + 1 + 3 10. 4 + 5 + 17 + 3 11. 23 + 5 + 17 + 3 12. 22 + 5 + 13 + 28 13. 35 + 6 + 15 + 7 + 14 14. 42 + 5 + 18 + 12 15. 21 + 16 + 19 + 7 + 44 16. 53 + 5 + 18 + 27 + 22 17. 155 + 16 + 25 + 7 + 344 18. 428 + 3 + 32 + 227 + 22 Basic Laws
  • 123. Basic Laws 19. List the all the factors and the first 4 multiples of the following numbers. 6, 9, 10, 15, 16, 24, 30, 36, 42, 56, 60. B. Calculate. 1. 33 2. 42 3. 52 4. 53 5. 62 6. 63 7. 72 8. 82 9. 92 10. 102 11. 103 12. 104 13. 105 14. 1002 15. 1003 16. 1004 17. 112 18. 122 20. Factor completely and arrange the factors from smallest to the largest in the exponential notation: 4, 8, 12, 16, 18, 24, 27, 32, 36, 45, 48, 56, 60, 63, 72, 75, 81, 120. 21. 3 * 5 * 4 * 2 22. 6 * 5 * 4 * 3 23. 6 * 15 * 3 * 2 24. 7 * 5 * 5 * 4 25. 6 * 7 * 4 * 3 26. 9 * 3 * 4 * 4 27. 2 * 25 * 3 * 4 * 2 28. 3 * 2 * 3 * 3 * 2 * 4 29. 3 * 5 * 2 * 5 * 2 * 4 30. 4 * 2 * 3 * 15 * 8 * 4 31. 24 32. 25 33. 26 34. 27 35. 28 36. 29 37. 210 38. 34 39. 35 40. 36 C. Multiply in two ways to find the correct answer.
  • 124. Basic Laws D. Packing and unpacking problems. 21. 3 * 5 * 4 * 2
  • 125. The Basics Factor 72 completely: 72 = 2*2*2*3*3 72 6 12 2 3 3 4 2 2 The factors of 18: 1, 2, 3, 6, 9, and 18. The multiples of 18: 18=1x18, 36=2x18, 54=3x18, 72, 90, etc… Answers to “Your Turn”: Calculate 24 = 16, 34 = 9*9 = 81, 44 = 16*16 =256 and 2*4 = 8, 3*4 = 12, 4*4 = 16