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WHAT IS IT?
WHEN DO WE USE IT?
•When we compare the means of two
independent groups
•When the data are normally distributed,
Sk=0 and Ku=0.265
•When data are expressed in interval and
ratio
•When the sample is less than 30
HOW DO WE USE IT?
EXAMPLE 1
The following are the scores in spelling of
10 male and 10 female AB students. Test
the null hypothesis that there is no
significant difference between the
performance of male and female AB
students in spelling. Use the t-test at .05
level of significance.
Male () Female ()
14 12
18 9
17 11
16 5
4 10
14 3
12 7
10 2
9 6
17 13
Male () ( Female ()
14 196 12
18 324 9
17 289 11
16 256 5
4 16 10
14 196 3
12 144 7
10 100 2
9 81 6
17 289 13
Male () ( Female () (
14 196 12 144
18 324 9 81
17 289 11 121
16 256 5 25
4 16 10 100
14 196 3 9
12 144 7 49
10 100 2 4
9 81 6 36
17 289 13 169
Male () ( Female () (
14 196 12 144
18 324 9 81
17 289 11 121
16 256 5 25
4 16 10 100
14 196 3 9
12 144 7 49
10 100 2 4
9 81 6 36
17 289 13 169
= 131 = 1891 = 78 =738
DETERMINE THE NUMBER OF
OBSERVATIONS
COMPUTE THE MEANS
CALCULATE TEST STATISTIC
STEPWISE METHOD
I. PROBLEM
Is there a significant
difference between the
performance of the male and
the female AB students in
spelling?
II. HYPOTHESES
III. LEVEL OF SIGNIFICANCE
IV. STATISTICS
T-test for two independent
samples
V. DECISION RULE
VI. CONCLUSION
Since the t-computed value of 2.88 is greater than
the t-tabular value of 2.101 at .05 level of
significance with 18 degrees of freedom, the null
hypothesis is disconfirmed. This means that there is
a significant difference between the performance of
the male and the female AB students in spelling
implying that the male students performed better
than the female students considering that the mean
score of the male student of 13.1 is greater
compared to the average score of female students of
EXAMPLE 2
Two groups of experimental rats were
injected with a tranquilizer at 1.0 mg and
1.5 mg dose respectively. The time given
in seconds that look them fall asleep is
hereby given. At .01 level of significance,
test the null hypothesis that the difference
in dosage has no effect on the length of
time it took to them to fall asleep.
1.0 mg dose () 1.5 mg dose ()
9.8 12.0
13.2 7.4
11.2 9.8
9.5 11.5
13.0 13.0
12.1 12.5
9.8 9.8
12.3 10.5
7.9 13.5
10.2
9.7
1.0 mg dose () ( 1.5 mg dose ()
9.8 96.04 12.0
13.2 174.24 7.4
11.2 125.44 9.8
9.5 90.25 11.5
13.0 169.00 13.0
12.1 146.41 12.5
9.8 96.04 9.8
12.3 151.29 10.5
7.9 62.41 13.5
10.2 104.04
9.7 94.09
1.0 mg dose () ( 1.5 mg dose () (
9.8 96.04 12.0 144.00
13.2 174.24 7.4 54.76
11.2 125.44 9.8 96.04
9.5 90.25 11.5 132.25
13.0 169.00 13.0 169.00
12.1 146.41 12.5 156.25
9.8 96.04 9.8 96.04
12.3 151.29 10.5 110.25
7.9 62.41 13.5 182.25
10.2 104.04
9.7 94.09
1.0 mg dose () ( 1.5 mg dose () (
9.8 96.04 12.0 144.00
13.2 174.24 7.4 54.76
11.2 125.44 9.8 96.04
9.5 90.25 11.5 132.25
13.0 169.00 13.0 169.00
12.1 146.41 12.5 156.25
9.8 96.04 9.8 96.04
12.3 151.29 10.5 110.25
7.9 62.41 13.5 182.25
10.2 104.04
9.7 94.09
= 118.7 = 1309.25 = 100 =1140.84
DETERMINE THE NUMBER OF
OBSERVATIONS
COMPUTE THE MEANS
CALCULATE TEST STATISTIC
STEPWISE METHOD
I. PROBLEM
Is there a significant
difference brought about by
the dosages on the length of
time it took for the rats to fall
asleep?
II. HYPOTHESES
III. LEVEL OF SIGNIFICANCE
IV. STATISTICS
T-test for two independent
samples
V. DECISION RULE
VI. CONCLUSION
Since the t-computed value of -0.40 is
within the critical value of -2.878 at
.01 level of significance with 18
degrees of freedom, the null
hypothesis is confirmed. This means
that no significant difference was
bought about by the dosages on the
EXAMPLE 1
The mean score in spelling of 10 males is
13.1 and standard deviation 4.108, while
10 females have a mean score of 7.8 and
standard deviation 3.795 . Test the null
hypothesis that there is no significant
difference between the performance of
male and female AB students in spelling.
Use the t-test at .05 level of significance.
GIVEN:
CALCULATE TEST STATISTIC
EXAMPLE 2
Two groups of experimental rats were
injected with a tranquilizer at 1.0 mg have
the average time of 10.79 seconds and
standard deviation of 1.684, and 1.5 mg
have the average time of 11.11 seconds and
standard deviation of 1.928. 11 rats were
injected by 1.0 mg and 9 rats by 1.5 mg. At
.01 level of significance, test the null
hypothesis that the difference in dosage has
no effect on the length of time it took to
GIVEN:
CALCULATE TEST STATISTIC
QUIZ
SOLVE THE FOLLOWING AND
USE STEPWISE METHOD.
1. A Math teacher wants to compare the male
and female in his, if they performed
differently on the tests he gave last semester.
The scores of male and female is hereby
given. Use the t-test for two independent
samples at .05 level of significance to test the
null hypothesis that there is no significant
difference in the performance of Class A and
Class B in the test given last semester.
Male 13.3, 6.0, 20.0, 8.0, 14.0, 19.0, 18.0, 25.0,
16.0, 24.0, 15.0, 1.0, 15.0
Female 22.0, 16.0, 21.7, 21.0, 30.0, 26.0, 12.0,
23.2, 28.0, 23.0
2. A statistic teacher wants to compare his
two classes to see if they performed any
differently on the tests he gave. Class A
had 15 students with an average score of
70, standard deviation 15. Class B had 14
students with an average score of 74,
standard deviation 25. Using alpha .05,
did these two classes perform differently
on the tests?
T-TABLE
THANK YOU SO
MUCH!

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T-test for two independent samples.pptx

  • 1.
  • 3. WHEN DO WE USE IT? •When we compare the means of two independent groups •When the data are normally distributed, Sk=0 and Ku=0.265 •When data are expressed in interval and ratio •When the sample is less than 30
  • 4. HOW DO WE USE IT?
  • 5.
  • 6. EXAMPLE 1 The following are the scores in spelling of 10 male and 10 female AB students. Test the null hypothesis that there is no significant difference between the performance of male and female AB students in spelling. Use the t-test at .05 level of significance.
  • 7. Male () Female () 14 12 18 9 17 11 16 5 4 10 14 3 12 7 10 2 9 6 17 13 Male () ( Female () 14 196 12 18 324 9 17 289 11 16 256 5 4 16 10 14 196 3 12 144 7 10 100 2 9 81 6 17 289 13 Male () ( Female () ( 14 196 12 144 18 324 9 81 17 289 11 121 16 256 5 25 4 16 10 100 14 196 3 9 12 144 7 49 10 100 2 4 9 81 6 36 17 289 13 169 Male () ( Female () ( 14 196 12 144 18 324 9 81 17 289 11 121 16 256 5 25 4 16 10 100 14 196 3 9 12 144 7 49 10 100 2 4 9 81 6 36 17 289 13 169 = 131 = 1891 = 78 =738
  • 8. DETERMINE THE NUMBER OF OBSERVATIONS COMPUTE THE MEANS
  • 9.
  • 12. I. PROBLEM Is there a significant difference between the performance of the male and the female AB students in spelling?
  • 14. III. LEVEL OF SIGNIFICANCE
  • 15. IV. STATISTICS T-test for two independent samples
  • 17. VI. CONCLUSION Since the t-computed value of 2.88 is greater than the t-tabular value of 2.101 at .05 level of significance with 18 degrees of freedom, the null hypothesis is disconfirmed. This means that there is a significant difference between the performance of the male and the female AB students in spelling implying that the male students performed better than the female students considering that the mean score of the male student of 13.1 is greater compared to the average score of female students of
  • 18. EXAMPLE 2 Two groups of experimental rats were injected with a tranquilizer at 1.0 mg and 1.5 mg dose respectively. The time given in seconds that look them fall asleep is hereby given. At .01 level of significance, test the null hypothesis that the difference in dosage has no effect on the length of time it took to them to fall asleep.
  • 19. 1.0 mg dose () 1.5 mg dose () 9.8 12.0 13.2 7.4 11.2 9.8 9.5 11.5 13.0 13.0 12.1 12.5 9.8 9.8 12.3 10.5 7.9 13.5 10.2 9.7 1.0 mg dose () ( 1.5 mg dose () 9.8 96.04 12.0 13.2 174.24 7.4 11.2 125.44 9.8 9.5 90.25 11.5 13.0 169.00 13.0 12.1 146.41 12.5 9.8 96.04 9.8 12.3 151.29 10.5 7.9 62.41 13.5 10.2 104.04 9.7 94.09 1.0 mg dose () ( 1.5 mg dose () ( 9.8 96.04 12.0 144.00 13.2 174.24 7.4 54.76 11.2 125.44 9.8 96.04 9.5 90.25 11.5 132.25 13.0 169.00 13.0 169.00 12.1 146.41 12.5 156.25 9.8 96.04 9.8 96.04 12.3 151.29 10.5 110.25 7.9 62.41 13.5 182.25 10.2 104.04 9.7 94.09 1.0 mg dose () ( 1.5 mg dose () ( 9.8 96.04 12.0 144.00 13.2 174.24 7.4 54.76 11.2 125.44 9.8 96.04 9.5 90.25 11.5 132.25 13.0 169.00 13.0 169.00 12.1 146.41 12.5 156.25 9.8 96.04 9.8 96.04 12.3 151.29 10.5 110.25 7.9 62.41 13.5 182.25 10.2 104.04 9.7 94.09 = 118.7 = 1309.25 = 100 =1140.84
  • 20. DETERMINE THE NUMBER OF OBSERVATIONS COMPUTE THE MEANS
  • 21.
  • 24. I. PROBLEM Is there a significant difference brought about by the dosages on the length of time it took for the rats to fall asleep?
  • 26. III. LEVEL OF SIGNIFICANCE
  • 27. IV. STATISTICS T-test for two independent samples
  • 29. VI. CONCLUSION Since the t-computed value of -0.40 is within the critical value of -2.878 at .01 level of significance with 18 degrees of freedom, the null hypothesis is confirmed. This means that no significant difference was bought about by the dosages on the
  • 30.
  • 31.
  • 32. EXAMPLE 1 The mean score in spelling of 10 males is 13.1 and standard deviation 4.108, while 10 females have a mean score of 7.8 and standard deviation 3.795 . Test the null hypothesis that there is no significant difference between the performance of male and female AB students in spelling. Use the t-test at .05 level of significance.
  • 34.
  • 36. EXAMPLE 2 Two groups of experimental rats were injected with a tranquilizer at 1.0 mg have the average time of 10.79 seconds and standard deviation of 1.684, and 1.5 mg have the average time of 11.11 seconds and standard deviation of 1.928. 11 rats were injected by 1.0 mg and 9 rats by 1.5 mg. At .01 level of significance, test the null hypothesis that the difference in dosage has no effect on the length of time it took to
  • 38.
  • 40. QUIZ SOLVE THE FOLLOWING AND USE STEPWISE METHOD.
  • 41. 1. A Math teacher wants to compare the male and female in his, if they performed differently on the tests he gave last semester. The scores of male and female is hereby given. Use the t-test for two independent samples at .05 level of significance to test the null hypothesis that there is no significant difference in the performance of Class A and Class B in the test given last semester. Male 13.3, 6.0, 20.0, 8.0, 14.0, 19.0, 18.0, 25.0, 16.0, 24.0, 15.0, 1.0, 15.0 Female 22.0, 16.0, 21.7, 21.0, 30.0, 26.0, 12.0, 23.2, 28.0, 23.0
  • 42. 2. A statistic teacher wants to compare his two classes to see if they performed any differently on the tests he gave. Class A had 15 students with an average score of 70, standard deviation 15. Class B had 14 students with an average score of 74, standard deviation 25. Using alpha .05, did these two classes perform differently on the tests?